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CHXI11:THE P-BLOCK ELEMENTS

316712 Which of the following is obtained by catalytic oxidation of ammonia?

1

N_{2} O

2

NO

3

{HNO}_{2}

4

N O_{2}

Explanation:

Nitric oxide (NO) is obtained by catalytic oxidation of ammonia. The catalytic oxidation of ammonia uses a metal catalyst such as platinum, copper or nickel. This metal catalyst is heated, so that ammonia can reduce it, oxygen added to the system can then oxidise the ammonia, forming nitric oxide.
$4N H_{3} + 5 O_{2} \to_{800 - 90 0^{o} C}^{Pt guage} 4NO + 6 H_{2} O; + 21 .5 K cal .$

MHTCET - 2020

CHXI11:THE P-BLOCK ELEMENTS

316713 Ammonia reacts with Nessler's reagent to give

1 Deep blue precipitate

2 White precipitate

3 Green precipitate

4 Brown precipitate

Explanation:

Nessler's reagent is used to detect the ammonia and its compounds.
$A m m o n i a + N e s s l e r^{'} s r e a g e n t \to B r o w n p p t .$

CHXI11:THE P-BLOCK ELEMENTS

316714 A balanced chemical equation for the reaction showing catalytic oxidation of ${NH}_{3}$ by atmospheric oxygen is

1

4N H_{3} + \underset{(From air)}{5 O_{2}} \to_{500K, 9 bar}^{Pt/Rh gauge catalyst} 4NO + 6 H_{2} O

2

N H_{3} + \underset{(Fromair)}{O_{2}} \to_{500 K, 9bar}^{Pt/Rh gauge catalyst} NO  + H_{2} O

3

4 N H_{3} + \underset{(From air)}{10 O_{2}} \to_{\underset{}{500 K, 9 bar}}^{Pt/Rh gauge catalyst} 4 NO + 6 H_{2} O

4

4N H_{3} + \underset{(From air)}{5 O_{2}} \to_{\overset{}{500 K, 9 bar}}^{Pt/Rh gauge catalyst} 4NO  +  6 H_{2}

CHXI11:THE P-BLOCK ELEMENTS

316715 In qualitative analysis when $H_{2} S$ is passed through an aqueous solution of salt acidified with dil. $HCl$ , a black precipitate is obtained. On boiling the precipitate with dil. ${HNO}_{3}$ , it forms a solution of blue colour. Addition of excess of aqueous solution of ammonia to this solution gives

1 Deep blue precipitate of

Cu (OH)_{2}

2 Deep blue solution of

{[Cu {({NH}_{3})}_{4}]}^{2 +}

3 Deep blue solution of

Cu {({NO}_{3})}_{2}

4 Deep blue solution of

Cu (OH)_{2} \cdot Cu {({NO}_{3})}_{2}

Explanation:

Qualitative analysis of ${Cu}^{2 +}$ ion

CHXI11:THE P-BLOCK ELEMENTS

316712 Which of the following is obtained by catalytic oxidation of ammonia?

1

N_{2} O

2

NO

3

{HNO}_{2}

4

N O_{2}

Explanation:

Nitric oxide (NO) is obtained by catalytic oxidation of ammonia. The catalytic oxidation of ammonia uses a metal catalyst such as platinum, copper or nickel. This metal catalyst is heated, so that ammonia can reduce it, oxygen added to the system can then oxidise the ammonia, forming nitric oxide.
$4N H_{3} + 5 O_{2} \to_{800 - 90 0^{o} C}^{Pt guage} 4NO + 6 H_{2} O; + 21 .5 K cal .$

MHTCET - 2020

CHXI11:THE P-BLOCK ELEMENTS

316713 Ammonia reacts with Nessler's reagent to give

1 Deep blue precipitate

2 White precipitate

3 Green precipitate

4 Brown precipitate

Explanation:

Nessler's reagent is used to detect the ammonia and its compounds.
$A m m o n i a + N e s s l e r^{'} s r e a g e n t \to B r o w n p p t .$

CHXI11:THE P-BLOCK ELEMENTS

316714 A balanced chemical equation for the reaction showing catalytic oxidation of ${NH}_{3}$ by atmospheric oxygen is

1

4N H_{3} + \underset{(From air)}{5 O_{2}} \to_{500K, 9 bar}^{Pt/Rh gauge catalyst} 4NO + 6 H_{2} O

2

N H_{3} + \underset{(Fromair)}{O_{2}} \to_{500 K, 9bar}^{Pt/Rh gauge catalyst} NO  + H_{2} O

3

4 N H_{3} + \underset{(From air)}{10 O_{2}} \to_{\underset{}{500 K, 9 bar}}^{Pt/Rh gauge catalyst} 4 NO + 6 H_{2} O

4

4N H_{3} + \underset{(From air)}{5 O_{2}} \to_{\overset{}{500 K, 9 bar}}^{Pt/Rh gauge catalyst} 4NO  +  6 H_{2}

CHXI11:THE P-BLOCK ELEMENTS

316715 In qualitative analysis when $H_{2} S$ is passed through an aqueous solution of salt acidified with dil. $HCl$ , a black precipitate is obtained. On boiling the precipitate with dil. ${HNO}_{3}$ , it forms a solution of blue colour. Addition of excess of aqueous solution of ammonia to this solution gives

1 Deep blue precipitate of

Cu (OH)_{2}

2 Deep blue solution of

{[Cu {({NH}_{3})}_{4}]}^{2 +}

3 Deep blue solution of

Cu {({NO}_{3})}_{2}

4 Deep blue solution of

Cu (OH)_{2} \cdot Cu {({NO}_{3})}_{2}

Explanation:

Qualitative analysis of ${Cu}^{2 +}$ ion

CHXI11:THE P-BLOCK ELEMENTS

316712 Which of the following is obtained by catalytic oxidation of ammonia?

1

N_{2} O

2

NO

3

{HNO}_{2}

4

N O_{2}

Explanation:

Nitric oxide (NO) is obtained by catalytic oxidation of ammonia. The catalytic oxidation of ammonia uses a metal catalyst such as platinum, copper or nickel. This metal catalyst is heated, so that ammonia can reduce it, oxygen added to the system can then oxidise the ammonia, forming nitric oxide.
$4N H_{3} + 5 O_{2} \to_{800 - 90 0^{o} C}^{Pt guage} 4NO + 6 H_{2} O; + 21 .5 K cal .$

MHTCET - 2020

CHXI11:THE P-BLOCK ELEMENTS

316713 Ammonia reacts with Nessler's reagent to give

1 Deep blue precipitate

2 White precipitate

3 Green precipitate

4 Brown precipitate

Explanation:

Nessler's reagent is used to detect the ammonia and its compounds.
$A m m o n i a + N e s s l e r^{'} s r e a g e n t \to B r o w n p p t .$

CHXI11:THE P-BLOCK ELEMENTS

316714 A balanced chemical equation for the reaction showing catalytic oxidation of ${NH}_{3}$ by atmospheric oxygen is

1

4N H_{3} + \underset{(From air)}{5 O_{2}} \to_{500K, 9 bar}^{Pt/Rh gauge catalyst} 4NO + 6 H_{2} O

2

N H_{3} + \underset{(Fromair)}{O_{2}} \to_{500 K, 9bar}^{Pt/Rh gauge catalyst} NO  + H_{2} O

3

4 N H_{3} + \underset{(From air)}{10 O_{2}} \to_{\underset{}{500 K, 9 bar}}^{Pt/Rh gauge catalyst} 4 NO + 6 H_{2} O

4

4N H_{3} + \underset{(From air)}{5 O_{2}} \to_{\overset{}{500 K, 9 bar}}^{Pt/Rh gauge catalyst} 4NO  +  6 H_{2}

CHXI11:THE P-BLOCK ELEMENTS

316715 In qualitative analysis when $H_{2} S$ is passed through an aqueous solution of salt acidified with dil. $HCl$ , a black precipitate is obtained. On boiling the precipitate with dil. ${HNO}_{3}$ , it forms a solution of blue colour. Addition of excess of aqueous solution of ammonia to this solution gives

1 Deep blue precipitate of

Cu (OH)_{2}

2 Deep blue solution of

{[Cu {({NH}_{3})}_{4}]}^{2 +}

3 Deep blue solution of

Cu {({NO}_{3})}_{2}

4 Deep blue solution of

Cu (OH)_{2} \cdot Cu {({NO}_{3})}_{2}

Explanation:

Qualitative analysis of ${Cu}^{2 +}$ ion

CHXI11:THE P-BLOCK ELEMENTS

316712 Which of the following is obtained by catalytic oxidation of ammonia?

1

N_{2} O

2

NO

3

{HNO}_{2}

4

N O_{2}

Explanation:

Nitric oxide (NO) is obtained by catalytic oxidation of ammonia. The catalytic oxidation of ammonia uses a metal catalyst such as platinum, copper or nickel. This metal catalyst is heated, so that ammonia can reduce it, oxygen added to the system can then oxidise the ammonia, forming nitric oxide.
$4N H_{3} + 5 O_{2} \to_{800 - 90 0^{o} C}^{Pt guage} 4NO + 6 H_{2} O; + 21 .5 K cal .$

MHTCET - 2020

CHXI11:THE P-BLOCK ELEMENTS

316713 Ammonia reacts with Nessler's reagent to give

1 Deep blue precipitate

2 White precipitate

3 Green precipitate

4 Brown precipitate

Explanation:

Nessler's reagent is used to detect the ammonia and its compounds.
$A m m o n i a + N e s s l e r^{'} s r e a g e n t \to B r o w n p p t .$

CHXI11:THE P-BLOCK ELEMENTS

316714 A balanced chemical equation for the reaction showing catalytic oxidation of ${NH}_{3}$ by atmospheric oxygen is

1

4N H_{3} + \underset{(From air)}{5 O_{2}} \to_{500K, 9 bar}^{Pt/Rh gauge catalyst} 4NO + 6 H_{2} O

2

N H_{3} + \underset{(Fromair)}{O_{2}} \to_{500 K, 9bar}^{Pt/Rh gauge catalyst} NO  + H_{2} O

3

4 N H_{3} + \underset{(From air)}{10 O_{2}} \to_{\underset{}{500 K, 9 bar}}^{Pt/Rh gauge catalyst} 4 NO + 6 H_{2} O

4

4N H_{3} + \underset{(From air)}{5 O_{2}} \to_{\overset{}{500 K, 9 bar}}^{Pt/Rh gauge catalyst} 4NO  +  6 H_{2}

CHXI11:THE P-BLOCK ELEMENTS

316715 In qualitative analysis when $H_{2} S$ is passed through an aqueous solution of salt acidified with dil. $HCl$ , a black precipitate is obtained. On boiling the precipitate with dil. ${HNO}_{3}$ , it forms a solution of blue colour. Addition of excess of aqueous solution of ammonia to this solution gives

1 Deep blue precipitate of

Cu (OH)_{2}

2 Deep blue solution of

{[Cu {({NH}_{3})}_{4}]}^{2 +}

3 Deep blue solution of

Cu {({NO}_{3})}_{2}

4 Deep blue solution of

Cu (OH)_{2} \cdot Cu {({NO}_{3})}_{2}

Explanation:

Qualitative analysis of ${Cu}^{2 +}$ ion

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