316536
In the ground state, the carbon atom has ____ unpaired electron/s.
1 2
2 3
3 4
4 5
Explanation:
Conceptual Questions
CHXI11:THE P-BLOCK ELEMENTS
316537
The number of stable isotopes of carbon is
1 3
2 2
3 1
4 4
Explanation:
Carbon has two stable isotopes; \(^{12}{\rm{C}}\left( {98.99\% } \right)\) and \({\mathrm{{ }^{13} \mathrm{C}(1.1 \%)}}\).\({\mathrm{{ }^{14} \mathrm{C}}}\) is radioactive.
CHXI11:THE P-BLOCK ELEMENTS
316538
Assertion : \(\mathrm{R}_{3} \mathrm{P}=\mathrm{O}\) exists but \(\mathrm{R}_{3} \mathrm{~N}=\mathrm{O}\) does not exist. Reason : P is more electronegative than \(\mathrm{N}\).
1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Assertion is incorrect but Reason is correct.
Explanation:
Due to small size and absence of d-orbital, \(\mathrm{N}\) cannot form \(\mathrm{R}_{3} \mathrm{~N}=\mathrm{O}\). The electronegativity of \(\mathrm{N}(3.0)\) is much higher than that of \(\mathrm{P}(2.1)\). So option (3) is correct.
CHXI11:THE P-BLOCK ELEMENTS
316539
Which of the following elements forms \(\mathrm{p} \pi-\mathrm{p} \pi\) bond with itself?
1 \(\mathrm{N}\)
2 \(\mathrm{Te}\)
3 \(\mathrm{P}\)
4 \(\mathrm{Se}\)
Explanation:
Nitrogen can form \(\mathrm{p} \pi-\mathrm{p} \pi\) bond with itself due to its small size and high electronegativity and exists as a diatomic molecule \((\mathrm{N} \equiv \mathrm{N}\), one \(\sigma\) and two \(\pi\)-bonds). While other given elements do not form \(\mathrm{p} \pi-\mathrm{p} \pi\) bonds due to their large atomic size they do not exhibit effective overlapping of orbitals.
KCET - 2017
CHXI11:THE P-BLOCK ELEMENTS
316540
Which is true regarding nitrogen?
1 Less electronegative
2 Has low ionisation enthalpy
3 d-orbitals are available
4 Ability to form \(\mathrm{p} \pi-\mathrm{p} \pi\) bonds with itself
Explanation:
Because of its small size, nitrogen has a strong tendency to form \(\mathrm{p} \pi-\mathrm{p} \pi\) bonds. It has high electronegativity and does not have any dorbital. Also, it has high ionisation enthalpy due to its stable half-filled electronic configuration.
316536
In the ground state, the carbon atom has ____ unpaired electron/s.
1 2
2 3
3 4
4 5
Explanation:
Conceptual Questions
CHXI11:THE P-BLOCK ELEMENTS
316537
The number of stable isotopes of carbon is
1 3
2 2
3 1
4 4
Explanation:
Carbon has two stable isotopes; \(^{12}{\rm{C}}\left( {98.99\% } \right)\) and \({\mathrm{{ }^{13} \mathrm{C}(1.1 \%)}}\).\({\mathrm{{ }^{14} \mathrm{C}}}\) is radioactive.
CHXI11:THE P-BLOCK ELEMENTS
316538
Assertion : \(\mathrm{R}_{3} \mathrm{P}=\mathrm{O}\) exists but \(\mathrm{R}_{3} \mathrm{~N}=\mathrm{O}\) does not exist. Reason : P is more electronegative than \(\mathrm{N}\).
1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Assertion is incorrect but Reason is correct.
Explanation:
Due to small size and absence of d-orbital, \(\mathrm{N}\) cannot form \(\mathrm{R}_{3} \mathrm{~N}=\mathrm{O}\). The electronegativity of \(\mathrm{N}(3.0)\) is much higher than that of \(\mathrm{P}(2.1)\). So option (3) is correct.
CHXI11:THE P-BLOCK ELEMENTS
316539
Which of the following elements forms \(\mathrm{p} \pi-\mathrm{p} \pi\) bond with itself?
1 \(\mathrm{N}\)
2 \(\mathrm{Te}\)
3 \(\mathrm{P}\)
4 \(\mathrm{Se}\)
Explanation:
Nitrogen can form \(\mathrm{p} \pi-\mathrm{p} \pi\) bond with itself due to its small size and high electronegativity and exists as a diatomic molecule \((\mathrm{N} \equiv \mathrm{N}\), one \(\sigma\) and two \(\pi\)-bonds). While other given elements do not form \(\mathrm{p} \pi-\mathrm{p} \pi\) bonds due to their large atomic size they do not exhibit effective overlapping of orbitals.
KCET - 2017
CHXI11:THE P-BLOCK ELEMENTS
316540
Which is true regarding nitrogen?
1 Less electronegative
2 Has low ionisation enthalpy
3 d-orbitals are available
4 Ability to form \(\mathrm{p} \pi-\mathrm{p} \pi\) bonds with itself
Explanation:
Because of its small size, nitrogen has a strong tendency to form \(\mathrm{p} \pi-\mathrm{p} \pi\) bonds. It has high electronegativity and does not have any dorbital. Also, it has high ionisation enthalpy due to its stable half-filled electronic configuration.
316536
In the ground state, the carbon atom has ____ unpaired electron/s.
1 2
2 3
3 4
4 5
Explanation:
Conceptual Questions
CHXI11:THE P-BLOCK ELEMENTS
316537
The number of stable isotopes of carbon is
1 3
2 2
3 1
4 4
Explanation:
Carbon has two stable isotopes; \(^{12}{\rm{C}}\left( {98.99\% } \right)\) and \({\mathrm{{ }^{13} \mathrm{C}(1.1 \%)}}\).\({\mathrm{{ }^{14} \mathrm{C}}}\) is radioactive.
CHXI11:THE P-BLOCK ELEMENTS
316538
Assertion : \(\mathrm{R}_{3} \mathrm{P}=\mathrm{O}\) exists but \(\mathrm{R}_{3} \mathrm{~N}=\mathrm{O}\) does not exist. Reason : P is more electronegative than \(\mathrm{N}\).
1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Assertion is incorrect but Reason is correct.
Explanation:
Due to small size and absence of d-orbital, \(\mathrm{N}\) cannot form \(\mathrm{R}_{3} \mathrm{~N}=\mathrm{O}\). The electronegativity of \(\mathrm{N}(3.0)\) is much higher than that of \(\mathrm{P}(2.1)\). So option (3) is correct.
CHXI11:THE P-BLOCK ELEMENTS
316539
Which of the following elements forms \(\mathrm{p} \pi-\mathrm{p} \pi\) bond with itself?
1 \(\mathrm{N}\)
2 \(\mathrm{Te}\)
3 \(\mathrm{P}\)
4 \(\mathrm{Se}\)
Explanation:
Nitrogen can form \(\mathrm{p} \pi-\mathrm{p} \pi\) bond with itself due to its small size and high electronegativity and exists as a diatomic molecule \((\mathrm{N} \equiv \mathrm{N}\), one \(\sigma\) and two \(\pi\)-bonds). While other given elements do not form \(\mathrm{p} \pi-\mathrm{p} \pi\) bonds due to their large atomic size they do not exhibit effective overlapping of orbitals.
KCET - 2017
CHXI11:THE P-BLOCK ELEMENTS
316540
Which is true regarding nitrogen?
1 Less electronegative
2 Has low ionisation enthalpy
3 d-orbitals are available
4 Ability to form \(\mathrm{p} \pi-\mathrm{p} \pi\) bonds with itself
Explanation:
Because of its small size, nitrogen has a strong tendency to form \(\mathrm{p} \pi-\mathrm{p} \pi\) bonds. It has high electronegativity and does not have any dorbital. Also, it has high ionisation enthalpy due to its stable half-filled electronic configuration.
316536
In the ground state, the carbon atom has ____ unpaired electron/s.
1 2
2 3
3 4
4 5
Explanation:
Conceptual Questions
CHXI11:THE P-BLOCK ELEMENTS
316537
The number of stable isotopes of carbon is
1 3
2 2
3 1
4 4
Explanation:
Carbon has two stable isotopes; \(^{12}{\rm{C}}\left( {98.99\% } \right)\) and \({\mathrm{{ }^{13} \mathrm{C}(1.1 \%)}}\).\({\mathrm{{ }^{14} \mathrm{C}}}\) is radioactive.
CHXI11:THE P-BLOCK ELEMENTS
316538
Assertion : \(\mathrm{R}_{3} \mathrm{P}=\mathrm{O}\) exists but \(\mathrm{R}_{3} \mathrm{~N}=\mathrm{O}\) does not exist. Reason : P is more electronegative than \(\mathrm{N}\).
1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Assertion is incorrect but Reason is correct.
Explanation:
Due to small size and absence of d-orbital, \(\mathrm{N}\) cannot form \(\mathrm{R}_{3} \mathrm{~N}=\mathrm{O}\). The electronegativity of \(\mathrm{N}(3.0)\) is much higher than that of \(\mathrm{P}(2.1)\). So option (3) is correct.
CHXI11:THE P-BLOCK ELEMENTS
316539
Which of the following elements forms \(\mathrm{p} \pi-\mathrm{p} \pi\) bond with itself?
1 \(\mathrm{N}\)
2 \(\mathrm{Te}\)
3 \(\mathrm{P}\)
4 \(\mathrm{Se}\)
Explanation:
Nitrogen can form \(\mathrm{p} \pi-\mathrm{p} \pi\) bond with itself due to its small size and high electronegativity and exists as a diatomic molecule \((\mathrm{N} \equiv \mathrm{N}\), one \(\sigma\) and two \(\pi\)-bonds). While other given elements do not form \(\mathrm{p} \pi-\mathrm{p} \pi\) bonds due to their large atomic size they do not exhibit effective overlapping of orbitals.
KCET - 2017
CHXI11:THE P-BLOCK ELEMENTS
316540
Which is true regarding nitrogen?
1 Less electronegative
2 Has low ionisation enthalpy
3 d-orbitals are available
4 Ability to form \(\mathrm{p} \pi-\mathrm{p} \pi\) bonds with itself
Explanation:
Because of its small size, nitrogen has a strong tendency to form \(\mathrm{p} \pi-\mathrm{p} \pi\) bonds. It has high electronegativity and does not have any dorbital. Also, it has high ionisation enthalpy due to its stable half-filled electronic configuration.
316536
In the ground state, the carbon atom has ____ unpaired electron/s.
1 2
2 3
3 4
4 5
Explanation:
Conceptual Questions
CHXI11:THE P-BLOCK ELEMENTS
316537
The number of stable isotopes of carbon is
1 3
2 2
3 1
4 4
Explanation:
Carbon has two stable isotopes; \(^{12}{\rm{C}}\left( {98.99\% } \right)\) and \({\mathrm{{ }^{13} \mathrm{C}(1.1 \%)}}\).\({\mathrm{{ }^{14} \mathrm{C}}}\) is radioactive.
CHXI11:THE P-BLOCK ELEMENTS
316538
Assertion : \(\mathrm{R}_{3} \mathrm{P}=\mathrm{O}\) exists but \(\mathrm{R}_{3} \mathrm{~N}=\mathrm{O}\) does not exist. Reason : P is more electronegative than \(\mathrm{N}\).
1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Assertion is incorrect but Reason is correct.
Explanation:
Due to small size and absence of d-orbital, \(\mathrm{N}\) cannot form \(\mathrm{R}_{3} \mathrm{~N}=\mathrm{O}\). The electronegativity of \(\mathrm{N}(3.0)\) is much higher than that of \(\mathrm{P}(2.1)\). So option (3) is correct.
CHXI11:THE P-BLOCK ELEMENTS
316539
Which of the following elements forms \(\mathrm{p} \pi-\mathrm{p} \pi\) bond with itself?
1 \(\mathrm{N}\)
2 \(\mathrm{Te}\)
3 \(\mathrm{P}\)
4 \(\mathrm{Se}\)
Explanation:
Nitrogen can form \(\mathrm{p} \pi-\mathrm{p} \pi\) bond with itself due to its small size and high electronegativity and exists as a diatomic molecule \((\mathrm{N} \equiv \mathrm{N}\), one \(\sigma\) and two \(\pi\)-bonds). While other given elements do not form \(\mathrm{p} \pi-\mathrm{p} \pi\) bonds due to their large atomic size they do not exhibit effective overlapping of orbitals.
KCET - 2017
CHXI11:THE P-BLOCK ELEMENTS
316540
Which is true regarding nitrogen?
1 Less electronegative
2 Has low ionisation enthalpy
3 d-orbitals are available
4 Ability to form \(\mathrm{p} \pi-\mathrm{p} \pi\) bonds with itself
Explanation:
Because of its small size, nitrogen has a strong tendency to form \(\mathrm{p} \pi-\mathrm{p} \pi\) bonds. It has high electronegativity and does not have any dorbital. Also, it has high ionisation enthalpy due to its stable half-filled electronic configuration.
