316606
Fluorine does not show positive oxidation states because
1 It is most electronegative element
2 It forms only anions in ionic compounds
3 It cannot form multiple bonds
4 It shows non-bonded electron pair repulsion due to small size
Explanation:
Conceptual Questions
CHXI11:THE P-BLOCK ELEMENTS
316607
Which of the following halogens does not exhibit a positive oxidation number in their compounds?
1 \({\rm{I}}\)
2 \(\mathrm{Br}\)
3 \(\mathrm{Cl}\)
4 \({\rm{F}}\)
Explanation:
\(\mathrm{F}\) is the most electronegative atom. So, it cannot exhibit positive oxidation state.
CHXI11:THE P-BLOCK ELEMENTS
316608
What is the oxidation state of Cl in \({\mathrm{\mathrm{HClO}_{4}}}\) ?
1 1
2 3
3 5
4 7
Explanation:
Let oxidation state of Cl in \({\mathrm{\mathrm{HClO}_{4}}}\) is \({\mathrm{x}}\). \(({\rm{ + 1}}){\rm{ + x + 4}}( - {\rm{2}}){\rm{ = 0}},{\rm{x}}\,{\rm{ = }}\,{\rm{ + 7}}.\)
CHXI11:THE P-BLOCK ELEMENTS
316609
What is the highest oxidation state exhibited by group 17 elements?
1 +1
2 +3
3 +5
4 +7
Explanation:
The highest oxidation state exhibited by group 17 elements is +7 . The elements that belong to the group 17 are called halogens. All elements of this group have seven electrons in their outermost shell. So, these elements can lose seven electrons to get +7 oxidation state.
316606
Fluorine does not show positive oxidation states because
1 It is most electronegative element
2 It forms only anions in ionic compounds
3 It cannot form multiple bonds
4 It shows non-bonded electron pair repulsion due to small size
Explanation:
Conceptual Questions
CHXI11:THE P-BLOCK ELEMENTS
316607
Which of the following halogens does not exhibit a positive oxidation number in their compounds?
1 \({\rm{I}}\)
2 \(\mathrm{Br}\)
3 \(\mathrm{Cl}\)
4 \({\rm{F}}\)
Explanation:
\(\mathrm{F}\) is the most electronegative atom. So, it cannot exhibit positive oxidation state.
CHXI11:THE P-BLOCK ELEMENTS
316608
What is the oxidation state of Cl in \({\mathrm{\mathrm{HClO}_{4}}}\) ?
1 1
2 3
3 5
4 7
Explanation:
Let oxidation state of Cl in \({\mathrm{\mathrm{HClO}_{4}}}\) is \({\mathrm{x}}\). \(({\rm{ + 1}}){\rm{ + x + 4}}( - {\rm{2}}){\rm{ = 0}},{\rm{x}}\,{\rm{ = }}\,{\rm{ + 7}}.\)
CHXI11:THE P-BLOCK ELEMENTS
316609
What is the highest oxidation state exhibited by group 17 elements?
1 +1
2 +3
3 +5
4 +7
Explanation:
The highest oxidation state exhibited by group 17 elements is +7 . The elements that belong to the group 17 are called halogens. All elements of this group have seven electrons in their outermost shell. So, these elements can lose seven electrons to get +7 oxidation state.
NEET Test Series from KOTA - 10 Papers In MS WORD
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CHXI11:THE P-BLOCK ELEMENTS
316606
Fluorine does not show positive oxidation states because
1 It is most electronegative element
2 It forms only anions in ionic compounds
3 It cannot form multiple bonds
4 It shows non-bonded electron pair repulsion due to small size
Explanation:
Conceptual Questions
CHXI11:THE P-BLOCK ELEMENTS
316607
Which of the following halogens does not exhibit a positive oxidation number in their compounds?
1 \({\rm{I}}\)
2 \(\mathrm{Br}\)
3 \(\mathrm{Cl}\)
4 \({\rm{F}}\)
Explanation:
\(\mathrm{F}\) is the most electronegative atom. So, it cannot exhibit positive oxidation state.
CHXI11:THE P-BLOCK ELEMENTS
316608
What is the oxidation state of Cl in \({\mathrm{\mathrm{HClO}_{4}}}\) ?
1 1
2 3
3 5
4 7
Explanation:
Let oxidation state of Cl in \({\mathrm{\mathrm{HClO}_{4}}}\) is \({\mathrm{x}}\). \(({\rm{ + 1}}){\rm{ + x + 4}}( - {\rm{2}}){\rm{ = 0}},{\rm{x}}\,{\rm{ = }}\,{\rm{ + 7}}.\)
CHXI11:THE P-BLOCK ELEMENTS
316609
What is the highest oxidation state exhibited by group 17 elements?
1 +1
2 +3
3 +5
4 +7
Explanation:
The highest oxidation state exhibited by group 17 elements is +7 . The elements that belong to the group 17 are called halogens. All elements of this group have seven electrons in their outermost shell. So, these elements can lose seven electrons to get +7 oxidation state.
316606
Fluorine does not show positive oxidation states because
1 It is most electronegative element
2 It forms only anions in ionic compounds
3 It cannot form multiple bonds
4 It shows non-bonded electron pair repulsion due to small size
Explanation:
Conceptual Questions
CHXI11:THE P-BLOCK ELEMENTS
316607
Which of the following halogens does not exhibit a positive oxidation number in their compounds?
1 \({\rm{I}}\)
2 \(\mathrm{Br}\)
3 \(\mathrm{Cl}\)
4 \({\rm{F}}\)
Explanation:
\(\mathrm{F}\) is the most electronegative atom. So, it cannot exhibit positive oxidation state.
CHXI11:THE P-BLOCK ELEMENTS
316608
What is the oxidation state of Cl in \({\mathrm{\mathrm{HClO}_{4}}}\) ?
1 1
2 3
3 5
4 7
Explanation:
Let oxidation state of Cl in \({\mathrm{\mathrm{HClO}_{4}}}\) is \({\mathrm{x}}\). \(({\rm{ + 1}}){\rm{ + x + 4}}( - {\rm{2}}){\rm{ = 0}},{\rm{x}}\,{\rm{ = }}\,{\rm{ + 7}}.\)
CHXI11:THE P-BLOCK ELEMENTS
316609
What is the highest oxidation state exhibited by group 17 elements?
1 +1
2 +3
3 +5
4 +7
Explanation:
The highest oxidation state exhibited by group 17 elements is +7 . The elements that belong to the group 17 are called halogens. All elements of this group have seven electrons in their outermost shell. So, these elements can lose seven electrons to get +7 oxidation state.