NEET Test Series from KOTA - 10 Papers In MS WORD
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CHXI11:THE P-BLOCK ELEMENTS
316602
The \({\mathrm{\mathrm{F}^{-}}}\)ions make the enamel on teeth much harder by converting hydroxyapatite (the enamel on the surface of teeth) into much harder fluoroapatite having the formula
Fluoroapatite formula is \({\mathrm{\left[3\left(\mathrm{Ca}_{3}\left(\mathrm{PO}_{4}\right)_{2}\right) \cdot \mathrm{CaF}_{2}\right]}}\). So, the correct option is (3).
JEE Main - 2024
CHXI11:THE P-BLOCK ELEMENTS
316603
Fluorine does not show positive oxidation state because
1 its atomic size is small
2 it is volatile
3 it is a gas
4 it has no d-orbital in valency shell
Explanation:
It is an anomalous behavior of fluorine.
CHXI11:THE P-BLOCK ELEMENTS
316604
Element not showing variable oxidation states is
1 bromine
2 chlorine
3 iodine
4 fluorine.
Explanation:
Fluorine is the most electronegative element and shows only \(-\)1 oxidation state, while other halogens show variable oxidation states like +1 , \({\mathrm{+3,+5,+7,-1}}\). So, the correct option is (4).
JEE Main - 2024
CHXI11:THE P-BLOCK ELEMENTS
316605
What is the oxidation state of iodine in \({\mathrm{\mathrm{H}_{5} \mathrm{IO}_{6}}}\) ?
1 1
2 7
3 3
4 5
Explanation:
Let oxidation state of I in \({\mathrm{\mathrm{H}_{5} \mathrm{IO}_{6}}}\) is ' \({\mathrm{x}}\) ' \({\mathrm{(+1) \times 5+x+(-2) \times 6=0, x=+7}}\)
316602
The \({\mathrm{\mathrm{F}^{-}}}\)ions make the enamel on teeth much harder by converting hydroxyapatite (the enamel on the surface of teeth) into much harder fluoroapatite having the formula
Fluoroapatite formula is \({\mathrm{\left[3\left(\mathrm{Ca}_{3}\left(\mathrm{PO}_{4}\right)_{2}\right) \cdot \mathrm{CaF}_{2}\right]}}\). So, the correct option is (3).
JEE Main - 2024
CHXI11:THE P-BLOCK ELEMENTS
316603
Fluorine does not show positive oxidation state because
1 its atomic size is small
2 it is volatile
3 it is a gas
4 it has no d-orbital in valency shell
Explanation:
It is an anomalous behavior of fluorine.
CHXI11:THE P-BLOCK ELEMENTS
316604
Element not showing variable oxidation states is
1 bromine
2 chlorine
3 iodine
4 fluorine.
Explanation:
Fluorine is the most electronegative element and shows only \(-\)1 oxidation state, while other halogens show variable oxidation states like +1 , \({\mathrm{+3,+5,+7,-1}}\). So, the correct option is (4).
JEE Main - 2024
CHXI11:THE P-BLOCK ELEMENTS
316605
What is the oxidation state of iodine in \({\mathrm{\mathrm{H}_{5} \mathrm{IO}_{6}}}\) ?
1 1
2 7
3 3
4 5
Explanation:
Let oxidation state of I in \({\mathrm{\mathrm{H}_{5} \mathrm{IO}_{6}}}\) is ' \({\mathrm{x}}\) ' \({\mathrm{(+1) \times 5+x+(-2) \times 6=0, x=+7}}\)
316602
The \({\mathrm{\mathrm{F}^{-}}}\)ions make the enamel on teeth much harder by converting hydroxyapatite (the enamel on the surface of teeth) into much harder fluoroapatite having the formula
Fluoroapatite formula is \({\mathrm{\left[3\left(\mathrm{Ca}_{3}\left(\mathrm{PO}_{4}\right)_{2}\right) \cdot \mathrm{CaF}_{2}\right]}}\). So, the correct option is (3).
JEE Main - 2024
CHXI11:THE P-BLOCK ELEMENTS
316603
Fluorine does not show positive oxidation state because
1 its atomic size is small
2 it is volatile
3 it is a gas
4 it has no d-orbital in valency shell
Explanation:
It is an anomalous behavior of fluorine.
CHXI11:THE P-BLOCK ELEMENTS
316604
Element not showing variable oxidation states is
1 bromine
2 chlorine
3 iodine
4 fluorine.
Explanation:
Fluorine is the most electronegative element and shows only \(-\)1 oxidation state, while other halogens show variable oxidation states like +1 , \({\mathrm{+3,+5,+7,-1}}\). So, the correct option is (4).
JEE Main - 2024
CHXI11:THE P-BLOCK ELEMENTS
316605
What is the oxidation state of iodine in \({\mathrm{\mathrm{H}_{5} \mathrm{IO}_{6}}}\) ?
1 1
2 7
3 3
4 5
Explanation:
Let oxidation state of I in \({\mathrm{\mathrm{H}_{5} \mathrm{IO}_{6}}}\) is ' \({\mathrm{x}}\) ' \({\mathrm{(+1) \times 5+x+(-2) \times 6=0, x=+7}}\)
NEET Test Series from KOTA - 10 Papers In MS WORD
WhatsApp Here
CHXI11:THE P-BLOCK ELEMENTS
316602
The \({\mathrm{\mathrm{F}^{-}}}\)ions make the enamel on teeth much harder by converting hydroxyapatite (the enamel on the surface of teeth) into much harder fluoroapatite having the formula
Fluoroapatite formula is \({\mathrm{\left[3\left(\mathrm{Ca}_{3}\left(\mathrm{PO}_{4}\right)_{2}\right) \cdot \mathrm{CaF}_{2}\right]}}\). So, the correct option is (3).
JEE Main - 2024
CHXI11:THE P-BLOCK ELEMENTS
316603
Fluorine does not show positive oxidation state because
1 its atomic size is small
2 it is volatile
3 it is a gas
4 it has no d-orbital in valency shell
Explanation:
It is an anomalous behavior of fluorine.
CHXI11:THE P-BLOCK ELEMENTS
316604
Element not showing variable oxidation states is
1 bromine
2 chlorine
3 iodine
4 fluorine.
Explanation:
Fluorine is the most electronegative element and shows only \(-\)1 oxidation state, while other halogens show variable oxidation states like +1 , \({\mathrm{+3,+5,+7,-1}}\). So, the correct option is (4).
JEE Main - 2024
CHXI11:THE P-BLOCK ELEMENTS
316605
What is the oxidation state of iodine in \({\mathrm{\mathrm{H}_{5} \mathrm{IO}_{6}}}\) ?
1 1
2 7
3 3
4 5
Explanation:
Let oxidation state of I in \({\mathrm{\mathrm{H}_{5} \mathrm{IO}_{6}}}\) is ' \({\mathrm{x}}\) ' \({\mathrm{(+1) \times 5+x+(-2) \times 6=0, x=+7}}\)