316074
The number of neutrons present in the more abundant isotope of boron is x . Amorphous boron upon heating with air forms a product, in which the oxidation state of boron is \({\mathrm{\mathrm{y}}}\). The value of \({\mathrm{\mathrm{x+y}}}\) is
1 6
2 3
3 4
4 9
Explanation:
The most abundant isotope of boron is \({\mathrm{\mathrm{{ }_{5}^{11} \mathrm{~B}}}}\). No. of neutrons in it \({\mathrm{\mathrm{=11-5=6(\mathrm{x})}}}\) Reactions of boron with air (i) \({\mathrm{\mathrm{2 \mathrm{~B}_{(\mathrm{s})}+\mathrm{N}_{2(\mathrm{~g})} \xrightarrow{\Delta} 2 \mathrm{BN}_{(\mathrm{s})}}}}\) (ii) \({\mathrm{\mathrm{4 \mathrm{~B}_{(\mathrm{s})}+3 \mathrm{O}_{2(\mathrm{~g})} \rightarrow 2 \mathrm{~B}_{2} \mathrm{O}_{3(\mathrm{~s})}}}}\) Oxidation state of boron in both BN and \({\mathrm{\mathrm{\mathrm{B}_{2} \mathrm{O}_{3}}}}\) is \({\mathrm{\mathrm{+3(\mathrm{y})}}}\) So, \({\mathrm{\mathrm{x+y=6+3=9}}}\) So, the correct option is (4)
JEE Main - 2024
CHXI11:THE P-BLOCK ELEMENTS
316075
Boron reacts with \(\mathrm{NaOH}\) to form
316074
The number of neutrons present in the more abundant isotope of boron is x . Amorphous boron upon heating with air forms a product, in which the oxidation state of boron is \({\mathrm{\mathrm{y}}}\). The value of \({\mathrm{\mathrm{x+y}}}\) is
1 6
2 3
3 4
4 9
Explanation:
The most abundant isotope of boron is \({\mathrm{\mathrm{{ }_{5}^{11} \mathrm{~B}}}}\). No. of neutrons in it \({\mathrm{\mathrm{=11-5=6(\mathrm{x})}}}\) Reactions of boron with air (i) \({\mathrm{\mathrm{2 \mathrm{~B}_{(\mathrm{s})}+\mathrm{N}_{2(\mathrm{~g})} \xrightarrow{\Delta} 2 \mathrm{BN}_{(\mathrm{s})}}}}\) (ii) \({\mathrm{\mathrm{4 \mathrm{~B}_{(\mathrm{s})}+3 \mathrm{O}_{2(\mathrm{~g})} \rightarrow 2 \mathrm{~B}_{2} \mathrm{O}_{3(\mathrm{~s})}}}}\) Oxidation state of boron in both BN and \({\mathrm{\mathrm{\mathrm{B}_{2} \mathrm{O}_{3}}}}\) is \({\mathrm{\mathrm{+3(\mathrm{y})}}}\) So, \({\mathrm{\mathrm{x+y=6+3=9}}}\) So, the correct option is (4)
JEE Main - 2024
CHXI11:THE P-BLOCK ELEMENTS
316075
Boron reacts with \(\mathrm{NaOH}\) to form
316074
The number of neutrons present in the more abundant isotope of boron is x . Amorphous boron upon heating with air forms a product, in which the oxidation state of boron is \({\mathrm{\mathrm{y}}}\). The value of \({\mathrm{\mathrm{x+y}}}\) is
1 6
2 3
3 4
4 9
Explanation:
The most abundant isotope of boron is \({\mathrm{\mathrm{{ }_{5}^{11} \mathrm{~B}}}}\). No. of neutrons in it \({\mathrm{\mathrm{=11-5=6(\mathrm{x})}}}\) Reactions of boron with air (i) \({\mathrm{\mathrm{2 \mathrm{~B}_{(\mathrm{s})}+\mathrm{N}_{2(\mathrm{~g})} \xrightarrow{\Delta} 2 \mathrm{BN}_{(\mathrm{s})}}}}\) (ii) \({\mathrm{\mathrm{4 \mathrm{~B}_{(\mathrm{s})}+3 \mathrm{O}_{2(\mathrm{~g})} \rightarrow 2 \mathrm{~B}_{2} \mathrm{O}_{3(\mathrm{~s})}}}}\) Oxidation state of boron in both BN and \({\mathrm{\mathrm{\mathrm{B}_{2} \mathrm{O}_{3}}}}\) is \({\mathrm{\mathrm{+3(\mathrm{y})}}}\) So, \({\mathrm{\mathrm{x+y=6+3=9}}}\) So, the correct option is (4)
JEE Main - 2024
CHXI11:THE P-BLOCK ELEMENTS
316075
Boron reacts with \(\mathrm{NaOH}\) to form
NEET Test Series from KOTA - 10 Papers In MS WORD
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CHXI11:THE P-BLOCK ELEMENTS
316074
The number of neutrons present in the more abundant isotope of boron is x . Amorphous boron upon heating with air forms a product, in which the oxidation state of boron is \({\mathrm{\mathrm{y}}}\). The value of \({\mathrm{\mathrm{x+y}}}\) is
1 6
2 3
3 4
4 9
Explanation:
The most abundant isotope of boron is \({\mathrm{\mathrm{{ }_{5}^{11} \mathrm{~B}}}}\). No. of neutrons in it \({\mathrm{\mathrm{=11-5=6(\mathrm{x})}}}\) Reactions of boron with air (i) \({\mathrm{\mathrm{2 \mathrm{~B}_{(\mathrm{s})}+\mathrm{N}_{2(\mathrm{~g})} \xrightarrow{\Delta} 2 \mathrm{BN}_{(\mathrm{s})}}}}\) (ii) \({\mathrm{\mathrm{4 \mathrm{~B}_{(\mathrm{s})}+3 \mathrm{O}_{2(\mathrm{~g})} \rightarrow 2 \mathrm{~B}_{2} \mathrm{O}_{3(\mathrm{~s})}}}}\) Oxidation state of boron in both BN and \({\mathrm{\mathrm{\mathrm{B}_{2} \mathrm{O}_{3}}}}\) is \({\mathrm{\mathrm{+3(\mathrm{y})}}}\) So, \({\mathrm{\mathrm{x+y=6+3=9}}}\) So, the correct option is (4)
JEE Main - 2024
CHXI11:THE P-BLOCK ELEMENTS
316075
Boron reacts with \(\mathrm{NaOH}\) to form
