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CHXI11:THE P-BLOCK ELEMENTS

316074 The number of neutrons present in the more abundant isotope of boron is x . Amorphous boron upon heating with air forms a product, in which the oxidation state of boron is $y$ . The value of $x + y$ is

1 6

2 3

3 4

4 9

Explanation:

The most abundant isotope of boron is $_{5}^{11} B$ .
No. of neutrons in it $= 11 - 5 = 6 (x)$
Reactions of boron with air
(i) $2 B_{(s)} + N_{2 (g)} \overset{Δ}{\to} 2 {BN}_{(s)}$
(ii) $4 B_{(s)} + 3 O_{2 (g)} \to 2 B_{2} O_{3 (s)}$
Oxidation state of boron in both BN and $B_{2} O_{3}$ is $+ 3 (y)$
So, $x + y = 6 + 3 = 9$
So, the correct option is (4)

JEE Main - 2024

CHXI11:THE P-BLOCK ELEMENTS

316075 Boron reacts with $NaOH$ to form

1 Boric acid

2 Borates

3 Boric anhydride

4 None

Explanation:

$2B + 6NaOH \overset{Fused}{\to} 2N a_{3} B O_{3} + 3 H_{2}$ .

CHXI11:THE P-BLOCK ELEMENTS

316076 Among the following the wrong statement regarding boron is

1 Boron forms an oxide and nitride with air.

2 Boron is a non metal and a non- conductor.

3 Boron displace hydrogen from acids and from bases.

4 Boron oxide is acidic.

CHXI11:THE P-BLOCK ELEMENTS

316077 The ultimate product obtained on heating $B_{2} H_{6}$ with ${NH}_{3}$ is

1

B_{3} N_{3} H_{6}

2

(B - N)_{3}

3

N_{2} H_{4}

4

{BH}^{- 4}

CHXI11:THE P-BLOCK ELEMENTS

316074 The number of neutrons present in the more abundant isotope of boron is x . Amorphous boron upon heating with air forms a product, in which the oxidation state of boron is $y$ . The value of $x + y$ is

1 6

2 3

3 4

4 9

Explanation:

The most abundant isotope of boron is $_{5}^{11} B$ .
No. of neutrons in it $= 11 - 5 = 6 (x)$
Reactions of boron with air
(i) $2 B_{(s)} + N_{2 (g)} \overset{Δ}{\to} 2 {BN}_{(s)}$
(ii) $4 B_{(s)} + 3 O_{2 (g)} \to 2 B_{2} O_{3 (s)}$
Oxidation state of boron in both BN and $B_{2} O_{3}$ is $+ 3 (y)$
So, $x + y = 6 + 3 = 9$
So, the correct option is (4)

JEE Main - 2024

CHXI11:THE P-BLOCK ELEMENTS

316075 Boron reacts with $NaOH$ to form

1 Boric acid

2 Borates

3 Boric anhydride

4 None

Explanation:

$2B + 6NaOH \overset{Fused}{\to} 2N a_{3} B O_{3} + 3 H_{2}$ .

CHXI11:THE P-BLOCK ELEMENTS

316076 Among the following the wrong statement regarding boron is

1 Boron forms an oxide and nitride with air.

2 Boron is a non metal and a non- conductor.

3 Boron displace hydrogen from acids and from bases.

4 Boron oxide is acidic.

CHXI11:THE P-BLOCK ELEMENTS

316077 The ultimate product obtained on heating $B_{2} H_{6}$ with ${NH}_{3}$ is

1

B_{3} N_{3} H_{6}

2

(B - N)_{3}

3

N_{2} H_{4}

4

{BH}^{- 4}

CHXI11:THE P-BLOCK ELEMENTS

316074 The number of neutrons present in the more abundant isotope of boron is x . Amorphous boron upon heating with air forms a product, in which the oxidation state of boron is $y$ . The value of $x + y$ is

1 6

2 3

3 4

4 9

Explanation:

The most abundant isotope of boron is $_{5}^{11} B$ .
No. of neutrons in it $= 11 - 5 = 6 (x)$
Reactions of boron with air
(i) $2 B_{(s)} + N_{2 (g)} \overset{Δ}{\to} 2 {BN}_{(s)}$
(ii) $4 B_{(s)} + 3 O_{2 (g)} \to 2 B_{2} O_{3 (s)}$
Oxidation state of boron in both BN and $B_{2} O_{3}$ is $+ 3 (y)$
So, $x + y = 6 + 3 = 9$
So, the correct option is (4)

JEE Main - 2024

CHXI11:THE P-BLOCK ELEMENTS

316075 Boron reacts with $NaOH$ to form

1 Boric acid

2 Borates

3 Boric anhydride

4 None

Explanation:

$2B + 6NaOH \overset{Fused}{\to} 2N a_{3} B O_{3} + 3 H_{2}$ .

CHXI11:THE P-BLOCK ELEMENTS

316076 Among the following the wrong statement regarding boron is

1 Boron forms an oxide and nitride with air.

2 Boron is a non metal and a non- conductor.

3 Boron displace hydrogen from acids and from bases.

4 Boron oxide is acidic.

CHXI11:THE P-BLOCK ELEMENTS

316077 The ultimate product obtained on heating $B_{2} H_{6}$ with ${NH}_{3}$ is

1

B_{3} N_{3} H_{6}

2

(B - N)_{3}

3

N_{2} H_{4}

4

{BH}^{- 4}

CHXI11:THE P-BLOCK ELEMENTS

316074 The number of neutrons present in the more abundant isotope of boron is x . Amorphous boron upon heating with air forms a product, in which the oxidation state of boron is $y$ . The value of $x + y$ is

1 6

2 3

3 4

4 9

Explanation:

The most abundant isotope of boron is $_{5}^{11} B$ .
No. of neutrons in it $= 11 - 5 = 6 (x)$
Reactions of boron with air
(i) $2 B_{(s)} + N_{2 (g)} \overset{Δ}{\to} 2 {BN}_{(s)}$
(ii) $4 B_{(s)} + 3 O_{2 (g)} \to 2 B_{2} O_{3 (s)}$
Oxidation state of boron in both BN and $B_{2} O_{3}$ is $+ 3 (y)$
So, $x + y = 6 + 3 = 9$
So, the correct option is (4)

JEE Main - 2024

CHXI11:THE P-BLOCK ELEMENTS

316075 Boron reacts with $NaOH$ to form

1 Boric acid

2 Borates

3 Boric anhydride

4 None

Explanation:

$2B + 6NaOH \overset{Fused}{\to} 2N a_{3} B O_{3} + 3 H_{2}$ .

CHXI11:THE P-BLOCK ELEMENTS

316076 Among the following the wrong statement regarding boron is

1 Boron forms an oxide and nitride with air.

2 Boron is a non metal and a non- conductor.

3 Boron displace hydrogen from acids and from bases.

4 Boron oxide is acidic.

CHXI11:THE P-BLOCK ELEMENTS

316077 The ultimate product obtained on heating $B_{2} H_{6}$ with ${NH}_{3}$ is

1

B_{3} N_{3} H_{6}

2

(B - N)_{3}

3

N_{2} H_{4}

4

{BH}^{- 4}

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