Some Important Compounds of Calcium
CHXI10:THE S-BLOCK ELEMENTS

315998 Commercial common salt becomes slightly damp on keeping. This is due to the fact that

1 Common salt is hygroscopic
2 Common salt contains some impurity which is hygroscopic
3 Salt is efflorescent
4 Salt is crystalline
CHXI10:THE S-BLOCK ELEMENTS

315999 Compounds \(\mathrm{X}\) and \(\mathrm{Y}\) are obtained by the reaction of \(\mathrm{Cl}_{2}\) with cold and dilute solution of \(\mathrm{NaOH}\) and compounds \(\mathrm{X}\) and \(\mathrm{Z}\) are formed with hot and concentrated solution of \(\mathrm{NaOH}\).
The compounds \(\mathrm{Y}\) and \(\mathrm{Z}\) respectively are

1 \(\mathrm{NaCl}, \mathrm{NaClO}\)
2 \(\mathrm{NaCl}, \mathrm{NaClO}_{3}\)
3 \(\mathrm{NaClO}, \mathrm{NaClO}_{3}\)
4 \(\mathrm{NaClO}, \mathrm{HCl}\)
CHXI10:THE S-BLOCK ELEMENTS

316000 In the Down's process for the extraction of sodium, the melting point of the electrolyte is lowered by adding

1 \(\mathrm{KF}\)
2 \(\mathrm{CaCl}_{2}\)
3 \(\mathrm{KCl}\)
4 \(\mathrm{KF}+\mathrm{CaCl}_{2}\)
CHXI10:THE S-BLOCK ELEMENTS

316001 In electrolysis of \(\mathrm{NaCl}\) when Pt electrode is taken then \(\mathrm{H}_{2}\) is liberated at cathode while with \(\mathrm{Hg}\) cathode it forms sodium amalgam. The reason for this is

1 \(\mathrm{Hg}\) is more inert than Pt.
2 more voltage is required to reduce \(\mathrm{H}^{+}\)at \(\mathrm{Hg}\) than at \(\mathrm{Pt}\).
3 \(\mathrm{Na}\) is dissolved in \(\mathrm{Hg}\) while it does not dissolve in Pt.
4 concentration of \(\mathrm{H}^{+}\)ions is larger when Pt electrode is taken.
CHXI10:THE S-BLOCK ELEMENTS

315998 Commercial common salt becomes slightly damp on keeping. This is due to the fact that

1 Common salt is hygroscopic
2 Common salt contains some impurity which is hygroscopic
3 Salt is efflorescent
4 Salt is crystalline
CHXI10:THE S-BLOCK ELEMENTS

315999 Compounds \(\mathrm{X}\) and \(\mathrm{Y}\) are obtained by the reaction of \(\mathrm{Cl}_{2}\) with cold and dilute solution of \(\mathrm{NaOH}\) and compounds \(\mathrm{X}\) and \(\mathrm{Z}\) are formed with hot and concentrated solution of \(\mathrm{NaOH}\).
The compounds \(\mathrm{Y}\) and \(\mathrm{Z}\) respectively are

1 \(\mathrm{NaCl}, \mathrm{NaClO}\)
2 \(\mathrm{NaCl}, \mathrm{NaClO}_{3}\)
3 \(\mathrm{NaClO}, \mathrm{NaClO}_{3}\)
4 \(\mathrm{NaClO}, \mathrm{HCl}\)
CHXI10:THE S-BLOCK ELEMENTS

316000 In the Down's process for the extraction of sodium, the melting point of the electrolyte is lowered by adding

1 \(\mathrm{KF}\)
2 \(\mathrm{CaCl}_{2}\)
3 \(\mathrm{KCl}\)
4 \(\mathrm{KF}+\mathrm{CaCl}_{2}\)
CHXI10:THE S-BLOCK ELEMENTS

316001 In electrolysis of \(\mathrm{NaCl}\) when Pt electrode is taken then \(\mathrm{H}_{2}\) is liberated at cathode while with \(\mathrm{Hg}\) cathode it forms sodium amalgam. The reason for this is

1 \(\mathrm{Hg}\) is more inert than Pt.
2 more voltage is required to reduce \(\mathrm{H}^{+}\)at \(\mathrm{Hg}\) than at \(\mathrm{Pt}\).
3 \(\mathrm{Na}\) is dissolved in \(\mathrm{Hg}\) while it does not dissolve in Pt.
4 concentration of \(\mathrm{H}^{+}\)ions is larger when Pt electrode is taken.
NEET Test Series from KOTA - 10 Papers In MS WORD WhatsApp Here
CHXI10:THE S-BLOCK ELEMENTS

315998 Commercial common salt becomes slightly damp on keeping. This is due to the fact that

1 Common salt is hygroscopic
2 Common salt contains some impurity which is hygroscopic
3 Salt is efflorescent
4 Salt is crystalline
CHXI10:THE S-BLOCK ELEMENTS

315999 Compounds \(\mathrm{X}\) and \(\mathrm{Y}\) are obtained by the reaction of \(\mathrm{Cl}_{2}\) with cold and dilute solution of \(\mathrm{NaOH}\) and compounds \(\mathrm{X}\) and \(\mathrm{Z}\) are formed with hot and concentrated solution of \(\mathrm{NaOH}\).
The compounds \(\mathrm{Y}\) and \(\mathrm{Z}\) respectively are

1 \(\mathrm{NaCl}, \mathrm{NaClO}\)
2 \(\mathrm{NaCl}, \mathrm{NaClO}_{3}\)
3 \(\mathrm{NaClO}, \mathrm{NaClO}_{3}\)
4 \(\mathrm{NaClO}, \mathrm{HCl}\)
CHXI10:THE S-BLOCK ELEMENTS

316000 In the Down's process for the extraction of sodium, the melting point of the electrolyte is lowered by adding

1 \(\mathrm{KF}\)
2 \(\mathrm{CaCl}_{2}\)
3 \(\mathrm{KCl}\)
4 \(\mathrm{KF}+\mathrm{CaCl}_{2}\)
CHXI10:THE S-BLOCK ELEMENTS

316001 In electrolysis of \(\mathrm{NaCl}\) when Pt electrode is taken then \(\mathrm{H}_{2}\) is liberated at cathode while with \(\mathrm{Hg}\) cathode it forms sodium amalgam. The reason for this is

1 \(\mathrm{Hg}\) is more inert than Pt.
2 more voltage is required to reduce \(\mathrm{H}^{+}\)at \(\mathrm{Hg}\) than at \(\mathrm{Pt}\).
3 \(\mathrm{Na}\) is dissolved in \(\mathrm{Hg}\) while it does not dissolve in Pt.
4 concentration of \(\mathrm{H}^{+}\)ions is larger when Pt electrode is taken.
CHXI10:THE S-BLOCK ELEMENTS

315998 Commercial common salt becomes slightly damp on keeping. This is due to the fact that

1 Common salt is hygroscopic
2 Common salt contains some impurity which is hygroscopic
3 Salt is efflorescent
4 Salt is crystalline
CHXI10:THE S-BLOCK ELEMENTS

315999 Compounds \(\mathrm{X}\) and \(\mathrm{Y}\) are obtained by the reaction of \(\mathrm{Cl}_{2}\) with cold and dilute solution of \(\mathrm{NaOH}\) and compounds \(\mathrm{X}\) and \(\mathrm{Z}\) are formed with hot and concentrated solution of \(\mathrm{NaOH}\).
The compounds \(\mathrm{Y}\) and \(\mathrm{Z}\) respectively are

1 \(\mathrm{NaCl}, \mathrm{NaClO}\)
2 \(\mathrm{NaCl}, \mathrm{NaClO}_{3}\)
3 \(\mathrm{NaClO}, \mathrm{NaClO}_{3}\)
4 \(\mathrm{NaClO}, \mathrm{HCl}\)
CHXI10:THE S-BLOCK ELEMENTS

316000 In the Down's process for the extraction of sodium, the melting point of the electrolyte is lowered by adding

1 \(\mathrm{KF}\)
2 \(\mathrm{CaCl}_{2}\)
3 \(\mathrm{KCl}\)
4 \(\mathrm{KF}+\mathrm{CaCl}_{2}\)
CHXI10:THE S-BLOCK ELEMENTS

316001 In electrolysis of \(\mathrm{NaCl}\) when Pt electrode is taken then \(\mathrm{H}_{2}\) is liberated at cathode while with \(\mathrm{Hg}\) cathode it forms sodium amalgam. The reason for this is

1 \(\mathrm{Hg}\) is more inert than Pt.
2 more voltage is required to reduce \(\mathrm{H}^{+}\)at \(\mathrm{Hg}\) than at \(\mathrm{Pt}\).
3 \(\mathrm{Na}\) is dissolved in \(\mathrm{Hg}\) while it does not dissolve in Pt.
4 concentration of \(\mathrm{H}^{+}\)ions is larger when Pt electrode is taken.