Explanation:
\(\mathrm{Ba}\left(\mathrm{NO}_{3}\right)_{2}\) responds to both dilute and concentrated \(\mathrm{H}_{2} \mathrm{SO}_{4}\).
\({\rm{Ba}}{\left( {{\rm{N}}{{\rm{O}}_{\rm{3}}}} \right)_{\rm{2}}}{\rm{ + }}{{\rm{H}}_{\rm{2}}}{\rm{S}}{{\rm{O}}_{\rm{4}}}{\rm{(dil)}} \to {\rm{BaS}}{{\rm{O}}_{{\rm{4(\;s)}}}} \downarrow \)
\(\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,{\rm{ + 2}}{{\rm{H}}^{{\rm{(aq)}}}}{\rm{ + 2NO}}_{\rm{3}}^{{\rm{ - (aq)}}}\)
\({\rm{Ba}}{\left( {{\rm{N}}{{\rm{O}}_{\rm{3}}}} \right)_{\rm{2}}}{\rm{ + }}{{\rm{H}}_{\rm{2}}}{\rm{S}}{{\rm{O}}_{\rm{4}}}{\rm{( conc )}} \to \mathop {{\rm{BaS}}{{\rm{O}}_{\rm{4}}}}\limits_{{\rm{( white ppt )}}} {\rm{ + 2HN}}{{\rm{O}}_{\rm{3}}}{\rm{ }}\)
\(\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,{\rm{or }}{\left( {{\rm{CaS}}{{\rm{O}}_{\rm{4}}}} \right)_{\rm{2}}} \cdot {{\rm{H}}_{\rm{2}}}{\rm{O}}\)