CHXI12:ORGANIC CHEMISTRY SOME BASIC PRINCIPLES AND TECHNIQUES
317255
In pyridine; Number of conjugated electrons are
1 6
2 8
3 Zero
4 5
Explanation:
If lone pair and \(\pi\) bond is present on key atom \((\mathrm{N}), \pi\) bond is involved in conjugation. i.e., 6 electrons involved.
CHXI12:ORGANIC CHEMISTRY SOME BASIC PRINCIPLES AND TECHNIQUES
317256
The decreasing order of electron density on the ring is
1 \({\rm{x}} > {\rm{w}} > {\rm{y}} > {\rm{z}}\)
2 \({\rm{z}} > {\rm{y}} > {\rm{w}} > {\rm{x}}\)
3 \({\rm{x}} > {\rm{z}} > {\rm{y}} > {\rm{w}}\)
4 \({\rm{y}} > {\rm{z}} > {\rm{w}} > {\rm{x}}\)
Explanation:
\(-\mathrm{NO}_{2}\) withdraws electron density, through strong \(-\mathrm{M}-\) and \(-\mathrm{I}-\) effect. So, it reduces maximum amount of electron density. \(-\mathrm{NH}_{2}\) at meta position withdraws electron density through weak \(-\mathrm{I}-\) effect. \(-\mathrm{CH}_{3}\) increases electron density through \(+\mathrm{I}-\) effect and hyper conjugation at para position. \(-\mathrm{I}-\) effect of \( - {\rm{Cl}}\) is stronger than its \(+\mathrm{M}-\) effect. So, it overall withdraws electron density from the ring.
CHXI12:ORGANIC CHEMISTRY SOME BASIC PRINCIPLES AND TECHNIQUES
317257
Which group from the following is responsible for \(-\mathrm{R}\) effect?
1 \(-\mathrm{COOR}\)
2 \(-\mathrm{OR}\)
3 \(-\mathrm{OH}\)
4 \(-\mathrm{NHR}\)
Explanation:
\(-\mathrm{COOR}\) show \(-\mathrm{R}\) effect while other groups show \(+\mathrm{R}\) effect.
MHTCET - 2021
CHXI12:ORGANIC CHEMISTRY SOME BASIC PRINCIPLES AND TECHNIQUES
317259
Relative stability of the contributing structures is
1 (II) \({\mathrm{>}}\) (I) \({\mathrm{>}}\) (III)
2 (III) \({\mathrm{>}}\) (II) \({\mathrm{>}}\) (I)
3 (I) \({\mathrm{>}}\) (II) \({\mathrm{>}}\) (III)
4 (I) \({\mathrm{>}}\) (III) \({\mathrm{>}}\) (II)
Explanation:
Neutral structure is more stable than the charged structures. Hence, (I) is most stable among the given resonating structures. The resonating structure with a negative charge on the more electronegative atom will be more stable. Thus, (II) is more stable than (III). Hence, the stability order is (I) \({\mathrm{>}}\) (II) \({\mathrm{>}}\) (III).So, the correct option is (3).
JEE Main - 2024
CHXI12:ORGANIC CHEMISTRY SOME BASIC PRINCIPLES AND TECHNIQUES
317260
Find order of resonance energy of following molecules & resonance energy/benzene also.
1 R.E I \(>\) II \(>\) III R.E/benzene \(\Rightarrow\) I \(>\) II \(>\) III
2 R.E \(\Rightarrow\) III \(>\) II \(>\) I R.E/benzene \(\Rightarrow\) III \(>\) II \(>\) I
3 R.E \(\Rightarrow\) I \(>\) II \(>\) III R.E/benzene \(\Rightarrow\) III \(>\) II \(>\) I
4 R.E \({\text{R}}.{\text{E}} \Rightarrow III{\text{ }} > II{\text{ }} > I\) R.E/benzene \(=\) I \(>\) II \(>\) III
Explanation:
Resonance energy in polynuclear hydrocarbon is greater compared to benzene. But resonance energy per ring is maximum in benzene.
CHXI12:ORGANIC CHEMISTRY SOME BASIC PRINCIPLES AND TECHNIQUES
317255
In pyridine; Number of conjugated electrons are
1 6
2 8
3 Zero
4 5
Explanation:
If lone pair and \(\pi\) bond is present on key atom \((\mathrm{N}), \pi\) bond is involved in conjugation. i.e., 6 electrons involved.
CHXI12:ORGANIC CHEMISTRY SOME BASIC PRINCIPLES AND TECHNIQUES
317256
The decreasing order of electron density on the ring is
1 \({\rm{x}} > {\rm{w}} > {\rm{y}} > {\rm{z}}\)
2 \({\rm{z}} > {\rm{y}} > {\rm{w}} > {\rm{x}}\)
3 \({\rm{x}} > {\rm{z}} > {\rm{y}} > {\rm{w}}\)
4 \({\rm{y}} > {\rm{z}} > {\rm{w}} > {\rm{x}}\)
Explanation:
\(-\mathrm{NO}_{2}\) withdraws electron density, through strong \(-\mathrm{M}-\) and \(-\mathrm{I}-\) effect. So, it reduces maximum amount of electron density. \(-\mathrm{NH}_{2}\) at meta position withdraws electron density through weak \(-\mathrm{I}-\) effect. \(-\mathrm{CH}_{3}\) increases electron density through \(+\mathrm{I}-\) effect and hyper conjugation at para position. \(-\mathrm{I}-\) effect of \( - {\rm{Cl}}\) is stronger than its \(+\mathrm{M}-\) effect. So, it overall withdraws electron density from the ring.
CHXI12:ORGANIC CHEMISTRY SOME BASIC PRINCIPLES AND TECHNIQUES
317257
Which group from the following is responsible for \(-\mathrm{R}\) effect?
1 \(-\mathrm{COOR}\)
2 \(-\mathrm{OR}\)
3 \(-\mathrm{OH}\)
4 \(-\mathrm{NHR}\)
Explanation:
\(-\mathrm{COOR}\) show \(-\mathrm{R}\) effect while other groups show \(+\mathrm{R}\) effect.
MHTCET - 2021
CHXI12:ORGANIC CHEMISTRY SOME BASIC PRINCIPLES AND TECHNIQUES
317259
Relative stability of the contributing structures is
1 (II) \({\mathrm{>}}\) (I) \({\mathrm{>}}\) (III)
2 (III) \({\mathrm{>}}\) (II) \({\mathrm{>}}\) (I)
3 (I) \({\mathrm{>}}\) (II) \({\mathrm{>}}\) (III)
4 (I) \({\mathrm{>}}\) (III) \({\mathrm{>}}\) (II)
Explanation:
Neutral structure is more stable than the charged structures. Hence, (I) is most stable among the given resonating structures. The resonating structure with a negative charge on the more electronegative atom will be more stable. Thus, (II) is more stable than (III). Hence, the stability order is (I) \({\mathrm{>}}\) (II) \({\mathrm{>}}\) (III).So, the correct option is (3).
JEE Main - 2024
CHXI12:ORGANIC CHEMISTRY SOME BASIC PRINCIPLES AND TECHNIQUES
317260
Find order of resonance energy of following molecules & resonance energy/benzene also.
1 R.E I \(>\) II \(>\) III R.E/benzene \(\Rightarrow\) I \(>\) II \(>\) III
2 R.E \(\Rightarrow\) III \(>\) II \(>\) I R.E/benzene \(\Rightarrow\) III \(>\) II \(>\) I
3 R.E \(\Rightarrow\) I \(>\) II \(>\) III R.E/benzene \(\Rightarrow\) III \(>\) II \(>\) I
4 R.E \({\text{R}}.{\text{E}} \Rightarrow III{\text{ }} > II{\text{ }} > I\) R.E/benzene \(=\) I \(>\) II \(>\) III
Explanation:
Resonance energy in polynuclear hydrocarbon is greater compared to benzene. But resonance energy per ring is maximum in benzene.
NEET Test Series from KOTA - 10 Papers In MS WORD
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CHXI12:ORGANIC CHEMISTRY SOME BASIC PRINCIPLES AND TECHNIQUES
317255
In pyridine; Number of conjugated electrons are
1 6
2 8
3 Zero
4 5
Explanation:
If lone pair and \(\pi\) bond is present on key atom \((\mathrm{N}), \pi\) bond is involved in conjugation. i.e., 6 electrons involved.
CHXI12:ORGANIC CHEMISTRY SOME BASIC PRINCIPLES AND TECHNIQUES
317256
The decreasing order of electron density on the ring is
1 \({\rm{x}} > {\rm{w}} > {\rm{y}} > {\rm{z}}\)
2 \({\rm{z}} > {\rm{y}} > {\rm{w}} > {\rm{x}}\)
3 \({\rm{x}} > {\rm{z}} > {\rm{y}} > {\rm{w}}\)
4 \({\rm{y}} > {\rm{z}} > {\rm{w}} > {\rm{x}}\)
Explanation:
\(-\mathrm{NO}_{2}\) withdraws electron density, through strong \(-\mathrm{M}-\) and \(-\mathrm{I}-\) effect. So, it reduces maximum amount of electron density. \(-\mathrm{NH}_{2}\) at meta position withdraws electron density through weak \(-\mathrm{I}-\) effect. \(-\mathrm{CH}_{3}\) increases electron density through \(+\mathrm{I}-\) effect and hyper conjugation at para position. \(-\mathrm{I}-\) effect of \( - {\rm{Cl}}\) is stronger than its \(+\mathrm{M}-\) effect. So, it overall withdraws electron density from the ring.
CHXI12:ORGANIC CHEMISTRY SOME BASIC PRINCIPLES AND TECHNIQUES
317257
Which group from the following is responsible for \(-\mathrm{R}\) effect?
1 \(-\mathrm{COOR}\)
2 \(-\mathrm{OR}\)
3 \(-\mathrm{OH}\)
4 \(-\mathrm{NHR}\)
Explanation:
\(-\mathrm{COOR}\) show \(-\mathrm{R}\) effect while other groups show \(+\mathrm{R}\) effect.
MHTCET - 2021
CHXI12:ORGANIC CHEMISTRY SOME BASIC PRINCIPLES AND TECHNIQUES
317259
Relative stability of the contributing structures is
1 (II) \({\mathrm{>}}\) (I) \({\mathrm{>}}\) (III)
2 (III) \({\mathrm{>}}\) (II) \({\mathrm{>}}\) (I)
3 (I) \({\mathrm{>}}\) (II) \({\mathrm{>}}\) (III)
4 (I) \({\mathrm{>}}\) (III) \({\mathrm{>}}\) (II)
Explanation:
Neutral structure is more stable than the charged structures. Hence, (I) is most stable among the given resonating structures. The resonating structure with a negative charge on the more electronegative atom will be more stable. Thus, (II) is more stable than (III). Hence, the stability order is (I) \({\mathrm{>}}\) (II) \({\mathrm{>}}\) (III).So, the correct option is (3).
JEE Main - 2024
CHXI12:ORGANIC CHEMISTRY SOME BASIC PRINCIPLES AND TECHNIQUES
317260
Find order of resonance energy of following molecules & resonance energy/benzene also.
1 R.E I \(>\) II \(>\) III R.E/benzene \(\Rightarrow\) I \(>\) II \(>\) III
2 R.E \(\Rightarrow\) III \(>\) II \(>\) I R.E/benzene \(\Rightarrow\) III \(>\) II \(>\) I
3 R.E \(\Rightarrow\) I \(>\) II \(>\) III R.E/benzene \(\Rightarrow\) III \(>\) II \(>\) I
4 R.E \({\text{R}}.{\text{E}} \Rightarrow III{\text{ }} > II{\text{ }} > I\) R.E/benzene \(=\) I \(>\) II \(>\) III
Explanation:
Resonance energy in polynuclear hydrocarbon is greater compared to benzene. But resonance energy per ring is maximum in benzene.
CHXI12:ORGANIC CHEMISTRY SOME BASIC PRINCIPLES AND TECHNIQUES
317255
In pyridine; Number of conjugated electrons are
1 6
2 8
3 Zero
4 5
Explanation:
If lone pair and \(\pi\) bond is present on key atom \((\mathrm{N}), \pi\) bond is involved in conjugation. i.e., 6 electrons involved.
CHXI12:ORGANIC CHEMISTRY SOME BASIC PRINCIPLES AND TECHNIQUES
317256
The decreasing order of electron density on the ring is
1 \({\rm{x}} > {\rm{w}} > {\rm{y}} > {\rm{z}}\)
2 \({\rm{z}} > {\rm{y}} > {\rm{w}} > {\rm{x}}\)
3 \({\rm{x}} > {\rm{z}} > {\rm{y}} > {\rm{w}}\)
4 \({\rm{y}} > {\rm{z}} > {\rm{w}} > {\rm{x}}\)
Explanation:
\(-\mathrm{NO}_{2}\) withdraws electron density, through strong \(-\mathrm{M}-\) and \(-\mathrm{I}-\) effect. So, it reduces maximum amount of electron density. \(-\mathrm{NH}_{2}\) at meta position withdraws electron density through weak \(-\mathrm{I}-\) effect. \(-\mathrm{CH}_{3}\) increases electron density through \(+\mathrm{I}-\) effect and hyper conjugation at para position. \(-\mathrm{I}-\) effect of \( - {\rm{Cl}}\) is stronger than its \(+\mathrm{M}-\) effect. So, it overall withdraws electron density from the ring.
CHXI12:ORGANIC CHEMISTRY SOME BASIC PRINCIPLES AND TECHNIQUES
317257
Which group from the following is responsible for \(-\mathrm{R}\) effect?
1 \(-\mathrm{COOR}\)
2 \(-\mathrm{OR}\)
3 \(-\mathrm{OH}\)
4 \(-\mathrm{NHR}\)
Explanation:
\(-\mathrm{COOR}\) show \(-\mathrm{R}\) effect while other groups show \(+\mathrm{R}\) effect.
MHTCET - 2021
CHXI12:ORGANIC CHEMISTRY SOME BASIC PRINCIPLES AND TECHNIQUES
317259
Relative stability of the contributing structures is
1 (II) \({\mathrm{>}}\) (I) \({\mathrm{>}}\) (III)
2 (III) \({\mathrm{>}}\) (II) \({\mathrm{>}}\) (I)
3 (I) \({\mathrm{>}}\) (II) \({\mathrm{>}}\) (III)
4 (I) \({\mathrm{>}}\) (III) \({\mathrm{>}}\) (II)
Explanation:
Neutral structure is more stable than the charged structures. Hence, (I) is most stable among the given resonating structures. The resonating structure with a negative charge on the more electronegative atom will be more stable. Thus, (II) is more stable than (III). Hence, the stability order is (I) \({\mathrm{>}}\) (II) \({\mathrm{>}}\) (III).So, the correct option is (3).
JEE Main - 2024
CHXI12:ORGANIC CHEMISTRY SOME BASIC PRINCIPLES AND TECHNIQUES
317260
Find order of resonance energy of following molecules & resonance energy/benzene also.
1 R.E I \(>\) II \(>\) III R.E/benzene \(\Rightarrow\) I \(>\) II \(>\) III
2 R.E \(\Rightarrow\) III \(>\) II \(>\) I R.E/benzene \(\Rightarrow\) III \(>\) II \(>\) I
3 R.E \(\Rightarrow\) I \(>\) II \(>\) III R.E/benzene \(\Rightarrow\) III \(>\) II \(>\) I
4 R.E \({\text{R}}.{\text{E}} \Rightarrow III{\text{ }} > II{\text{ }} > I\) R.E/benzene \(=\) I \(>\) II \(>\) III
Explanation:
Resonance energy in polynuclear hydrocarbon is greater compared to benzene. But resonance energy per ring is maximum in benzene.
CHXI12:ORGANIC CHEMISTRY SOME BASIC PRINCIPLES AND TECHNIQUES
317255
In pyridine; Number of conjugated electrons are
1 6
2 8
3 Zero
4 5
Explanation:
If lone pair and \(\pi\) bond is present on key atom \((\mathrm{N}), \pi\) bond is involved in conjugation. i.e., 6 electrons involved.
CHXI12:ORGANIC CHEMISTRY SOME BASIC PRINCIPLES AND TECHNIQUES
317256
The decreasing order of electron density on the ring is
1 \({\rm{x}} > {\rm{w}} > {\rm{y}} > {\rm{z}}\)
2 \({\rm{z}} > {\rm{y}} > {\rm{w}} > {\rm{x}}\)
3 \({\rm{x}} > {\rm{z}} > {\rm{y}} > {\rm{w}}\)
4 \({\rm{y}} > {\rm{z}} > {\rm{w}} > {\rm{x}}\)
Explanation:
\(-\mathrm{NO}_{2}\) withdraws electron density, through strong \(-\mathrm{M}-\) and \(-\mathrm{I}-\) effect. So, it reduces maximum amount of electron density. \(-\mathrm{NH}_{2}\) at meta position withdraws electron density through weak \(-\mathrm{I}-\) effect. \(-\mathrm{CH}_{3}\) increases electron density through \(+\mathrm{I}-\) effect and hyper conjugation at para position. \(-\mathrm{I}-\) effect of \( - {\rm{Cl}}\) is stronger than its \(+\mathrm{M}-\) effect. So, it overall withdraws electron density from the ring.
CHXI12:ORGANIC CHEMISTRY SOME BASIC PRINCIPLES AND TECHNIQUES
317257
Which group from the following is responsible for \(-\mathrm{R}\) effect?
1 \(-\mathrm{COOR}\)
2 \(-\mathrm{OR}\)
3 \(-\mathrm{OH}\)
4 \(-\mathrm{NHR}\)
Explanation:
\(-\mathrm{COOR}\) show \(-\mathrm{R}\) effect while other groups show \(+\mathrm{R}\) effect.
MHTCET - 2021
CHXI12:ORGANIC CHEMISTRY SOME BASIC PRINCIPLES AND TECHNIQUES
317259
Relative stability of the contributing structures is
1 (II) \({\mathrm{>}}\) (I) \({\mathrm{>}}\) (III)
2 (III) \({\mathrm{>}}\) (II) \({\mathrm{>}}\) (I)
3 (I) \({\mathrm{>}}\) (II) \({\mathrm{>}}\) (III)
4 (I) \({\mathrm{>}}\) (III) \({\mathrm{>}}\) (II)
Explanation:
Neutral structure is more stable than the charged structures. Hence, (I) is most stable among the given resonating structures. The resonating structure with a negative charge on the more electronegative atom will be more stable. Thus, (II) is more stable than (III). Hence, the stability order is (I) \({\mathrm{>}}\) (II) \({\mathrm{>}}\) (III).So, the correct option is (3).
JEE Main - 2024
CHXI12:ORGANIC CHEMISTRY SOME BASIC PRINCIPLES AND TECHNIQUES
317260
Find order of resonance energy of following molecules & resonance energy/benzene also.
1 R.E I \(>\) II \(>\) III R.E/benzene \(\Rightarrow\) I \(>\) II \(>\) III
2 R.E \(\Rightarrow\) III \(>\) II \(>\) I R.E/benzene \(\Rightarrow\) III \(>\) II \(>\) I
3 R.E \(\Rightarrow\) I \(>\) II \(>\) III R.E/benzene \(\Rightarrow\) III \(>\) II \(>\) I
4 R.E \({\text{R}}.{\text{E}} \Rightarrow III{\text{ }} > II{\text{ }} > I\) R.E/benzene \(=\) I \(>\) II \(>\) III
Explanation:
Resonance energy in polynuclear hydrocarbon is greater compared to benzene. But resonance energy per ring is maximum in benzene.
