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CHXI09:HYDROGEN

315503 Which one of the following pairs of substances will not produce hydrogen when reacted together?

1 Copper and conc. nitric acid

2 Ethanol and metallic sodium

3 Magnesium and steam

4 Phenol and metallic sodium

Explanation:

$\begin{aligned} Cu + 4 {HNO}_{3} (conc.) ⟶ Cu {({NO}_{3})}_{2} + 2 {NO}_{2} + 2 H_{2} O \\ C_{2} H_{5} OH + Na \to C_{2} H_{5} O^{-} {Na}^{+} + 1 / 2 H_{2} ↑ \\ Mg + 2 H_{2} O (steam) \to Mg (OH)_{2} + H_{2} ↑ \\ C_{6} H_{5} OH + Na \to C_{6} H_{5} O^{-} {Na}^{+} + 1 / 2 H_{2} ↑ \\ NaH + H_{2} O \to NaOH + H_{2} ↑ \end{aligned}$

CHXI09:HYDROGEN

315504 In Bosch's process, the gas that is utilised for the production of hydrogen gas is

1 Producer gas

2 Water gas

3 Coal gas

4 Petroleum gas

Explanation:

$\underset{Water gas}{\underset{⏟}{CO + H_{2}}} + \underset{Steam}{H_{2} O} \overset{catalyst}{\to} C O_{2} + H_{2}$

CHXI09:HYDROGEN

315505 Hydrogen is evolved by the action of cold dilute ${HNO}_{3}$ is

1

Fe

2

Cu

3

Mg

4

Al

Explanation:

$Mg$ present above hydrogen in electrochemical series and liberates hydrogen when it combines with ${HNO}_{3}$

CHXI09:HYDROGEN

315506 The metal that produces $H_{2}$ with both dil $HCl$ and ${NaOH}_{(aq)}$ is

1

Mg

2

Ca

3

Fe

4

Zn

Explanation:

$Zn$ liberates $H_{2}$ gas with both dil. $HCl$ and ${NaOH}_{(aq)}$ . $\begin{aligned} {Zn}_{(s)} + 2 {HCl}_{(aq)} \to {ZnCl}_{2 (aq)} + H_{2 (g)} ↑ \\ {Zn}_{(s)} + 2 {NaOH}_{(aq)} \to \underset{(sodium zincate)}{{Na}_{2} {ZnO}_{2 (aq)} + H_{2 (g)} ↑} \end{aligned}$

CHXI09:HYDROGEN

315507 The products of the electrolysis of concentrated aqueous solution of common salt are

1

Na + {Cl}_{2}

2

H_{2} + O_{2}

3

NaOH + H_{2} + {Cl}_{2}

4

NaOH + {Cl}_{2} + O_{2}

Explanation:

At anode: $2 {Cl}^{-} \to {Cl}_{2} + 2 e$
At cathode: $2 H^{+} + 2 e \to H_{2}$

CHXI09:HYDROGEN

315503 Which one of the following pairs of substances will not produce hydrogen when reacted together?

1 Copper and conc. nitric acid

2 Ethanol and metallic sodium

3 Magnesium and steam

4 Phenol and metallic sodium

Explanation:

$\begin{aligned} Cu + 4 {HNO}_{3} (conc.) ⟶ Cu {({NO}_{3})}_{2} + 2 {NO}_{2} + 2 H_{2} O \\ C_{2} H_{5} OH + Na \to C_{2} H_{5} O^{-} {Na}^{+} + 1 / 2 H_{2} ↑ \\ Mg + 2 H_{2} O (steam) \to Mg (OH)_{2} + H_{2} ↑ \\ C_{6} H_{5} OH + Na \to C_{6} H_{5} O^{-} {Na}^{+} + 1 / 2 H_{2} ↑ \\ NaH + H_{2} O \to NaOH + H_{2} ↑ \end{aligned}$

CHXI09:HYDROGEN

315504 In Bosch's process, the gas that is utilised for the production of hydrogen gas is

1 Producer gas

2 Water gas

3 Coal gas

4 Petroleum gas

Explanation:

$\underset{Water gas}{\underset{⏟}{CO + H_{2}}} + \underset{Steam}{H_{2} O} \overset{catalyst}{\to} C O_{2} + H_{2}$

CHXI09:HYDROGEN

315505 Hydrogen is evolved by the action of cold dilute ${HNO}_{3}$ is

1

Fe

2

Cu

3

Mg

4

Al

Explanation:

$Mg$ present above hydrogen in electrochemical series and liberates hydrogen when it combines with ${HNO}_{3}$

CHXI09:HYDROGEN

315506 The metal that produces $H_{2}$ with both dil $HCl$ and ${NaOH}_{(aq)}$ is

1

Mg

2

Ca

3

Fe

4

Zn

Explanation:

$Zn$ liberates $H_{2}$ gas with both dil. $HCl$ and ${NaOH}_{(aq)}$ . $\begin{aligned} {Zn}_{(s)} + 2 {HCl}_{(aq)} \to {ZnCl}_{2 (aq)} + H_{2 (g)} ↑ \\ {Zn}_{(s)} + 2 {NaOH}_{(aq)} \to \underset{(sodium zincate)}{{Na}_{2} {ZnO}_{2 (aq)} + H_{2 (g)} ↑} \end{aligned}$

CHXI09:HYDROGEN

315507 The products of the electrolysis of concentrated aqueous solution of common salt are

1

Na + {Cl}_{2}

2

H_{2} + O_{2}

3

NaOH + H_{2} + {Cl}_{2}

4

NaOH + {Cl}_{2} + O_{2}

Explanation:

At anode: $2 {Cl}^{-} \to {Cl}_{2} + 2 e$
At cathode: $2 H^{+} + 2 e \to H_{2}$

CHXI09:HYDROGEN

315503 Which one of the following pairs of substances will not produce hydrogen when reacted together?

1 Copper and conc. nitric acid

2 Ethanol and metallic sodium

3 Magnesium and steam

4 Phenol and metallic sodium

Explanation:

$\begin{aligned} Cu + 4 {HNO}_{3} (conc.) ⟶ Cu {({NO}_{3})}_{2} + 2 {NO}_{2} + 2 H_{2} O \\ C_{2} H_{5} OH + Na \to C_{2} H_{5} O^{-} {Na}^{+} + 1 / 2 H_{2} ↑ \\ Mg + 2 H_{2} O (steam) \to Mg (OH)_{2} + H_{2} ↑ \\ C_{6} H_{5} OH + Na \to C_{6} H_{5} O^{-} {Na}^{+} + 1 / 2 H_{2} ↑ \\ NaH + H_{2} O \to NaOH + H_{2} ↑ \end{aligned}$

CHXI09:HYDROGEN

315504 In Bosch's process, the gas that is utilised for the production of hydrogen gas is

1 Producer gas

2 Water gas

3 Coal gas

4 Petroleum gas

Explanation:

$\underset{Water gas}{\underset{⏟}{CO + H_{2}}} + \underset{Steam}{H_{2} O} \overset{catalyst}{\to} C O_{2} + H_{2}$

CHXI09:HYDROGEN

315505 Hydrogen is evolved by the action of cold dilute ${HNO}_{3}$ is

1

Fe

2

Cu

3

Mg

4

Al

Explanation:

$Mg$ present above hydrogen in electrochemical series and liberates hydrogen when it combines with ${HNO}_{3}$

CHXI09:HYDROGEN

315506 The metal that produces $H_{2}$ with both dil $HCl$ and ${NaOH}_{(aq)}$ is

1

Mg

2

Ca

3

Fe

4

Zn

Explanation:

$Zn$ liberates $H_{2}$ gas with both dil. $HCl$ and ${NaOH}_{(aq)}$ . $\begin{aligned} {Zn}_{(s)} + 2 {HCl}_{(aq)} \to {ZnCl}_{2 (aq)} + H_{2 (g)} ↑ \\ {Zn}_{(s)} + 2 {NaOH}_{(aq)} \to \underset{(sodium zincate)}{{Na}_{2} {ZnO}_{2 (aq)} + H_{2 (g)} ↑} \end{aligned}$

CHXI09:HYDROGEN

315507 The products of the electrolysis of concentrated aqueous solution of common salt are

1

Na + {Cl}_{2}

2

H_{2} + O_{2}

3

NaOH + H_{2} + {Cl}_{2}

4

NaOH + {Cl}_{2} + O_{2}

Explanation:

At anode: $2 {Cl}^{-} \to {Cl}_{2} + 2 e$
At cathode: $2 H^{+} + 2 e \to H_{2}$

CHXI09:HYDROGEN

315503 Which one of the following pairs of substances will not produce hydrogen when reacted together?

1 Copper and conc. nitric acid

2 Ethanol and metallic sodium

3 Magnesium and steam

4 Phenol and metallic sodium

Explanation:

$\begin{aligned} Cu + 4 {HNO}_{3} (conc.) ⟶ Cu {({NO}_{3})}_{2} + 2 {NO}_{2} + 2 H_{2} O \\ C_{2} H_{5} OH + Na \to C_{2} H_{5} O^{-} {Na}^{+} + 1 / 2 H_{2} ↑ \\ Mg + 2 H_{2} O (steam) \to Mg (OH)_{2} + H_{2} ↑ \\ C_{6} H_{5} OH + Na \to C_{6} H_{5} O^{-} {Na}^{+} + 1 / 2 H_{2} ↑ \\ NaH + H_{2} O \to NaOH + H_{2} ↑ \end{aligned}$

CHXI09:HYDROGEN

315504 In Bosch's process, the gas that is utilised for the production of hydrogen gas is

1 Producer gas

2 Water gas

3 Coal gas

4 Petroleum gas

Explanation:

$\underset{Water gas}{\underset{⏟}{CO + H_{2}}} + \underset{Steam}{H_{2} O} \overset{catalyst}{\to} C O_{2} + H_{2}$

CHXI09:HYDROGEN

315505 Hydrogen is evolved by the action of cold dilute ${HNO}_{3}$ is

1

Fe

2

Cu

3

Mg

4

Al

Explanation:

$Mg$ present above hydrogen in electrochemical series and liberates hydrogen when it combines with ${HNO}_{3}$

CHXI09:HYDROGEN

315506 The metal that produces $H_{2}$ with both dil $HCl$ and ${NaOH}_{(aq)}$ is

1

Mg

2

Ca

3

Fe

4

Zn

Explanation:

$Zn$ liberates $H_{2}$ gas with both dil. $HCl$ and ${NaOH}_{(aq)}$ . $\begin{aligned} {Zn}_{(s)} + 2 {HCl}_{(aq)} \to {ZnCl}_{2 (aq)} + H_{2 (g)} ↑ \\ {Zn}_{(s)} + 2 {NaOH}_{(aq)} \to \underset{(sodium zincate)}{{Na}_{2} {ZnO}_{2 (aq)} + H_{2 (g)} ↑} \end{aligned}$

CHXI09:HYDROGEN

315507 The products of the electrolysis of concentrated aqueous solution of common salt are

1

Na + {Cl}_{2}

2

H_{2} + O_{2}

3

NaOH + H_{2} + {Cl}_{2}

4

NaOH + {Cl}_{2} + O_{2}

Explanation:

At anode: $2 {Cl}^{-} \to {Cl}_{2} + 2 e$
At cathode: $2 H^{+} + 2 e \to H_{2}$

CHXI09:HYDROGEN

315503 Which one of the following pairs of substances will not produce hydrogen when reacted together?

1 Copper and conc. nitric acid

2 Ethanol and metallic sodium

3 Magnesium and steam

4 Phenol and metallic sodium

Explanation:

$\begin{aligned} Cu + 4 {HNO}_{3} (conc.) ⟶ Cu {({NO}_{3})}_{2} + 2 {NO}_{2} + 2 H_{2} O \\ C_{2} H_{5} OH + Na \to C_{2} H_{5} O^{-} {Na}^{+} + 1 / 2 H_{2} ↑ \\ Mg + 2 H_{2} O (steam) \to Mg (OH)_{2} + H_{2} ↑ \\ C_{6} H_{5} OH + Na \to C_{6} H_{5} O^{-} {Na}^{+} + 1 / 2 H_{2} ↑ \\ NaH + H_{2} O \to NaOH + H_{2} ↑ \end{aligned}$

CHXI09:HYDROGEN

315504 In Bosch's process, the gas that is utilised for the production of hydrogen gas is

1 Producer gas

2 Water gas

3 Coal gas

4 Petroleum gas

Explanation:

$\underset{Water gas}{\underset{⏟}{CO + H_{2}}} + \underset{Steam}{H_{2} O} \overset{catalyst}{\to} C O_{2} + H_{2}$

CHXI09:HYDROGEN

315505 Hydrogen is evolved by the action of cold dilute ${HNO}_{3}$ is

1

Fe

2

Cu

3

Mg

4

Al

Explanation:

$Mg$ present above hydrogen in electrochemical series and liberates hydrogen when it combines with ${HNO}_{3}$

CHXI09:HYDROGEN

315506 The metal that produces $H_{2}$ with both dil $HCl$ and ${NaOH}_{(aq)}$ is

1

Mg

2

Ca

3

Fe

4

Zn

Explanation:

$Zn$ liberates $H_{2}$ gas with both dil. $HCl$ and ${NaOH}_{(aq)}$ . $\begin{aligned} {Zn}_{(s)} + 2 {HCl}_{(aq)} \to {ZnCl}_{2 (aq)} + H_{2 (g)} ↑ \\ {Zn}_{(s)} + 2 {NaOH}_{(aq)} \to \underset{(sodium zincate)}{{Na}_{2} {ZnO}_{2 (aq)} + H_{2 (g)} ↑} \end{aligned}$

CHXI09:HYDROGEN

315507 The products of the electrolysis of concentrated aqueous solution of common salt are

1

Na + {Cl}_{2}

2

H_{2} + O_{2}

3

NaOH + H_{2} + {Cl}_{2}

4

NaOH + {Cl}_{2} + O_{2}

Explanation:

At anode: $2 {Cl}^{-} \to {Cl}_{2} + 2 e$
At cathode: $2 H^{+} + 2 e \to H_{2}$

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