NEET Test Series from KOTA - 10 Papers In MS WORD
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CHXI08:REDOX REACTIONS
315177
The oxidation state of the most electronegative element in the products of the reaction between \(\mathrm{\mathrm{BaO}_{2}}\) and \(\mathrm{\mathrm{H}_{2} \mathrm{SO}_{4}}\) are
1 \({\rm{0}}\,\,{\rm{and}}\,\,{\rm{ - 1}}\)
2 \({\rm{ - 1}}\,\,{\rm{and}}\,\,{\rm{ - 2}}\)
3 \({\rm{ - 2}}\,\,{\rm{and}}\,\,{\rm{0}}\)
4 \({\rm{ - 2}}\,\,{\rm{and}}\,\,{\rm{ + 1}}\)
Explanation:
\(\mathrm{\mathrm{BaO}_{2}+\mathrm{H}_{2} \mathrm{SO}_{4} \rightarrow \mathrm{BaSO}_{4}+\mathrm{H}_{2} \mathrm{O}_{2}}\) The most electronegative element \(\mathrm{\mathrm{O}}\) is present in \(\mathrm{\mathrm{BaSO}_{4}}\) and \(\mathrm{\mathrm{H}_{2} \mathrm{O}_{2}}\), where its O.N. are \({\rm{ - 2}}\,\,{\rm{and}}\,\,{\rm{ - 1}}\) respectively.
CHXI08:REDOX REACTIONS
315178
In which of the following compounds, iron has an oxidation number of +3 ?
\(\mathrm{\therefore \mathrm{In} \mathrm{Fe}\left(\mathrm{NO}_{3}\right)_{2}}\), Fe has oxidation number +2 (as \(\mathrm{\mathrm{NO}_{3}^{-}}\)has 1 unit -ve charge) \(\mathrm{\therefore}\) In \(\mathrm{\mathrm{FeC}_{2} \mathrm{O}_{4}}\), \(\mathrm{\mathrm{Fe}}\) has oxidation number +2 as \(\mathrm{\mathrm{C}_{2} \mathrm{O}_{4}^{-2}}\) has 2 units -ve charge. In \(\mathrm{\mathrm{FeCl}_{3}}\), \(\mathrm{\mathrm{Fe}}\) has +3 oxidation state as \(\mathrm{\mathrm{Cl}^{-}}\)has 1 unit -ve charge
CHXI08:REDOX REACTIONS
315179
The oxidation states of sulphur in the anions \(\mathrm{SO}_{3}^{2-}, \mathrm{S}_{2} \mathrm{O}_{4}^{2-}\) and \(\mathrm{S}_{2} \mathrm{O}_{6}^{2-}\) follow the order.
In \(\mathrm{\mathrm{BaO}_{2}+\mathrm{H}_{2} \mathrm{SO}_{4} \rightarrow \mathrm{BaSO}_{4}+\mathrm{H}_{2} \mathrm{O}_{2}}\) all atoms are present in the same O.S. in reactants and products.
315177
The oxidation state of the most electronegative element in the products of the reaction between \(\mathrm{\mathrm{BaO}_{2}}\) and \(\mathrm{\mathrm{H}_{2} \mathrm{SO}_{4}}\) are
1 \({\rm{0}}\,\,{\rm{and}}\,\,{\rm{ - 1}}\)
2 \({\rm{ - 1}}\,\,{\rm{and}}\,\,{\rm{ - 2}}\)
3 \({\rm{ - 2}}\,\,{\rm{and}}\,\,{\rm{0}}\)
4 \({\rm{ - 2}}\,\,{\rm{and}}\,\,{\rm{ + 1}}\)
Explanation:
\(\mathrm{\mathrm{BaO}_{2}+\mathrm{H}_{2} \mathrm{SO}_{4} \rightarrow \mathrm{BaSO}_{4}+\mathrm{H}_{2} \mathrm{O}_{2}}\) The most electronegative element \(\mathrm{\mathrm{O}}\) is present in \(\mathrm{\mathrm{BaSO}_{4}}\) and \(\mathrm{\mathrm{H}_{2} \mathrm{O}_{2}}\), where its O.N. are \({\rm{ - 2}}\,\,{\rm{and}}\,\,{\rm{ - 1}}\) respectively.
CHXI08:REDOX REACTIONS
315178
In which of the following compounds, iron has an oxidation number of +3 ?
\(\mathrm{\therefore \mathrm{In} \mathrm{Fe}\left(\mathrm{NO}_{3}\right)_{2}}\), Fe has oxidation number +2 (as \(\mathrm{\mathrm{NO}_{3}^{-}}\)has 1 unit -ve charge) \(\mathrm{\therefore}\) In \(\mathrm{\mathrm{FeC}_{2} \mathrm{O}_{4}}\), \(\mathrm{\mathrm{Fe}}\) has oxidation number +2 as \(\mathrm{\mathrm{C}_{2} \mathrm{O}_{4}^{-2}}\) has 2 units -ve charge. In \(\mathrm{\mathrm{FeCl}_{3}}\), \(\mathrm{\mathrm{Fe}}\) has +3 oxidation state as \(\mathrm{\mathrm{Cl}^{-}}\)has 1 unit -ve charge
CHXI08:REDOX REACTIONS
315179
The oxidation states of sulphur in the anions \(\mathrm{SO}_{3}^{2-}, \mathrm{S}_{2} \mathrm{O}_{4}^{2-}\) and \(\mathrm{S}_{2} \mathrm{O}_{6}^{2-}\) follow the order.
In \(\mathrm{\mathrm{BaO}_{2}+\mathrm{H}_{2} \mathrm{SO}_{4} \rightarrow \mathrm{BaSO}_{4}+\mathrm{H}_{2} \mathrm{O}_{2}}\) all atoms are present in the same O.S. in reactants and products.
315177
The oxidation state of the most electronegative element in the products of the reaction between \(\mathrm{\mathrm{BaO}_{2}}\) and \(\mathrm{\mathrm{H}_{2} \mathrm{SO}_{4}}\) are
1 \({\rm{0}}\,\,{\rm{and}}\,\,{\rm{ - 1}}\)
2 \({\rm{ - 1}}\,\,{\rm{and}}\,\,{\rm{ - 2}}\)
3 \({\rm{ - 2}}\,\,{\rm{and}}\,\,{\rm{0}}\)
4 \({\rm{ - 2}}\,\,{\rm{and}}\,\,{\rm{ + 1}}\)
Explanation:
\(\mathrm{\mathrm{BaO}_{2}+\mathrm{H}_{2} \mathrm{SO}_{4} \rightarrow \mathrm{BaSO}_{4}+\mathrm{H}_{2} \mathrm{O}_{2}}\) The most electronegative element \(\mathrm{\mathrm{O}}\) is present in \(\mathrm{\mathrm{BaSO}_{4}}\) and \(\mathrm{\mathrm{H}_{2} \mathrm{O}_{2}}\), where its O.N. are \({\rm{ - 2}}\,\,{\rm{and}}\,\,{\rm{ - 1}}\) respectively.
CHXI08:REDOX REACTIONS
315178
In which of the following compounds, iron has an oxidation number of +3 ?
\(\mathrm{\therefore \mathrm{In} \mathrm{Fe}\left(\mathrm{NO}_{3}\right)_{2}}\), Fe has oxidation number +2 (as \(\mathrm{\mathrm{NO}_{3}^{-}}\)has 1 unit -ve charge) \(\mathrm{\therefore}\) In \(\mathrm{\mathrm{FeC}_{2} \mathrm{O}_{4}}\), \(\mathrm{\mathrm{Fe}}\) has oxidation number +2 as \(\mathrm{\mathrm{C}_{2} \mathrm{O}_{4}^{-2}}\) has 2 units -ve charge. In \(\mathrm{\mathrm{FeCl}_{3}}\), \(\mathrm{\mathrm{Fe}}\) has +3 oxidation state as \(\mathrm{\mathrm{Cl}^{-}}\)has 1 unit -ve charge
CHXI08:REDOX REACTIONS
315179
The oxidation states of sulphur in the anions \(\mathrm{SO}_{3}^{2-}, \mathrm{S}_{2} \mathrm{O}_{4}^{2-}\) and \(\mathrm{S}_{2} \mathrm{O}_{6}^{2-}\) follow the order.
In \(\mathrm{\mathrm{BaO}_{2}+\mathrm{H}_{2} \mathrm{SO}_{4} \rightarrow \mathrm{BaSO}_{4}+\mathrm{H}_{2} \mathrm{O}_{2}}\) all atoms are present in the same O.S. in reactants and products.
NEET Test Series from KOTA - 10 Papers In MS WORD
WhatsApp Here
CHXI08:REDOX REACTIONS
315177
The oxidation state of the most electronegative element in the products of the reaction between \(\mathrm{\mathrm{BaO}_{2}}\) and \(\mathrm{\mathrm{H}_{2} \mathrm{SO}_{4}}\) are
1 \({\rm{0}}\,\,{\rm{and}}\,\,{\rm{ - 1}}\)
2 \({\rm{ - 1}}\,\,{\rm{and}}\,\,{\rm{ - 2}}\)
3 \({\rm{ - 2}}\,\,{\rm{and}}\,\,{\rm{0}}\)
4 \({\rm{ - 2}}\,\,{\rm{and}}\,\,{\rm{ + 1}}\)
Explanation:
\(\mathrm{\mathrm{BaO}_{2}+\mathrm{H}_{2} \mathrm{SO}_{4} \rightarrow \mathrm{BaSO}_{4}+\mathrm{H}_{2} \mathrm{O}_{2}}\) The most electronegative element \(\mathrm{\mathrm{O}}\) is present in \(\mathrm{\mathrm{BaSO}_{4}}\) and \(\mathrm{\mathrm{H}_{2} \mathrm{O}_{2}}\), where its O.N. are \({\rm{ - 2}}\,\,{\rm{and}}\,\,{\rm{ - 1}}\) respectively.
CHXI08:REDOX REACTIONS
315178
In which of the following compounds, iron has an oxidation number of +3 ?
\(\mathrm{\therefore \mathrm{In} \mathrm{Fe}\left(\mathrm{NO}_{3}\right)_{2}}\), Fe has oxidation number +2 (as \(\mathrm{\mathrm{NO}_{3}^{-}}\)has 1 unit -ve charge) \(\mathrm{\therefore}\) In \(\mathrm{\mathrm{FeC}_{2} \mathrm{O}_{4}}\), \(\mathrm{\mathrm{Fe}}\) has oxidation number +2 as \(\mathrm{\mathrm{C}_{2} \mathrm{O}_{4}^{-2}}\) has 2 units -ve charge. In \(\mathrm{\mathrm{FeCl}_{3}}\), \(\mathrm{\mathrm{Fe}}\) has +3 oxidation state as \(\mathrm{\mathrm{Cl}^{-}}\)has 1 unit -ve charge
CHXI08:REDOX REACTIONS
315179
The oxidation states of sulphur in the anions \(\mathrm{SO}_{3}^{2-}, \mathrm{S}_{2} \mathrm{O}_{4}^{2-}\) and \(\mathrm{S}_{2} \mathrm{O}_{6}^{2-}\) follow the order.
In \(\mathrm{\mathrm{BaO}_{2}+\mathrm{H}_{2} \mathrm{SO}_{4} \rightarrow \mathrm{BaSO}_{4}+\mathrm{H}_{2} \mathrm{O}_{2}}\) all atoms are present in the same O.S. in reactants and products.