Calculation of x-factor or Valency Factor and Equivalent Weight
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CHXI08:REDOX REACTIONS

315132 In the reaction:
\(\mathrm{Na}_{2} \mathrm{~S}_{2} \mathrm{O}_{3}+4 \mathrm{Cl}_{2}+5 \mathrm{H}_{2} \mathrm{O} \rightarrow\) \(\mathrm{Na}_{2} \mathrm{SO}_{4}+\mathrm{H}_{2} \mathrm{SO}_{4}+8 \mathrm{HCl}\) the equivalent weight of \(\mathrm{Na}_{2} \mathrm{~S}_{2} \mathrm{O}_{3}\) will be: \((\mathrm{M}=\) molecular weight of \(\mathrm{Na}_{2} \mathrm{~S}_{2} \mathrm{O}_{3}\) )

1 \(\dfrac{M}{4}\)
2 \(\dfrac{M}{8}\)
3 \(\dfrac{M}{1}\)
4 \(\dfrac{M}{2}\)
CHXI08:REDOX REACTIONS

315133 In the reaction:
\(\mathrm{2 \mathrm{CuSO}_{4}+4 \mathrm{KI} \rightarrow \mathrm{Cu}_{2} \mathrm{I}_{2}+\mathrm{I}_{2}+2 \mathrm{~K}_{2} \mathrm{SO}_{4}}\)
the equivalent weight of \(\mathrm{\mathrm{Cu}}\) will be (atomic weight of \(\mathrm{\mathrm{Cu}=63.5}\) )

1 31.75
2 63.5
3 127
4 15.88
CHXI08:REDOX REACTIONS

315134 Calculate the equivalent weight of \(\mathrm{\mathrm{KHC}_{2} \mathrm{O}_{4}}\) when it is oxidised by \(\mathrm{\mathrm{MnO}_{4}^{-}}\)in basic medium

1 64
2 128
3 32
4 15
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CHXI08:REDOX REACTIONS

315132 In the reaction:
\(\mathrm{Na}_{2} \mathrm{~S}_{2} \mathrm{O}_{3}+4 \mathrm{Cl}_{2}+5 \mathrm{H}_{2} \mathrm{O} \rightarrow\) \(\mathrm{Na}_{2} \mathrm{SO}_{4}+\mathrm{H}_{2} \mathrm{SO}_{4}+8 \mathrm{HCl}\) the equivalent weight of \(\mathrm{Na}_{2} \mathrm{~S}_{2} \mathrm{O}_{3}\) will be: \((\mathrm{M}=\) molecular weight of \(\mathrm{Na}_{2} \mathrm{~S}_{2} \mathrm{O}_{3}\) )

1 \(\dfrac{M}{4}\)
2 \(\dfrac{M}{8}\)
3 \(\dfrac{M}{1}\)
4 \(\dfrac{M}{2}\)
CHXI08:REDOX REACTIONS

315133 In the reaction:
\(\mathrm{2 \mathrm{CuSO}_{4}+4 \mathrm{KI} \rightarrow \mathrm{Cu}_{2} \mathrm{I}_{2}+\mathrm{I}_{2}+2 \mathrm{~K}_{2} \mathrm{SO}_{4}}\)
the equivalent weight of \(\mathrm{\mathrm{Cu}}\) will be (atomic weight of \(\mathrm{\mathrm{Cu}=63.5}\) )

1 31.75
2 63.5
3 127
4 15.88
CHXI08:REDOX REACTIONS

315134 Calculate the equivalent weight of \(\mathrm{\mathrm{KHC}_{2} \mathrm{O}_{4}}\) when it is oxidised by \(\mathrm{\mathrm{MnO}_{4}^{-}}\)in basic medium

1 64
2 128
3 32
4 15
For More Updates join with Us
CHXI08:REDOX REACTIONS

315132 In the reaction:
\(\mathrm{Na}_{2} \mathrm{~S}_{2} \mathrm{O}_{3}+4 \mathrm{Cl}_{2}+5 \mathrm{H}_{2} \mathrm{O} \rightarrow\) \(\mathrm{Na}_{2} \mathrm{SO}_{4}+\mathrm{H}_{2} \mathrm{SO}_{4}+8 \mathrm{HCl}\) the equivalent weight of \(\mathrm{Na}_{2} \mathrm{~S}_{2} \mathrm{O}_{3}\) will be: \((\mathrm{M}=\) molecular weight of \(\mathrm{Na}_{2} \mathrm{~S}_{2} \mathrm{O}_{3}\) )

1 \(\dfrac{M}{4}\)
2 \(\dfrac{M}{8}\)
3 \(\dfrac{M}{1}\)
4 \(\dfrac{M}{2}\)
CHXI08:REDOX REACTIONS

315133 In the reaction:
\(\mathrm{2 \mathrm{CuSO}_{4}+4 \mathrm{KI} \rightarrow \mathrm{Cu}_{2} \mathrm{I}_{2}+\mathrm{I}_{2}+2 \mathrm{~K}_{2} \mathrm{SO}_{4}}\)
the equivalent weight of \(\mathrm{\mathrm{Cu}}\) will be (atomic weight of \(\mathrm{\mathrm{Cu}=63.5}\) )

1 31.75
2 63.5
3 127
4 15.88
CHXI08:REDOX REACTIONS

315134 Calculate the equivalent weight of \(\mathrm{\mathrm{KHC}_{2} \mathrm{O}_{4}}\) when it is oxidised by \(\mathrm{\mathrm{MnO}_{4}^{-}}\)in basic medium

1 64
2 128
3 32
4 15
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