315109
Which of the following ion is spectator ion in the reaction given below? \(\rm{\mathrm{Zn}+\mathrm{CuSO}_{4} \rightarrow \mathrm{ZnSO}_{4}+\mathrm{Cu}}\)
1 \(\mathrm{\mathrm{Zn}^{2+}}\)
2 \(\mathrm{\mathrm{H}^{+}}\)
3 \(\mathrm{\mathrm{SO}_{4}^{2-}}\)
4 \(\mathrm{\mathrm{Zn}}\)
Explanation:
The species present in solution but does not take part in the reaction is called spectator ion. It may be omitted while writing the net ionic reaction. Given, \({\rm{Zn + CuS}}{{\rm{O}}_{\rm{4}}} \to {\rm{Zn}}\,{\rm{S}}{{\rm{O}}_{\rm{4}}}{\rm{ + Cu}}\) Ionic equation is \({\rm{Zn + C}}{{\rm{u}}^{{\rm{ + 2}}}}{\rm{ + SO}}_{\rm{4}}^{{\rm{ - 2}}} \to {\rm{Zn}}{\,^{{\rm{ + 2}}}}{\rm{ + SO}}_{\rm{4}}^{{\rm{ - 2}}}{\rm{ + Cu}}\) \({\rm{SO}}_{\rm{4}}^{{\rm{ - 2}}}\) is a spectator ion as it is present both sides of reaction.
