CHXI07:EQUILIBRIUM
315048
\(\mathrm{pH}\) of soft drink is 3.6. Calculate the concentration of hydrogen ions in it.
1 \(2.51 \times 10^{-4} \mathrm{M}\)
2 \(2.3 \times 10^{-3} \mathrm{M}\)
3 \(2.0 \times 10^{-3} \mathrm{M}\)
4 \(2.81 \times 10^{-4} \mathrm{M}\)
Explanation:
\(\mathrm{pH}=3.6,\left[\mathrm{H}^{+}\right]=\)?
\(\begin{aligned}& \mathrm{pH}=-\log _{10}\left[\mathrm{H}^{+}\right] \\& \therefore \log _{10}\left[\mathrm{H}^{+}\right]=-\mathrm{pH} \\& =-3.6 \\& =-3-0.6-1+1 \\& =-4+0.4=\overline{4} .4\end{aligned}\)
\(\therefore\left[\mathrm{H}^{+}\right]=\operatorname{Antilog}(\overline{4} .4)=2.512 \times 10^{-4} \mathrm{M}\)