pH concept
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CHXI07:EQUILIBRIUM

315021 Assuming complete dissociation, calculate the \(\mathrm{pH}\) of \({\text{0}}{\text{.003}}\) \({\text{M}}\) \({\text{HCl}}\) solution

1 1.52
2 2.52
3 3.52
4 11.48
CHXI07:EQUILIBRIUM

315022 In which case change in \(\mathrm{pH}\) is maximum ?

1 \({\text{1}}\) \({\text{ml}}\) of \(\mathrm{pH}=2\) solution is diluted to \(100 \mathrm{~mL}\)
2 \(0.01 \mathrm{~mol}\) of \(\mathrm{NaOH}\) is added to \(100 \mathrm{~mL}\) of \({\text{0}}{\text{.01 M NaOH solution}}\)
3 \(100 \mathrm{~mL}\) of \(\mathrm{H}_{2} \mathrm{O}\) is added to \(900 \mathrm{~mL}\) \({\text{of}}\,\,{\text{1}}{{\text{0}}^{{\text{ -6}}}} {\text{ M}} \,\,{\text{HCl}}\)
4 \(100 \mathrm{~mL}\) of \(\mathrm{pH}=2\) solution is mixed with \(100 \mathrm{~mL}\) of \(\mathrm{pH}=12\).
CHXI07:EQUILIBRIUM

315023 \(\mathrm{pH}\) of a sample of \(\mathrm{KOH}\) and another sample of \(\mathrm{NaOH}\) are 10 and 12 respectively. Their normalities are related as \(\mathrm{N}_{\mathrm{NaOH}}=\mathrm{xN}_{\mathrm{KOH}}\). What is the value of \({\text{x}}\) ?

1 \(5 / 6\)
2 \(6 / 5\)
3 \(10^{2}\)
4 \(10^{-2}\)
CHXI07:EQUILIBRIUM

315025 \({\text{10 mL}}\) of \({\text{0}}{\text{.1 N HCl}}\) is added to \({\text{ 990 mL}}\) solution of \(\mathrm{NaCl}\), the \(\mathrm{pH}\) of resulting solution is

1 Zero
2 2
3 3
4 7
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CHXI07:EQUILIBRIUM

315021 Assuming complete dissociation, calculate the \(\mathrm{pH}\) of \({\text{0}}{\text{.003}}\) \({\text{M}}\) \({\text{HCl}}\) solution

1 1.52
2 2.52
3 3.52
4 11.48
CHXI07:EQUILIBRIUM

315022 In which case change in \(\mathrm{pH}\) is maximum ?

1 \({\text{1}}\) \({\text{ml}}\) of \(\mathrm{pH}=2\) solution is diluted to \(100 \mathrm{~mL}\)
2 \(0.01 \mathrm{~mol}\) of \(\mathrm{NaOH}\) is added to \(100 \mathrm{~mL}\) of \({\text{0}}{\text{.01 M NaOH solution}}\)
3 \(100 \mathrm{~mL}\) of \(\mathrm{H}_{2} \mathrm{O}\) is added to \(900 \mathrm{~mL}\) \({\text{of}}\,\,{\text{1}}{{\text{0}}^{{\text{ -6}}}} {\text{ M}} \,\,{\text{HCl}}\)
4 \(100 \mathrm{~mL}\) of \(\mathrm{pH}=2\) solution is mixed with \(100 \mathrm{~mL}\) of \(\mathrm{pH}=12\).
CHXI07:EQUILIBRIUM

315023 \(\mathrm{pH}\) of a sample of \(\mathrm{KOH}\) and another sample of \(\mathrm{NaOH}\) are 10 and 12 respectively. Their normalities are related as \(\mathrm{N}_{\mathrm{NaOH}}=\mathrm{xN}_{\mathrm{KOH}}\). What is the value of \({\text{x}}\) ?

1 \(5 / 6\)
2 \(6 / 5\)
3 \(10^{2}\)
4 \(10^{-2}\)
CHXI07:EQUILIBRIUM

315025 \({\text{10 mL}}\) of \({\text{0}}{\text{.1 N HCl}}\) is added to \({\text{ 990 mL}}\) solution of \(\mathrm{NaCl}\), the \(\mathrm{pH}\) of resulting solution is

1 Zero
2 2
3 3
4 7
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CHXI07:EQUILIBRIUM

315021 Assuming complete dissociation, calculate the \(\mathrm{pH}\) of \({\text{0}}{\text{.003}}\) \({\text{M}}\) \({\text{HCl}}\) solution

1 1.52
2 2.52
3 3.52
4 11.48
CHXI07:EQUILIBRIUM

315022 In which case change in \(\mathrm{pH}\) is maximum ?

1 \({\text{1}}\) \({\text{ml}}\) of \(\mathrm{pH}=2\) solution is diluted to \(100 \mathrm{~mL}\)
2 \(0.01 \mathrm{~mol}\) of \(\mathrm{NaOH}\) is added to \(100 \mathrm{~mL}\) of \({\text{0}}{\text{.01 M NaOH solution}}\)
3 \(100 \mathrm{~mL}\) of \(\mathrm{H}_{2} \mathrm{O}\) is added to \(900 \mathrm{~mL}\) \({\text{of}}\,\,{\text{1}}{{\text{0}}^{{\text{ -6}}}} {\text{ M}} \,\,{\text{HCl}}\)
4 \(100 \mathrm{~mL}\) of \(\mathrm{pH}=2\) solution is mixed with \(100 \mathrm{~mL}\) of \(\mathrm{pH}=12\).
CHXI07:EQUILIBRIUM

315023 \(\mathrm{pH}\) of a sample of \(\mathrm{KOH}\) and another sample of \(\mathrm{NaOH}\) are 10 and 12 respectively. Their normalities are related as \(\mathrm{N}_{\mathrm{NaOH}}=\mathrm{xN}_{\mathrm{KOH}}\). What is the value of \({\text{x}}\) ?

1 \(5 / 6\)
2 \(6 / 5\)
3 \(10^{2}\)
4 \(10^{-2}\)
CHXI07:EQUILIBRIUM

315025 \({\text{10 mL}}\) of \({\text{0}}{\text{.1 N HCl}}\) is added to \({\text{ 990 mL}}\) solution of \(\mathrm{NaCl}\), the \(\mathrm{pH}\) of resulting solution is

1 Zero
2 2
3 3
4 7
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CHXI07:EQUILIBRIUM

315021 Assuming complete dissociation, calculate the \(\mathrm{pH}\) of \({\text{0}}{\text{.003}}\) \({\text{M}}\) \({\text{HCl}}\) solution

1 1.52
2 2.52
3 3.52
4 11.48
CHXI07:EQUILIBRIUM

315022 In which case change in \(\mathrm{pH}\) is maximum ?

1 \({\text{1}}\) \({\text{ml}}\) of \(\mathrm{pH}=2\) solution is diluted to \(100 \mathrm{~mL}\)
2 \(0.01 \mathrm{~mol}\) of \(\mathrm{NaOH}\) is added to \(100 \mathrm{~mL}\) of \({\text{0}}{\text{.01 M NaOH solution}}\)
3 \(100 \mathrm{~mL}\) of \(\mathrm{H}_{2} \mathrm{O}\) is added to \(900 \mathrm{~mL}\) \({\text{of}}\,\,{\text{1}}{{\text{0}}^{{\text{ -6}}}} {\text{ M}} \,\,{\text{HCl}}\)
4 \(100 \mathrm{~mL}\) of \(\mathrm{pH}=2\) solution is mixed with \(100 \mathrm{~mL}\) of \(\mathrm{pH}=12\).
CHXI07:EQUILIBRIUM

315023 \(\mathrm{pH}\) of a sample of \(\mathrm{KOH}\) and another sample of \(\mathrm{NaOH}\) are 10 and 12 respectively. Their normalities are related as \(\mathrm{N}_{\mathrm{NaOH}}=\mathrm{xN}_{\mathrm{KOH}}\). What is the value of \({\text{x}}\) ?

1 \(5 / 6\)
2 \(6 / 5\)
3 \(10^{2}\)
4 \(10^{-2}\)
CHXI07:EQUILIBRIUM

315025 \({\text{10 mL}}\) of \({\text{0}}{\text{.1 N HCl}}\) is added to \({\text{ 990 mL}}\) solution of \(\mathrm{NaCl}\), the \(\mathrm{pH}\) of resulting solution is

1 Zero
2 2
3 3
4 7
For More Updates join with Us