Solubility Equilibria of Sparingly Soluble Salts
CHXI07:EQUILIBRIUM

314918 A sparingly soluble salt gets precipitated only when the product of concentration of its ions in the solution \(\left(\mathrm{Q}_{\mathrm{sp}}\right)\) becomes greater than its solubility product. If the solubility of \(\mathrm{BaSO}_{4}\) in water is \({\text{8}} \times {\text{1}}{{\text{0}}^{{\text{ - 4}}}}{\text{mol d}}{{\text{m}}^{{\text{ - 3}}}}\) Its solubility in 0.01 \({\text{mol d}}{{\text{m}}^{ - 3}}\) of \({{\text{H}}_2}{\text{S}}{{\text{O}}_4}\) in \({\text{mol d}}{{\text{m}}^{{\text{ - 3}}}}{\text{?}}\)

1 \(6.4 \times 10^{-5}\)
2 \(8 \times 10^{-4}\)
3 \(7 \times 10^{-4}\)
4 \(8 \times 10^{-4}\)
CHXI07:EQUILIBRIUM

314919 Specify if addition of the second substance in each of the following increases (i) or decreases (D),
the solubility of the first substance.
(I) \(\mathrm{Al}(\mathrm{OH})_{3}, \mathrm{NaOH}\)
(II) \(\mathrm{PbCl}_{2}, \mathrm{~Pb}\left(\mathrm{NO}_{3}\right)_{2}\)
(III) \(\mathrm{CuSO}_{4}, \mathrm{NH}_{3}\)

1 I -D, II-i, III-i
2 I-i, II-D, III-i
3 I-i, II-D, III-i
4 I-D, II-D, III-i
CHXI07:EQUILIBRIUM

314920 In presence of \({\text{HCl, }}{{\text{H}}_{\text{2}}}{\text{S}}\) results the precipitation of group-2 elements but not group4 elements during qualitative analysis. It is due to

1 higher concentration of \(\mathrm{H}^{+}\)
2 lower concentration of \(\mathrm{H}^{+}\)
3 higher concentration of \(\mathrm{S}^{2-}\)
4 lower concentration of \(\mathrm{S}^{2-}\)
CHXI07:EQUILIBRIUM

314921 Solubility product of a salt \({\text{AB}}\) is \({\text{1}} \times {\text{1}}{{\text{0}}^{{\text{ - 8}}}}{\text{ }}{{\text{M}}^{\text{2}}}\) in a solution in which the concentration of \(\mathrm{A}^{+}\)ions is \({10^{ - 3}}{\text{ M}}\). The salt will precipitate when the concentration of \(\mathrm{B}^{-}\) ions is kept

1 \({\text{Between 1}}{{\text{0}}^{{\text{ - 8}}}}{\text{ M to 1}}{{\text{0}}^{{\text{ - 7}}}}{\text{ M}}\)
2 \({\text{Between 1}}{{\text{0}}^{{\text{ - 7}}}}{\text{ M to 1}}{{\text{0}}^{{\text{ - 8}}}}{\text{ M}}\)
3 \({\text{ > 1}}{{\text{0}}^{{\text{ - 5}}}}{\text{ M}}\)
4 \({\text{ < 1}}{{\text{0}}^{{\text{ - 8}}}}{\text{ M}}\)
CHXI07:EQUILIBRIUM

314922 The least soluble compound (salt) of the following is

1 \(\mathrm{CsCl}\left(\mathrm{K}_{\mathrm{sp}}=10^{-12}\right)\)
2 \(\mathrm{HgS}\left(\mathrm{K}_{\mathrm{sp}}=1 \times 10^{-52}\right)\)
3 \(\mathrm{MnS}\left(\mathrm{K}_{\mathrm{sp}}=7 \times 10^{-16}\right)\)
4 \(\mathrm{ZnS}\left(\mathrm{K}_{\mathrm{sp}}=1.2 \times 10^{-23}\right)\)
CHXI07:EQUILIBRIUM

314918 A sparingly soluble salt gets precipitated only when the product of concentration of its ions in the solution \(\left(\mathrm{Q}_{\mathrm{sp}}\right)\) becomes greater than its solubility product. If the solubility of \(\mathrm{BaSO}_{4}\) in water is \({\text{8}} \times {\text{1}}{{\text{0}}^{{\text{ - 4}}}}{\text{mol d}}{{\text{m}}^{{\text{ - 3}}}}\) Its solubility in 0.01 \({\text{mol d}}{{\text{m}}^{ - 3}}\) of \({{\text{H}}_2}{\text{S}}{{\text{O}}_4}\) in \({\text{mol d}}{{\text{m}}^{{\text{ - 3}}}}{\text{?}}\)

1 \(6.4 \times 10^{-5}\)
2 \(8 \times 10^{-4}\)
3 \(7 \times 10^{-4}\)
4 \(8 \times 10^{-4}\)
CHXI07:EQUILIBRIUM

314919 Specify if addition of the second substance in each of the following increases (i) or decreases (D),
the solubility of the first substance.
(I) \(\mathrm{Al}(\mathrm{OH})_{3}, \mathrm{NaOH}\)
(II) \(\mathrm{PbCl}_{2}, \mathrm{~Pb}\left(\mathrm{NO}_{3}\right)_{2}\)
(III) \(\mathrm{CuSO}_{4}, \mathrm{NH}_{3}\)

1 I -D, II-i, III-i
2 I-i, II-D, III-i
3 I-i, II-D, III-i
4 I-D, II-D, III-i
CHXI07:EQUILIBRIUM

314920 In presence of \({\text{HCl, }}{{\text{H}}_{\text{2}}}{\text{S}}\) results the precipitation of group-2 elements but not group4 elements during qualitative analysis. It is due to

1 higher concentration of \(\mathrm{H}^{+}\)
2 lower concentration of \(\mathrm{H}^{+}\)
3 higher concentration of \(\mathrm{S}^{2-}\)
4 lower concentration of \(\mathrm{S}^{2-}\)
CHXI07:EQUILIBRIUM

314921 Solubility product of a salt \({\text{AB}}\) is \({\text{1}} \times {\text{1}}{{\text{0}}^{{\text{ - 8}}}}{\text{ }}{{\text{M}}^{\text{2}}}\) in a solution in which the concentration of \(\mathrm{A}^{+}\)ions is \({10^{ - 3}}{\text{ M}}\). The salt will precipitate when the concentration of \(\mathrm{B}^{-}\) ions is kept

1 \({\text{Between 1}}{{\text{0}}^{{\text{ - 8}}}}{\text{ M to 1}}{{\text{0}}^{{\text{ - 7}}}}{\text{ M}}\)
2 \({\text{Between 1}}{{\text{0}}^{{\text{ - 7}}}}{\text{ M to 1}}{{\text{0}}^{{\text{ - 8}}}}{\text{ M}}\)
3 \({\text{ > 1}}{{\text{0}}^{{\text{ - 5}}}}{\text{ M}}\)
4 \({\text{ < 1}}{{\text{0}}^{{\text{ - 8}}}}{\text{ M}}\)
CHXI07:EQUILIBRIUM

314922 The least soluble compound (salt) of the following is

1 \(\mathrm{CsCl}\left(\mathrm{K}_{\mathrm{sp}}=10^{-12}\right)\)
2 \(\mathrm{HgS}\left(\mathrm{K}_{\mathrm{sp}}=1 \times 10^{-52}\right)\)
3 \(\mathrm{MnS}\left(\mathrm{K}_{\mathrm{sp}}=7 \times 10^{-16}\right)\)
4 \(\mathrm{ZnS}\left(\mathrm{K}_{\mathrm{sp}}=1.2 \times 10^{-23}\right)\)
CHXI07:EQUILIBRIUM

314918 A sparingly soluble salt gets precipitated only when the product of concentration of its ions in the solution \(\left(\mathrm{Q}_{\mathrm{sp}}\right)\) becomes greater than its solubility product. If the solubility of \(\mathrm{BaSO}_{4}\) in water is \({\text{8}} \times {\text{1}}{{\text{0}}^{{\text{ - 4}}}}{\text{mol d}}{{\text{m}}^{{\text{ - 3}}}}\) Its solubility in 0.01 \({\text{mol d}}{{\text{m}}^{ - 3}}\) of \({{\text{H}}_2}{\text{S}}{{\text{O}}_4}\) in \({\text{mol d}}{{\text{m}}^{{\text{ - 3}}}}{\text{?}}\)

1 \(6.4 \times 10^{-5}\)
2 \(8 \times 10^{-4}\)
3 \(7 \times 10^{-4}\)
4 \(8 \times 10^{-4}\)
CHXI07:EQUILIBRIUM

314919 Specify if addition of the second substance in each of the following increases (i) or decreases (D),
the solubility of the first substance.
(I) \(\mathrm{Al}(\mathrm{OH})_{3}, \mathrm{NaOH}\)
(II) \(\mathrm{PbCl}_{2}, \mathrm{~Pb}\left(\mathrm{NO}_{3}\right)_{2}\)
(III) \(\mathrm{CuSO}_{4}, \mathrm{NH}_{3}\)

1 I -D, II-i, III-i
2 I-i, II-D, III-i
3 I-i, II-D, III-i
4 I-D, II-D, III-i
CHXI07:EQUILIBRIUM

314920 In presence of \({\text{HCl, }}{{\text{H}}_{\text{2}}}{\text{S}}\) results the precipitation of group-2 elements but not group4 elements during qualitative analysis. It is due to

1 higher concentration of \(\mathrm{H}^{+}\)
2 lower concentration of \(\mathrm{H}^{+}\)
3 higher concentration of \(\mathrm{S}^{2-}\)
4 lower concentration of \(\mathrm{S}^{2-}\)
CHXI07:EQUILIBRIUM

314921 Solubility product of a salt \({\text{AB}}\) is \({\text{1}} \times {\text{1}}{{\text{0}}^{{\text{ - 8}}}}{\text{ }}{{\text{M}}^{\text{2}}}\) in a solution in which the concentration of \(\mathrm{A}^{+}\)ions is \({10^{ - 3}}{\text{ M}}\). The salt will precipitate when the concentration of \(\mathrm{B}^{-}\) ions is kept

1 \({\text{Between 1}}{{\text{0}}^{{\text{ - 8}}}}{\text{ M to 1}}{{\text{0}}^{{\text{ - 7}}}}{\text{ M}}\)
2 \({\text{Between 1}}{{\text{0}}^{{\text{ - 7}}}}{\text{ M to 1}}{{\text{0}}^{{\text{ - 8}}}}{\text{ M}}\)
3 \({\text{ > 1}}{{\text{0}}^{{\text{ - 5}}}}{\text{ M}}\)
4 \({\text{ < 1}}{{\text{0}}^{{\text{ - 8}}}}{\text{ M}}\)
CHXI07:EQUILIBRIUM

314922 The least soluble compound (salt) of the following is

1 \(\mathrm{CsCl}\left(\mathrm{K}_{\mathrm{sp}}=10^{-12}\right)\)
2 \(\mathrm{HgS}\left(\mathrm{K}_{\mathrm{sp}}=1 \times 10^{-52}\right)\)
3 \(\mathrm{MnS}\left(\mathrm{K}_{\mathrm{sp}}=7 \times 10^{-16}\right)\)
4 \(\mathrm{ZnS}\left(\mathrm{K}_{\mathrm{sp}}=1.2 \times 10^{-23}\right)\)
CHXI07:EQUILIBRIUM

314918 A sparingly soluble salt gets precipitated only when the product of concentration of its ions in the solution \(\left(\mathrm{Q}_{\mathrm{sp}}\right)\) becomes greater than its solubility product. If the solubility of \(\mathrm{BaSO}_{4}\) in water is \({\text{8}} \times {\text{1}}{{\text{0}}^{{\text{ - 4}}}}{\text{mol d}}{{\text{m}}^{{\text{ - 3}}}}\) Its solubility in 0.01 \({\text{mol d}}{{\text{m}}^{ - 3}}\) of \({{\text{H}}_2}{\text{S}}{{\text{O}}_4}\) in \({\text{mol d}}{{\text{m}}^{{\text{ - 3}}}}{\text{?}}\)

1 \(6.4 \times 10^{-5}\)
2 \(8 \times 10^{-4}\)
3 \(7 \times 10^{-4}\)
4 \(8 \times 10^{-4}\)
CHXI07:EQUILIBRIUM

314919 Specify if addition of the second substance in each of the following increases (i) or decreases (D),
the solubility of the first substance.
(I) \(\mathrm{Al}(\mathrm{OH})_{3}, \mathrm{NaOH}\)
(II) \(\mathrm{PbCl}_{2}, \mathrm{~Pb}\left(\mathrm{NO}_{3}\right)_{2}\)
(III) \(\mathrm{CuSO}_{4}, \mathrm{NH}_{3}\)

1 I -D, II-i, III-i
2 I-i, II-D, III-i
3 I-i, II-D, III-i
4 I-D, II-D, III-i
CHXI07:EQUILIBRIUM

314920 In presence of \({\text{HCl, }}{{\text{H}}_{\text{2}}}{\text{S}}\) results the precipitation of group-2 elements but not group4 elements during qualitative analysis. It is due to

1 higher concentration of \(\mathrm{H}^{+}\)
2 lower concentration of \(\mathrm{H}^{+}\)
3 higher concentration of \(\mathrm{S}^{2-}\)
4 lower concentration of \(\mathrm{S}^{2-}\)
CHXI07:EQUILIBRIUM

314921 Solubility product of a salt \({\text{AB}}\) is \({\text{1}} \times {\text{1}}{{\text{0}}^{{\text{ - 8}}}}{\text{ }}{{\text{M}}^{\text{2}}}\) in a solution in which the concentration of \(\mathrm{A}^{+}\)ions is \({10^{ - 3}}{\text{ M}}\). The salt will precipitate when the concentration of \(\mathrm{B}^{-}\) ions is kept

1 \({\text{Between 1}}{{\text{0}}^{{\text{ - 8}}}}{\text{ M to 1}}{{\text{0}}^{{\text{ - 7}}}}{\text{ M}}\)
2 \({\text{Between 1}}{{\text{0}}^{{\text{ - 7}}}}{\text{ M to 1}}{{\text{0}}^{{\text{ - 8}}}}{\text{ M}}\)
3 \({\text{ > 1}}{{\text{0}}^{{\text{ - 5}}}}{\text{ M}}\)
4 \({\text{ < 1}}{{\text{0}}^{{\text{ - 8}}}}{\text{ M}}\)
CHXI07:EQUILIBRIUM

314922 The least soluble compound (salt) of the following is

1 \(\mathrm{CsCl}\left(\mathrm{K}_{\mathrm{sp}}=10^{-12}\right)\)
2 \(\mathrm{HgS}\left(\mathrm{K}_{\mathrm{sp}}=1 \times 10^{-52}\right)\)
3 \(\mathrm{MnS}\left(\mathrm{K}_{\mathrm{sp}}=7 \times 10^{-16}\right)\)
4 \(\mathrm{ZnS}\left(\mathrm{K}_{\mathrm{sp}}=1.2 \times 10^{-23}\right)\)
CHXI07:EQUILIBRIUM

314918 A sparingly soluble salt gets precipitated only when the product of concentration of its ions in the solution \(\left(\mathrm{Q}_{\mathrm{sp}}\right)\) becomes greater than its solubility product. If the solubility of \(\mathrm{BaSO}_{4}\) in water is \({\text{8}} \times {\text{1}}{{\text{0}}^{{\text{ - 4}}}}{\text{mol d}}{{\text{m}}^{{\text{ - 3}}}}\) Its solubility in 0.01 \({\text{mol d}}{{\text{m}}^{ - 3}}\) of \({{\text{H}}_2}{\text{S}}{{\text{O}}_4}\) in \({\text{mol d}}{{\text{m}}^{{\text{ - 3}}}}{\text{?}}\)

1 \(6.4 \times 10^{-5}\)
2 \(8 \times 10^{-4}\)
3 \(7 \times 10^{-4}\)
4 \(8 \times 10^{-4}\)
CHXI07:EQUILIBRIUM

314919 Specify if addition of the second substance in each of the following increases (i) or decreases (D),
the solubility of the first substance.
(I) \(\mathrm{Al}(\mathrm{OH})_{3}, \mathrm{NaOH}\)
(II) \(\mathrm{PbCl}_{2}, \mathrm{~Pb}\left(\mathrm{NO}_{3}\right)_{2}\)
(III) \(\mathrm{CuSO}_{4}, \mathrm{NH}_{3}\)

1 I -D, II-i, III-i
2 I-i, II-D, III-i
3 I-i, II-D, III-i
4 I-D, II-D, III-i
CHXI07:EQUILIBRIUM

314920 In presence of \({\text{HCl, }}{{\text{H}}_{\text{2}}}{\text{S}}\) results the precipitation of group-2 elements but not group4 elements during qualitative analysis. It is due to

1 higher concentration of \(\mathrm{H}^{+}\)
2 lower concentration of \(\mathrm{H}^{+}\)
3 higher concentration of \(\mathrm{S}^{2-}\)
4 lower concentration of \(\mathrm{S}^{2-}\)
CHXI07:EQUILIBRIUM

314921 Solubility product of a salt \({\text{AB}}\) is \({\text{1}} \times {\text{1}}{{\text{0}}^{{\text{ - 8}}}}{\text{ }}{{\text{M}}^{\text{2}}}\) in a solution in which the concentration of \(\mathrm{A}^{+}\)ions is \({10^{ - 3}}{\text{ M}}\). The salt will precipitate when the concentration of \(\mathrm{B}^{-}\) ions is kept

1 \({\text{Between 1}}{{\text{0}}^{{\text{ - 8}}}}{\text{ M to 1}}{{\text{0}}^{{\text{ - 7}}}}{\text{ M}}\)
2 \({\text{Between 1}}{{\text{0}}^{{\text{ - 7}}}}{\text{ M to 1}}{{\text{0}}^{{\text{ - 8}}}}{\text{ M}}\)
3 \({\text{ > 1}}{{\text{0}}^{{\text{ - 5}}}}{\text{ M}}\)
4 \({\text{ < 1}}{{\text{0}}^{{\text{ - 8}}}}{\text{ M}}\)
CHXI07:EQUILIBRIUM

314922 The least soluble compound (salt) of the following is

1 \(\mathrm{CsCl}\left(\mathrm{K}_{\mathrm{sp}}=10^{-12}\right)\)
2 \(\mathrm{HgS}\left(\mathrm{K}_{\mathrm{sp}}=1 \times 10^{-52}\right)\)
3 \(\mathrm{MnS}\left(\mathrm{K}_{\mathrm{sp}}=7 \times 10^{-16}\right)\)
4 \(\mathrm{ZnS}\left(\mathrm{K}_{\mathrm{sp}}=1.2 \times 10^{-23}\right)\)