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CHXI07:EQUILIBRIUM

314743 Which of the following salt solutions is highly acidic?

1 Ammonium acetate

2 Ammonium cyanide

3 Sodium chloride

4 Ammonium nitrate

Explanation:

${NH}_{4} {NO}_{3}$ is a salt of strong acid, ${HNO}_{3}$ and weak base, ${NH}_{4} OH$ . So highly acidic ${CH}_{3} {COONH}_{4}, {NH}_{4} CN$ -almost neutral (WAWB salts)
$NaCl$ (SA-SB salt), neutral

MHTCET - 2021

CHXI07:EQUILIBRIUM

314716 The order of $pH$ of $0.2 M$ solutions of ${NH}_{4} {NO}_{3}$ , ${NaNO}_{3}$ and ${Na}_{2} {CO}_{3}$ is :

1

{NH}_{4} {NO}_{3} < {Na}_{2} {CO}_{3} < {NaNO}_{3}

2

{NH}_{4} {NO}_{3} < {NaNO}_{3} < {Na}_{2} {CO}_{3}

3

{Na}_{2} {CO}_{3} < {NaNO}_{3} < {NH}_{4} {NO}_{3}

4

{NaNO}_{3} < {NH}_{4} {NO}_{3} < {Na}_{2} {CO}_{3}

Explanation:

${NH}_{4} {NO}_{3}$ solution is acidic as it is salt of weak base and strong acid. ${NaNO}_{3}$ solution is neural as it is salt of strong acid and strong base ${Na}_{2} {CO}_{3}$ solution is alkaline as it is salt of strong base and weak acid.

CHXI07:EQUILIBRIUM

314717 The ${pK}_{b}$ of dimethylamine and ${pK}_{a}$ of acetic acid are 3.27 and 4.77 respectively at $TK$ . The correct option for the $pH$ of dimethylammonium acetate solution is :

1 5.50

2 7.75

3 6.25

4 8.50

Explanation:

${pK}_{b} = 3.27$ (dimethylamine)
${pK}_{a} = 4.77$ (acetic acid)
Dimethyl ammonium acetate salt is consists of $WA + WB$ .
$pH = 7 + \frac{1}{2} p K_{a} - \frac{1}{2} p K_{b}$
$= 7 + \frac{1}{2} \times 4.77 - \frac{1}{2} \times 3.27$
$p H = 7 + 2 .385 - 1 .635$
$p H = 7 .75$

NEET - 2021

CHXI07:EQUILIBRIUM

314718 Assertion :
$pH$ of ammonium chloride solution is less than 7.
Reason :
Solution of a salt of weak base and strong acid is acidic.

1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.

2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.

3 Assertion is correct but Reason is incorrect.

4 Assertion is incorrect but Reason is correct.

Explanation:

Ammonium chloride is formed by the reaction of ammonia $({NH}_{3})$ , a weak base, with hydrochloric acid $(HCl)$ , a strong acid. The presence of the strong acid $(HCl)$ in this salt means it can readily furnish more $H^{+}$ ions to the solution. Consequently, this leads to an increase in the concentration of $H^{+}$ . Therefore, the solution is acidic and its $pH$ is less than 7. So option (1) is correct.

CHXI07:EQUILIBRIUM

314743 Which of the following salt solutions is highly acidic?

1 Ammonium acetate

2 Ammonium cyanide

3 Sodium chloride

4 Ammonium nitrate

Explanation:

${NH}_{4} {NO}_{3}$ is a salt of strong acid, ${HNO}_{3}$ and weak base, ${NH}_{4} OH$ . So highly acidic ${CH}_{3} {COONH}_{4}, {NH}_{4} CN$ -almost neutral (WAWB salts)
$NaCl$ (SA-SB salt), neutral

MHTCET - 2021

CHXI07:EQUILIBRIUM

314716 The order of $pH$ of $0.2 M$ solutions of ${NH}_{4} {NO}_{3}$ , ${NaNO}_{3}$ and ${Na}_{2} {CO}_{3}$ is :

1

{NH}_{4} {NO}_{3} < {Na}_{2} {CO}_{3} < {NaNO}_{3}

2

{NH}_{4} {NO}_{3} < {NaNO}_{3} < {Na}_{2} {CO}_{3}

3

{Na}_{2} {CO}_{3} < {NaNO}_{3} < {NH}_{4} {NO}_{3}

4

{NaNO}_{3} < {NH}_{4} {NO}_{3} < {Na}_{2} {CO}_{3}

Explanation:

${NH}_{4} {NO}_{3}$ solution is acidic as it is salt of weak base and strong acid. ${NaNO}_{3}$ solution is neural as it is salt of strong acid and strong base ${Na}_{2} {CO}_{3}$ solution is alkaline as it is salt of strong base and weak acid.

CHXI07:EQUILIBRIUM

314717 The ${pK}_{b}$ of dimethylamine and ${pK}_{a}$ of acetic acid are 3.27 and 4.77 respectively at $TK$ . The correct option for the $pH$ of dimethylammonium acetate solution is :

1 5.50

2 7.75

3 6.25

4 8.50

Explanation:

${pK}_{b} = 3.27$ (dimethylamine)
${pK}_{a} = 4.77$ (acetic acid)
Dimethyl ammonium acetate salt is consists of $WA + WB$ .
$pH = 7 + \frac{1}{2} p K_{a} - \frac{1}{2} p K_{b}$
$= 7 + \frac{1}{2} \times 4.77 - \frac{1}{2} \times 3.27$
$p H = 7 + 2 .385 - 1 .635$
$p H = 7 .75$

NEET - 2021

CHXI07:EQUILIBRIUM

314718 Assertion :
$pH$ of ammonium chloride solution is less than 7.
Reason :
Solution of a salt of weak base and strong acid is acidic.

1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.

2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.

3 Assertion is correct but Reason is incorrect.

4 Assertion is incorrect but Reason is correct.

Explanation:

Ammonium chloride is formed by the reaction of ammonia $({NH}_{3})$ , a weak base, with hydrochloric acid $(HCl)$ , a strong acid. The presence of the strong acid $(HCl)$ in this salt means it can readily furnish more $H^{+}$ ions to the solution. Consequently, this leads to an increase in the concentration of $H^{+}$ . Therefore, the solution is acidic and its $pH$ is less than 7. So option (1) is correct.

CHXI07:EQUILIBRIUM

314743 Which of the following salt solutions is highly acidic?

1 Ammonium acetate

2 Ammonium cyanide

3 Sodium chloride

4 Ammonium nitrate

Explanation:

${NH}_{4} {NO}_{3}$ is a salt of strong acid, ${HNO}_{3}$ and weak base, ${NH}_{4} OH$ . So highly acidic ${CH}_{3} {COONH}_{4}, {NH}_{4} CN$ -almost neutral (WAWB salts)
$NaCl$ (SA-SB salt), neutral

MHTCET - 2021

CHXI07:EQUILIBRIUM

314716 The order of $pH$ of $0.2 M$ solutions of ${NH}_{4} {NO}_{3}$ , ${NaNO}_{3}$ and ${Na}_{2} {CO}_{3}$ is :

1

{NH}_{4} {NO}_{3} < {Na}_{2} {CO}_{3} < {NaNO}_{3}

2

{NH}_{4} {NO}_{3} < {NaNO}_{3} < {Na}_{2} {CO}_{3}

3

{Na}_{2} {CO}_{3} < {NaNO}_{3} < {NH}_{4} {NO}_{3}

4

{NaNO}_{3} < {NH}_{4} {NO}_{3} < {Na}_{2} {CO}_{3}

Explanation:

${NH}_{4} {NO}_{3}$ solution is acidic as it is salt of weak base and strong acid. ${NaNO}_{3}$ solution is neural as it is salt of strong acid and strong base ${Na}_{2} {CO}_{3}$ solution is alkaline as it is salt of strong base and weak acid.

CHXI07:EQUILIBRIUM

314717 The ${pK}_{b}$ of dimethylamine and ${pK}_{a}$ of acetic acid are 3.27 and 4.77 respectively at $TK$ . The correct option for the $pH$ of dimethylammonium acetate solution is :

1 5.50

2 7.75

3 6.25

4 8.50

Explanation:

${pK}_{b} = 3.27$ (dimethylamine)
${pK}_{a} = 4.77$ (acetic acid)
Dimethyl ammonium acetate salt is consists of $WA + WB$ .
$pH = 7 + \frac{1}{2} p K_{a} - \frac{1}{2} p K_{b}$
$= 7 + \frac{1}{2} \times 4.77 - \frac{1}{2} \times 3.27$
$p H = 7 + 2 .385 - 1 .635$
$p H = 7 .75$

NEET - 2021

CHXI07:EQUILIBRIUM

314718 Assertion :
$pH$ of ammonium chloride solution is less than 7.
Reason :
Solution of a salt of weak base and strong acid is acidic.

1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.

2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.

3 Assertion is correct but Reason is incorrect.

4 Assertion is incorrect but Reason is correct.

Explanation:

Ammonium chloride is formed by the reaction of ammonia $({NH}_{3})$ , a weak base, with hydrochloric acid $(HCl)$ , a strong acid. The presence of the strong acid $(HCl)$ in this salt means it can readily furnish more $H^{+}$ ions to the solution. Consequently, this leads to an increase in the concentration of $H^{+}$ . Therefore, the solution is acidic and its $pH$ is less than 7. So option (1) is correct.

CHXI07:EQUILIBRIUM

314743 Which of the following salt solutions is highly acidic?

1 Ammonium acetate

2 Ammonium cyanide

3 Sodium chloride

4 Ammonium nitrate

Explanation:

${NH}_{4} {NO}_{3}$ is a salt of strong acid, ${HNO}_{3}$ and weak base, ${NH}_{4} OH$ . So highly acidic ${CH}_{3} {COONH}_{4}, {NH}_{4} CN$ -almost neutral (WAWB salts)
$NaCl$ (SA-SB salt), neutral

MHTCET - 2021

CHXI07:EQUILIBRIUM

314716 The order of $pH$ of $0.2 M$ solutions of ${NH}_{4} {NO}_{3}$ , ${NaNO}_{3}$ and ${Na}_{2} {CO}_{3}$ is :

1

{NH}_{4} {NO}_{3} < {Na}_{2} {CO}_{3} < {NaNO}_{3}

2

{NH}_{4} {NO}_{3} < {NaNO}_{3} < {Na}_{2} {CO}_{3}

3

{Na}_{2} {CO}_{3} < {NaNO}_{3} < {NH}_{4} {NO}_{3}

4

{NaNO}_{3} < {NH}_{4} {NO}_{3} < {Na}_{2} {CO}_{3}

Explanation:

${NH}_{4} {NO}_{3}$ solution is acidic as it is salt of weak base and strong acid. ${NaNO}_{3}$ solution is neural as it is salt of strong acid and strong base ${Na}_{2} {CO}_{3}$ solution is alkaline as it is salt of strong base and weak acid.

CHXI07:EQUILIBRIUM

314717 The ${pK}_{b}$ of dimethylamine and ${pK}_{a}$ of acetic acid are 3.27 and 4.77 respectively at $TK$ . The correct option for the $pH$ of dimethylammonium acetate solution is :

1 5.50

2 7.75

3 6.25

4 8.50

Explanation:

${pK}_{b} = 3.27$ (dimethylamine)
${pK}_{a} = 4.77$ (acetic acid)
Dimethyl ammonium acetate salt is consists of $WA + WB$ .
$pH = 7 + \frac{1}{2} p K_{a} - \frac{1}{2} p K_{b}$
$= 7 + \frac{1}{2} \times 4.77 - \frac{1}{2} \times 3.27$
$p H = 7 + 2 .385 - 1 .635$
$p H = 7 .75$

NEET - 2021

CHXI07:EQUILIBRIUM

314718 Assertion :
$pH$ of ammonium chloride solution is less than 7.
Reason :
Solution of a salt of weak base and strong acid is acidic.

1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.

2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.

3 Assertion is correct but Reason is incorrect.

4 Assertion is incorrect but Reason is correct.

Explanation:

Ammonium chloride is formed by the reaction of ammonia $({NH}_{3})$ , a weak base, with hydrochloric acid $(HCl)$ , a strong acid. The presence of the strong acid $(HCl)$ in this salt means it can readily furnish more $H^{+}$ ions to the solution. Consequently, this leads to an increase in the concentration of $H^{+}$ . Therefore, the solution is acidic and its $pH$ is less than 7. So option (1) is correct.