314791
The dissociation constant of weak monobasic acid is \(2.7 \times 10^{-5}\). If degree of dissociation of acid is \(3 \times 10^{-2}\), what is the concentration of acid?
\(\propto=\sqrt{\mathrm{K}_{\mathrm{a}} \cdot V}, \mathrm{~K}_{\mathrm{a}}=\mathrm{C} \alpha^{2}, \alpha=\sqrt{\dfrac{\mathrm{K}_{\mathrm{a}}}{\mathrm{C}}}\) are correct expressions.
MHTCET - 2021
CHXI07:EQUILIBRIUM
314793
\(\mathrm{K}_{\mathrm{a}}\) for \(\mathrm{HA}\) is \(4.9 \times {10^{ - 8}}\). After making the necessary approximation the \(\%\) dissociation for its decimolar solution is ____.
314795
BOH is a weak base. Molar concentration of BOH that provides a \(\left[ {{\text{O}}{{\text{H}}^ - }} \right]\,\,{\text{of}}\,1.5 \times {10^{ - 3}}{\text{M}}\,{\mkern 1mu} {\text{is}}\) \({{\text{K}}_{\text{b}}} = ({\text{BOH}}) = 1.5 \times {10^{ - 5}}\)
314791
The dissociation constant of weak monobasic acid is \(2.7 \times 10^{-5}\). If degree of dissociation of acid is \(3 \times 10^{-2}\), what is the concentration of acid?
\(\propto=\sqrt{\mathrm{K}_{\mathrm{a}} \cdot V}, \mathrm{~K}_{\mathrm{a}}=\mathrm{C} \alpha^{2}, \alpha=\sqrt{\dfrac{\mathrm{K}_{\mathrm{a}}}{\mathrm{C}}}\) are correct expressions.
MHTCET - 2021
CHXI07:EQUILIBRIUM
314793
\(\mathrm{K}_{\mathrm{a}}\) for \(\mathrm{HA}\) is \(4.9 \times {10^{ - 8}}\). After making the necessary approximation the \(\%\) dissociation for its decimolar solution is ____.
314795
BOH is a weak base. Molar concentration of BOH that provides a \(\left[ {{\text{O}}{{\text{H}}^ - }} \right]\,\,{\text{of}}\,1.5 \times {10^{ - 3}}{\text{M}}\,{\mkern 1mu} {\text{is}}\) \({{\text{K}}_{\text{b}}} = ({\text{BOH}}) = 1.5 \times {10^{ - 5}}\)
314791
The dissociation constant of weak monobasic acid is \(2.7 \times 10^{-5}\). If degree of dissociation of acid is \(3 \times 10^{-2}\), what is the concentration of acid?
\(\propto=\sqrt{\mathrm{K}_{\mathrm{a}} \cdot V}, \mathrm{~K}_{\mathrm{a}}=\mathrm{C} \alpha^{2}, \alpha=\sqrt{\dfrac{\mathrm{K}_{\mathrm{a}}}{\mathrm{C}}}\) are correct expressions.
MHTCET - 2021
CHXI07:EQUILIBRIUM
314793
\(\mathrm{K}_{\mathrm{a}}\) for \(\mathrm{HA}\) is \(4.9 \times {10^{ - 8}}\). After making the necessary approximation the \(\%\) dissociation for its decimolar solution is ____.
314795
BOH is a weak base. Molar concentration of BOH that provides a \(\left[ {{\text{O}}{{\text{H}}^ - }} \right]\,\,{\text{of}}\,1.5 \times {10^{ - 3}}{\text{M}}\,{\mkern 1mu} {\text{is}}\) \({{\text{K}}_{\text{b}}} = ({\text{BOH}}) = 1.5 \times {10^{ - 5}}\)
314791
The dissociation constant of weak monobasic acid is \(2.7 \times 10^{-5}\). If degree of dissociation of acid is \(3 \times 10^{-2}\), what is the concentration of acid?
\(\propto=\sqrt{\mathrm{K}_{\mathrm{a}} \cdot V}, \mathrm{~K}_{\mathrm{a}}=\mathrm{C} \alpha^{2}, \alpha=\sqrt{\dfrac{\mathrm{K}_{\mathrm{a}}}{\mathrm{C}}}\) are correct expressions.
MHTCET - 2021
CHXI07:EQUILIBRIUM
314793
\(\mathrm{K}_{\mathrm{a}}\) for \(\mathrm{HA}\) is \(4.9 \times {10^{ - 8}}\). After making the necessary approximation the \(\%\) dissociation for its decimolar solution is ____.
314795
BOH is a weak base. Molar concentration of BOH that provides a \(\left[ {{\text{O}}{{\text{H}}^ - }} \right]\,\,{\text{of}}\,1.5 \times {10^{ - 3}}{\text{M}}\,{\mkern 1mu} {\text{is}}\) \({{\text{K}}_{\text{b}}} = ({\text{BOH}}) = 1.5 \times {10^{ - 5}}\)
314791
The dissociation constant of weak monobasic acid is \(2.7 \times 10^{-5}\). If degree of dissociation of acid is \(3 \times 10^{-2}\), what is the concentration of acid?
\(\propto=\sqrt{\mathrm{K}_{\mathrm{a}} \cdot V}, \mathrm{~K}_{\mathrm{a}}=\mathrm{C} \alpha^{2}, \alpha=\sqrt{\dfrac{\mathrm{K}_{\mathrm{a}}}{\mathrm{C}}}\) are correct expressions.
MHTCET - 2021
CHXI07:EQUILIBRIUM
314793
\(\mathrm{K}_{\mathrm{a}}\) for \(\mathrm{HA}\) is \(4.9 \times {10^{ - 8}}\). After making the necessary approximation the \(\%\) dissociation for its decimolar solution is ____.
314795
BOH is a weak base. Molar concentration of BOH that provides a \(\left[ {{\text{O}}{{\text{H}}^ - }} \right]\,\,{\text{of}}\,1.5 \times {10^{ - 3}}{\text{M}}\,{\mkern 1mu} {\text{is}}\) \({{\text{K}}_{\text{b}}} = ({\text{BOH}}) = 1.5 \times {10^{ - 5}}\)
