314233
The temperature at which methane molecules have the same average kinetic energy as that of oxygen molecules at \(\mathrm{27^{\circ} \mathrm{C}}\) is
1 \(\mathrm{327^{\circ} \mathrm{C}}\)
2 \(\mathrm{27^{\circ} \mathrm{C}}\)
3 \(\mathrm{927^{\circ} \mathrm{C}}\)
4 \(\mathrm{627^{\circ} \mathrm{C}}\)
Explanation:
K.E. depends on temperature not on the nature of the gas
CHXI06:STATES OF MATTER
314234
If X is the total number of collisions which a gas molecule register with others per unit time under particular conditions, then the collision frequency of the gas containing N molecules per unit volume is
1 \(\frac{{\rm{X}}}{{\rm{N}}}\)
2 NX
3 \(2{\rm{NX}}\)
4 \(\frac{{{\rm{NX}}}}{2}\)
Explanation:
Number of collisions of one molecule/unit time = X Number of collisions of N molecules/unit time =NX \(\therefore\) Collision frequency= NX/2
CHXI06:STATES OF MATTER
314230
As the temperature is raised from \(\mathrm{20^{\circ} \mathrm{C}}\) to \(\mathrm{40^{\circ} \mathrm{C}}\), the average kinetic energy of neon atoms changes by a factor
Average kinetic energy \(\mathrm{\propto T}\) (in \(\mathrm{\mathrm{K}}\) ) \(\mathrm{\dfrac{K \cdot E_{2}}{K \cdot E_{1}}=\dfrac{T_{2}}{T_{1}}=\dfrac{40+273}{20+273}=\dfrac{313}{293}}\).
314233
The temperature at which methane molecules have the same average kinetic energy as that of oxygen molecules at \(\mathrm{27^{\circ} \mathrm{C}}\) is
1 \(\mathrm{327^{\circ} \mathrm{C}}\)
2 \(\mathrm{27^{\circ} \mathrm{C}}\)
3 \(\mathrm{927^{\circ} \mathrm{C}}\)
4 \(\mathrm{627^{\circ} \mathrm{C}}\)
Explanation:
K.E. depends on temperature not on the nature of the gas
CHXI06:STATES OF MATTER
314234
If X is the total number of collisions which a gas molecule register with others per unit time under particular conditions, then the collision frequency of the gas containing N molecules per unit volume is
1 \(\frac{{\rm{X}}}{{\rm{N}}}\)
2 NX
3 \(2{\rm{NX}}\)
4 \(\frac{{{\rm{NX}}}}{2}\)
Explanation:
Number of collisions of one molecule/unit time = X Number of collisions of N molecules/unit time =NX \(\therefore\) Collision frequency= NX/2
CHXI06:STATES OF MATTER
314230
As the temperature is raised from \(\mathrm{20^{\circ} \mathrm{C}}\) to \(\mathrm{40^{\circ} \mathrm{C}}\), the average kinetic energy of neon atoms changes by a factor
Average kinetic energy \(\mathrm{\propto T}\) (in \(\mathrm{\mathrm{K}}\) ) \(\mathrm{\dfrac{K \cdot E_{2}}{K \cdot E_{1}}=\dfrac{T_{2}}{T_{1}}=\dfrac{40+273}{20+273}=\dfrac{313}{293}}\).
314233
The temperature at which methane molecules have the same average kinetic energy as that of oxygen molecules at \(\mathrm{27^{\circ} \mathrm{C}}\) is
1 \(\mathrm{327^{\circ} \mathrm{C}}\)
2 \(\mathrm{27^{\circ} \mathrm{C}}\)
3 \(\mathrm{927^{\circ} \mathrm{C}}\)
4 \(\mathrm{627^{\circ} \mathrm{C}}\)
Explanation:
K.E. depends on temperature not on the nature of the gas
CHXI06:STATES OF MATTER
314234
If X is the total number of collisions which a gas molecule register with others per unit time under particular conditions, then the collision frequency of the gas containing N molecules per unit volume is
1 \(\frac{{\rm{X}}}{{\rm{N}}}\)
2 NX
3 \(2{\rm{NX}}\)
4 \(\frac{{{\rm{NX}}}}{2}\)
Explanation:
Number of collisions of one molecule/unit time = X Number of collisions of N molecules/unit time =NX \(\therefore\) Collision frequency= NX/2
CHXI06:STATES OF MATTER
314230
As the temperature is raised from \(\mathrm{20^{\circ} \mathrm{C}}\) to \(\mathrm{40^{\circ} \mathrm{C}}\), the average kinetic energy of neon atoms changes by a factor
Average kinetic energy \(\mathrm{\propto T}\) (in \(\mathrm{\mathrm{K}}\) ) \(\mathrm{\dfrac{K \cdot E_{2}}{K \cdot E_{1}}=\dfrac{T_{2}}{T_{1}}=\dfrac{40+273}{20+273}=\dfrac{313}{293}}\).
314233
The temperature at which methane molecules have the same average kinetic energy as that of oxygen molecules at \(\mathrm{27^{\circ} \mathrm{C}}\) is
1 \(\mathrm{327^{\circ} \mathrm{C}}\)
2 \(\mathrm{27^{\circ} \mathrm{C}}\)
3 \(\mathrm{927^{\circ} \mathrm{C}}\)
4 \(\mathrm{627^{\circ} \mathrm{C}}\)
Explanation:
K.E. depends on temperature not on the nature of the gas
CHXI06:STATES OF MATTER
314234
If X is the total number of collisions which a gas molecule register with others per unit time under particular conditions, then the collision frequency of the gas containing N molecules per unit volume is
1 \(\frac{{\rm{X}}}{{\rm{N}}}\)
2 NX
3 \(2{\rm{NX}}\)
4 \(\frac{{{\rm{NX}}}}{2}\)
Explanation:
Number of collisions of one molecule/unit time = X Number of collisions of N molecules/unit time =NX \(\therefore\) Collision frequency= NX/2
CHXI06:STATES OF MATTER
314230
As the temperature is raised from \(\mathrm{20^{\circ} \mathrm{C}}\) to \(\mathrm{40^{\circ} \mathrm{C}}\), the average kinetic energy of neon atoms changes by a factor
Average kinetic energy \(\mathrm{\propto T}\) (in \(\mathrm{\mathrm{K}}\) ) \(\mathrm{\dfrac{K \cdot E_{2}}{K \cdot E_{1}}=\dfrac{T_{2}}{T_{1}}=\dfrac{40+273}{20+273}=\dfrac{313}{293}}\).
314233
The temperature at which methane molecules have the same average kinetic energy as that of oxygen molecules at \(\mathrm{27^{\circ} \mathrm{C}}\) is
1 \(\mathrm{327^{\circ} \mathrm{C}}\)
2 \(\mathrm{27^{\circ} \mathrm{C}}\)
3 \(\mathrm{927^{\circ} \mathrm{C}}\)
4 \(\mathrm{627^{\circ} \mathrm{C}}\)
Explanation:
K.E. depends on temperature not on the nature of the gas
CHXI06:STATES OF MATTER
314234
If X is the total number of collisions which a gas molecule register with others per unit time under particular conditions, then the collision frequency of the gas containing N molecules per unit volume is
1 \(\frac{{\rm{X}}}{{\rm{N}}}\)
2 NX
3 \(2{\rm{NX}}\)
4 \(\frac{{{\rm{NX}}}}{2}\)
Explanation:
Number of collisions of one molecule/unit time = X Number of collisions of N molecules/unit time =NX \(\therefore\) Collision frequency= NX/2
CHXI06:STATES OF MATTER
314230
As the temperature is raised from \(\mathrm{20^{\circ} \mathrm{C}}\) to \(\mathrm{40^{\circ} \mathrm{C}}\), the average kinetic energy of neon atoms changes by a factor
Average kinetic energy \(\mathrm{\propto T}\) (in \(\mathrm{\mathrm{K}}\) ) \(\mathrm{\dfrac{K \cdot E_{2}}{K \cdot E_{1}}=\dfrac{T_{2}}{T_{1}}=\dfrac{40+273}{20+273}=\dfrac{313}{293}}\).