1 Work done by gas is \( = 5{\rm{R}}\)
2 Work done over the gas is \( = 10{\rm{R}}\)
3 Work done by the gas \( = 10{\rm{R}}\)
4 Work done \( = 0\)
Explanation:
For 5 moles of gas at temperature T,
\({\rm{P}}{{\rm{V}}_{\rm{1}}}{\rm{ = 5RT}}\)
For 5 moles of gas at temperature \({\rm{T - 2}}\),
\({\rm{P}}{{\rm{V}}_{\rm{2}}}{\rm{ = 5R(T - 2)}}\)
\(\therefore \,\,\,{\rm{P}}\left( {{{\rm{V}}_{\rm{2}}}{\rm{ - }}{{\rm{V}}_{\rm{1}}}} \right){\rm{ = 5R(T - 2 - T)}}\,{\rm{;}}\)
\({\rm{P\Delta V = - 10R,}}\,\,\,{\rm{ - P\Delta V = 10R}}\)
When \({\rm{\Delta V}}\) is negative, W is +ve.