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CHXI04:CHEMICAL BONDING AND MOLECULAR STRUCTURE

313827 Which of the following has highest ionic character?

1

M g C l_{2}

2

C a C l_{2}

3

B a C l_{2}

4

B e C l_{2}

Explanation:

Ionic character: $B e C l_{2} < M g C l_{2} < C a C l_{2} < B a C l_{2}$
The above order is due to increase in size and decrease in I.E. of metals

CHXI04:CHEMICAL BONDING AND MOLECULAR STRUCTURE

313828 Anhydrous $A l C l_{3}$ is covalent while $A l F_{3}$ is ionic. This is justified by

1 Crystal structure

2 VB theory

3 Fajan's rules

4 Lattice enthalpy

CHXI04:CHEMICAL BONDING AND MOLECULAR STRUCTURE

313829 Arrange the bonds in order of increasing ionic character in the molecules :
$LiF, K_{2} O, N_{2}, {SO}_{2}$ and ${ClF}_{3}$ .

1

N_{2} < {SO}_{2} < {ClF}_{3} < K_{2} O < LiF

2

{ClF}_{3} < N_{2} < {SO}_{2} < K_{2} O < LiF

3

LiF < K_{2} O < {ClF}_{3} < {SO}_{2} < N_{2}

4

N_{2} < {ClF}_{3} < {SO}_{2} < K_{2} O < LiF

Explanation:

Greater the electronegativity difference between the atoms, greater will be the ionic character of molecule. So, increasing order of ionic character in the molecules is
$N_{2} < {SO}_{2} < {ClF}_{3} < K_{2} O < LiF$
So, the correct option is (1).

JEE Main - 2024

CHXI04:CHEMICAL BONDING AND MOLECULAR STRUCTURE

313830 Amongst $L i C l, R b C l, B e C l_{2} a n d M g C l_{2}$ the compounds with the greatest and the least ionic character, respectively are:

1

L i C l a n d R b C l

2

R b C l a n d B e C l_{2}

3

M g C l_{2} a n d B e C l_{2}

4

R b C l a n d M g C l_{2}

JEE - 2014

CHXI04:CHEMICAL BONDING AND MOLECULAR STRUCTURE

313831 Most ionic compound among the following is

1 Sodium fluoride

2 Sodium chloride

3 Sodium bromide

4 Sodium iodide

CHXI04:CHEMICAL BONDING AND MOLECULAR STRUCTURE

313827 Which of the following has highest ionic character?

1

M g C l_{2}

2

C a C l_{2}

3

B a C l_{2}

4

B e C l_{2}

Explanation:

Ionic character: $B e C l_{2} < M g C l_{2} < C a C l_{2} < B a C l_{2}$
The above order is due to increase in size and decrease in I.E. of metals

CHXI04:CHEMICAL BONDING AND MOLECULAR STRUCTURE

313828 Anhydrous $A l C l_{3}$ is covalent while $A l F_{3}$ is ionic. This is justified by

1 Crystal structure

2 VB theory

3 Fajan's rules

4 Lattice enthalpy

CHXI04:CHEMICAL BONDING AND MOLECULAR STRUCTURE

313829 Arrange the bonds in order of increasing ionic character in the molecules :
$LiF, K_{2} O, N_{2}, {SO}_{2}$ and ${ClF}_{3}$ .

1

N_{2} < {SO}_{2} < {ClF}_{3} < K_{2} O < LiF

2

{ClF}_{3} < N_{2} < {SO}_{2} < K_{2} O < LiF

3

LiF < K_{2} O < {ClF}_{3} < {SO}_{2} < N_{2}

4

N_{2} < {ClF}_{3} < {SO}_{2} < K_{2} O < LiF

Explanation:

Greater the electronegativity difference between the atoms, greater will be the ionic character of molecule. So, increasing order of ionic character in the molecules is
$N_{2} < {SO}_{2} < {ClF}_{3} < K_{2} O < LiF$
So, the correct option is (1).

JEE Main - 2024

CHXI04:CHEMICAL BONDING AND MOLECULAR STRUCTURE

313830 Amongst $L i C l, R b C l, B e C l_{2} a n d M g C l_{2}$ the compounds with the greatest and the least ionic character, respectively are:

1

L i C l a n d R b C l

2

R b C l a n d B e C l_{2}

3

M g C l_{2} a n d B e C l_{2}

4

R b C l a n d M g C l_{2}

JEE - 2014

CHXI04:CHEMICAL BONDING AND MOLECULAR STRUCTURE

313831 Most ionic compound among the following is

1 Sodium fluoride

2 Sodium chloride

3 Sodium bromide

4 Sodium iodide

CHXI04:CHEMICAL BONDING AND MOLECULAR STRUCTURE

313827 Which of the following has highest ionic character?

1

M g C l_{2}

2

C a C l_{2}

3

B a C l_{2}

4

B e C l_{2}

Explanation:

Ionic character: $B e C l_{2} < M g C l_{2} < C a C l_{2} < B a C l_{2}$
The above order is due to increase in size and decrease in I.E. of metals

CHXI04:CHEMICAL BONDING AND MOLECULAR STRUCTURE

313828 Anhydrous $A l C l_{3}$ is covalent while $A l F_{3}$ is ionic. This is justified by

1 Crystal structure

2 VB theory

3 Fajan's rules

4 Lattice enthalpy

CHXI04:CHEMICAL BONDING AND MOLECULAR STRUCTURE

313829 Arrange the bonds in order of increasing ionic character in the molecules :
$LiF, K_{2} O, N_{2}, {SO}_{2}$ and ${ClF}_{3}$ .

1

N_{2} < {SO}_{2} < {ClF}_{3} < K_{2} O < LiF

2

{ClF}_{3} < N_{2} < {SO}_{2} < K_{2} O < LiF

3

LiF < K_{2} O < {ClF}_{3} < {SO}_{2} < N_{2}

4

N_{2} < {ClF}_{3} < {SO}_{2} < K_{2} O < LiF

Explanation:

Greater the electronegativity difference between the atoms, greater will be the ionic character of molecule. So, increasing order of ionic character in the molecules is
$N_{2} < {SO}_{2} < {ClF}_{3} < K_{2} O < LiF$
So, the correct option is (1).

JEE Main - 2024

CHXI04:CHEMICAL BONDING AND MOLECULAR STRUCTURE

313830 Amongst $L i C l, R b C l, B e C l_{2} a n d M g C l_{2}$ the compounds with the greatest and the least ionic character, respectively are:

1

L i C l a n d R b C l

2

R b C l a n d B e C l_{2}

3

M g C l_{2} a n d B e C l_{2}

4

R b C l a n d M g C l_{2}

JEE - 2014

CHXI04:CHEMICAL BONDING AND MOLECULAR STRUCTURE

313831 Most ionic compound among the following is

1 Sodium fluoride

2 Sodium chloride

3 Sodium bromide

4 Sodium iodide

CHXI04:CHEMICAL BONDING AND MOLECULAR STRUCTURE

313827 Which of the following has highest ionic character?

1

M g C l_{2}

2

C a C l_{2}

3

B a C l_{2}

4

B e C l_{2}

Explanation:

Ionic character: $B e C l_{2} < M g C l_{2} < C a C l_{2} < B a C l_{2}$
The above order is due to increase in size and decrease in I.E. of metals

CHXI04:CHEMICAL BONDING AND MOLECULAR STRUCTURE

313828 Anhydrous $A l C l_{3}$ is covalent while $A l F_{3}$ is ionic. This is justified by

1 Crystal structure

2 VB theory

3 Fajan's rules

4 Lattice enthalpy

CHXI04:CHEMICAL BONDING AND MOLECULAR STRUCTURE

313829 Arrange the bonds in order of increasing ionic character in the molecules :
$LiF, K_{2} O, N_{2}, {SO}_{2}$ and ${ClF}_{3}$ .

1

N_{2} < {SO}_{2} < {ClF}_{3} < K_{2} O < LiF

2

{ClF}_{3} < N_{2} < {SO}_{2} < K_{2} O < LiF

3

LiF < K_{2} O < {ClF}_{3} < {SO}_{2} < N_{2}

4

N_{2} < {ClF}_{3} < {SO}_{2} < K_{2} O < LiF

Explanation:

Greater the electronegativity difference between the atoms, greater will be the ionic character of molecule. So, increasing order of ionic character in the molecules is
$N_{2} < {SO}_{2} < {ClF}_{3} < K_{2} O < LiF$
So, the correct option is (1).

JEE Main - 2024

CHXI04:CHEMICAL BONDING AND MOLECULAR STRUCTURE

313830 Amongst $L i C l, R b C l, B e C l_{2} a n d M g C l_{2}$ the compounds with the greatest and the least ionic character, respectively are:

1

L i C l a n d R b C l

2

R b C l a n d B e C l_{2}

3

M g C l_{2} a n d B e C l_{2}

4

R b C l a n d M g C l_{2}

JEE - 2014

CHXI04:CHEMICAL BONDING AND MOLECULAR STRUCTURE

313831 Most ionic compound among the following is

1 Sodium fluoride

2 Sodium chloride

3 Sodium bromide

4 Sodium iodide

CHXI04:CHEMICAL BONDING AND MOLECULAR STRUCTURE

313827 Which of the following has highest ionic character?

1

M g C l_{2}

2

C a C l_{2}

3

B a C l_{2}

4

B e C l_{2}

Explanation:

Ionic character: $B e C l_{2} < M g C l_{2} < C a C l_{2} < B a C l_{2}$
The above order is due to increase in size and decrease in I.E. of metals

CHXI04:CHEMICAL BONDING AND MOLECULAR STRUCTURE

313828 Anhydrous $A l C l_{3}$ is covalent while $A l F_{3}$ is ionic. This is justified by

1 Crystal structure

2 VB theory

3 Fajan's rules

4 Lattice enthalpy

CHXI04:CHEMICAL BONDING AND MOLECULAR STRUCTURE

313829 Arrange the bonds in order of increasing ionic character in the molecules :
$LiF, K_{2} O, N_{2}, {SO}_{2}$ and ${ClF}_{3}$ .

1

N_{2} < {SO}_{2} < {ClF}_{3} < K_{2} O < LiF

2

{ClF}_{3} < N_{2} < {SO}_{2} < K_{2} O < LiF

3

LiF < K_{2} O < {ClF}_{3} < {SO}_{2} < N_{2}

4

N_{2} < {ClF}_{3} < {SO}_{2} < K_{2} O < LiF

Explanation:

Greater the electronegativity difference between the atoms, greater will be the ionic character of molecule. So, increasing order of ionic character in the molecules is
$N_{2} < {SO}_{2} < {ClF}_{3} < K_{2} O < LiF$
So, the correct option is (1).

JEE Main - 2024

CHXI04:CHEMICAL BONDING AND MOLECULAR STRUCTURE

313830 Amongst $L i C l, R b C l, B e C l_{2} a n d M g C l_{2}$ the compounds with the greatest and the least ionic character, respectively are:

1

L i C l a n d R b C l

2

R b C l a n d B e C l_{2}

3

M g C l_{2} a n d B e C l_{2}

4

R b C l a n d M g C l_{2}

JEE - 2014

CHXI04:CHEMICAL BONDING AND MOLECULAR STRUCTURE

313831 Most ionic compound among the following is

1 Sodium fluoride

2 Sodium chloride

3 Sodium bromide

4 Sodium iodide

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