313553
In which of the following pairs (of molecules/ ions) the central atom has the same hybridisation?
1 \(\mathrm{XeF}_{4}\) and \(\mathrm{ClO}_{4}^{-}\)
2 \(\mathrm{BeCl}_{2}\) and \(\mathrm{SO}_{2}\)
3 \(\mathrm{BH}_{3}\) and \(\mathrm{ClF}_{3}\)
4 \(\mathrm{NH}_{3}\) and \(\mathrm{NH}_{4}^{+}\)
Explanation:
\({\rm{In}}\,{\rm{N}}{{\rm{H}}_{\rm{3}}}{\rm{,}}\,{\rm{No}}{\mkern 1mu} \,{\rm{.}}{\mkern 1mu} \,{\rm{of}}\,{\mkern 1mu} {\rm{\sigma }} - {\rm{bonds}} = 3\) No. of lone pair of electrons on N atom \(=1\) Total no. of electron pairs \( = 3 + 1 = 4\,;\,{\text{s}}{{\text{p}}^3}\) hybridisation. For \(\mathrm{NH}_{4}^{+}\), we can use the formula, \({\text{H}} = \frac{1}{2}({\text{V}} + {\text{M}} - {\text{C}} + {\text{A}})\) \( = \frac{1}{2}(5 + 4 - 1 + 0) \Rightarrow 4\,;\,{\text{s}}{{\text{p}}^3}\) hybridisation.
CHXI04:CHEMICAL BONDING AND MOLECULAR STRUCTURE
313554
The correct order of bond angles of following species are
313555
Choose the molecules in which hybridization occurs in the ground state. (P) \(\mathrm{BCl}_{3}\) (Q) \(\mathrm{NH}_{3}\) (R) \(\mathrm{PCl}_{3}\) (S) \(\mathrm{BeF}_{2}\) The correct answer is
1 P, Q and S
2 P, Q and R
3 Q and R
4 R and S
Explanation:
Q and R show hybridization in ground state. \(\mathrm{N}: 2 \mathrm{~s}^{2} 2 \mathrm{p}^{3}-\mathrm{NH}_{3}\) \(\mathrm{P}: 3 \mathrm{~s}^{2} 3 \mathrm{p}^{3}-\mathrm{PCl}_{3}\) In \(\mathrm{BeF}_{2}, \mathrm{BCl}_{3}\), central atoms show hybridization in first excited state.
CHXI04:CHEMICAL BONDING AND MOLECULAR STRUCTURE
313556
In which of the excitation state of chlorine \({\rm{Cl}}{{\rm{F}}_{\rm{3}}}\) is formed
1 In ground state
2 In third excitation state
3 In first excitation state
4 In second excitation state
Explanation:
\(_{{\rm{17}}}{\rm{Cl}} \to {\left[ {{\rm{Ne}}} \right]^{{\rm{10}}}}{\rm{3}}{{\rm{s}}^{\rm{2}}}{\rm{3}}{{\rm{p}}^{\rm{5}}}\) In first excited state, it has 3 unpaired electrons and forms 3 bonds 'C' means number of unpaired electrons.
313553
In which of the following pairs (of molecules/ ions) the central atom has the same hybridisation?
1 \(\mathrm{XeF}_{4}\) and \(\mathrm{ClO}_{4}^{-}\)
2 \(\mathrm{BeCl}_{2}\) and \(\mathrm{SO}_{2}\)
3 \(\mathrm{BH}_{3}\) and \(\mathrm{ClF}_{3}\)
4 \(\mathrm{NH}_{3}\) and \(\mathrm{NH}_{4}^{+}\)
Explanation:
\({\rm{In}}\,{\rm{N}}{{\rm{H}}_{\rm{3}}}{\rm{,}}\,{\rm{No}}{\mkern 1mu} \,{\rm{.}}{\mkern 1mu} \,{\rm{of}}\,{\mkern 1mu} {\rm{\sigma }} - {\rm{bonds}} = 3\) No. of lone pair of electrons on N atom \(=1\) Total no. of electron pairs \( = 3 + 1 = 4\,;\,{\text{s}}{{\text{p}}^3}\) hybridisation. For \(\mathrm{NH}_{4}^{+}\), we can use the formula, \({\text{H}} = \frac{1}{2}({\text{V}} + {\text{M}} - {\text{C}} + {\text{A}})\) \( = \frac{1}{2}(5 + 4 - 1 + 0) \Rightarrow 4\,;\,{\text{s}}{{\text{p}}^3}\) hybridisation.
CHXI04:CHEMICAL BONDING AND MOLECULAR STRUCTURE
313554
The correct order of bond angles of following species are
313555
Choose the molecules in which hybridization occurs in the ground state. (P) \(\mathrm{BCl}_{3}\) (Q) \(\mathrm{NH}_{3}\) (R) \(\mathrm{PCl}_{3}\) (S) \(\mathrm{BeF}_{2}\) The correct answer is
1 P, Q and S
2 P, Q and R
3 Q and R
4 R and S
Explanation:
Q and R show hybridization in ground state. \(\mathrm{N}: 2 \mathrm{~s}^{2} 2 \mathrm{p}^{3}-\mathrm{NH}_{3}\) \(\mathrm{P}: 3 \mathrm{~s}^{2} 3 \mathrm{p}^{3}-\mathrm{PCl}_{3}\) In \(\mathrm{BeF}_{2}, \mathrm{BCl}_{3}\), central atoms show hybridization in first excited state.
CHXI04:CHEMICAL BONDING AND MOLECULAR STRUCTURE
313556
In which of the excitation state of chlorine \({\rm{Cl}}{{\rm{F}}_{\rm{3}}}\) is formed
1 In ground state
2 In third excitation state
3 In first excitation state
4 In second excitation state
Explanation:
\(_{{\rm{17}}}{\rm{Cl}} \to {\left[ {{\rm{Ne}}} \right]^{{\rm{10}}}}{\rm{3}}{{\rm{s}}^{\rm{2}}}{\rm{3}}{{\rm{p}}^{\rm{5}}}\) In first excited state, it has 3 unpaired electrons and forms 3 bonds 'C' means number of unpaired electrons.
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CHXI04:CHEMICAL BONDING AND MOLECULAR STRUCTURE
313553
In which of the following pairs (of molecules/ ions) the central atom has the same hybridisation?
1 \(\mathrm{XeF}_{4}\) and \(\mathrm{ClO}_{4}^{-}\)
2 \(\mathrm{BeCl}_{2}\) and \(\mathrm{SO}_{2}\)
3 \(\mathrm{BH}_{3}\) and \(\mathrm{ClF}_{3}\)
4 \(\mathrm{NH}_{3}\) and \(\mathrm{NH}_{4}^{+}\)
Explanation:
\({\rm{In}}\,{\rm{N}}{{\rm{H}}_{\rm{3}}}{\rm{,}}\,{\rm{No}}{\mkern 1mu} \,{\rm{.}}{\mkern 1mu} \,{\rm{of}}\,{\mkern 1mu} {\rm{\sigma }} - {\rm{bonds}} = 3\) No. of lone pair of electrons on N atom \(=1\) Total no. of electron pairs \( = 3 + 1 = 4\,;\,{\text{s}}{{\text{p}}^3}\) hybridisation. For \(\mathrm{NH}_{4}^{+}\), we can use the formula, \({\text{H}} = \frac{1}{2}({\text{V}} + {\text{M}} - {\text{C}} + {\text{A}})\) \( = \frac{1}{2}(5 + 4 - 1 + 0) \Rightarrow 4\,;\,{\text{s}}{{\text{p}}^3}\) hybridisation.
CHXI04:CHEMICAL BONDING AND MOLECULAR STRUCTURE
313554
The correct order of bond angles of following species are
313555
Choose the molecules in which hybridization occurs in the ground state. (P) \(\mathrm{BCl}_{3}\) (Q) \(\mathrm{NH}_{3}\) (R) \(\mathrm{PCl}_{3}\) (S) \(\mathrm{BeF}_{2}\) The correct answer is
1 P, Q and S
2 P, Q and R
3 Q and R
4 R and S
Explanation:
Q and R show hybridization in ground state. \(\mathrm{N}: 2 \mathrm{~s}^{2} 2 \mathrm{p}^{3}-\mathrm{NH}_{3}\) \(\mathrm{P}: 3 \mathrm{~s}^{2} 3 \mathrm{p}^{3}-\mathrm{PCl}_{3}\) In \(\mathrm{BeF}_{2}, \mathrm{BCl}_{3}\), central atoms show hybridization in first excited state.
CHXI04:CHEMICAL BONDING AND MOLECULAR STRUCTURE
313556
In which of the excitation state of chlorine \({\rm{Cl}}{{\rm{F}}_{\rm{3}}}\) is formed
1 In ground state
2 In third excitation state
3 In first excitation state
4 In second excitation state
Explanation:
\(_{{\rm{17}}}{\rm{Cl}} \to {\left[ {{\rm{Ne}}} \right]^{{\rm{10}}}}{\rm{3}}{{\rm{s}}^{\rm{2}}}{\rm{3}}{{\rm{p}}^{\rm{5}}}\) In first excited state, it has 3 unpaired electrons and forms 3 bonds 'C' means number of unpaired electrons.
313553
In which of the following pairs (of molecules/ ions) the central atom has the same hybridisation?
1 \(\mathrm{XeF}_{4}\) and \(\mathrm{ClO}_{4}^{-}\)
2 \(\mathrm{BeCl}_{2}\) and \(\mathrm{SO}_{2}\)
3 \(\mathrm{BH}_{3}\) and \(\mathrm{ClF}_{3}\)
4 \(\mathrm{NH}_{3}\) and \(\mathrm{NH}_{4}^{+}\)
Explanation:
\({\rm{In}}\,{\rm{N}}{{\rm{H}}_{\rm{3}}}{\rm{,}}\,{\rm{No}}{\mkern 1mu} \,{\rm{.}}{\mkern 1mu} \,{\rm{of}}\,{\mkern 1mu} {\rm{\sigma }} - {\rm{bonds}} = 3\) No. of lone pair of electrons on N atom \(=1\) Total no. of electron pairs \( = 3 + 1 = 4\,;\,{\text{s}}{{\text{p}}^3}\) hybridisation. For \(\mathrm{NH}_{4}^{+}\), we can use the formula, \({\text{H}} = \frac{1}{2}({\text{V}} + {\text{M}} - {\text{C}} + {\text{A}})\) \( = \frac{1}{2}(5 + 4 - 1 + 0) \Rightarrow 4\,;\,{\text{s}}{{\text{p}}^3}\) hybridisation.
CHXI04:CHEMICAL BONDING AND MOLECULAR STRUCTURE
313554
The correct order of bond angles of following species are
313555
Choose the molecules in which hybridization occurs in the ground state. (P) \(\mathrm{BCl}_{3}\) (Q) \(\mathrm{NH}_{3}\) (R) \(\mathrm{PCl}_{3}\) (S) \(\mathrm{BeF}_{2}\) The correct answer is
1 P, Q and S
2 P, Q and R
3 Q and R
4 R and S
Explanation:
Q and R show hybridization in ground state. \(\mathrm{N}: 2 \mathrm{~s}^{2} 2 \mathrm{p}^{3}-\mathrm{NH}_{3}\) \(\mathrm{P}: 3 \mathrm{~s}^{2} 3 \mathrm{p}^{3}-\mathrm{PCl}_{3}\) In \(\mathrm{BeF}_{2}, \mathrm{BCl}_{3}\), central atoms show hybridization in first excited state.
CHXI04:CHEMICAL BONDING AND MOLECULAR STRUCTURE
313556
In which of the excitation state of chlorine \({\rm{Cl}}{{\rm{F}}_{\rm{3}}}\) is formed
1 In ground state
2 In third excitation state
3 In first excitation state
4 In second excitation state
Explanation:
\(_{{\rm{17}}}{\rm{Cl}} \to {\left[ {{\rm{Ne}}} \right]^{{\rm{10}}}}{\rm{3}}{{\rm{s}}^{\rm{2}}}{\rm{3}}{{\rm{p}}^{\rm{5}}}\) In first excited state, it has 3 unpaired electrons and forms 3 bonds 'C' means number of unpaired electrons.
