313739
The magnetic behavior of \(\mathrm{Li}_2 \mathrm{O}, \mathrm{Na}_2 \mathrm{O}_2\) and \(\mathrm{KO}_2\), respectively, are
1 diamagnetic, paramagnetic and diamagnetic
2 diamagnetic, diamagnetic and paramagnetic
3 paramagnetic, diamagnetic and paramagnetic.
4 paramagnetic, paramagnetic and diamagnetic
Explanation:
\({\rm{L}}{{\rm{i}}_2}{\rm{O}}\) is normal oxide \(\left(\mathrm{O}^{2-}\right)\) and it is diamagnetic. \({\rm{N}}{{\rm{a}}_2}{{\rm{O}}_2}\) is peroxide \(\left(\mathrm{O}_{2}^{2-}\right)\) and it is also diamagnetic. \({\rm{K}}{{\rm{O}}_2}\) is superoxide \(\left( {{\rm{O}}_2^ - } \right)\) and it is paramagnetic, due to odd no. of electrons (unpaired electron)
JEE - 2023
CHXI04:CHEMICAL BONDING AND MOLECULAR STRUCTURE
313740
Which of the following has unpaired electron (s) ?
For any species to have same bond order we can expect them to have same number of electrons. Calculating the number of electrons in various species. \({\rm{O}}_{\rm{2}}^{\rm{ - }}\left( {{\rm{8 + 8 + 1 = 17}}} \right){\rm{;C}}{{\rm{N}}^{\rm{ - }}}\left( {{\rm{6 + 7 + 1 = 14}}} \right)\) \({\rm{N}}{{\rm{O}}^{\rm{ + }}}\left( {{\rm{7 + 8 - 1 = 14}}} \right){\rm{;C}}{{\rm{N}}^{\rm{ + }}}\left( {{\rm{6 + 7 - 1 = 12}}} \right)\) We find \({\rm{C}}{{\rm{N}}^{\rm{ - }}}\,\,{\rm{and}}\,\,{\rm{N}}{{\rm{O}}^{\rm{ + }}}\) both have 14 electrons so they have same bond order.
CHXI04:CHEMICAL BONDING AND MOLECULAR STRUCTURE
313742
The increasing order of bond order \({{\rm{O}}_{\rm{2}}}{\rm{,}}\,\,{\rm{O}}_{\rm{2}}^{\rm{ + }}{\rm{,}}\,\,{\rm{O}}_{\rm{2}}^{\rm{ - }}\,\,{\rm{and}}\,\,{\rm{O}}_{\rm{2}}^{{\rm{ - 2}}}\,\,{\rm{is}}\)
313739
The magnetic behavior of \(\mathrm{Li}_2 \mathrm{O}, \mathrm{Na}_2 \mathrm{O}_2\) and \(\mathrm{KO}_2\), respectively, are
1 diamagnetic, paramagnetic and diamagnetic
2 diamagnetic, diamagnetic and paramagnetic
3 paramagnetic, diamagnetic and paramagnetic.
4 paramagnetic, paramagnetic and diamagnetic
Explanation:
\({\rm{L}}{{\rm{i}}_2}{\rm{O}}\) is normal oxide \(\left(\mathrm{O}^{2-}\right)\) and it is diamagnetic. \({\rm{N}}{{\rm{a}}_2}{{\rm{O}}_2}\) is peroxide \(\left(\mathrm{O}_{2}^{2-}\right)\) and it is also diamagnetic. \({\rm{K}}{{\rm{O}}_2}\) is superoxide \(\left( {{\rm{O}}_2^ - } \right)\) and it is paramagnetic, due to odd no. of electrons (unpaired electron)
JEE - 2023
CHXI04:CHEMICAL BONDING AND MOLECULAR STRUCTURE
313740
Which of the following has unpaired electron (s) ?
For any species to have same bond order we can expect them to have same number of electrons. Calculating the number of electrons in various species. \({\rm{O}}_{\rm{2}}^{\rm{ - }}\left( {{\rm{8 + 8 + 1 = 17}}} \right){\rm{;C}}{{\rm{N}}^{\rm{ - }}}\left( {{\rm{6 + 7 + 1 = 14}}} \right)\) \({\rm{N}}{{\rm{O}}^{\rm{ + }}}\left( {{\rm{7 + 8 - 1 = 14}}} \right){\rm{;C}}{{\rm{N}}^{\rm{ + }}}\left( {{\rm{6 + 7 - 1 = 12}}} \right)\) We find \({\rm{C}}{{\rm{N}}^{\rm{ - }}}\,\,{\rm{and}}\,\,{\rm{N}}{{\rm{O}}^{\rm{ + }}}\) both have 14 electrons so they have same bond order.
CHXI04:CHEMICAL BONDING AND MOLECULAR STRUCTURE
313742
The increasing order of bond order \({{\rm{O}}_{\rm{2}}}{\rm{,}}\,\,{\rm{O}}_{\rm{2}}^{\rm{ + }}{\rm{,}}\,\,{\rm{O}}_{\rm{2}}^{\rm{ - }}\,\,{\rm{and}}\,\,{\rm{O}}_{\rm{2}}^{{\rm{ - 2}}}\,\,{\rm{is}}\)
313739
The magnetic behavior of \(\mathrm{Li}_2 \mathrm{O}, \mathrm{Na}_2 \mathrm{O}_2\) and \(\mathrm{KO}_2\), respectively, are
1 diamagnetic, paramagnetic and diamagnetic
2 diamagnetic, diamagnetic and paramagnetic
3 paramagnetic, diamagnetic and paramagnetic.
4 paramagnetic, paramagnetic and diamagnetic
Explanation:
\({\rm{L}}{{\rm{i}}_2}{\rm{O}}\) is normal oxide \(\left(\mathrm{O}^{2-}\right)\) and it is diamagnetic. \({\rm{N}}{{\rm{a}}_2}{{\rm{O}}_2}\) is peroxide \(\left(\mathrm{O}_{2}^{2-}\right)\) and it is also diamagnetic. \({\rm{K}}{{\rm{O}}_2}\) is superoxide \(\left( {{\rm{O}}_2^ - } \right)\) and it is paramagnetic, due to odd no. of electrons (unpaired electron)
JEE - 2023
CHXI04:CHEMICAL BONDING AND MOLECULAR STRUCTURE
313740
Which of the following has unpaired electron (s) ?
For any species to have same bond order we can expect them to have same number of electrons. Calculating the number of electrons in various species. \({\rm{O}}_{\rm{2}}^{\rm{ - }}\left( {{\rm{8 + 8 + 1 = 17}}} \right){\rm{;C}}{{\rm{N}}^{\rm{ - }}}\left( {{\rm{6 + 7 + 1 = 14}}} \right)\) \({\rm{N}}{{\rm{O}}^{\rm{ + }}}\left( {{\rm{7 + 8 - 1 = 14}}} \right){\rm{;C}}{{\rm{N}}^{\rm{ + }}}\left( {{\rm{6 + 7 - 1 = 12}}} \right)\) We find \({\rm{C}}{{\rm{N}}^{\rm{ - }}}\,\,{\rm{and}}\,\,{\rm{N}}{{\rm{O}}^{\rm{ + }}}\) both have 14 electrons so they have same bond order.
CHXI04:CHEMICAL BONDING AND MOLECULAR STRUCTURE
313742
The increasing order of bond order \({{\rm{O}}_{\rm{2}}}{\rm{,}}\,\,{\rm{O}}_{\rm{2}}^{\rm{ + }}{\rm{,}}\,\,{\rm{O}}_{\rm{2}}^{\rm{ - }}\,\,{\rm{and}}\,\,{\rm{O}}_{\rm{2}}^{{\rm{ - 2}}}\,\,{\rm{is}}\)
313739
The magnetic behavior of \(\mathrm{Li}_2 \mathrm{O}, \mathrm{Na}_2 \mathrm{O}_2\) and \(\mathrm{KO}_2\), respectively, are
1 diamagnetic, paramagnetic and diamagnetic
2 diamagnetic, diamagnetic and paramagnetic
3 paramagnetic, diamagnetic and paramagnetic.
4 paramagnetic, paramagnetic and diamagnetic
Explanation:
\({\rm{L}}{{\rm{i}}_2}{\rm{O}}\) is normal oxide \(\left(\mathrm{O}^{2-}\right)\) and it is diamagnetic. \({\rm{N}}{{\rm{a}}_2}{{\rm{O}}_2}\) is peroxide \(\left(\mathrm{O}_{2}^{2-}\right)\) and it is also diamagnetic. \({\rm{K}}{{\rm{O}}_2}\) is superoxide \(\left( {{\rm{O}}_2^ - } \right)\) and it is paramagnetic, due to odd no. of electrons (unpaired electron)
JEE - 2023
CHXI04:CHEMICAL BONDING AND MOLECULAR STRUCTURE
313740
Which of the following has unpaired electron (s) ?
For any species to have same bond order we can expect them to have same number of electrons. Calculating the number of electrons in various species. \({\rm{O}}_{\rm{2}}^{\rm{ - }}\left( {{\rm{8 + 8 + 1 = 17}}} \right){\rm{;C}}{{\rm{N}}^{\rm{ - }}}\left( {{\rm{6 + 7 + 1 = 14}}} \right)\) \({\rm{N}}{{\rm{O}}^{\rm{ + }}}\left( {{\rm{7 + 8 - 1 = 14}}} \right){\rm{;C}}{{\rm{N}}^{\rm{ + }}}\left( {{\rm{6 + 7 - 1 = 12}}} \right)\) We find \({\rm{C}}{{\rm{N}}^{\rm{ - }}}\,\,{\rm{and}}\,\,{\rm{N}}{{\rm{O}}^{\rm{ + }}}\) both have 14 electrons so they have same bond order.
CHXI04:CHEMICAL BONDING AND MOLECULAR STRUCTURE
313742
The increasing order of bond order \({{\rm{O}}_{\rm{2}}}{\rm{,}}\,\,{\rm{O}}_{\rm{2}}^{\rm{ + }}{\rm{,}}\,\,{\rm{O}}_{\rm{2}}^{\rm{ - }}\,\,{\rm{and}}\,\,{\rm{O}}_{\rm{2}}^{{\rm{ - 2}}}\,\,{\rm{is}}\)