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CHXI04:CHEMICAL BONDING AND MOLECULAR STRUCTURE

313767 Match List-I (Molecules) with List-II (Bond order) and select the correct answer using the codes.

Column I	Column II
A. $L i_{2}$	P. $3$
B. $N_{2}$	Q. $1.5$
C. $B e_{2}$	R. $1$
D. $O_{2}$	S. $0$
	T. $2$

1

A - Q, B - R, C - P, D - S

2

A - R, B - P, C - S, D - T

3

A - S, B - P, C - S, D - E

4

A - R, B - Q, C - T, D - P

Explanation:

Bond order $= \frac{1}{2} (N_{b} - N_{a})$
Bond order of ${Li}_{2} = 1, N_{2} = 3, {Be}_{2} = 0, O_{2} = 2$

CHXI04:CHEMICAL BONDING AND MOLECULAR STRUCTURE

313724 Identify a molecule which does not exist.

1

L i_{2}

2

C_{2}

3

O_{2}

4

H e_{2}

Explanation:

$H e_{2}$ does not exist due to zero bond order according to MOT.

NEET - 2020

CHXI04:CHEMICAL BONDING AND MOLECULAR STRUCTURE

313725 The correct order of energies of molecular orbitals of $N_{2}$ molecule, is

1

σ 1s < σ^{*} 1s < σ 2s < σ^{*} 2s < σ 2 p_{z} <

(π 2 p_{x} = π 2 p_{y}) < (π^{*} 2 p_{x} = π^{*} 2 p_{y}) < σ^{*} 2 p_{z}

2

σ 1s < σ^{*} 1s < σ 2s < σ^{*} 2s < σ 2 p_{z} <

σ^{*} 2 p_{z} < (π 2 p_{x} = π 2 p_{y}) < (π^{*} 2 p_{x} = π^{*} 2 p_{y})

3

σ 1 s < σ^{*} 1s < σ 2s < σ^{*} 2s < (π 2 p_{x} = π 2 p_{y}) <

(π^{*} 2 p_{x} = π^{*} 2 p_{y}) < σ 2 p_{z} < σ^{*} 2 p_{z}

4

σ 1s < σ^{*} 1s < σ 2s < σ^{*} 2s < (π 2 p_{x} = π 2 p_{y}) <

σ 2 p_{z} < (π^{*} 2 p_{x} = π^{*} 2 p_{y}) < σ^{*} 2 p_{z}

Explanation:

Molecular orbital (energy) diagram/sequence of $N_{2}$
supporting img

NEET - 2023

CHXI04:CHEMICAL BONDING AND MOLECULAR STRUCTURE

313726 In which of the following processes, the bond order increases and paramagnetic character changes to diamagnetic one?

1

O_{2} \to O_{2}^{+}

2

N O \to N O^{+}

3

O_{2} \to O_{2}^{2 -}

4

N_{2} \to N_{2}^{+}

Explanation:

$O_{2} - 16 e^{-} -$ B.O. $= 2$ , Paramagnetic
$O_{2}^{+} - 15 e^{-} -$ B.O. $= 2.5$ , Paramagnetic
$O_{2}^{2 -} - 18 e^{-} -$ B.O. $= 1$ , Diamagnetic
NO $- 15 e^{-} -$ B.O. $= 2.5$ , Paramagnetic
${NO}^{+} - 14 e^{-} -$ B.O. $= 3$ , Diamagnetic
$N_{2} - 14 e^{-} -$ B.O. $= 3$ , Diamagnetic
$N_{2}^{+} - 13 e^{-} -$ B.O. $= 2.5$ , Paramagnetic
So, correct option is (2).

JEE - 2023

CHXI04:CHEMICAL BONDING AND MOLECULAR STRUCTURE

313727 Which statement is correct about $O_{2}^{+}$ ?

1 Paramagnetic and bond order

< O_{2}

2 Paramagnetic and bond order

> O_{2}

3 Diamagnetic and bond order

< O_{2}

4 Diamagnetic and bond order

> O_{2}

Explanation:

Both $O_{2}^{+}$ and $O_{2}$ are paramagnetic bond order of $O_{2}^{+} = 2.5$ and $O_{2} = 2$

CHXI04:CHEMICAL BONDING AND MOLECULAR STRUCTURE

313767 Match List-I (Molecules) with List-II (Bond order) and select the correct answer using the codes.

Column I	Column II
A. $L i_{2}$	P. $3$
B. $N_{2}$	Q. $1.5$
C. $B e_{2}$	R. $1$
D. $O_{2}$	S. $0$
	T. $2$

1

A - Q, B - R, C - P, D - S

2

A - R, B - P, C - S, D - T

3

A - S, B - P, C - S, D - E

4

A - R, B - Q, C - T, D - P

Explanation:

Bond order $= \frac{1}{2} (N_{b} - N_{a})$
Bond order of ${Li}_{2} = 1, N_{2} = 3, {Be}_{2} = 0, O_{2} = 2$

CHXI04:CHEMICAL BONDING AND MOLECULAR STRUCTURE

313724 Identify a molecule which does not exist.

1

L i_{2}

2

C_{2}

3

O_{2}

4

H e_{2}

Explanation:

$H e_{2}$ does not exist due to zero bond order according to MOT.

NEET - 2020

CHXI04:CHEMICAL BONDING AND MOLECULAR STRUCTURE

313725 The correct order of energies of molecular orbitals of $N_{2}$ molecule, is

1

σ 1s < σ^{*} 1s < σ 2s < σ^{*} 2s < σ 2 p_{z} <

(π 2 p_{x} = π 2 p_{y}) < (π^{*} 2 p_{x} = π^{*} 2 p_{y}) < σ^{*} 2 p_{z}

2

σ 1s < σ^{*} 1s < σ 2s < σ^{*} 2s < σ 2 p_{z} <

σ^{*} 2 p_{z} < (π 2 p_{x} = π 2 p_{y}) < (π^{*} 2 p_{x} = π^{*} 2 p_{y})

3

σ 1 s < σ^{*} 1s < σ 2s < σ^{*} 2s < (π 2 p_{x} = π 2 p_{y}) <

(π^{*} 2 p_{x} = π^{*} 2 p_{y}) < σ 2 p_{z} < σ^{*} 2 p_{z}

4

σ 1s < σ^{*} 1s < σ 2s < σ^{*} 2s < (π 2 p_{x} = π 2 p_{y}) <

σ 2 p_{z} < (π^{*} 2 p_{x} = π^{*} 2 p_{y}) < σ^{*} 2 p_{z}

Explanation:

Molecular orbital (energy) diagram/sequence of $N_{2}$
supporting img

NEET - 2023

CHXI04:CHEMICAL BONDING AND MOLECULAR STRUCTURE

313726 In which of the following processes, the bond order increases and paramagnetic character changes to diamagnetic one?

1

O_{2} \to O_{2}^{+}

2

N O \to N O^{+}

3

O_{2} \to O_{2}^{2 -}

4

N_{2} \to N_{2}^{+}

Explanation:

$O_{2} - 16 e^{-} -$ B.O. $= 2$ , Paramagnetic
$O_{2}^{+} - 15 e^{-} -$ B.O. $= 2.5$ , Paramagnetic
$O_{2}^{2 -} - 18 e^{-} -$ B.O. $= 1$ , Diamagnetic
NO $- 15 e^{-} -$ B.O. $= 2.5$ , Paramagnetic
${NO}^{+} - 14 e^{-} -$ B.O. $= 3$ , Diamagnetic
$N_{2} - 14 e^{-} -$ B.O. $= 3$ , Diamagnetic
$N_{2}^{+} - 13 e^{-} -$ B.O. $= 2.5$ , Paramagnetic
So, correct option is (2).

JEE - 2023

CHXI04:CHEMICAL BONDING AND MOLECULAR STRUCTURE

313727 Which statement is correct about $O_{2}^{+}$ ?

1 Paramagnetic and bond order

< O_{2}

2 Paramagnetic and bond order

> O_{2}

3 Diamagnetic and bond order

< O_{2}

4 Diamagnetic and bond order

> O_{2}

Explanation:

Both $O_{2}^{+}$ and $O_{2}$ are paramagnetic bond order of $O_{2}^{+} = 2.5$ and $O_{2} = 2$

CHXI04:CHEMICAL BONDING AND MOLECULAR STRUCTURE

313767 Match List-I (Molecules) with List-II (Bond order) and select the correct answer using the codes.

Column I	Column II
A. $L i_{2}$	P. $3$
B. $N_{2}$	Q. $1.5$
C. $B e_{2}$	R. $1$
D. $O_{2}$	S. $0$
	T. $2$

1

A - Q, B - R, C - P, D - S

2

A - R, B - P, C - S, D - T

3

A - S, B - P, C - S, D - E

4

A - R, B - Q, C - T, D - P

Explanation:

Bond order $= \frac{1}{2} (N_{b} - N_{a})$
Bond order of ${Li}_{2} = 1, N_{2} = 3, {Be}_{2} = 0, O_{2} = 2$

CHXI04:CHEMICAL BONDING AND MOLECULAR STRUCTURE

313724 Identify a molecule which does not exist.

1

L i_{2}

2

C_{2}

3

O_{2}

4

H e_{2}

Explanation:

$H e_{2}$ does not exist due to zero bond order according to MOT.

NEET - 2020

CHXI04:CHEMICAL BONDING AND MOLECULAR STRUCTURE

313725 The correct order of energies of molecular orbitals of $N_{2}$ molecule, is

1

σ 1s < σ^{*} 1s < σ 2s < σ^{*} 2s < σ 2 p_{z} <

(π 2 p_{x} = π 2 p_{y}) < (π^{*} 2 p_{x} = π^{*} 2 p_{y}) < σ^{*} 2 p_{z}

2

σ 1s < σ^{*} 1s < σ 2s < σ^{*} 2s < σ 2 p_{z} <

σ^{*} 2 p_{z} < (π 2 p_{x} = π 2 p_{y}) < (π^{*} 2 p_{x} = π^{*} 2 p_{y})

3

σ 1 s < σ^{*} 1s < σ 2s < σ^{*} 2s < (π 2 p_{x} = π 2 p_{y}) <

(π^{*} 2 p_{x} = π^{*} 2 p_{y}) < σ 2 p_{z} < σ^{*} 2 p_{z}

4

σ 1s < σ^{*} 1s < σ 2s < σ^{*} 2s < (π 2 p_{x} = π 2 p_{y}) <

σ 2 p_{z} < (π^{*} 2 p_{x} = π^{*} 2 p_{y}) < σ^{*} 2 p_{z}

Explanation:

Molecular orbital (energy) diagram/sequence of $N_{2}$
supporting img

NEET - 2023

CHXI04:CHEMICAL BONDING AND MOLECULAR STRUCTURE

313726 In which of the following processes, the bond order increases and paramagnetic character changes to diamagnetic one?

1

O_{2} \to O_{2}^{+}

2

N O \to N O^{+}

3

O_{2} \to O_{2}^{2 -}

4

N_{2} \to N_{2}^{+}

Explanation:

$O_{2} - 16 e^{-} -$ B.O. $= 2$ , Paramagnetic
$O_{2}^{+} - 15 e^{-} -$ B.O. $= 2.5$ , Paramagnetic
$O_{2}^{2 -} - 18 e^{-} -$ B.O. $= 1$ , Diamagnetic
NO $- 15 e^{-} -$ B.O. $= 2.5$ , Paramagnetic
${NO}^{+} - 14 e^{-} -$ B.O. $= 3$ , Diamagnetic
$N_{2} - 14 e^{-} -$ B.O. $= 3$ , Diamagnetic
$N_{2}^{+} - 13 e^{-} -$ B.O. $= 2.5$ , Paramagnetic
So, correct option is (2).

JEE - 2023

CHXI04:CHEMICAL BONDING AND MOLECULAR STRUCTURE

313727 Which statement is correct about $O_{2}^{+}$ ?

1 Paramagnetic and bond order

< O_{2}

2 Paramagnetic and bond order

> O_{2}

3 Diamagnetic and bond order

< O_{2}

4 Diamagnetic and bond order

> O_{2}

Explanation:

Both $O_{2}^{+}$ and $O_{2}$ are paramagnetic bond order of $O_{2}^{+} = 2.5$ and $O_{2} = 2$

CHXI04:CHEMICAL BONDING AND MOLECULAR STRUCTURE

313767 Match List-I (Molecules) with List-II (Bond order) and select the correct answer using the codes.

Column I	Column II
A. $L i_{2}$	P. $3$
B. $N_{2}$	Q. $1.5$
C. $B e_{2}$	R. $1$
D. $O_{2}$	S. $0$
	T. $2$

1

A - Q, B - R, C - P, D - S

2

A - R, B - P, C - S, D - T

3

A - S, B - P, C - S, D - E

4

A - R, B - Q, C - T, D - P

Explanation:

Bond order $= \frac{1}{2} (N_{b} - N_{a})$
Bond order of ${Li}_{2} = 1, N_{2} = 3, {Be}_{2} = 0, O_{2} = 2$

CHXI04:CHEMICAL BONDING AND MOLECULAR STRUCTURE

313724 Identify a molecule which does not exist.

1

L i_{2}

2

C_{2}

3

O_{2}

4

H e_{2}

Explanation:

$H e_{2}$ does not exist due to zero bond order according to MOT.

NEET - 2020

CHXI04:CHEMICAL BONDING AND MOLECULAR STRUCTURE

313725 The correct order of energies of molecular orbitals of $N_{2}$ molecule, is

1

σ 1s < σ^{*} 1s < σ 2s < σ^{*} 2s < σ 2 p_{z} <

(π 2 p_{x} = π 2 p_{y}) < (π^{*} 2 p_{x} = π^{*} 2 p_{y}) < σ^{*} 2 p_{z}

2

σ 1s < σ^{*} 1s < σ 2s < σ^{*} 2s < σ 2 p_{z} <

σ^{*} 2 p_{z} < (π 2 p_{x} = π 2 p_{y}) < (π^{*} 2 p_{x} = π^{*} 2 p_{y})

3

σ 1 s < σ^{*} 1s < σ 2s < σ^{*} 2s < (π 2 p_{x} = π 2 p_{y}) <

(π^{*} 2 p_{x} = π^{*} 2 p_{y}) < σ 2 p_{z} < σ^{*} 2 p_{z}

4

σ 1s < σ^{*} 1s < σ 2s < σ^{*} 2s < (π 2 p_{x} = π 2 p_{y}) <

σ 2 p_{z} < (π^{*} 2 p_{x} = π^{*} 2 p_{y}) < σ^{*} 2 p_{z}

Explanation:

Molecular orbital (energy) diagram/sequence of $N_{2}$
supporting img

NEET - 2023

CHXI04:CHEMICAL BONDING AND MOLECULAR STRUCTURE

313726 In which of the following processes, the bond order increases and paramagnetic character changes to diamagnetic one?

1

O_{2} \to O_{2}^{+}

2

N O \to N O^{+}

3

O_{2} \to O_{2}^{2 -}

4

N_{2} \to N_{2}^{+}

Explanation:

$O_{2} - 16 e^{-} -$ B.O. $= 2$ , Paramagnetic
$O_{2}^{+} - 15 e^{-} -$ B.O. $= 2.5$ , Paramagnetic
$O_{2}^{2 -} - 18 e^{-} -$ B.O. $= 1$ , Diamagnetic
NO $- 15 e^{-} -$ B.O. $= 2.5$ , Paramagnetic
${NO}^{+} - 14 e^{-} -$ B.O. $= 3$ , Diamagnetic
$N_{2} - 14 e^{-} -$ B.O. $= 3$ , Diamagnetic
$N_{2}^{+} - 13 e^{-} -$ B.O. $= 2.5$ , Paramagnetic
So, correct option is (2).

JEE - 2023

CHXI04:CHEMICAL BONDING AND MOLECULAR STRUCTURE

313727 Which statement is correct about $O_{2}^{+}$ ?

1 Paramagnetic and bond order

< O_{2}

2 Paramagnetic and bond order

> O_{2}

3 Diamagnetic and bond order

< O_{2}

4 Diamagnetic and bond order

> O_{2}

Explanation:

Both $O_{2}^{+}$ and $O_{2}$ are paramagnetic bond order of $O_{2}^{+} = 2.5$ and $O_{2} = 2$

CHXI04:CHEMICAL BONDING AND MOLECULAR STRUCTURE

313767 Match List-I (Molecules) with List-II (Bond order) and select the correct answer using the codes.

Column I	Column II
A. $L i_{2}$	P. $3$
B. $N_{2}$	Q. $1.5$
C. $B e_{2}$	R. $1$
D. $O_{2}$	S. $0$
	T. $2$

1

A - Q, B - R, C - P, D - S

2

A - R, B - P, C - S, D - T

3

A - S, B - P, C - S, D - E

4

A - R, B - Q, C - T, D - P

Explanation:

Bond order $= \frac{1}{2} (N_{b} - N_{a})$
Bond order of ${Li}_{2} = 1, N_{2} = 3, {Be}_{2} = 0, O_{2} = 2$

CHXI04:CHEMICAL BONDING AND MOLECULAR STRUCTURE

313724 Identify a molecule which does not exist.

1

L i_{2}

2

C_{2}

3

O_{2}

4

H e_{2}

Explanation:

$H e_{2}$ does not exist due to zero bond order according to MOT.

NEET - 2020

CHXI04:CHEMICAL BONDING AND MOLECULAR STRUCTURE

313725 The correct order of energies of molecular orbitals of $N_{2}$ molecule, is

1

σ 1s < σ^{*} 1s < σ 2s < σ^{*} 2s < σ 2 p_{z} <

(π 2 p_{x} = π 2 p_{y}) < (π^{*} 2 p_{x} = π^{*} 2 p_{y}) < σ^{*} 2 p_{z}

2

σ 1s < σ^{*} 1s < σ 2s < σ^{*} 2s < σ 2 p_{z} <

σ^{*} 2 p_{z} < (π 2 p_{x} = π 2 p_{y}) < (π^{*} 2 p_{x} = π^{*} 2 p_{y})

3

σ 1 s < σ^{*} 1s < σ 2s < σ^{*} 2s < (π 2 p_{x} = π 2 p_{y}) <

(π^{*} 2 p_{x} = π^{*} 2 p_{y}) < σ 2 p_{z} < σ^{*} 2 p_{z}

4

σ 1s < σ^{*} 1s < σ 2s < σ^{*} 2s < (π 2 p_{x} = π 2 p_{y}) <

σ 2 p_{z} < (π^{*} 2 p_{x} = π^{*} 2 p_{y}) < σ^{*} 2 p_{z}

Explanation:

Molecular orbital (energy) diagram/sequence of $N_{2}$
supporting img

NEET - 2023

CHXI04:CHEMICAL BONDING AND MOLECULAR STRUCTURE

313726 In which of the following processes, the bond order increases and paramagnetic character changes to diamagnetic one?

1

O_{2} \to O_{2}^{+}

2

N O \to N O^{+}

3

O_{2} \to O_{2}^{2 -}

4

N_{2} \to N_{2}^{+}

Explanation:

$O_{2} - 16 e^{-} -$ B.O. $= 2$ , Paramagnetic
$O_{2}^{+} - 15 e^{-} -$ B.O. $= 2.5$ , Paramagnetic
$O_{2}^{2 -} - 18 e^{-} -$ B.O. $= 1$ , Diamagnetic
NO $- 15 e^{-} -$ B.O. $= 2.5$ , Paramagnetic
${NO}^{+} - 14 e^{-} -$ B.O. $= 3$ , Diamagnetic
$N_{2} - 14 e^{-} -$ B.O. $= 3$ , Diamagnetic
$N_{2}^{+} - 13 e^{-} -$ B.O. $= 2.5$ , Paramagnetic
So, correct option is (2).

JEE - 2023

CHXI04:CHEMICAL BONDING AND MOLECULAR STRUCTURE

313727 Which statement is correct about $O_{2}^{+}$ ?

1 Paramagnetic and bond order

< O_{2}

2 Paramagnetic and bond order

> O_{2}

3 Diamagnetic and bond order

< O_{2}

4 Diamagnetic and bond order

> O_{2}

Explanation:

Both $O_{2}^{+}$ and $O_{2}$ are paramagnetic bond order of $O_{2}^{+} = 2.5$ and $O_{2} = 2$