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CHXI04:CHEMICAL BONDING AND MOLECULAR STRUCTURE

313698 The internuclear distances in $O - O$ bonds for $O_{2}^{+}, O_{2}, O_{2}^{-} a n d O_{2}^{2 -}$ respectively are :

1

1 .30 \overset{^{\circ}}{A}, 1 .49 \overset{^{\circ}}{A}, 1 .12 \overset{^{\circ}}{A}, 1 .21 \overset{^{\circ}}{A}

2

1 .49 \overset{^{\circ}}{A}, 1 .21 \overset{^{\circ}}{A}, 1 .49 \overset{^{\circ}}{A}, 1 .30 \overset{^{\circ}}{A}

3

1 .21 \overset{^{\circ}}{A}, 1 .12 \overset{^{\circ}}{A}, 1 .49 \overset{^{\circ}}{A}, 1 .30 \overset{^{\circ}}{A}

4

1 .12 \overset{^{\circ}}{A}, 1 .21 \overset{^{\circ}}{A}, 1 .30 \overset{^{\circ}}{A}, 1 .49 \overset{^{\circ}}{A}

Explanation:

The bond length follows the order
$O_{2}^{+} < O_{2} {< O}_{2}^{-} {< O}_{2}^{2 -}$
According to this the possible values are
$1 .12 \overset{^{\circ}}{A}, 1 .21 \overset{^{\circ}}{A}, 1 .30 \overset{^{\circ}}{A}, 1 .49 \overset{^{\circ}}{A}$

JEE - 2013

CHXI04:CHEMICAL BONDING AND MOLECULAR STRUCTURE

313699 Which of the following is diamagnetic?

1

H_{2}^{+}

2

{H e}_{2}^{+}

3

O_{2}

4

N_{2}

Explanation:

$N_{2} (14) : K K, σ 2 s^{2} σ^{*} 2 s^{2}, {π 2 p}_{x}^{2} {= π 2 p}_{y}^{2}, {σ 2 p}_{z}^{2}$
It does not have any unpaired electrons. Hence, it is diamagnetic.
$H_{2}^{+}$ (1 electron), ${H e}_{2}^{+}$ (3 electrons) and $O_{2}$ (16 electrons) have unpaired $e^{-}$ and are paramagnetic.

CHXI04:CHEMICAL BONDING AND MOLECULAR STRUCTURE

313701 Which of the following is the wrong statement?

1

O N C l a n d O N O^{-}

are not isoelectronic.

2

O_{3}

molecule is bent.

3 Ozone is violet-black in solid state.

4 Ozone is paramagnetic gas.

Explanation:

$(1) \begin{array}{l} O N C l = 8 + 7 + 17 = 32 e^{-} \\ O N O^{-} = 8 + 7 + 8 + 1 = 24 e^{-} \end{array}} n o t i s o e l e c t r o n i c$
(2)
supporting img
The central atom is $s p^{2}$ hybridised with one lone pair.
(3) It is a pale blue gas. At $- 249 {.7}^{\circ},$ it forms violet black crystals.
(4) $O_{3}$ is diamagnetic in nature due to absence of unpaired electrons.

CHXI04:CHEMICAL BONDING AND MOLECULAR STRUCTURE

313702 Which of the following options represents the correct bond order?

1

O_{2}^{-} > O_{2} {> O}_{2}^{+}

2

O_{2}^{-} < O_{2} {< O}_{2}^{+}

3

O_{2}^{-} > O_{2} {< O}_{2}^{+}

4

O_{2}^{-} < O_{2} {> O}_{2}^{+}

Explanation:

Ions B.O.
$O_{2}^{-}$ 1.5
$O_{2}$ 2
$O_{2}^{+}$ 2.5

CHXI04:CHEMICAL BONDING AND MOLECULAR STRUCTURE

313698 The internuclear distances in $O - O$ bonds for $O_{2}^{+}, O_{2}, O_{2}^{-} a n d O_{2}^{2 -}$ respectively are :

1

1 .30 \overset{^{\circ}}{A}, 1 .49 \overset{^{\circ}}{A}, 1 .12 \overset{^{\circ}}{A}, 1 .21 \overset{^{\circ}}{A}

2

1 .49 \overset{^{\circ}}{A}, 1 .21 \overset{^{\circ}}{A}, 1 .49 \overset{^{\circ}}{A}, 1 .30 \overset{^{\circ}}{A}

3

1 .21 \overset{^{\circ}}{A}, 1 .12 \overset{^{\circ}}{A}, 1 .49 \overset{^{\circ}}{A}, 1 .30 \overset{^{\circ}}{A}

4

1 .12 \overset{^{\circ}}{A}, 1 .21 \overset{^{\circ}}{A}, 1 .30 \overset{^{\circ}}{A}, 1 .49 \overset{^{\circ}}{A}

Explanation:

The bond length follows the order
$O_{2}^{+} < O_{2} {< O}_{2}^{-} {< O}_{2}^{2 -}$
According to this the possible values are
$1 .12 \overset{^{\circ}}{A}, 1 .21 \overset{^{\circ}}{A}, 1 .30 \overset{^{\circ}}{A}, 1 .49 \overset{^{\circ}}{A}$

JEE - 2013

CHXI04:CHEMICAL BONDING AND MOLECULAR STRUCTURE

313699 Which of the following is diamagnetic?

1

H_{2}^{+}

2

{H e}_{2}^{+}

3

O_{2}

4

N_{2}

Explanation:

$N_{2} (14) : K K, σ 2 s^{2} σ^{*} 2 s^{2}, {π 2 p}_{x}^{2} {= π 2 p}_{y}^{2}, {σ 2 p}_{z}^{2}$
It does not have any unpaired electrons. Hence, it is diamagnetic.
$H_{2}^{+}$ (1 electron), ${H e}_{2}^{+}$ (3 electrons) and $O_{2}$ (16 electrons) have unpaired $e^{-}$ and are paramagnetic.

CHXI04:CHEMICAL BONDING AND MOLECULAR STRUCTURE

313701 Which of the following is the wrong statement?

1

O N C l a n d O N O^{-}

are not isoelectronic.

2

O_{3}

molecule is bent.

3 Ozone is violet-black in solid state.

4 Ozone is paramagnetic gas.

Explanation:

$(1) \begin{array}{l} O N C l = 8 + 7 + 17 = 32 e^{-} \\ O N O^{-} = 8 + 7 + 8 + 1 = 24 e^{-} \end{array}} n o t i s o e l e c t r o n i c$
(2)
supporting img
The central atom is $s p^{2}$ hybridised with one lone pair.
(3) It is a pale blue gas. At $- 249 {.7}^{\circ},$ it forms violet black crystals.
(4) $O_{3}$ is diamagnetic in nature due to absence of unpaired electrons.

CHXI04:CHEMICAL BONDING AND MOLECULAR STRUCTURE

313702 Which of the following options represents the correct bond order?

1

O_{2}^{-} > O_{2} {> O}_{2}^{+}

2

O_{2}^{-} < O_{2} {< O}_{2}^{+}

3

O_{2}^{-} > O_{2} {< O}_{2}^{+}

4

O_{2}^{-} < O_{2} {> O}_{2}^{+}

Explanation:

Ions B.O.
$O_{2}^{-}$ 1.5
$O_{2}$ 2
$O_{2}^{+}$ 2.5

CHXI04:CHEMICAL BONDING AND MOLECULAR STRUCTURE

313698 The internuclear distances in $O - O$ bonds for $O_{2}^{+}, O_{2}, O_{2}^{-} a n d O_{2}^{2 -}$ respectively are :

1

1 .30 \overset{^{\circ}}{A}, 1 .49 \overset{^{\circ}}{A}, 1 .12 \overset{^{\circ}}{A}, 1 .21 \overset{^{\circ}}{A}

2

1 .49 \overset{^{\circ}}{A}, 1 .21 \overset{^{\circ}}{A}, 1 .49 \overset{^{\circ}}{A}, 1 .30 \overset{^{\circ}}{A}

3

1 .21 \overset{^{\circ}}{A}, 1 .12 \overset{^{\circ}}{A}, 1 .49 \overset{^{\circ}}{A}, 1 .30 \overset{^{\circ}}{A}

4

1 .12 \overset{^{\circ}}{A}, 1 .21 \overset{^{\circ}}{A}, 1 .30 \overset{^{\circ}}{A}, 1 .49 \overset{^{\circ}}{A}

Explanation:

The bond length follows the order
$O_{2}^{+} < O_{2} {< O}_{2}^{-} {< O}_{2}^{2 -}$
According to this the possible values are
$1 .12 \overset{^{\circ}}{A}, 1 .21 \overset{^{\circ}}{A}, 1 .30 \overset{^{\circ}}{A}, 1 .49 \overset{^{\circ}}{A}$

JEE - 2013

CHXI04:CHEMICAL BONDING AND MOLECULAR STRUCTURE

313699 Which of the following is diamagnetic?

1

H_{2}^{+}

2

{H e}_{2}^{+}

3

O_{2}

4

N_{2}

Explanation:

$N_{2} (14) : K K, σ 2 s^{2} σ^{*} 2 s^{2}, {π 2 p}_{x}^{2} {= π 2 p}_{y}^{2}, {σ 2 p}_{z}^{2}$
It does not have any unpaired electrons. Hence, it is diamagnetic.
$H_{2}^{+}$ (1 electron), ${H e}_{2}^{+}$ (3 electrons) and $O_{2}$ (16 electrons) have unpaired $e^{-}$ and are paramagnetic.

CHXI04:CHEMICAL BONDING AND MOLECULAR STRUCTURE

313701 Which of the following is the wrong statement?

1

O N C l a n d O N O^{-}

are not isoelectronic.

2

O_{3}

molecule is bent.

3 Ozone is violet-black in solid state.

4 Ozone is paramagnetic gas.

Explanation:

$(1) \begin{array}{l} O N C l = 8 + 7 + 17 = 32 e^{-} \\ O N O^{-} = 8 + 7 + 8 + 1 = 24 e^{-} \end{array}} n o t i s o e l e c t r o n i c$
(2)
supporting img
The central atom is $s p^{2}$ hybridised with one lone pair.
(3) It is a pale blue gas. At $- 249 {.7}^{\circ},$ it forms violet black crystals.
(4) $O_{3}$ is diamagnetic in nature due to absence of unpaired electrons.

CHXI04:CHEMICAL BONDING AND MOLECULAR STRUCTURE

313702 Which of the following options represents the correct bond order?

1

O_{2}^{-} > O_{2} {> O}_{2}^{+}

2

O_{2}^{-} < O_{2} {< O}_{2}^{+}

3

O_{2}^{-} > O_{2} {< O}_{2}^{+}

4

O_{2}^{-} < O_{2} {> O}_{2}^{+}

Explanation:

Ions B.O.
$O_{2}^{-}$ 1.5
$O_{2}$ 2
$O_{2}^{+}$ 2.5

CHXI04:CHEMICAL BONDING AND MOLECULAR STRUCTURE

313698 The internuclear distances in $O - O$ bonds for $O_{2}^{+}, O_{2}, O_{2}^{-} a n d O_{2}^{2 -}$ respectively are :

1

1 .30 \overset{^{\circ}}{A}, 1 .49 \overset{^{\circ}}{A}, 1 .12 \overset{^{\circ}}{A}, 1 .21 \overset{^{\circ}}{A}

2

1 .49 \overset{^{\circ}}{A}, 1 .21 \overset{^{\circ}}{A}, 1 .49 \overset{^{\circ}}{A}, 1 .30 \overset{^{\circ}}{A}

3

1 .21 \overset{^{\circ}}{A}, 1 .12 \overset{^{\circ}}{A}, 1 .49 \overset{^{\circ}}{A}, 1 .30 \overset{^{\circ}}{A}

4

1 .12 \overset{^{\circ}}{A}, 1 .21 \overset{^{\circ}}{A}, 1 .30 \overset{^{\circ}}{A}, 1 .49 \overset{^{\circ}}{A}

Explanation:

The bond length follows the order
$O_{2}^{+} < O_{2} {< O}_{2}^{-} {< O}_{2}^{2 -}$
According to this the possible values are
$1 .12 \overset{^{\circ}}{A}, 1 .21 \overset{^{\circ}}{A}, 1 .30 \overset{^{\circ}}{A}, 1 .49 \overset{^{\circ}}{A}$

JEE - 2013

CHXI04:CHEMICAL BONDING AND MOLECULAR STRUCTURE

313699 Which of the following is diamagnetic?

1

H_{2}^{+}

2

{H e}_{2}^{+}

3

O_{2}

4

N_{2}

Explanation:

$N_{2} (14) : K K, σ 2 s^{2} σ^{*} 2 s^{2}, {π 2 p}_{x}^{2} {= π 2 p}_{y}^{2}, {σ 2 p}_{z}^{2}$
It does not have any unpaired electrons. Hence, it is diamagnetic.
$H_{2}^{+}$ (1 electron), ${H e}_{2}^{+}$ (3 electrons) and $O_{2}$ (16 electrons) have unpaired $e^{-}$ and are paramagnetic.

CHXI04:CHEMICAL BONDING AND MOLECULAR STRUCTURE

313701 Which of the following is the wrong statement?

1

O N C l a n d O N O^{-}

are not isoelectronic.

2

O_{3}

molecule is bent.

3 Ozone is violet-black in solid state.

4 Ozone is paramagnetic gas.

Explanation:

$(1) \begin{array}{l} O N C l = 8 + 7 + 17 = 32 e^{-} \\ O N O^{-} = 8 + 7 + 8 + 1 = 24 e^{-} \end{array}} n o t i s o e l e c t r o n i c$
(2)
supporting img
The central atom is $s p^{2}$ hybridised with one lone pair.
(3) It is a pale blue gas. At $- 249 {.7}^{\circ},$ it forms violet black crystals.
(4) $O_{3}$ is diamagnetic in nature due to absence of unpaired electrons.

CHXI04:CHEMICAL BONDING AND MOLECULAR STRUCTURE

313702 Which of the following options represents the correct bond order?

1

O_{2}^{-} > O_{2} {> O}_{2}^{+}

2

O_{2}^{-} < O_{2} {< O}_{2}^{+}

3

O_{2}^{-} > O_{2} {< O}_{2}^{+}

4

O_{2}^{-} < O_{2} {> O}_{2}^{+}

Explanation:

Ions B.O.
$O_{2}^{-}$ 1.5
$O_{2}$ 2
$O_{2}^{+}$ 2.5

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