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CHXI02:STRUCTURE OF ATOM

307569 Assertion :
The spectra of $H e^{+}$ is similar to that of $L i^{2 +}$ .
Reason :
Both are positively charged.

1 If both Assertion & Reason are true and reason is the correct explanation of the assertion.

2 If both Assertion & Reason are true but reason is not the correct explanation of the assertion.

3 If Assertion is true statement but Reason is false.

4 Assertion is false but reason is true.

CHXI02:STRUCTURE OF ATOM

307570 The frequency of radiation emitted when the electron falls from $n = 4$ to $n = 1$ in a hydrogen atom will be (Given: ionization energy of $H = 2 .18 \times 1 0^{- 18} J a t o m^{- 1}$ and $h = 6 .625 \times 1 0^{- 34} J s)$

1

1 .03 \times 1 0^{15} s^{- 1}

2

3 .08 \times 1 0^{15} s^{- 1}

3

2 .00 \times 1 0^{15} s^{- 1}

4

1 .54 \times 1 0^{15} s^{- 1}

Explanation:

$E_{1 (H)} = - I . E ._{(H)} = - 2 .18 \times 1 0^{- 18} J a t o m^{- 1}$
$E_{4 (H)} = - \frac{2 .18 \times 1 0^{- 8}}{4^{2}} J$
$Δ E = E_{4} - E_{1} = 2 .18 \times 1 0^{- 18} [\frac{1}{1^{2}} - \frac{1}{4^{2}}] J$
$= 2 .18 \times 1 0^{- 18} \times \frac{15}{16} J .$
$Δ E = h ν$
$ν = \frac{Δ E}{h} = \frac{2 .18 \times 1 0^{- 18} \times 15}{6 .625 \times 1 0^{- 34} \times 16} = 3 .08 \times 1 0^{15} s^{- 1}$

CHXI02:STRUCTURE OF ATOM

307571 Match Column I (Spectral Series for Hydrogen) with Column II (Spectral Region/Higher Energy State).
Column I
Column II
A
Lyman
P
Infrared region
B
Balmer
Q
UV region
C
Paschen
R
Infrared region
D
Pfund
S
Visible region

1

A - Q, B - R, C - P, D - S

2

A - P, B - Q, C - R, D - S

3

A - P, B - R, C - Q, D - S

4

A - Q, B - S, C - R, D - P

JEE Main - 2024

CHXI02:STRUCTURE OF ATOM

307573 Match the type of series given in Column I with the wavelength range given in Column II and choose the correct option
supporting img

1

A - P, B - Q, C - S, D - R

2

A - S, B - R, C - P, D - Q

3

A - R, B - P, C - Q, D - S

4

A - S, B - R, C - Q, D - P

Explanation:

The correct match is
(A) $\to$ Lyman $\to$ (P) $\to$ Ultraviolet
$(B) \to P a s c h e n \to (Q) \to N e a r i n f r a r e d$
(C) $\to$ Balmer $\to$ (S) $\to$ Visible
(D) $\to$ Pfund $\to$ (R) $\to$ Far infrared

CHXI02:STRUCTURE OF ATOM

307569 Assertion :
The spectra of $H e^{+}$ is similar to that of $L i^{2 +}$ .
Reason :
Both are positively charged.

1 If both Assertion & Reason are true and reason is the correct explanation of the assertion.

2 If both Assertion & Reason are true but reason is not the correct explanation of the assertion.

3 If Assertion is true statement but Reason is false.

4 Assertion is false but reason is true.

CHXI02:STRUCTURE OF ATOM

307570 The frequency of radiation emitted when the electron falls from $n = 4$ to $n = 1$ in a hydrogen atom will be (Given: ionization energy of $H = 2 .18 \times 1 0^{- 18} J a t o m^{- 1}$ and $h = 6 .625 \times 1 0^{- 34} J s)$

1

1 .03 \times 1 0^{15} s^{- 1}

2

3 .08 \times 1 0^{15} s^{- 1}

3

2 .00 \times 1 0^{15} s^{- 1}

4

1 .54 \times 1 0^{15} s^{- 1}

Explanation:

$E_{1 (H)} = - I . E ._{(H)} = - 2 .18 \times 1 0^{- 18} J a t o m^{- 1}$
$E_{4 (H)} = - \frac{2 .18 \times 1 0^{- 8}}{4^{2}} J$
$Δ E = E_{4} - E_{1} = 2 .18 \times 1 0^{- 18} [\frac{1}{1^{2}} - \frac{1}{4^{2}}] J$
$= 2 .18 \times 1 0^{- 18} \times \frac{15}{16} J .$
$Δ E = h ν$
$ν = \frac{Δ E}{h} = \frac{2 .18 \times 1 0^{- 18} \times 15}{6 .625 \times 1 0^{- 34} \times 16} = 3 .08 \times 1 0^{15} s^{- 1}$

CHXI02:STRUCTURE OF ATOM

307571 Match Column I (Spectral Series for Hydrogen) with Column II (Spectral Region/Higher Energy State).
Column I
Column II
A
Lyman
P
Infrared region
B
Balmer
Q
UV region
C
Paschen
R
Infrared region
D
Pfund
S
Visible region

1

A - Q, B - R, C - P, D - S

2

A - P, B - Q, C - R, D - S

3

A - P, B - R, C - Q, D - S

4

A - Q, B - S, C - R, D - P

JEE Main - 2024

CHXI02:STRUCTURE OF ATOM

307573 Match the type of series given in Column I with the wavelength range given in Column II and choose the correct option
supporting img

1

A - P, B - Q, C - S, D - R

2

A - S, B - R, C - P, D - Q

3

A - R, B - P, C - Q, D - S

4

A - S, B - R, C - Q, D - P

Explanation:

The correct match is
(A) $\to$ Lyman $\to$ (P) $\to$ Ultraviolet
$(B) \to P a s c h e n \to (Q) \to N e a r i n f r a r e d$
(C) $\to$ Balmer $\to$ (S) $\to$ Visible
(D) $\to$ Pfund $\to$ (R) $\to$ Far infrared

CHXI02:STRUCTURE OF ATOM

307569 Assertion :
The spectra of $H e^{+}$ is similar to that of $L i^{2 +}$ .
Reason :
Both are positively charged.

1 If both Assertion & Reason are true and reason is the correct explanation of the assertion.

2 If both Assertion & Reason are true but reason is not the correct explanation of the assertion.

3 If Assertion is true statement but Reason is false.

4 Assertion is false but reason is true.

CHXI02:STRUCTURE OF ATOM

307570 The frequency of radiation emitted when the electron falls from $n = 4$ to $n = 1$ in a hydrogen atom will be (Given: ionization energy of $H = 2 .18 \times 1 0^{- 18} J a t o m^{- 1}$ and $h = 6 .625 \times 1 0^{- 34} J s)$

1

1 .03 \times 1 0^{15} s^{- 1}

2

3 .08 \times 1 0^{15} s^{- 1}

3

2 .00 \times 1 0^{15} s^{- 1}

4

1 .54 \times 1 0^{15} s^{- 1}

Explanation:

$E_{1 (H)} = - I . E ._{(H)} = - 2 .18 \times 1 0^{- 18} J a t o m^{- 1}$
$E_{4 (H)} = - \frac{2 .18 \times 1 0^{- 8}}{4^{2}} J$
$Δ E = E_{4} - E_{1} = 2 .18 \times 1 0^{- 18} [\frac{1}{1^{2}} - \frac{1}{4^{2}}] J$
$= 2 .18 \times 1 0^{- 18} \times \frac{15}{16} J .$
$Δ E = h ν$
$ν = \frac{Δ E}{h} = \frac{2 .18 \times 1 0^{- 18} \times 15}{6 .625 \times 1 0^{- 34} \times 16} = 3 .08 \times 1 0^{15} s^{- 1}$

CHXI02:STRUCTURE OF ATOM

307571 Match Column I (Spectral Series for Hydrogen) with Column II (Spectral Region/Higher Energy State).
Column I
Column II
A
Lyman
P
Infrared region
B
Balmer
Q
UV region
C
Paschen
R
Infrared region
D
Pfund
S
Visible region

1

A - Q, B - R, C - P, D - S

2

A - P, B - Q, C - R, D - S

3

A - P, B - R, C - Q, D - S

4

A - Q, B - S, C - R, D - P

JEE Main - 2024

CHXI02:STRUCTURE OF ATOM

307573 Match the type of series given in Column I with the wavelength range given in Column II and choose the correct option
supporting img

1

A - P, B - Q, C - S, D - R

2

A - S, B - R, C - P, D - Q

3

A - R, B - P, C - Q, D - S

4

A - S, B - R, C - Q, D - P

Explanation:

The correct match is
(A) $\to$ Lyman $\to$ (P) $\to$ Ultraviolet
$(B) \to P a s c h e n \to (Q) \to N e a r i n f r a r e d$
(C) $\to$ Balmer $\to$ (S) $\to$ Visible
(D) $\to$ Pfund $\to$ (R) $\to$ Far infrared

CHXI02:STRUCTURE OF ATOM

307569 Assertion :
The spectra of $H e^{+}$ is similar to that of $L i^{2 +}$ .
Reason :
Both are positively charged.

1 If both Assertion & Reason are true and reason is the correct explanation of the assertion.

2 If both Assertion & Reason are true but reason is not the correct explanation of the assertion.

3 If Assertion is true statement but Reason is false.

4 Assertion is false but reason is true.

CHXI02:STRUCTURE OF ATOM

307570 The frequency of radiation emitted when the electron falls from $n = 4$ to $n = 1$ in a hydrogen atom will be (Given: ionization energy of $H = 2 .18 \times 1 0^{- 18} J a t o m^{- 1}$ and $h = 6 .625 \times 1 0^{- 34} J s)$

1

1 .03 \times 1 0^{15} s^{- 1}

2

3 .08 \times 1 0^{15} s^{- 1}

3

2 .00 \times 1 0^{15} s^{- 1}

4

1 .54 \times 1 0^{15} s^{- 1}

Explanation:

$E_{1 (H)} = - I . E ._{(H)} = - 2 .18 \times 1 0^{- 18} J a t o m^{- 1}$
$E_{4 (H)} = - \frac{2 .18 \times 1 0^{- 8}}{4^{2}} J$
$Δ E = E_{4} - E_{1} = 2 .18 \times 1 0^{- 18} [\frac{1}{1^{2}} - \frac{1}{4^{2}}] J$
$= 2 .18 \times 1 0^{- 18} \times \frac{15}{16} J .$
$Δ E = h ν$
$ν = \frac{Δ E}{h} = \frac{2 .18 \times 1 0^{- 18} \times 15}{6 .625 \times 1 0^{- 34} \times 16} = 3 .08 \times 1 0^{15} s^{- 1}$

CHXI02:STRUCTURE OF ATOM

307571 Match Column I (Spectral Series for Hydrogen) with Column II (Spectral Region/Higher Energy State).
Column I
Column II
A
Lyman
P
Infrared region
B
Balmer
Q
UV region
C
Paschen
R
Infrared region
D
Pfund
S
Visible region

1

A - Q, B - R, C - P, D - S

2

A - P, B - Q, C - R, D - S

3

A - P, B - R, C - Q, D - S

4

A - Q, B - S, C - R, D - P

JEE Main - 2024

CHXI02:STRUCTURE OF ATOM

307573 Match the type of series given in Column I with the wavelength range given in Column II and choose the correct option
supporting img

1

A - P, B - Q, C - S, D - R

2

A - S, B - R, C - P, D - Q

3

A - R, B - P, C - Q, D - S

4

A - S, B - R, C - Q, D - P

Explanation:

The correct match is
(A) $\to$ Lyman $\to$ (P) $\to$ Ultraviolet
$(B) \to P a s c h e n \to (Q) \to N e a r i n f r a r e d$
(C) $\to$ Balmer $\to$ (S) $\to$ Visible
(D) $\to$ Pfund $\to$ (R) $\to$ Far infrared

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