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CHXI02:STRUCTURE OF ATOM

307214 If velocity of an electron in the first Bohr orbit of H is $v_{1}$ then velocity in second orbit will be

1

v_{1}

2 2

v_{1}

3

\frac{v_{1}}{2}

4

\frac{v_{1}}{4}

Explanation:

We know that,
$v_{n} = v_{0} \times \frac{Z}{n} \begin{array}{r} (w h e r e, v_{0} = v e l o c i t y o f a n \\ e l e c t r o n i n f i r s t B o h r o r b i t) \end{array}$
$G i v e n, v_{0} = v_{1}$
$\Rightarrow v_{2} = v_{1} \times \frac{1}{2} \Rightarrow v_{2} = \frac{v_{1}}{2}$

CHXI02:STRUCTURE OF ATOM

307215 The velocity of an electron in the third orbit of hydrogen atom

1

7 .28 \times 1 0^{7} c m s e c^{- 1}

2

6 .08 \times 1 0^{7} c m s e c^{- 1}

3

9 .38 \times 1 0^{7} c m s e c^{- 1}

4

7 .48 \times 1 0^{6} c m s e c^{- 1}

Explanation:

$u_{n} = \frac{2 .18 \times 1 0^{8} c m / s}{n}$
$\Rightarrow u_{3} = \frac{2 .18 \times 1 0^{8} c m / s}{3}$
$= 7 .27 \times 1 0^{7} c m / s$

CHXI02:STRUCTURE OF ATOM

307216 The velocity of an electron revolving in the second orbit of a hydrogen atom is

1

2 .19 \times 1 0^{8} c m / s

2

1 .095 \times 1 0^{8} c m . s

3

2 .19 \times 1 0^{8} m / s

4

1 .095 \times 1 0^{8} m / s

Explanation:

$u_{n} = \frac{2 .18 \times 1 0^{8} c m / s}{n}$
$u_{2} = \frac{2 .18 \times 1 0^{8} c m / s}{2} (n = 2)$
$= 1 .09 \times 1 0^{8} c m / s$

CHXI02:STRUCTURE OF ATOM

307217 If velocity of an electron in first orbit of $H$ atom is $V$ , what will be the velocity of the third orbit of $L i^{+ 2}$ ?

1

V

2

V / 3

3

3 V

4

9 V

Explanation:

$V = 2 .188 \times 1 0^{6} \frac{z}{n} m / s$
Now, $V \propto \frac{z}{n}$
so, $\frac{V_{L i^{2 +}}}{V_{H}} = \frac{Z_{1} / H_{1}}{Z_{2} / H_{2}} = \frac{3 / 3}{1 / 1} = 1$
or, $V_{L i^{2 +}} = V_{H}$

CHXI02:STRUCTURE OF ATOM

307214 If velocity of an electron in the first Bohr orbit of H is $v_{1}$ then velocity in second orbit will be

1

v_{1}

2 2

v_{1}

3

\frac{v_{1}}{2}

4

\frac{v_{1}}{4}

Explanation:

We know that,
$v_{n} = v_{0} \times \frac{Z}{n} \begin{array}{r} (w h e r e, v_{0} = v e l o c i t y o f a n \\ e l e c t r o n i n f i r s t B o h r o r b i t) \end{array}$
$G i v e n, v_{0} = v_{1}$
$\Rightarrow v_{2} = v_{1} \times \frac{1}{2} \Rightarrow v_{2} = \frac{v_{1}}{2}$

CHXI02:STRUCTURE OF ATOM

307215 The velocity of an electron in the third orbit of hydrogen atom

1

7 .28 \times 1 0^{7} c m s e c^{- 1}

2

6 .08 \times 1 0^{7} c m s e c^{- 1}

3

9 .38 \times 1 0^{7} c m s e c^{- 1}

4

7 .48 \times 1 0^{6} c m s e c^{- 1}

Explanation:

$u_{n} = \frac{2 .18 \times 1 0^{8} c m / s}{n}$
$\Rightarrow u_{3} = \frac{2 .18 \times 1 0^{8} c m / s}{3}$
$= 7 .27 \times 1 0^{7} c m / s$

CHXI02:STRUCTURE OF ATOM

307216 The velocity of an electron revolving in the second orbit of a hydrogen atom is

1

2 .19 \times 1 0^{8} c m / s

2

1 .095 \times 1 0^{8} c m . s

3

2 .19 \times 1 0^{8} m / s

4

1 .095 \times 1 0^{8} m / s

Explanation:

$u_{n} = \frac{2 .18 \times 1 0^{8} c m / s}{n}$
$u_{2} = \frac{2 .18 \times 1 0^{8} c m / s}{2} (n = 2)$
$= 1 .09 \times 1 0^{8} c m / s$

CHXI02:STRUCTURE OF ATOM

307217 If velocity of an electron in first orbit of $H$ atom is $V$ , what will be the velocity of the third orbit of $L i^{+ 2}$ ?

1

V

2

V / 3

3

3 V

4

9 V

Explanation:

$V = 2 .188 \times 1 0^{6} \frac{z}{n} m / s$
Now, $V \propto \frac{z}{n}$
so, $\frac{V_{L i^{2 +}}}{V_{H}} = \frac{Z_{1} / H_{1}}{Z_{2} / H_{2}} = \frac{3 / 3}{1 / 1} = 1$
or, $V_{L i^{2 +}} = V_{H}$

CHXI02:STRUCTURE OF ATOM

307214 If velocity of an electron in the first Bohr orbit of H is $v_{1}$ then velocity in second orbit will be

1

v_{1}

2 2

v_{1}

3

\frac{v_{1}}{2}

4

\frac{v_{1}}{4}

Explanation:

We know that,
$v_{n} = v_{0} \times \frac{Z}{n} \begin{array}{r} (w h e r e, v_{0} = v e l o c i t y o f a n \\ e l e c t r o n i n f i r s t B o h r o r b i t) \end{array}$
$G i v e n, v_{0} = v_{1}$
$\Rightarrow v_{2} = v_{1} \times \frac{1}{2} \Rightarrow v_{2} = \frac{v_{1}}{2}$

CHXI02:STRUCTURE OF ATOM

307215 The velocity of an electron in the third orbit of hydrogen atom

1

7 .28 \times 1 0^{7} c m s e c^{- 1}

2

6 .08 \times 1 0^{7} c m s e c^{- 1}

3

9 .38 \times 1 0^{7} c m s e c^{- 1}

4

7 .48 \times 1 0^{6} c m s e c^{- 1}

Explanation:

$u_{n} = \frac{2 .18 \times 1 0^{8} c m / s}{n}$
$\Rightarrow u_{3} = \frac{2 .18 \times 1 0^{8} c m / s}{3}$
$= 7 .27 \times 1 0^{7} c m / s$

CHXI02:STRUCTURE OF ATOM

307216 The velocity of an electron revolving in the second orbit of a hydrogen atom is

1

2 .19 \times 1 0^{8} c m / s

2

1 .095 \times 1 0^{8} c m . s

3

2 .19 \times 1 0^{8} m / s

4

1 .095 \times 1 0^{8} m / s

Explanation:

$u_{n} = \frac{2 .18 \times 1 0^{8} c m / s}{n}$
$u_{2} = \frac{2 .18 \times 1 0^{8} c m / s}{2} (n = 2)$
$= 1 .09 \times 1 0^{8} c m / s$

CHXI02:STRUCTURE OF ATOM

307217 If velocity of an electron in first orbit of $H$ atom is $V$ , what will be the velocity of the third orbit of $L i^{+ 2}$ ?

1

V

2

V / 3

3

3 V

4

9 V

Explanation:

$V = 2 .188 \times 1 0^{6} \frac{z}{n} m / s$
Now, $V \propto \frac{z}{n}$
so, $\frac{V_{L i^{2 +}}}{V_{H}} = \frac{Z_{1} / H_{1}}{Z_{2} / H_{2}} = \frac{3 / 3}{1 / 1} = 1$
or, $V_{L i^{2 +}} = V_{H}$

CHXI02:STRUCTURE OF ATOM

307214 If velocity of an electron in the first Bohr orbit of H is $v_{1}$ then velocity in second orbit will be

1

v_{1}

2 2

v_{1}

3

\frac{v_{1}}{2}

4

\frac{v_{1}}{4}

Explanation:

We know that,
$v_{n} = v_{0} \times \frac{Z}{n} \begin{array}{r} (w h e r e, v_{0} = v e l o c i t y o f a n \\ e l e c t r o n i n f i r s t B o h r o r b i t) \end{array}$
$G i v e n, v_{0} = v_{1}$
$\Rightarrow v_{2} = v_{1} \times \frac{1}{2} \Rightarrow v_{2} = \frac{v_{1}}{2}$

CHXI02:STRUCTURE OF ATOM

307215 The velocity of an electron in the third orbit of hydrogen atom

1

7 .28 \times 1 0^{7} c m s e c^{- 1}

2

6 .08 \times 1 0^{7} c m s e c^{- 1}

3

9 .38 \times 1 0^{7} c m s e c^{- 1}

4

7 .48 \times 1 0^{6} c m s e c^{- 1}

Explanation:

$u_{n} = \frac{2 .18 \times 1 0^{8} c m / s}{n}$
$\Rightarrow u_{3} = \frac{2 .18 \times 1 0^{8} c m / s}{3}$
$= 7 .27 \times 1 0^{7} c m / s$

CHXI02:STRUCTURE OF ATOM

307216 The velocity of an electron revolving in the second orbit of a hydrogen atom is

1

2 .19 \times 1 0^{8} c m / s

2

1 .095 \times 1 0^{8} c m . s

3

2 .19 \times 1 0^{8} m / s

4

1 .095 \times 1 0^{8} m / s

Explanation:

$u_{n} = \frac{2 .18 \times 1 0^{8} c m / s}{n}$
$u_{2} = \frac{2 .18 \times 1 0^{8} c m / s}{2} (n = 2)$
$= 1 .09 \times 1 0^{8} c m / s$

CHXI02:STRUCTURE OF ATOM

307217 If velocity of an electron in first orbit of $H$ atom is $V$ , what will be the velocity of the third orbit of $L i^{+ 2}$ ?

1

V

2

V / 3

3

3 V

4

9 V

Explanation:

$V = 2 .188 \times 1 0^{6} \frac{z}{n} m / s$
Now, $V \propto \frac{z}{n}$
so, $\frac{V_{L i^{2 +}}}{V_{H}} = \frac{Z_{1} / H_{1}}{Z_{2} / H_{2}} = \frac{3 / 3}{1 / 1} = 1$
or, $V_{L i^{2 +}} = V_{H}$