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CHXI02:STRUCTURE OF ATOM

307201 The radius of the $2^{nd}$ orbit of ${Li}^{2 +}$ is x. The expected radius of the $3^{rd}$ orbit of ${Be}^{3 +}$ is

1

\frac{4}{9} x

2

\frac{16}{27} x

3

\frac{9}{4} x

4

\frac{27}{16} x

Explanation:

Radius of $2^{nd}$ orbit of ${Li}^{2 +} = \frac{n^{2}}{Z} \times r_{0}$
$x = \frac{2 \times 2}{3} \times r_{0} \Rightarrow r_{0} = \frac{3 x}{4}$
Radius of $3^{rd}$ orbit of $B^{+ 3} = \frac{n^{2}}{Z}$ . $r_{o}$
$= \frac{3 \times 3}{4} \times \frac{3 x}{4} = \frac{27}{16} x$

JEE - 2023

CHXI02:STRUCTURE OF ATOM

307202 The radius of second stationary orbit in Bohr’s atom is R. The radius of 3rd orbit will be

1

9 R

2

\frac{R}{4}

3

\frac{9 R}{4}

4

2 R

Explanation:

$r α n^{2}$
$\frac{r_{2}}{r_{1}} = \frac{{(2)}^{2}}{{(3)}^{3}}$
$\frac{R}{r_{3}} = \frac{4}{9}$
$r_{3} = \frac{9 R}{4}$

CHXI02:STRUCTURE OF ATOM

307203 The radius of the first orbit of hydrogen atom is $0.52 \times 10^{- 8} cm$ . The radius of the first orbit of ${He}^{+}$ ion is

1

0.26 \times 10^{- 8} cm

2

0.52 \times 10^{- 8} cm

3

1.04 \times 10^{- 8} cm

4

2.08 \times 10^{- 8} cm

Explanation:

$r_{n} = 0 .52 \times \frac{n^{2}}{Z}$ $A^{\circ}$
for $He, n = 1; Z = 2$
$= (0.52 \times \frac{1^{2}}{2}) \overset{\circ}{A} = 0.26 A = 0.26 \times 10^{- 8} cm$ .

CHXI02:STRUCTURE OF ATOM

307204 On the basis of Bohr’s model, the radius of the $5^{t h}$ orbit is

1 Equal to the radius of first orbit

2 Three times the radius of first orbit

3 Five times the radius of first orbit

4 25 times the radius of first orbit

Explanation:

$r_{n} α n^{2}$
$\frac{r_{5}}{r_{1}} = \frac{5^{2}}{1} = 25$
$∴$ $r_{5} = 25 r_{1}$

CHXI02:STRUCTURE OF ATOM

307201 The radius of the $2^{nd}$ orbit of ${Li}^{2 +}$ is x. The expected radius of the $3^{rd}$ orbit of ${Be}^{3 +}$ is

1

\frac{4}{9} x

2

\frac{16}{27} x

3

\frac{9}{4} x

4

\frac{27}{16} x

Explanation:

Radius of $2^{nd}$ orbit of ${Li}^{2 +} = \frac{n^{2}}{Z} \times r_{0}$
$x = \frac{2 \times 2}{3} \times r_{0} \Rightarrow r_{0} = \frac{3 x}{4}$
Radius of $3^{rd}$ orbit of $B^{+ 3} = \frac{n^{2}}{Z}$ . $r_{o}$
$= \frac{3 \times 3}{4} \times \frac{3 x}{4} = \frac{27}{16} x$

JEE - 2023

CHXI02:STRUCTURE OF ATOM

307202 The radius of second stationary orbit in Bohr’s atom is R. The radius of 3rd orbit will be

1

9 R

2

\frac{R}{4}

3

\frac{9 R}{4}

4

2 R

Explanation:

$r α n^{2}$
$\frac{r_{2}}{r_{1}} = \frac{{(2)}^{2}}{{(3)}^{3}}$
$\frac{R}{r_{3}} = \frac{4}{9}$
$r_{3} = \frac{9 R}{4}$

CHXI02:STRUCTURE OF ATOM

307203 The radius of the first orbit of hydrogen atom is $0.52 \times 10^{- 8} cm$ . The radius of the first orbit of ${He}^{+}$ ion is

1

0.26 \times 10^{- 8} cm

2

0.52 \times 10^{- 8} cm

3

1.04 \times 10^{- 8} cm

4

2.08 \times 10^{- 8} cm

Explanation:

$r_{n} = 0 .52 \times \frac{n^{2}}{Z}$ $A^{\circ}$
for $He, n = 1; Z = 2$
$= (0.52 \times \frac{1^{2}}{2}) \overset{\circ}{A} = 0.26 A = 0.26 \times 10^{- 8} cm$ .

CHXI02:STRUCTURE OF ATOM

307204 On the basis of Bohr’s model, the radius of the $5^{t h}$ orbit is

1 Equal to the radius of first orbit

2 Three times the radius of first orbit

3 Five times the radius of first orbit

4 25 times the radius of first orbit

Explanation:

$r_{n} α n^{2}$
$\frac{r_{5}}{r_{1}} = \frac{5^{2}}{1} = 25$
$∴$ $r_{5} = 25 r_{1}$

CHXI02:STRUCTURE OF ATOM

307201 The radius of the $2^{nd}$ orbit of ${Li}^{2 +}$ is x. The expected radius of the $3^{rd}$ orbit of ${Be}^{3 +}$ is

1

\frac{4}{9} x

2

\frac{16}{27} x

3

\frac{9}{4} x

4

\frac{27}{16} x

Explanation:

Radius of $2^{nd}$ orbit of ${Li}^{2 +} = \frac{n^{2}}{Z} \times r_{0}$
$x = \frac{2 \times 2}{3} \times r_{0} \Rightarrow r_{0} = \frac{3 x}{4}$
Radius of $3^{rd}$ orbit of $B^{+ 3} = \frac{n^{2}}{Z}$ . $r_{o}$
$= \frac{3 \times 3}{4} \times \frac{3 x}{4} = \frac{27}{16} x$

JEE - 2023

CHXI02:STRUCTURE OF ATOM

307202 The radius of second stationary orbit in Bohr’s atom is R. The radius of 3rd orbit will be

1

9 R

2

\frac{R}{4}

3

\frac{9 R}{4}

4

2 R

Explanation:

$r α n^{2}$
$\frac{r_{2}}{r_{1}} = \frac{{(2)}^{2}}{{(3)}^{3}}$
$\frac{R}{r_{3}} = \frac{4}{9}$
$r_{3} = \frac{9 R}{4}$

CHXI02:STRUCTURE OF ATOM

307203 The radius of the first orbit of hydrogen atom is $0.52 \times 10^{- 8} cm$ . The radius of the first orbit of ${He}^{+}$ ion is

1

0.26 \times 10^{- 8} cm

2

0.52 \times 10^{- 8} cm

3

1.04 \times 10^{- 8} cm

4

2.08 \times 10^{- 8} cm

Explanation:

$r_{n} = 0 .52 \times \frac{n^{2}}{Z}$ $A^{\circ}$
for $He, n = 1; Z = 2$
$= (0.52 \times \frac{1^{2}}{2}) \overset{\circ}{A} = 0.26 A = 0.26 \times 10^{- 8} cm$ .

CHXI02:STRUCTURE OF ATOM

307204 On the basis of Bohr’s model, the radius of the $5^{t h}$ orbit is

1 Equal to the radius of first orbit

2 Three times the radius of first orbit

3 Five times the radius of first orbit

4 25 times the radius of first orbit

Explanation:

$r_{n} α n^{2}$
$\frac{r_{5}}{r_{1}} = \frac{5^{2}}{1} = 25$
$∴$ $r_{5} = 25 r_{1}$

CHXI02:STRUCTURE OF ATOM

307201 The radius of the $2^{nd}$ orbit of ${Li}^{2 +}$ is x. The expected radius of the $3^{rd}$ orbit of ${Be}^{3 +}$ is

1

\frac{4}{9} x

2

\frac{16}{27} x

3

\frac{9}{4} x

4

\frac{27}{16} x

Explanation:

Radius of $2^{nd}$ orbit of ${Li}^{2 +} = \frac{n^{2}}{Z} \times r_{0}$
$x = \frac{2 \times 2}{3} \times r_{0} \Rightarrow r_{0} = \frac{3 x}{4}$
Radius of $3^{rd}$ orbit of $B^{+ 3} = \frac{n^{2}}{Z}$ . $r_{o}$
$= \frac{3 \times 3}{4} \times \frac{3 x}{4} = \frac{27}{16} x$

JEE - 2023

CHXI02:STRUCTURE OF ATOM

307202 The radius of second stationary orbit in Bohr’s atom is R. The radius of 3rd orbit will be

1

9 R

2

\frac{R}{4}

3

\frac{9 R}{4}

4

2 R

Explanation:

$r α n^{2}$
$\frac{r_{2}}{r_{1}} = \frac{{(2)}^{2}}{{(3)}^{3}}$
$\frac{R}{r_{3}} = \frac{4}{9}$
$r_{3} = \frac{9 R}{4}$

CHXI02:STRUCTURE OF ATOM

307203 The radius of the first orbit of hydrogen atom is $0.52 \times 10^{- 8} cm$ . The radius of the first orbit of ${He}^{+}$ ion is

1

0.26 \times 10^{- 8} cm

2

0.52 \times 10^{- 8} cm

3

1.04 \times 10^{- 8} cm

4

2.08 \times 10^{- 8} cm

Explanation:

$r_{n} = 0 .52 \times \frac{n^{2}}{Z}$ $A^{\circ}$
for $He, n = 1; Z = 2$
$= (0.52 \times \frac{1^{2}}{2}) \overset{\circ}{A} = 0.26 A = 0.26 \times 10^{- 8} cm$ .

CHXI02:STRUCTURE OF ATOM

307204 On the basis of Bohr’s model, the radius of the $5^{t h}$ orbit is

1 Equal to the radius of first orbit

2 Three times the radius of first orbit

3 Five times the radius of first orbit

4 25 times the radius of first orbit

Explanation:

$r_{n} α n^{2}$
$\frac{r_{5}}{r_{1}} = \frac{5^{2}}{1} = 25$
$∴$ $r_{5} = 25 r_{1}$

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