306880 Assertion :
Equivalent weight of a compound differs in different reactions.
Reason :
Equivalent weight \(=\dfrac{\text { Molecular weight }}{\text { No. of electrons involved }}\)

306881 The mass of a metal, with equivalent mass 31.75 which would combine with 8 g of oxygen is

306882 For the reaction, \({{\rm{N}}_{\rm{2}}}{\rm{(g) + 3}}{{\rm{H}}_{\rm{2}}}{\rm{(g)}} \to {\rm{2N}}{{\rm{H}}^{\rm{3}}}{\rm{(g)}}\), if molecular masses of \({\rm{N}}{{\rm{H}}_{\rm{3}}}{\mkern 1mu} {\mkern 1mu} {\rm{and}}{\mkern 1mu} {\mkern 1mu} {{\rm{N}}_{\rm{2}}}\) are \({{\rm{M}}_{\rm{1}}}{\mkern 1mu} {\mkern 1mu} {\rm{and}}{\mkern 1mu} {\mkern 1mu} {{\rm{M}}_{\rm{2}}}\), their equivalent weights are \({{\rm{E}}_{\rm{1}}}{\mkern 1mu} {\mkern 1mu} {\rm{and}}{\mkern 1mu} {\mkern 1mu} {{\rm{E}}_{\rm{2}}}\) then \({{\rm{E}}_{\rm{1}}}{\rm{ - }}{{\rm{E}}_{\rm{2}}}\) is

306883 The equivalent mass of a certain bivalent metal is 20. The molecular mass of its anhydrous chloride is

306880 Assertion :
Equivalent weight of a compound differs in different reactions.
Reason :
Equivalent weight \(=\dfrac{\text { Molecular weight }}{\text { No. of electrons involved }}\)

306881 The mass of a metal, with equivalent mass 31.75 which would combine with 8 g of oxygen is

306882 For the reaction, \({{\rm{N}}_{\rm{2}}}{\rm{(g) + 3}}{{\rm{H}}_{\rm{2}}}{\rm{(g)}} \to {\rm{2N}}{{\rm{H}}^{\rm{3}}}{\rm{(g)}}\), if molecular masses of \({\rm{N}}{{\rm{H}}_{\rm{3}}}{\mkern 1mu} {\mkern 1mu} {\rm{and}}{\mkern 1mu} {\mkern 1mu} {{\rm{N}}_{\rm{2}}}\) are \({{\rm{M}}_{\rm{1}}}{\mkern 1mu} {\mkern 1mu} {\rm{and}}{\mkern 1mu} {\mkern 1mu} {{\rm{M}}_{\rm{2}}}\), their equivalent weights are \({{\rm{E}}_{\rm{1}}}{\mkern 1mu} {\mkern 1mu} {\rm{and}}{\mkern 1mu} {\mkern 1mu} {{\rm{E}}_{\rm{2}}}\) then \({{\rm{E}}_{\rm{1}}}{\rm{ - }}{{\rm{E}}_{\rm{2}}}\) is

306883 The equivalent mass of a certain bivalent metal is 20. The molecular mass of its anhydrous chloride is

306880 Assertion :
Equivalent weight of a compound differs in different reactions.
Reason :
Equivalent weight \(=\dfrac{\text { Molecular weight }}{\text { No. of electrons involved }}\)

306881 The mass of a metal, with equivalent mass 31.75 which would combine with 8 g of oxygen is

306882 For the reaction, \({{\rm{N}}_{\rm{2}}}{\rm{(g) + 3}}{{\rm{H}}_{\rm{2}}}{\rm{(g)}} \to {\rm{2N}}{{\rm{H}}^{\rm{3}}}{\rm{(g)}}\), if molecular masses of \({\rm{N}}{{\rm{H}}_{\rm{3}}}{\mkern 1mu} {\mkern 1mu} {\rm{and}}{\mkern 1mu} {\mkern 1mu} {{\rm{N}}_{\rm{2}}}\) are \({{\rm{M}}_{\rm{1}}}{\mkern 1mu} {\mkern 1mu} {\rm{and}}{\mkern 1mu} {\mkern 1mu} {{\rm{M}}_{\rm{2}}}\), their equivalent weights are \({{\rm{E}}_{\rm{1}}}{\mkern 1mu} {\mkern 1mu} {\rm{and}}{\mkern 1mu} {\mkern 1mu} {{\rm{E}}_{\rm{2}}}\) then \({{\rm{E}}_{\rm{1}}}{\rm{ - }}{{\rm{E}}_{\rm{2}}}\) is

306883 The equivalent mass of a certain bivalent metal is 20. The molecular mass of its anhydrous chloride is

306880 Assertion :
Equivalent weight of a compound differs in different reactions.
Reason :
Equivalent weight \(=\dfrac{\text { Molecular weight }}{\text { No. of electrons involved }}\)

306881 The mass of a metal, with equivalent mass 31.75 which would combine with 8 g of oxygen is

306882 For the reaction, \({{\rm{N}}_{\rm{2}}}{\rm{(g) + 3}}{{\rm{H}}_{\rm{2}}}{\rm{(g)}} \to {\rm{2N}}{{\rm{H}}^{\rm{3}}}{\rm{(g)}}\), if molecular masses of \({\rm{N}}{{\rm{H}}_{\rm{3}}}{\mkern 1mu} {\mkern 1mu} {\rm{and}}{\mkern 1mu} {\mkern 1mu} {{\rm{N}}_{\rm{2}}}\) are \({{\rm{M}}_{\rm{1}}}{\mkern 1mu} {\mkern 1mu} {\rm{and}}{\mkern 1mu} {\mkern 1mu} {{\rm{M}}_{\rm{2}}}\), their equivalent weights are \({{\rm{E}}_{\rm{1}}}{\mkern 1mu} {\mkern 1mu} {\rm{and}}{\mkern 1mu} {\mkern 1mu} {{\rm{E}}_{\rm{2}}}\) then \({{\rm{E}}_{\rm{1}}}{\rm{ - }}{{\rm{E}}_{\rm{2}}}\) is

306883 The equivalent mass of a certain bivalent metal is 20. The molecular mass of its anhydrous chloride is