306855 10 mL of 0.02 M \({\rm{KMn}}{{\rm{O}}_{\rm{4}}}\) is required to oxidise 20 ml of oxalic acid of certain strength. 25 ml of the same oxalic acid is required to neutralise 20 ml of NaOH of unknown strength. Find the amount of NaOH in a litre of the solution
(Molecular weight of NaOH = 40):

306856 A metal oxide has the formula \(\mathrm{\mathrm{A}_{2} \mathrm{O}_{3}}\). It can be reduced by hydrogen to give free metal and water. \(\mathrm{0.1596 \mathrm{~g}}\) of this metal oxide requires \(\mathrm{6 \mathrm{mg}}\) of hydrogen for complete reduction. What is the atomic weight of metal?

306857 In an experiment, \(4 \mathrm{~g}\) of \(\mathrm{M}_{2} \mathrm{O}_{\mathrm{x}}\) oxide was reduced to \(2.8 \mathrm{~g}\) of the metal. If the atomic mass of the metal is \(56 \mathrm{~g} \mathrm{~mol}^{-1}\), the number of \(\mathrm{O}\) - atoms in the oxide is

306858 Molarity of a given orthophosphoric acid solution is 3 M. Its normality is

306859 An element forms an oxide in which the oxygen is 20% of the oxide by weight, the equivalent weight of the given element will be

306855 10 mL of 0.02 M \({\rm{KMn}}{{\rm{O}}_{\rm{4}}}\) is required to oxidise 20 ml of oxalic acid of certain strength. 25 ml of the same oxalic acid is required to neutralise 20 ml of NaOH of unknown strength. Find the amount of NaOH in a litre of the solution
(Molecular weight of NaOH = 40):

306856 A metal oxide has the formula \(\mathrm{\mathrm{A}_{2} \mathrm{O}_{3}}\). It can be reduced by hydrogen to give free metal and water. \(\mathrm{0.1596 \mathrm{~g}}\) of this metal oxide requires \(\mathrm{6 \mathrm{mg}}\) of hydrogen for complete reduction. What is the atomic weight of metal?

306857 In an experiment, \(4 \mathrm{~g}\) of \(\mathrm{M}_{2} \mathrm{O}_{\mathrm{x}}\) oxide was reduced to \(2.8 \mathrm{~g}\) of the metal. If the atomic mass of the metal is \(56 \mathrm{~g} \mathrm{~mol}^{-1}\), the number of \(\mathrm{O}\) - atoms in the oxide is

306858 Molarity of a given orthophosphoric acid solution is 3 M. Its normality is

306859 An element forms an oxide in which the oxygen is 20% of the oxide by weight, the equivalent weight of the given element will be

306855 10 mL of 0.02 M \({\rm{KMn}}{{\rm{O}}_{\rm{4}}}\) is required to oxidise 20 ml of oxalic acid of certain strength. 25 ml of the same oxalic acid is required to neutralise 20 ml of NaOH of unknown strength. Find the amount of NaOH in a litre of the solution
(Molecular weight of NaOH = 40):

306856 A metal oxide has the formula \(\mathrm{\mathrm{A}_{2} \mathrm{O}_{3}}\). It can be reduced by hydrogen to give free metal and water. \(\mathrm{0.1596 \mathrm{~g}}\) of this metal oxide requires \(\mathrm{6 \mathrm{mg}}\) of hydrogen for complete reduction. What is the atomic weight of metal?

306857 In an experiment, \(4 \mathrm{~g}\) of \(\mathrm{M}_{2} \mathrm{O}_{\mathrm{x}}\) oxide was reduced to \(2.8 \mathrm{~g}\) of the metal. If the atomic mass of the metal is \(56 \mathrm{~g} \mathrm{~mol}^{-1}\), the number of \(\mathrm{O}\) - atoms in the oxide is

306858 Molarity of a given orthophosphoric acid solution is 3 M. Its normality is

306859 An element forms an oxide in which the oxygen is 20% of the oxide by weight, the equivalent weight of the given element will be

306855 10 mL of 0.02 M \({\rm{KMn}}{{\rm{O}}_{\rm{4}}}\) is required to oxidise 20 ml of oxalic acid of certain strength. 25 ml of the same oxalic acid is required to neutralise 20 ml of NaOH of unknown strength. Find the amount of NaOH in a litre of the solution
(Molecular weight of NaOH = 40):

306856 A metal oxide has the formula \(\mathrm{\mathrm{A}_{2} \mathrm{O}_{3}}\). It can be reduced by hydrogen to give free metal and water. \(\mathrm{0.1596 \mathrm{~g}}\) of this metal oxide requires \(\mathrm{6 \mathrm{mg}}\) of hydrogen for complete reduction. What is the atomic weight of metal?

306857 In an experiment, \(4 \mathrm{~g}\) of \(\mathrm{M}_{2} \mathrm{O}_{\mathrm{x}}\) oxide was reduced to \(2.8 \mathrm{~g}\) of the metal. If the atomic mass of the metal is \(56 \mathrm{~g} \mathrm{~mol}^{-1}\), the number of \(\mathrm{O}\) - atoms in the oxide is

306858 Molarity of a given orthophosphoric acid solution is 3 M. Its normality is

306859 An element forms an oxide in which the oxygen is 20% of the oxide by weight, the equivalent weight of the given element will be

306855 10 mL of 0.02 M \({\rm{KMn}}{{\rm{O}}_{\rm{4}}}\) is required to oxidise 20 ml of oxalic acid of certain strength. 25 ml of the same oxalic acid is required to neutralise 20 ml of NaOH of unknown strength. Find the amount of NaOH in a litre of the solution
(Molecular weight of NaOH = 40):

306856 A metal oxide has the formula \(\mathrm{\mathrm{A}_{2} \mathrm{O}_{3}}\). It can be reduced by hydrogen to give free metal and water. \(\mathrm{0.1596 \mathrm{~g}}\) of this metal oxide requires \(\mathrm{6 \mathrm{mg}}\) of hydrogen for complete reduction. What is the atomic weight of metal?

306857 In an experiment, \(4 \mathrm{~g}\) of \(\mathrm{M}_{2} \mathrm{O}_{\mathrm{x}}\) oxide was reduced to \(2.8 \mathrm{~g}\) of the metal. If the atomic mass of the metal is \(56 \mathrm{~g} \mathrm{~mol}^{-1}\), the number of \(\mathrm{O}\) - atoms in the oxide is

306858 Molarity of a given orthophosphoric acid solution is 3 M. Its normality is

306859 An element forms an oxide in which the oxygen is 20% of the oxide by weight, the equivalent weight of the given element will be