358286
The electric flux linked with the closed surface in \(N m^{2} C^{-1}\) is \(\left(\epsilon_{0}=8.85 \times 10^{-12} C^{2} N^{-1} m^{-2}\right)\)
358287
An infinitely long line of charge having a uniform charge per unit length \(\lambda \) lies at a distance \(x\) from a point \(O\) as shown in the figure. Determine the total electric flux through the surface of a sphere of radius \(R\). \((x < R)\)
The length of the rod present inside the sphere is \(2\sqrt {{R^2} - {x^2}} \) Flux through the sphere is \(\Phi = \frac{{2\lambda \sqrt {{R^2} - {x^2}} }}{{{\varepsilon _o}}}\)
PHXII01:ELECTRIC CHARGES AND FIELDS
358288
What is the electric flux linked with closed surface?
1 \({10^{12}}N{m^2}{C^{ - 1}}\)
2 \({10^{11}}N{m^2}{C^{ - 1}}\)
3 \(8.86 \times {10^{13}}N{m^2}{C^{ - 1}}\)
4 \({10^{10}}N{m^2}{C^{ - 1}}\)
Explanation:
According to Gauss’s law Electric flux,\(\phi = \frac{q}{{{\varepsilon _0}}}\) Where,\(q = \) total charge enclosed by closed surface \(\therefore \;\phi = \frac{{1.25 + 7 + 1 - 0.4}}{{{\varepsilon _0}}}\) \( = \frac{{8.85C}}{{8.85 \times {{10}^{ - 12}}{C^2}{N^{ - 1}}{m^{ - 2}}}} = {10^{12}}N{m^2}{C^{ - 1}}\)
PHXII01:ELECTRIC CHARGES AND FIELDS
358289
The electric field in a region is \(E = \frac{{5 \times {{10}^3}(N{C^{ - 1}}c{m^{ - 1}})x}}{2}\widehat i\) The charge contained inside a cubical volume bounded by the surfaces \(x = 0,x = 2,y = 0,y = 2,z = 0,z = 2\) is (where \(x\),\(y\),\(z\) are in \(cm\))
358290
Consider an infinite line of charge having uniform linear charge density and passing through the axis of a cylinder. What will be the effect on the flux passing through the curved surface if the portions of the line charge outside the cylinder is removed.
1 Decreases
2 Increases
3 Remains same
4 Cannot say
Explanation:
The net electric field at a point on the curved surface of the cylinder is the resultant of fields produced by the charges present inside and outside cylinders. If portion outside the cylinder is removed, electric field at points on curved surface will decrease.
358286
The electric flux linked with the closed surface in \(N m^{2} C^{-1}\) is \(\left(\epsilon_{0}=8.85 \times 10^{-12} C^{2} N^{-1} m^{-2}\right)\)
358287
An infinitely long line of charge having a uniform charge per unit length \(\lambda \) lies at a distance \(x\) from a point \(O\) as shown in the figure. Determine the total electric flux through the surface of a sphere of radius \(R\). \((x < R)\)
The length of the rod present inside the sphere is \(2\sqrt {{R^2} - {x^2}} \) Flux through the sphere is \(\Phi = \frac{{2\lambda \sqrt {{R^2} - {x^2}} }}{{{\varepsilon _o}}}\)
PHXII01:ELECTRIC CHARGES AND FIELDS
358288
What is the electric flux linked with closed surface?
1 \({10^{12}}N{m^2}{C^{ - 1}}\)
2 \({10^{11}}N{m^2}{C^{ - 1}}\)
3 \(8.86 \times {10^{13}}N{m^2}{C^{ - 1}}\)
4 \({10^{10}}N{m^2}{C^{ - 1}}\)
Explanation:
According to Gauss’s law Electric flux,\(\phi = \frac{q}{{{\varepsilon _0}}}\) Where,\(q = \) total charge enclosed by closed surface \(\therefore \;\phi = \frac{{1.25 + 7 + 1 - 0.4}}{{{\varepsilon _0}}}\) \( = \frac{{8.85C}}{{8.85 \times {{10}^{ - 12}}{C^2}{N^{ - 1}}{m^{ - 2}}}} = {10^{12}}N{m^2}{C^{ - 1}}\)
PHXII01:ELECTRIC CHARGES AND FIELDS
358289
The electric field in a region is \(E = \frac{{5 \times {{10}^3}(N{C^{ - 1}}c{m^{ - 1}})x}}{2}\widehat i\) The charge contained inside a cubical volume bounded by the surfaces \(x = 0,x = 2,y = 0,y = 2,z = 0,z = 2\) is (where \(x\),\(y\),\(z\) are in \(cm\))
358290
Consider an infinite line of charge having uniform linear charge density and passing through the axis of a cylinder. What will be the effect on the flux passing through the curved surface if the portions of the line charge outside the cylinder is removed.
1 Decreases
2 Increases
3 Remains same
4 Cannot say
Explanation:
The net electric field at a point on the curved surface of the cylinder is the resultant of fields produced by the charges present inside and outside cylinders. If portion outside the cylinder is removed, electric field at points on curved surface will decrease.
358286
The electric flux linked with the closed surface in \(N m^{2} C^{-1}\) is \(\left(\epsilon_{0}=8.85 \times 10^{-12} C^{2} N^{-1} m^{-2}\right)\)
358287
An infinitely long line of charge having a uniform charge per unit length \(\lambda \) lies at a distance \(x\) from a point \(O\) as shown in the figure. Determine the total electric flux through the surface of a sphere of radius \(R\). \((x < R)\)
The length of the rod present inside the sphere is \(2\sqrt {{R^2} - {x^2}} \) Flux through the sphere is \(\Phi = \frac{{2\lambda \sqrt {{R^2} - {x^2}} }}{{{\varepsilon _o}}}\)
PHXII01:ELECTRIC CHARGES AND FIELDS
358288
What is the electric flux linked with closed surface?
1 \({10^{12}}N{m^2}{C^{ - 1}}\)
2 \({10^{11}}N{m^2}{C^{ - 1}}\)
3 \(8.86 \times {10^{13}}N{m^2}{C^{ - 1}}\)
4 \({10^{10}}N{m^2}{C^{ - 1}}\)
Explanation:
According to Gauss’s law Electric flux,\(\phi = \frac{q}{{{\varepsilon _0}}}\) Where,\(q = \) total charge enclosed by closed surface \(\therefore \;\phi = \frac{{1.25 + 7 + 1 - 0.4}}{{{\varepsilon _0}}}\) \( = \frac{{8.85C}}{{8.85 \times {{10}^{ - 12}}{C^2}{N^{ - 1}}{m^{ - 2}}}} = {10^{12}}N{m^2}{C^{ - 1}}\)
PHXII01:ELECTRIC CHARGES AND FIELDS
358289
The electric field in a region is \(E = \frac{{5 \times {{10}^3}(N{C^{ - 1}}c{m^{ - 1}})x}}{2}\widehat i\) The charge contained inside a cubical volume bounded by the surfaces \(x = 0,x = 2,y = 0,y = 2,z = 0,z = 2\) is (where \(x\),\(y\),\(z\) are in \(cm\))
358290
Consider an infinite line of charge having uniform linear charge density and passing through the axis of a cylinder. What will be the effect on the flux passing through the curved surface if the portions of the line charge outside the cylinder is removed.
1 Decreases
2 Increases
3 Remains same
4 Cannot say
Explanation:
The net electric field at a point on the curved surface of the cylinder is the resultant of fields produced by the charges present inside and outside cylinders. If portion outside the cylinder is removed, electric field at points on curved surface will decrease.
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PHXII01:ELECTRIC CHARGES AND FIELDS
358286
The electric flux linked with the closed surface in \(N m^{2} C^{-1}\) is \(\left(\epsilon_{0}=8.85 \times 10^{-12} C^{2} N^{-1} m^{-2}\right)\)
358287
An infinitely long line of charge having a uniform charge per unit length \(\lambda \) lies at a distance \(x\) from a point \(O\) as shown in the figure. Determine the total electric flux through the surface of a sphere of radius \(R\). \((x < R)\)
The length of the rod present inside the sphere is \(2\sqrt {{R^2} - {x^2}} \) Flux through the sphere is \(\Phi = \frac{{2\lambda \sqrt {{R^2} - {x^2}} }}{{{\varepsilon _o}}}\)
PHXII01:ELECTRIC CHARGES AND FIELDS
358288
What is the electric flux linked with closed surface?
1 \({10^{12}}N{m^2}{C^{ - 1}}\)
2 \({10^{11}}N{m^2}{C^{ - 1}}\)
3 \(8.86 \times {10^{13}}N{m^2}{C^{ - 1}}\)
4 \({10^{10}}N{m^2}{C^{ - 1}}\)
Explanation:
According to Gauss’s law Electric flux,\(\phi = \frac{q}{{{\varepsilon _0}}}\) Where,\(q = \) total charge enclosed by closed surface \(\therefore \;\phi = \frac{{1.25 + 7 + 1 - 0.4}}{{{\varepsilon _0}}}\) \( = \frac{{8.85C}}{{8.85 \times {{10}^{ - 12}}{C^2}{N^{ - 1}}{m^{ - 2}}}} = {10^{12}}N{m^2}{C^{ - 1}}\)
PHXII01:ELECTRIC CHARGES AND FIELDS
358289
The electric field in a region is \(E = \frac{{5 \times {{10}^3}(N{C^{ - 1}}c{m^{ - 1}})x}}{2}\widehat i\) The charge contained inside a cubical volume bounded by the surfaces \(x = 0,x = 2,y = 0,y = 2,z = 0,z = 2\) is (where \(x\),\(y\),\(z\) are in \(cm\))
358290
Consider an infinite line of charge having uniform linear charge density and passing through the axis of a cylinder. What will be the effect on the flux passing through the curved surface if the portions of the line charge outside the cylinder is removed.
1 Decreases
2 Increases
3 Remains same
4 Cannot say
Explanation:
The net electric field at a point on the curved surface of the cylinder is the resultant of fields produced by the charges present inside and outside cylinders. If portion outside the cylinder is removed, electric field at points on curved surface will decrease.
358286
The electric flux linked with the closed surface in \(N m^{2} C^{-1}\) is \(\left(\epsilon_{0}=8.85 \times 10^{-12} C^{2} N^{-1} m^{-2}\right)\)
358287
An infinitely long line of charge having a uniform charge per unit length \(\lambda \) lies at a distance \(x\) from a point \(O\) as shown in the figure. Determine the total electric flux through the surface of a sphere of radius \(R\). \((x < R)\)
The length of the rod present inside the sphere is \(2\sqrt {{R^2} - {x^2}} \) Flux through the sphere is \(\Phi = \frac{{2\lambda \sqrt {{R^2} - {x^2}} }}{{{\varepsilon _o}}}\)
PHXII01:ELECTRIC CHARGES AND FIELDS
358288
What is the electric flux linked with closed surface?
1 \({10^{12}}N{m^2}{C^{ - 1}}\)
2 \({10^{11}}N{m^2}{C^{ - 1}}\)
3 \(8.86 \times {10^{13}}N{m^2}{C^{ - 1}}\)
4 \({10^{10}}N{m^2}{C^{ - 1}}\)
Explanation:
According to Gauss’s law Electric flux,\(\phi = \frac{q}{{{\varepsilon _0}}}\) Where,\(q = \) total charge enclosed by closed surface \(\therefore \;\phi = \frac{{1.25 + 7 + 1 - 0.4}}{{{\varepsilon _0}}}\) \( = \frac{{8.85C}}{{8.85 \times {{10}^{ - 12}}{C^2}{N^{ - 1}}{m^{ - 2}}}} = {10^{12}}N{m^2}{C^{ - 1}}\)
PHXII01:ELECTRIC CHARGES AND FIELDS
358289
The electric field in a region is \(E = \frac{{5 \times {{10}^3}(N{C^{ - 1}}c{m^{ - 1}})x}}{2}\widehat i\) The charge contained inside a cubical volume bounded by the surfaces \(x = 0,x = 2,y = 0,y = 2,z = 0,z = 2\) is (where \(x\),\(y\),\(z\) are in \(cm\))
358290
Consider an infinite line of charge having uniform linear charge density and passing through the axis of a cylinder. What will be the effect on the flux passing through the curved surface if the portions of the line charge outside the cylinder is removed.
1 Decreases
2 Increases
3 Remains same
4 Cannot say
Explanation:
The net electric field at a point on the curved surface of the cylinder is the resultant of fields produced by the charges present inside and outside cylinders. If portion outside the cylinder is removed, electric field at points on curved surface will decrease.
