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PHXII01:ELECTRIC CHARGES AND FIELDS

358146 Assertion :
If the medium between two charges is replaced by another medium of dielectric constant then the electric force between them decreases.
Reason :
Electric dipole moment varies inversely as the dielectric constant.

1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.

2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.

3 Assertion is correct but Reason is incorrect.

4 Assertion is incorrect but reason is correct.

Explanation:

Assertion is true by coulomb law but reason is false as $| \vec{p} | = q d, p$ does not depend on $ϵ_{r}$ . So correct option is (3).

PHXII01:ELECTRIC CHARGES AND FIELDS

358147 The formation of a dipole is due to two equal and dissimilar point charges placed at a

1 Short distance

2 Long distance

3 Above each other

4 None of these

PHXII01:ELECTRIC CHARGES AND FIELDS

358148 A region surrounding a stationary electric dipoles has

1 Both electric and magnetic fields

2 Electric field only

3 Magnetic field only

4 No electric and magnetic fields

PHXII01:ELECTRIC CHARGES AND FIELDS

358149 An electric dipole is placed along the $x$ -axis at the origin $O$ . A point $P$ is at a distance of 10 $c m$ from this origin such that $O P$ makes an angle $\frac{π}{6}$ with $x$ -axis. If the electric field at $P$ makes an angle $β$ with the $x$ -axis, the value of $β$ would be

1

\frac{π}{6}

2

\frac{π}{6} + \tan^{- 1} (\frac{1}{2 \sqrt{3}})

3

\frac{2 π}{6}

4

\tan^{- 1} (\frac{1}{2 \sqrt{3}})

Explanation:

Let $E_{1} a n d E_{2}$ be the fields along and perpendicular to the radial line $O P$ respectively
From figure, $β = \frac{π}{6} + α,$ where
$\tan α = \frac{E_{2}}{E_{1}} = (\frac{k p \sin θ}{r^{3}}) (\frac{r^{3}}{2 k p \cos θ}) = \frac{1}{2} \tan θ$
$\tan (β - \frac{π}{6}) = \frac{1}{2} \tan \frac{π}{6} = \frac{1}{2 \sqrt{3}}$
$β - \frac{π}{6} = \tan^{- 1} (\frac{1}{2 \sqrt{3}})$
$β = \frac{π}{6} + \tan^{- 1} (\frac{1}{2 \sqrt{3}})$
supporting img

PHXII01:ELECTRIC CHARGES AND FIELDS

358150 The direction of electric field intensity $(\vec{E})$ at a point on the equtorial line of an electric dipole of dipole moment $(\vec{p})$ is

1 Along equatorial line away from the dipole

2 Along the equatorial line towards the dipole

3 Perpendicular to the equatorial line and parallel to

(\vec{p})

4 Perpendicular to the equatorial line and opposite to

(\vec{p})

PHXII01:ELECTRIC CHARGES AND FIELDS

358146 Assertion :
If the medium between two charges is replaced by another medium of dielectric constant then the electric force between them decreases.
Reason :
Electric dipole moment varies inversely as the dielectric constant.

1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.

2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.

3 Assertion is correct but Reason is incorrect.

4 Assertion is incorrect but reason is correct.

Explanation:

Assertion is true by coulomb law but reason is false as $| \vec{p} | = q d, p$ does not depend on $ϵ_{r}$ . So correct option is (3).

PHXII01:ELECTRIC CHARGES AND FIELDS

358147 The formation of a dipole is due to two equal and dissimilar point charges placed at a

1 Short distance

2 Long distance

3 Above each other

4 None of these

PHXII01:ELECTRIC CHARGES AND FIELDS

358148 A region surrounding a stationary electric dipoles has

1 Both electric and magnetic fields

2 Electric field only

3 Magnetic field only

4 No electric and magnetic fields

PHXII01:ELECTRIC CHARGES AND FIELDS

358149 An electric dipole is placed along the $x$ -axis at the origin $O$ . A point $P$ is at a distance of 10 $c m$ from this origin such that $O P$ makes an angle $\frac{π}{6}$ with $x$ -axis. If the electric field at $P$ makes an angle $β$ with the $x$ -axis, the value of $β$ would be

1

\frac{π}{6}

2

\frac{π}{6} + \tan^{- 1} (\frac{1}{2 \sqrt{3}})

3

\frac{2 π}{6}

4

\tan^{- 1} (\frac{1}{2 \sqrt{3}})

Explanation:

Let $E_{1} a n d E_{2}$ be the fields along and perpendicular to the radial line $O P$ respectively
From figure, $β = \frac{π}{6} + α,$ where
$\tan α = \frac{E_{2}}{E_{1}} = (\frac{k p \sin θ}{r^{3}}) (\frac{r^{3}}{2 k p \cos θ}) = \frac{1}{2} \tan θ$
$\tan (β - \frac{π}{6}) = \frac{1}{2} \tan \frac{π}{6} = \frac{1}{2 \sqrt{3}}$
$β - \frac{π}{6} = \tan^{- 1} (\frac{1}{2 \sqrt{3}})$
$β = \frac{π}{6} + \tan^{- 1} (\frac{1}{2 \sqrt{3}})$
supporting img

PHXII01:ELECTRIC CHARGES AND FIELDS

358150 The direction of electric field intensity $(\vec{E})$ at a point on the equtorial line of an electric dipole of dipole moment $(\vec{p})$ is

1 Along equatorial line away from the dipole

2 Along the equatorial line towards the dipole

3 Perpendicular to the equatorial line and parallel to

(\vec{p})

4 Perpendicular to the equatorial line and opposite to

(\vec{p})

PHXII01:ELECTRIC CHARGES AND FIELDS

358146 Assertion :
If the medium between two charges is replaced by another medium of dielectric constant then the electric force between them decreases.
Reason :
Electric dipole moment varies inversely as the dielectric constant.

1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.

2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.

3 Assertion is correct but Reason is incorrect.

4 Assertion is incorrect but reason is correct.

Explanation:

Assertion is true by coulomb law but reason is false as $| \vec{p} | = q d, p$ does not depend on $ϵ_{r}$ . So correct option is (3).

PHXII01:ELECTRIC CHARGES AND FIELDS

358147 The formation of a dipole is due to two equal and dissimilar point charges placed at a

1 Short distance

2 Long distance

3 Above each other

4 None of these

PHXII01:ELECTRIC CHARGES AND FIELDS

358148 A region surrounding a stationary electric dipoles has

1 Both electric and magnetic fields

2 Electric field only

3 Magnetic field only

4 No electric and magnetic fields

PHXII01:ELECTRIC CHARGES AND FIELDS

358149 An electric dipole is placed along the $x$ -axis at the origin $O$ . A point $P$ is at a distance of 10 $c m$ from this origin such that $O P$ makes an angle $\frac{π}{6}$ with $x$ -axis. If the electric field at $P$ makes an angle $β$ with the $x$ -axis, the value of $β$ would be

1

\frac{π}{6}

2

\frac{π}{6} + \tan^{- 1} (\frac{1}{2 \sqrt{3}})

3

\frac{2 π}{6}

4

\tan^{- 1} (\frac{1}{2 \sqrt{3}})

Explanation:

Let $E_{1} a n d E_{2}$ be the fields along and perpendicular to the radial line $O P$ respectively
From figure, $β = \frac{π}{6} + α,$ where
$\tan α = \frac{E_{2}}{E_{1}} = (\frac{k p \sin θ}{r^{3}}) (\frac{r^{3}}{2 k p \cos θ}) = \frac{1}{2} \tan θ$
$\tan (β - \frac{π}{6}) = \frac{1}{2} \tan \frac{π}{6} = \frac{1}{2 \sqrt{3}}$
$β - \frac{π}{6} = \tan^{- 1} (\frac{1}{2 \sqrt{3}})$
$β = \frac{π}{6} + \tan^{- 1} (\frac{1}{2 \sqrt{3}})$
supporting img

PHXII01:ELECTRIC CHARGES AND FIELDS

358150 The direction of electric field intensity $(\vec{E})$ at a point on the equtorial line of an electric dipole of dipole moment $(\vec{p})$ is

1 Along equatorial line away from the dipole

2 Along the equatorial line towards the dipole

3 Perpendicular to the equatorial line and parallel to

(\vec{p})

4 Perpendicular to the equatorial line and opposite to

(\vec{p})

PHXII01:ELECTRIC CHARGES AND FIELDS

358146 Assertion :
If the medium between two charges is replaced by another medium of dielectric constant then the electric force between them decreases.
Reason :
Electric dipole moment varies inversely as the dielectric constant.

1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.

2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.

3 Assertion is correct but Reason is incorrect.

4 Assertion is incorrect but reason is correct.

Explanation:

Assertion is true by coulomb law but reason is false as $| \vec{p} | = q d, p$ does not depend on $ϵ_{r}$ . So correct option is (3).

PHXII01:ELECTRIC CHARGES AND FIELDS

358147 The formation of a dipole is due to two equal and dissimilar point charges placed at a

1 Short distance

2 Long distance

3 Above each other

4 None of these

PHXII01:ELECTRIC CHARGES AND FIELDS

358148 A region surrounding a stationary electric dipoles has

1 Both electric and magnetic fields

2 Electric field only

3 Magnetic field only

4 No electric and magnetic fields

PHXII01:ELECTRIC CHARGES AND FIELDS

358149 An electric dipole is placed along the $x$ -axis at the origin $O$ . A point $P$ is at a distance of 10 $c m$ from this origin such that $O P$ makes an angle $\frac{π}{6}$ with $x$ -axis. If the electric field at $P$ makes an angle $β$ with the $x$ -axis, the value of $β$ would be

1

\frac{π}{6}

2

\frac{π}{6} + \tan^{- 1} (\frac{1}{2 \sqrt{3}})

3

\frac{2 π}{6}

4

\tan^{- 1} (\frac{1}{2 \sqrt{3}})

Explanation:

Let $E_{1} a n d E_{2}$ be the fields along and perpendicular to the radial line $O P$ respectively
From figure, $β = \frac{π}{6} + α,$ where
$\tan α = \frac{E_{2}}{E_{1}} = (\frac{k p \sin θ}{r^{3}}) (\frac{r^{3}}{2 k p \cos θ}) = \frac{1}{2} \tan θ$
$\tan (β - \frac{π}{6}) = \frac{1}{2} \tan \frac{π}{6} = \frac{1}{2 \sqrt{3}}$
$β - \frac{π}{6} = \tan^{- 1} (\frac{1}{2 \sqrt{3}})$
$β = \frac{π}{6} + \tan^{- 1} (\frac{1}{2 \sqrt{3}})$
supporting img

PHXII01:ELECTRIC CHARGES AND FIELDS

358150 The direction of electric field intensity $(\vec{E})$ at a point on the equtorial line of an electric dipole of dipole moment $(\vec{p})$ is

1 Along equatorial line away from the dipole

2 Along the equatorial line towards the dipole

3 Perpendicular to the equatorial line and parallel to

(\vec{p})

4 Perpendicular to the equatorial line and opposite to

(\vec{p})

PHXII01:ELECTRIC CHARGES AND FIELDS

358146 Assertion :
If the medium between two charges is replaced by another medium of dielectric constant then the electric force between them decreases.
Reason :
Electric dipole moment varies inversely as the dielectric constant.

1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.

2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.

3 Assertion is correct but Reason is incorrect.

4 Assertion is incorrect but reason is correct.

Explanation:

Assertion is true by coulomb law but reason is false as $| \vec{p} | = q d, p$ does not depend on $ϵ_{r}$ . So correct option is (3).

PHXII01:ELECTRIC CHARGES AND FIELDS

358147 The formation of a dipole is due to two equal and dissimilar point charges placed at a

1 Short distance

2 Long distance

3 Above each other

4 None of these

PHXII01:ELECTRIC CHARGES AND FIELDS

358148 A region surrounding a stationary electric dipoles has

1 Both electric and magnetic fields

2 Electric field only

3 Magnetic field only

4 No electric and magnetic fields

PHXII01:ELECTRIC CHARGES AND FIELDS

358149 An electric dipole is placed along the $x$ -axis at the origin $O$ . A point $P$ is at a distance of 10 $c m$ from this origin such that $O P$ makes an angle $\frac{π}{6}$ with $x$ -axis. If the electric field at $P$ makes an angle $β$ with the $x$ -axis, the value of $β$ would be

1

\frac{π}{6}

2

\frac{π}{6} + \tan^{- 1} (\frac{1}{2 \sqrt{3}})

3

\frac{2 π}{6}

4

\tan^{- 1} (\frac{1}{2 \sqrt{3}})

Explanation:

Let $E_{1} a n d E_{2}$ be the fields along and perpendicular to the radial line $O P$ respectively
From figure, $β = \frac{π}{6} + α,$ where
$\tan α = \frac{E_{2}}{E_{1}} = (\frac{k p \sin θ}{r^{3}}) (\frac{r^{3}}{2 k p \cos θ}) = \frac{1}{2} \tan θ$
$\tan (β - \frac{π}{6}) = \frac{1}{2} \tan \frac{π}{6} = \frac{1}{2 \sqrt{3}}$
$β - \frac{π}{6} = \tan^{- 1} (\frac{1}{2 \sqrt{3}})$
$β = \frac{π}{6} + \tan^{- 1} (\frac{1}{2 \sqrt{3}})$
supporting img

PHXII01:ELECTRIC CHARGES AND FIELDS

358150 The direction of electric field intensity $(\vec{E})$ at a point on the equtorial line of an electric dipole of dipole moment $(\vec{p})$ is

1 Along equatorial line away from the dipole

2 Along the equatorial line towards the dipole

3 Perpendicular to the equatorial line and parallel to

(\vec{p})

4 Perpendicular to the equatorial line and opposite to

(\vec{p})

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