NEET Test Series from KOTA - 10 Papers In MS WORD
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PHXII01:ELECTRIC CHARGES AND FIELDS
358041
A copper rod \(AB\) of length \(l\) is rotated about end \(A\) with a constant angular velocity \(\omega \). The electric field at a distance \(x\) from the axis of rotation is
1 \(\frac{{m{\omega ^2}x}}{e}\)
2 \(\frac{{m\omega x}}{e}\)
3 \(\frac{{mx}}{{{\omega ^2}l}}\)
4 \(\frac{{mx}}{{{\omega ^2}x}}\)
Explanation:
For an electron at a distance \(x\) from rotation axis, the force from electric field \({F_E} = eE\) provides the centripetal force \({F_C} = m{\omega ^2}x\) required for uniform circular motion. Equating these two forces,\(E = \frac{{m{\omega ^2}x}}{e}\)
KCET - 2021
PHXII01:ELECTRIC CHARGES AND FIELDS
358042
Electric field due to infinite, straight uniformly charged wire varies with distance \(r\) as
1 \(r\)
2 \(\frac{1}{r}\)
3 \(\frac{1}{{{r^2}}}\)
4 \({r^2}\)
Explanation:
\(E = \frac{\lambda }{{2\pi {\varepsilon _0}r}} \Rightarrow E \propto \frac{1}{r}\)
KCET - 2021
PHXII01:ELECTRIC CHARGES AND FIELDS
358043
Two parallel line charges \(+\lambda\) and \(-\lambda\) are placed with a separation distance \(R\) in free space. The net electric field exactly mid way between the two line charge is
358044
The expression for electric field intensity at a point outside uniformly charged thin plane sheet is ( where ‘\(d\)’ is the distance of point from plane sheet)
1 Independent of \(d\)
2 Directly proportional to \(\sqrt d \)
3 Directly proportional to \(d\)
4 Directly proportional to \(\frac{1}{{\sqrt d }}\)
Explanation:
Electric field intensity at a point outside a uniformly charged thin infinite sheet is given by \({E_{outside}} = \frac{\sigma }{{2{\varepsilon _0}}}\) Therefore, the electric field intensity is independent of \(d\)
358041
A copper rod \(AB\) of length \(l\) is rotated about end \(A\) with a constant angular velocity \(\omega \). The electric field at a distance \(x\) from the axis of rotation is
1 \(\frac{{m{\omega ^2}x}}{e}\)
2 \(\frac{{m\omega x}}{e}\)
3 \(\frac{{mx}}{{{\omega ^2}l}}\)
4 \(\frac{{mx}}{{{\omega ^2}x}}\)
Explanation:
For an electron at a distance \(x\) from rotation axis, the force from electric field \({F_E} = eE\) provides the centripetal force \({F_C} = m{\omega ^2}x\) required for uniform circular motion. Equating these two forces,\(E = \frac{{m{\omega ^2}x}}{e}\)
KCET - 2021
PHXII01:ELECTRIC CHARGES AND FIELDS
358042
Electric field due to infinite, straight uniformly charged wire varies with distance \(r\) as
1 \(r\)
2 \(\frac{1}{r}\)
3 \(\frac{1}{{{r^2}}}\)
4 \({r^2}\)
Explanation:
\(E = \frac{\lambda }{{2\pi {\varepsilon _0}r}} \Rightarrow E \propto \frac{1}{r}\)
KCET - 2021
PHXII01:ELECTRIC CHARGES AND FIELDS
358043
Two parallel line charges \(+\lambda\) and \(-\lambda\) are placed with a separation distance \(R\) in free space. The net electric field exactly mid way between the two line charge is
358044
The expression for electric field intensity at a point outside uniformly charged thin plane sheet is ( where ‘\(d\)’ is the distance of point from plane sheet)
1 Independent of \(d\)
2 Directly proportional to \(\sqrt d \)
3 Directly proportional to \(d\)
4 Directly proportional to \(\frac{1}{{\sqrt d }}\)
Explanation:
Electric field intensity at a point outside a uniformly charged thin infinite sheet is given by \({E_{outside}} = \frac{\sigma }{{2{\varepsilon _0}}}\) Therefore, the electric field intensity is independent of \(d\)
358041
A copper rod \(AB\) of length \(l\) is rotated about end \(A\) with a constant angular velocity \(\omega \). The electric field at a distance \(x\) from the axis of rotation is
1 \(\frac{{m{\omega ^2}x}}{e}\)
2 \(\frac{{m\omega x}}{e}\)
3 \(\frac{{mx}}{{{\omega ^2}l}}\)
4 \(\frac{{mx}}{{{\omega ^2}x}}\)
Explanation:
For an electron at a distance \(x\) from rotation axis, the force from electric field \({F_E} = eE\) provides the centripetal force \({F_C} = m{\omega ^2}x\) required for uniform circular motion. Equating these two forces,\(E = \frac{{m{\omega ^2}x}}{e}\)
KCET - 2021
PHXII01:ELECTRIC CHARGES AND FIELDS
358042
Electric field due to infinite, straight uniformly charged wire varies with distance \(r\) as
1 \(r\)
2 \(\frac{1}{r}\)
3 \(\frac{1}{{{r^2}}}\)
4 \({r^2}\)
Explanation:
\(E = \frac{\lambda }{{2\pi {\varepsilon _0}r}} \Rightarrow E \propto \frac{1}{r}\)
KCET - 2021
PHXII01:ELECTRIC CHARGES AND FIELDS
358043
Two parallel line charges \(+\lambda\) and \(-\lambda\) are placed with a separation distance \(R\) in free space. The net electric field exactly mid way between the two line charge is
358044
The expression for electric field intensity at a point outside uniformly charged thin plane sheet is ( where ‘\(d\)’ is the distance of point from plane sheet)
1 Independent of \(d\)
2 Directly proportional to \(\sqrt d \)
3 Directly proportional to \(d\)
4 Directly proportional to \(\frac{1}{{\sqrt d }}\)
Explanation:
Electric field intensity at a point outside a uniformly charged thin infinite sheet is given by \({E_{outside}} = \frac{\sigma }{{2{\varepsilon _0}}}\) Therefore, the electric field intensity is independent of \(d\)
358041
A copper rod \(AB\) of length \(l\) is rotated about end \(A\) with a constant angular velocity \(\omega \). The electric field at a distance \(x\) from the axis of rotation is
1 \(\frac{{m{\omega ^2}x}}{e}\)
2 \(\frac{{m\omega x}}{e}\)
3 \(\frac{{mx}}{{{\omega ^2}l}}\)
4 \(\frac{{mx}}{{{\omega ^2}x}}\)
Explanation:
For an electron at a distance \(x\) from rotation axis, the force from electric field \({F_E} = eE\) provides the centripetal force \({F_C} = m{\omega ^2}x\) required for uniform circular motion. Equating these two forces,\(E = \frac{{m{\omega ^2}x}}{e}\)
KCET - 2021
PHXII01:ELECTRIC CHARGES AND FIELDS
358042
Electric field due to infinite, straight uniformly charged wire varies with distance \(r\) as
1 \(r\)
2 \(\frac{1}{r}\)
3 \(\frac{1}{{{r^2}}}\)
4 \({r^2}\)
Explanation:
\(E = \frac{\lambda }{{2\pi {\varepsilon _0}r}} \Rightarrow E \propto \frac{1}{r}\)
KCET - 2021
PHXII01:ELECTRIC CHARGES AND FIELDS
358043
Two parallel line charges \(+\lambda\) and \(-\lambda\) are placed with a separation distance \(R\) in free space. The net electric field exactly mid way between the two line charge is
358044
The expression for electric field intensity at a point outside uniformly charged thin plane sheet is ( where ‘\(d\)’ is the distance of point from plane sheet)
1 Independent of \(d\)
2 Directly proportional to \(\sqrt d \)
3 Directly proportional to \(d\)
4 Directly proportional to \(\frac{1}{{\sqrt d }}\)
Explanation:
Electric field intensity at a point outside a uniformly charged thin infinite sheet is given by \({E_{outside}} = \frac{\sigma }{{2{\varepsilon _0}}}\) Therefore, the electric field intensity is independent of \(d\)
