357976
Assertion : Charging is due to transfer of electrons. Reason : Mass of a body decreases much when it is negatively charged.
1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Assertion is incorrect but reason is correct.
Explanation:
Charging can occur due to the transfer of electrons, which can result in an object becoming negatively charged. But \(\mathrm{m}_{\mathrm{e}}\) is very low (for electrons). \(\Rightarrow\) Reason is false So correct option is (3).
PHXII01:ELECTRIC CHARGES AND FIELDS
357977
If an object of mass 1 \(kg\) contains \(4 \times {10^{20}}\) atoms. If one electron is removed from every atom of the solid, the charge gained by the solid in 1 \(g\) is
1 \(6.4 \times {10^{ - 2}}C\)
2 \(2.8\,C\)
3 \(9.2 \times {10^{ - 4}}C\)
4 \(3.6 \times {10^{ - 3}}C\)
Explanation:
Here, number of electrons removed \({\rm{ = }}\) number of atoms in 1\(g\) \( \Rightarrow n = \frac{{4 \times {{10}^{20}}}}{{{\rm{1}}{{\rm{0}}^3}}} = 4 \times {10^{17}}\) \(q = ne = 4 \times {10^{17}} \times 1.6 \times {\rm{1}}{{\rm{0}}^{ - 19}}C\) \( = {\rm{ }}6.4 \times {10^{ - 2}}C\)
PHXII01:ELECTRIC CHARGES AND FIELDS
357978
Quantisation of charge implies
1 Charge cannot be destroyed
2 Charge exists on particles
3 There is a minimum permissible charge on a particle
4 Charge of any object is an integer multiple of the elementary charge.
Explanation:
\(q = \pm ne\) shows that maximum value of \(q = \pm 1e\,\). where \(e = 1.6 \times {10^{ - 19}}\) Coulomb = Charge of one electron
PHXII01:ELECTRIC CHARGES AND FIELDS
357979
What is the amount of charge possessed by 1 \(kg\) of electrons? \(({m_e} = 9.1 \times {10^{ - 31}}kg)\)
1 \(1.76 \times {10^{11}}C\)
2 \(6.25 \times {10^{10}}C\)
3 \(1.25 \times {10^{10}}C\)
4 \(1.76 \times {10^{10}}C\)
Explanation:
The number of electrons \(n\) is \(n = \frac{M}{{{m_e}}} = \frac{{1kg}}{{9.1 \times {{10}^{ - 31}}kg}} = 1.1 \times {10^{30}}\) Therefore, charge on 1 kg of electrons, \(q = ne = 1.1 \times {10^{30}} \times 1.6 \times {10^{ - 19}}\) \( = 1.76 \times {10^{11}}C\)
PHXII01:ELECTRIC CHARGES AND FIELDS
357980
How many electrons should be removed from a coin of mass \(1.6g,\) so that it may float in an electric field of intensity \({10^9}N{C^{ - 1}}\) directed upward? (Take \(g = 10m/{s^2}\))
1 \({10^7}\)
2 \({10^6}\)
3 \({10^8}\)
4 \({10^9}\)
Explanation:
Let \(n\) be the number of electrons removed from the coin. Then, charge on coin, \(q = + ne\) Now, \(qE = mg\) or \(\left( {ne} \right)E = mg\) or \(n = \frac{{mg}}{{eE}} = \frac{{1.6 \times {{10}^{ - 3}} \times 10}}{{1.6 \times {{10}^{ - 19}} \times {{10}^9}}} = {10^8}\)
357976
Assertion : Charging is due to transfer of electrons. Reason : Mass of a body decreases much when it is negatively charged.
1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Assertion is incorrect but reason is correct.
Explanation:
Charging can occur due to the transfer of electrons, which can result in an object becoming negatively charged. But \(\mathrm{m}_{\mathrm{e}}\) is very low (for electrons). \(\Rightarrow\) Reason is false So correct option is (3).
PHXII01:ELECTRIC CHARGES AND FIELDS
357977
If an object of mass 1 \(kg\) contains \(4 \times {10^{20}}\) atoms. If one electron is removed from every atom of the solid, the charge gained by the solid in 1 \(g\) is
1 \(6.4 \times {10^{ - 2}}C\)
2 \(2.8\,C\)
3 \(9.2 \times {10^{ - 4}}C\)
4 \(3.6 \times {10^{ - 3}}C\)
Explanation:
Here, number of electrons removed \({\rm{ = }}\) number of atoms in 1\(g\) \( \Rightarrow n = \frac{{4 \times {{10}^{20}}}}{{{\rm{1}}{{\rm{0}}^3}}} = 4 \times {10^{17}}\) \(q = ne = 4 \times {10^{17}} \times 1.6 \times {\rm{1}}{{\rm{0}}^{ - 19}}C\) \( = {\rm{ }}6.4 \times {10^{ - 2}}C\)
PHXII01:ELECTRIC CHARGES AND FIELDS
357978
Quantisation of charge implies
1 Charge cannot be destroyed
2 Charge exists on particles
3 There is a minimum permissible charge on a particle
4 Charge of any object is an integer multiple of the elementary charge.
Explanation:
\(q = \pm ne\) shows that maximum value of \(q = \pm 1e\,\). where \(e = 1.6 \times {10^{ - 19}}\) Coulomb = Charge of one electron
PHXII01:ELECTRIC CHARGES AND FIELDS
357979
What is the amount of charge possessed by 1 \(kg\) of electrons? \(({m_e} = 9.1 \times {10^{ - 31}}kg)\)
1 \(1.76 \times {10^{11}}C\)
2 \(6.25 \times {10^{10}}C\)
3 \(1.25 \times {10^{10}}C\)
4 \(1.76 \times {10^{10}}C\)
Explanation:
The number of electrons \(n\) is \(n = \frac{M}{{{m_e}}} = \frac{{1kg}}{{9.1 \times {{10}^{ - 31}}kg}} = 1.1 \times {10^{30}}\) Therefore, charge on 1 kg of electrons, \(q = ne = 1.1 \times {10^{30}} \times 1.6 \times {10^{ - 19}}\) \( = 1.76 \times {10^{11}}C\)
PHXII01:ELECTRIC CHARGES AND FIELDS
357980
How many electrons should be removed from a coin of mass \(1.6g,\) so that it may float in an electric field of intensity \({10^9}N{C^{ - 1}}\) directed upward? (Take \(g = 10m/{s^2}\))
1 \({10^7}\)
2 \({10^6}\)
3 \({10^8}\)
4 \({10^9}\)
Explanation:
Let \(n\) be the number of electrons removed from the coin. Then, charge on coin, \(q = + ne\) Now, \(qE = mg\) or \(\left( {ne} \right)E = mg\) or \(n = \frac{{mg}}{{eE}} = \frac{{1.6 \times {{10}^{ - 3}} \times 10}}{{1.6 \times {{10}^{ - 19}} \times {{10}^9}}} = {10^8}\)
357976
Assertion : Charging is due to transfer of electrons. Reason : Mass of a body decreases much when it is negatively charged.
1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Assertion is incorrect but reason is correct.
Explanation:
Charging can occur due to the transfer of electrons, which can result in an object becoming negatively charged. But \(\mathrm{m}_{\mathrm{e}}\) is very low (for electrons). \(\Rightarrow\) Reason is false So correct option is (3).
PHXII01:ELECTRIC CHARGES AND FIELDS
357977
If an object of mass 1 \(kg\) contains \(4 \times {10^{20}}\) atoms. If one electron is removed from every atom of the solid, the charge gained by the solid in 1 \(g\) is
1 \(6.4 \times {10^{ - 2}}C\)
2 \(2.8\,C\)
3 \(9.2 \times {10^{ - 4}}C\)
4 \(3.6 \times {10^{ - 3}}C\)
Explanation:
Here, number of electrons removed \({\rm{ = }}\) number of atoms in 1\(g\) \( \Rightarrow n = \frac{{4 \times {{10}^{20}}}}{{{\rm{1}}{{\rm{0}}^3}}} = 4 \times {10^{17}}\) \(q = ne = 4 \times {10^{17}} \times 1.6 \times {\rm{1}}{{\rm{0}}^{ - 19}}C\) \( = {\rm{ }}6.4 \times {10^{ - 2}}C\)
PHXII01:ELECTRIC CHARGES AND FIELDS
357978
Quantisation of charge implies
1 Charge cannot be destroyed
2 Charge exists on particles
3 There is a minimum permissible charge on a particle
4 Charge of any object is an integer multiple of the elementary charge.
Explanation:
\(q = \pm ne\) shows that maximum value of \(q = \pm 1e\,\). where \(e = 1.6 \times {10^{ - 19}}\) Coulomb = Charge of one electron
PHXII01:ELECTRIC CHARGES AND FIELDS
357979
What is the amount of charge possessed by 1 \(kg\) of electrons? \(({m_e} = 9.1 \times {10^{ - 31}}kg)\)
1 \(1.76 \times {10^{11}}C\)
2 \(6.25 \times {10^{10}}C\)
3 \(1.25 \times {10^{10}}C\)
4 \(1.76 \times {10^{10}}C\)
Explanation:
The number of electrons \(n\) is \(n = \frac{M}{{{m_e}}} = \frac{{1kg}}{{9.1 \times {{10}^{ - 31}}kg}} = 1.1 \times {10^{30}}\) Therefore, charge on 1 kg of electrons, \(q = ne = 1.1 \times {10^{30}} \times 1.6 \times {10^{ - 19}}\) \( = 1.76 \times {10^{11}}C\)
PHXII01:ELECTRIC CHARGES AND FIELDS
357980
How many electrons should be removed from a coin of mass \(1.6g,\) so that it may float in an electric field of intensity \({10^9}N{C^{ - 1}}\) directed upward? (Take \(g = 10m/{s^2}\))
1 \({10^7}\)
2 \({10^6}\)
3 \({10^8}\)
4 \({10^9}\)
Explanation:
Let \(n\) be the number of electrons removed from the coin. Then, charge on coin, \(q = + ne\) Now, \(qE = mg\) or \(\left( {ne} \right)E = mg\) or \(n = \frac{{mg}}{{eE}} = \frac{{1.6 \times {{10}^{ - 3}} \times 10}}{{1.6 \times {{10}^{ - 19}} \times {{10}^9}}} = {10^8}\)
357976
Assertion : Charging is due to transfer of electrons. Reason : Mass of a body decreases much when it is negatively charged.
1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Assertion is incorrect but reason is correct.
Explanation:
Charging can occur due to the transfer of electrons, which can result in an object becoming negatively charged. But \(\mathrm{m}_{\mathrm{e}}\) is very low (for electrons). \(\Rightarrow\) Reason is false So correct option is (3).
PHXII01:ELECTRIC CHARGES AND FIELDS
357977
If an object of mass 1 \(kg\) contains \(4 \times {10^{20}}\) atoms. If one electron is removed from every atom of the solid, the charge gained by the solid in 1 \(g\) is
1 \(6.4 \times {10^{ - 2}}C\)
2 \(2.8\,C\)
3 \(9.2 \times {10^{ - 4}}C\)
4 \(3.6 \times {10^{ - 3}}C\)
Explanation:
Here, number of electrons removed \({\rm{ = }}\) number of atoms in 1\(g\) \( \Rightarrow n = \frac{{4 \times {{10}^{20}}}}{{{\rm{1}}{{\rm{0}}^3}}} = 4 \times {10^{17}}\) \(q = ne = 4 \times {10^{17}} \times 1.6 \times {\rm{1}}{{\rm{0}}^{ - 19}}C\) \( = {\rm{ }}6.4 \times {10^{ - 2}}C\)
PHXII01:ELECTRIC CHARGES AND FIELDS
357978
Quantisation of charge implies
1 Charge cannot be destroyed
2 Charge exists on particles
3 There is a minimum permissible charge on a particle
4 Charge of any object is an integer multiple of the elementary charge.
Explanation:
\(q = \pm ne\) shows that maximum value of \(q = \pm 1e\,\). where \(e = 1.6 \times {10^{ - 19}}\) Coulomb = Charge of one electron
PHXII01:ELECTRIC CHARGES AND FIELDS
357979
What is the amount of charge possessed by 1 \(kg\) of electrons? \(({m_e} = 9.1 \times {10^{ - 31}}kg)\)
1 \(1.76 \times {10^{11}}C\)
2 \(6.25 \times {10^{10}}C\)
3 \(1.25 \times {10^{10}}C\)
4 \(1.76 \times {10^{10}}C\)
Explanation:
The number of electrons \(n\) is \(n = \frac{M}{{{m_e}}} = \frac{{1kg}}{{9.1 \times {{10}^{ - 31}}kg}} = 1.1 \times {10^{30}}\) Therefore, charge on 1 kg of electrons, \(q = ne = 1.1 \times {10^{30}} \times 1.6 \times {10^{ - 19}}\) \( = 1.76 \times {10^{11}}C\)
PHXII01:ELECTRIC CHARGES AND FIELDS
357980
How many electrons should be removed from a coin of mass \(1.6g,\) so that it may float in an electric field of intensity \({10^9}N{C^{ - 1}}\) directed upward? (Take \(g = 10m/{s^2}\))
1 \({10^7}\)
2 \({10^6}\)
3 \({10^8}\)
4 \({10^9}\)
Explanation:
Let \(n\) be the number of electrons removed from the coin. Then, charge on coin, \(q = + ne\) Now, \(qE = mg\) or \(\left( {ne} \right)E = mg\) or \(n = \frac{{mg}}{{eE}} = \frac{{1.6 \times {{10}^{ - 3}} \times 10}}{{1.6 \times {{10}^{ - 19}} \times {{10}^9}}} = {10^8}\)
357976
Assertion : Charging is due to transfer of electrons. Reason : Mass of a body decreases much when it is negatively charged.
1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Assertion is incorrect but reason is correct.
Explanation:
Charging can occur due to the transfer of electrons, which can result in an object becoming negatively charged. But \(\mathrm{m}_{\mathrm{e}}\) is very low (for electrons). \(\Rightarrow\) Reason is false So correct option is (3).
PHXII01:ELECTRIC CHARGES AND FIELDS
357977
If an object of mass 1 \(kg\) contains \(4 \times {10^{20}}\) atoms. If one electron is removed from every atom of the solid, the charge gained by the solid in 1 \(g\) is
1 \(6.4 \times {10^{ - 2}}C\)
2 \(2.8\,C\)
3 \(9.2 \times {10^{ - 4}}C\)
4 \(3.6 \times {10^{ - 3}}C\)
Explanation:
Here, number of electrons removed \({\rm{ = }}\) number of atoms in 1\(g\) \( \Rightarrow n = \frac{{4 \times {{10}^{20}}}}{{{\rm{1}}{{\rm{0}}^3}}} = 4 \times {10^{17}}\) \(q = ne = 4 \times {10^{17}} \times 1.6 \times {\rm{1}}{{\rm{0}}^{ - 19}}C\) \( = {\rm{ }}6.4 \times {10^{ - 2}}C\)
PHXII01:ELECTRIC CHARGES AND FIELDS
357978
Quantisation of charge implies
1 Charge cannot be destroyed
2 Charge exists on particles
3 There is a minimum permissible charge on a particle
4 Charge of any object is an integer multiple of the elementary charge.
Explanation:
\(q = \pm ne\) shows that maximum value of \(q = \pm 1e\,\). where \(e = 1.6 \times {10^{ - 19}}\) Coulomb = Charge of one electron
PHXII01:ELECTRIC CHARGES AND FIELDS
357979
What is the amount of charge possessed by 1 \(kg\) of electrons? \(({m_e} = 9.1 \times {10^{ - 31}}kg)\)
1 \(1.76 \times {10^{11}}C\)
2 \(6.25 \times {10^{10}}C\)
3 \(1.25 \times {10^{10}}C\)
4 \(1.76 \times {10^{10}}C\)
Explanation:
The number of electrons \(n\) is \(n = \frac{M}{{{m_e}}} = \frac{{1kg}}{{9.1 \times {{10}^{ - 31}}kg}} = 1.1 \times {10^{30}}\) Therefore, charge on 1 kg of electrons, \(q = ne = 1.1 \times {10^{30}} \times 1.6 \times {10^{ - 19}}\) \( = 1.76 \times {10^{11}}C\)
PHXII01:ELECTRIC CHARGES AND FIELDS
357980
How many electrons should be removed from a coin of mass \(1.6g,\) so that it may float in an electric field of intensity \({10^9}N{C^{ - 1}}\) directed upward? (Take \(g = 10m/{s^2}\))
1 \({10^7}\)
2 \({10^6}\)
3 \({10^8}\)
4 \({10^9}\)
Explanation:
Let \(n\) be the number of electrons removed from the coin. Then, charge on coin, \(q = + ne\) Now, \(qE = mg\) or \(\left( {ne} \right)E = mg\) or \(n = \frac{{mg}}{{eE}} = \frac{{1.6 \times {{10}^{ - 3}} \times 10}}{{1.6 \times {{10}^{ - 19}} \times {{10}^9}}} = {10^8}\)
