357954
Let \(\sigma\) be the uniform surface charge density of two infinite thin plane sheets shown in figure. Then the electric fields in three different region \(E_{I}, E_{I I}\) and \(E_{I I I}\) are
1 \(\vec{E}_{I}=0, \vec{E}_{I I}=\dfrac{\sigma}{\epsilon_{0}} \hat{n}, \vec{E}_{I I I}=0\)
357955
Two parallel large thin metal sheets have equal surface charge densities \(\left( {\sigma = 26.4 \times {{10}^{ - 12}}C/{m^2}} \right)\) of opposite signs. The electric field between these sheets is
1 \(1.5N{\rm{/}}C\)
2 \(1.5 \times {10^{ - 10}}N{\rm{/}}C\)
3 \(3N{\rm{/}}C\)
4 \(3 \times {10^{ - 10}}N{\rm{/}}C\)
Explanation:
The net electric field is \(E = \frac{\sigma }{{{\varepsilon _0}}} = \frac{{26.4 \times {{10}^{ - 12}}}}{{9 \times {{10}^{ - 12}}}}\) \( \approx 3N/C\)
PHXII01:ELECTRIC CHARGES AND FIELDS
357956
If the uniform surface charge density of the infinite plane sheet is \(\sigma\), electric field near the surface will be
1 \(\dfrac{\sigma}{2 \varepsilon_{0}}\)
2 \(\dfrac{3 \sigma}{\varepsilon_{0}}\)
3 \(\dfrac{\sigma}{\varepsilon_{0}}\)
4 None of these
Explanation:
From Gauss law the electric field produced by a plane sheet having surface charge density \(\sigma\) is given by \(\dfrac{\sigma}{2 \varepsilon_{0}}\).
PHXII01:ELECTRIC CHARGES AND FIELDS
357957
Three infinitely long charged sheets are placed as shown in figure. The electric field at point \(P\) is
The electric field due to an infinite plane sheet of charge is independent of distance of point from the sheet. Applying the principle of superposition of electric field, the total electric field at \(p\) due to various plane sheets of charge will be \({\overrightarrow E _P} = \frac{\sigma }{{2{\varepsilon _0}}}( - \hat k) + \frac{{2\sigma }}{{2{\varepsilon _0}}}( - \hat k) + \frac{\sigma }{{2{\varepsilon _0}}}( - \hat k)\) \( = - \frac{{2\sigma }}{{{\varepsilon _0}}}(\hat k)\)
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PHXII01:ELECTRIC CHARGES AND FIELDS
357954
Let \(\sigma\) be the uniform surface charge density of two infinite thin plane sheets shown in figure. Then the electric fields in three different region \(E_{I}, E_{I I}\) and \(E_{I I I}\) are
1 \(\vec{E}_{I}=0, \vec{E}_{I I}=\dfrac{\sigma}{\epsilon_{0}} \hat{n}, \vec{E}_{I I I}=0\)
357955
Two parallel large thin metal sheets have equal surface charge densities \(\left( {\sigma = 26.4 \times {{10}^{ - 12}}C/{m^2}} \right)\) of opposite signs. The electric field between these sheets is
1 \(1.5N{\rm{/}}C\)
2 \(1.5 \times {10^{ - 10}}N{\rm{/}}C\)
3 \(3N{\rm{/}}C\)
4 \(3 \times {10^{ - 10}}N{\rm{/}}C\)
Explanation:
The net electric field is \(E = \frac{\sigma }{{{\varepsilon _0}}} = \frac{{26.4 \times {{10}^{ - 12}}}}{{9 \times {{10}^{ - 12}}}}\) \( \approx 3N/C\)
PHXII01:ELECTRIC CHARGES AND FIELDS
357956
If the uniform surface charge density of the infinite plane sheet is \(\sigma\), electric field near the surface will be
1 \(\dfrac{\sigma}{2 \varepsilon_{0}}\)
2 \(\dfrac{3 \sigma}{\varepsilon_{0}}\)
3 \(\dfrac{\sigma}{\varepsilon_{0}}\)
4 None of these
Explanation:
From Gauss law the electric field produced by a plane sheet having surface charge density \(\sigma\) is given by \(\dfrac{\sigma}{2 \varepsilon_{0}}\).
PHXII01:ELECTRIC CHARGES AND FIELDS
357957
Three infinitely long charged sheets are placed as shown in figure. The electric field at point \(P\) is
The electric field due to an infinite plane sheet of charge is independent of distance of point from the sheet. Applying the principle of superposition of electric field, the total electric field at \(p\) due to various plane sheets of charge will be \({\overrightarrow E _P} = \frac{\sigma }{{2{\varepsilon _0}}}( - \hat k) + \frac{{2\sigma }}{{2{\varepsilon _0}}}( - \hat k) + \frac{\sigma }{{2{\varepsilon _0}}}( - \hat k)\) \( = - \frac{{2\sigma }}{{{\varepsilon _0}}}(\hat k)\)
357954
Let \(\sigma\) be the uniform surface charge density of two infinite thin plane sheets shown in figure. Then the electric fields in three different region \(E_{I}, E_{I I}\) and \(E_{I I I}\) are
1 \(\vec{E}_{I}=0, \vec{E}_{I I}=\dfrac{\sigma}{\epsilon_{0}} \hat{n}, \vec{E}_{I I I}=0\)
357955
Two parallel large thin metal sheets have equal surface charge densities \(\left( {\sigma = 26.4 \times {{10}^{ - 12}}C/{m^2}} \right)\) of opposite signs. The electric field between these sheets is
1 \(1.5N{\rm{/}}C\)
2 \(1.5 \times {10^{ - 10}}N{\rm{/}}C\)
3 \(3N{\rm{/}}C\)
4 \(3 \times {10^{ - 10}}N{\rm{/}}C\)
Explanation:
The net electric field is \(E = \frac{\sigma }{{{\varepsilon _0}}} = \frac{{26.4 \times {{10}^{ - 12}}}}{{9 \times {{10}^{ - 12}}}}\) \( \approx 3N/C\)
PHXII01:ELECTRIC CHARGES AND FIELDS
357956
If the uniform surface charge density of the infinite plane sheet is \(\sigma\), electric field near the surface will be
1 \(\dfrac{\sigma}{2 \varepsilon_{0}}\)
2 \(\dfrac{3 \sigma}{\varepsilon_{0}}\)
3 \(\dfrac{\sigma}{\varepsilon_{0}}\)
4 None of these
Explanation:
From Gauss law the electric field produced by a plane sheet having surface charge density \(\sigma\) is given by \(\dfrac{\sigma}{2 \varepsilon_{0}}\).
PHXII01:ELECTRIC CHARGES AND FIELDS
357957
Three infinitely long charged sheets are placed as shown in figure. The electric field at point \(P\) is
The electric field due to an infinite plane sheet of charge is independent of distance of point from the sheet. Applying the principle of superposition of electric field, the total electric field at \(p\) due to various plane sheets of charge will be \({\overrightarrow E _P} = \frac{\sigma }{{2{\varepsilon _0}}}( - \hat k) + \frac{{2\sigma }}{{2{\varepsilon _0}}}( - \hat k) + \frac{\sigma }{{2{\varepsilon _0}}}( - \hat k)\) \( = - \frac{{2\sigma }}{{{\varepsilon _0}}}(\hat k)\)
357954
Let \(\sigma\) be the uniform surface charge density of two infinite thin plane sheets shown in figure. Then the electric fields in three different region \(E_{I}, E_{I I}\) and \(E_{I I I}\) are
1 \(\vec{E}_{I}=0, \vec{E}_{I I}=\dfrac{\sigma}{\epsilon_{0}} \hat{n}, \vec{E}_{I I I}=0\)
357955
Two parallel large thin metal sheets have equal surface charge densities \(\left( {\sigma = 26.4 \times {{10}^{ - 12}}C/{m^2}} \right)\) of opposite signs. The electric field between these sheets is
1 \(1.5N{\rm{/}}C\)
2 \(1.5 \times {10^{ - 10}}N{\rm{/}}C\)
3 \(3N{\rm{/}}C\)
4 \(3 \times {10^{ - 10}}N{\rm{/}}C\)
Explanation:
The net electric field is \(E = \frac{\sigma }{{{\varepsilon _0}}} = \frac{{26.4 \times {{10}^{ - 12}}}}{{9 \times {{10}^{ - 12}}}}\) \( \approx 3N/C\)
PHXII01:ELECTRIC CHARGES AND FIELDS
357956
If the uniform surface charge density of the infinite plane sheet is \(\sigma\), electric field near the surface will be
1 \(\dfrac{\sigma}{2 \varepsilon_{0}}\)
2 \(\dfrac{3 \sigma}{\varepsilon_{0}}\)
3 \(\dfrac{\sigma}{\varepsilon_{0}}\)
4 None of these
Explanation:
From Gauss law the electric field produced by a plane sheet having surface charge density \(\sigma\) is given by \(\dfrac{\sigma}{2 \varepsilon_{0}}\).
PHXII01:ELECTRIC CHARGES AND FIELDS
357957
Three infinitely long charged sheets are placed as shown in figure. The electric field at point \(P\) is
The electric field due to an infinite plane sheet of charge is independent of distance of point from the sheet. Applying the principle of superposition of electric field, the total electric field at \(p\) due to various plane sheets of charge will be \({\overrightarrow E _P} = \frac{\sigma }{{2{\varepsilon _0}}}( - \hat k) + \frac{{2\sigma }}{{2{\varepsilon _0}}}( - \hat k) + \frac{\sigma }{{2{\varepsilon _0}}}( - \hat k)\) \( = - \frac{{2\sigma }}{{{\varepsilon _0}}}(\hat k)\)
