Wave Nature of Matter
PHXII11:DUAL NATURE OF RADIATION AND MATTER

357939 What is the de Broglie wavelength of a nitrogen molecule in air at \(300\;K\) ? Assume that the molecule is moving with the root-mean-square speed of molecules at this temperature.(Atomic mass of nitrogen \( = 14.0076\,u\) )

1 \(0.09\;nm\)
2 \(0.01\;nm\)
3 \(0.2\;nm\)
4 \(0.03\;nm\)
PHXII11:DUAL NATURE OF RADIATION AND MATTER

357940 An electron accelerated through a potential difference \(V_{1}\) has a de-Broglie wavelength of \(\lambda\). When the potential is changed to \(V_{2}\), its deBroglie wavelength increases by \(50 \%\). The value of \(\left(\dfrac{V_{1}}{V_{2}}\right)\) is equal to

1 3
2 \(\dfrac{9}{4}\)
3 4
4 \(\dfrac{3}{2}\)
PHXII11:DUAL NATURE OF RADIATION AND MATTER

357941 The de-Broglie wavelength of a molecule in a gas at room temperature \((300 K)\) is \(\lambda_{1}\). If the temperature of the gas is increased to \(600\;K\), then the de Broglie wavelength of the same gas molecule becomes

1 \(\sqrt{2} \lambda\)
2 \(\dfrac{1}{2} \lambda_{1}\)
3 \(2 \lambda_{1}\)
4 \(\dfrac{1}{\sqrt{2}} \lambda_{1}\)
PHXII11:DUAL NATURE OF RADIATION AND MATTER

357942 de Broglie wavelength of uncharged particles depends on

1 Mass of particle
2 Kinetic energy of particle
3 Velocity of particle
4 All the above
PHXII11:DUAL NATURE OF RADIATION AND MATTER

357943 An \(\alpha\)-particle, a proton and an electron have the same kinetic energy. Which one of the following is correct in case of their de-Broglie wavelength?

1 \(\lambda_{\alpha}=\lambda_{p}=\lambda_{e}\)
2 \(\lambda_{\alpha} < \lambda_{p} < \lambda_{e}\)
3 \(\lambda_{\alpha}>\lambda_{p}>\lambda_{e}\)
4 \(\lambda_{\alpha}>\lambda_{p} < \lambda_{c}\)
PHXII11:DUAL NATURE OF RADIATION AND MATTER

357939 What is the de Broglie wavelength of a nitrogen molecule in air at \(300\;K\) ? Assume that the molecule is moving with the root-mean-square speed of molecules at this temperature.(Atomic mass of nitrogen \( = 14.0076\,u\) )

1 \(0.09\;nm\)
2 \(0.01\;nm\)
3 \(0.2\;nm\)
4 \(0.03\;nm\)
PHXII11:DUAL NATURE OF RADIATION AND MATTER

357940 An electron accelerated through a potential difference \(V_{1}\) has a de-Broglie wavelength of \(\lambda\). When the potential is changed to \(V_{2}\), its deBroglie wavelength increases by \(50 \%\). The value of \(\left(\dfrac{V_{1}}{V_{2}}\right)\) is equal to

1 3
2 \(\dfrac{9}{4}\)
3 4
4 \(\dfrac{3}{2}\)
PHXII11:DUAL NATURE OF RADIATION AND MATTER

357941 The de-Broglie wavelength of a molecule in a gas at room temperature \((300 K)\) is \(\lambda_{1}\). If the temperature of the gas is increased to \(600\;K\), then the de Broglie wavelength of the same gas molecule becomes

1 \(\sqrt{2} \lambda\)
2 \(\dfrac{1}{2} \lambda_{1}\)
3 \(2 \lambda_{1}\)
4 \(\dfrac{1}{\sqrt{2}} \lambda_{1}\)
PHXII11:DUAL NATURE OF RADIATION AND MATTER

357942 de Broglie wavelength of uncharged particles depends on

1 Mass of particle
2 Kinetic energy of particle
3 Velocity of particle
4 All the above
PHXII11:DUAL NATURE OF RADIATION AND MATTER

357943 An \(\alpha\)-particle, a proton and an electron have the same kinetic energy. Which one of the following is correct in case of their de-Broglie wavelength?

1 \(\lambda_{\alpha}=\lambda_{p}=\lambda_{e}\)
2 \(\lambda_{\alpha} < \lambda_{p} < \lambda_{e}\)
3 \(\lambda_{\alpha}>\lambda_{p}>\lambda_{e}\)
4 \(\lambda_{\alpha}>\lambda_{p} < \lambda_{c}\)
PHXII11:DUAL NATURE OF RADIATION AND MATTER

357939 What is the de Broglie wavelength of a nitrogen molecule in air at \(300\;K\) ? Assume that the molecule is moving with the root-mean-square speed of molecules at this temperature.(Atomic mass of nitrogen \( = 14.0076\,u\) )

1 \(0.09\;nm\)
2 \(0.01\;nm\)
3 \(0.2\;nm\)
4 \(0.03\;nm\)
PHXII11:DUAL NATURE OF RADIATION AND MATTER

357940 An electron accelerated through a potential difference \(V_{1}\) has a de-Broglie wavelength of \(\lambda\). When the potential is changed to \(V_{2}\), its deBroglie wavelength increases by \(50 \%\). The value of \(\left(\dfrac{V_{1}}{V_{2}}\right)\) is equal to

1 3
2 \(\dfrac{9}{4}\)
3 4
4 \(\dfrac{3}{2}\)
PHXII11:DUAL NATURE OF RADIATION AND MATTER

357941 The de-Broglie wavelength of a molecule in a gas at room temperature \((300 K)\) is \(\lambda_{1}\). If the temperature of the gas is increased to \(600\;K\), then the de Broglie wavelength of the same gas molecule becomes

1 \(\sqrt{2} \lambda\)
2 \(\dfrac{1}{2} \lambda_{1}\)
3 \(2 \lambda_{1}\)
4 \(\dfrac{1}{\sqrt{2}} \lambda_{1}\)
PHXII11:DUAL NATURE OF RADIATION AND MATTER

357942 de Broglie wavelength of uncharged particles depends on

1 Mass of particle
2 Kinetic energy of particle
3 Velocity of particle
4 All the above
PHXII11:DUAL NATURE OF RADIATION AND MATTER

357943 An \(\alpha\)-particle, a proton and an electron have the same kinetic energy. Which one of the following is correct in case of their de-Broglie wavelength?

1 \(\lambda_{\alpha}=\lambda_{p}=\lambda_{e}\)
2 \(\lambda_{\alpha} < \lambda_{p} < \lambda_{e}\)
3 \(\lambda_{\alpha}>\lambda_{p}>\lambda_{e}\)
4 \(\lambda_{\alpha}>\lambda_{p} < \lambda_{c}\)
PHXII11:DUAL NATURE OF RADIATION AND MATTER

357939 What is the de Broglie wavelength of a nitrogen molecule in air at \(300\;K\) ? Assume that the molecule is moving with the root-mean-square speed of molecules at this temperature.(Atomic mass of nitrogen \( = 14.0076\,u\) )

1 \(0.09\;nm\)
2 \(0.01\;nm\)
3 \(0.2\;nm\)
4 \(0.03\;nm\)
PHXII11:DUAL NATURE OF RADIATION AND MATTER

357940 An electron accelerated through a potential difference \(V_{1}\) has a de-Broglie wavelength of \(\lambda\). When the potential is changed to \(V_{2}\), its deBroglie wavelength increases by \(50 \%\). The value of \(\left(\dfrac{V_{1}}{V_{2}}\right)\) is equal to

1 3
2 \(\dfrac{9}{4}\)
3 4
4 \(\dfrac{3}{2}\)
PHXII11:DUAL NATURE OF RADIATION AND MATTER

357941 The de-Broglie wavelength of a molecule in a gas at room temperature \((300 K)\) is \(\lambda_{1}\). If the temperature of the gas is increased to \(600\;K\), then the de Broglie wavelength of the same gas molecule becomes

1 \(\sqrt{2} \lambda\)
2 \(\dfrac{1}{2} \lambda_{1}\)
3 \(2 \lambda_{1}\)
4 \(\dfrac{1}{\sqrt{2}} \lambda_{1}\)
PHXII11:DUAL NATURE OF RADIATION AND MATTER

357942 de Broglie wavelength of uncharged particles depends on

1 Mass of particle
2 Kinetic energy of particle
3 Velocity of particle
4 All the above
PHXII11:DUAL NATURE OF RADIATION AND MATTER

357943 An \(\alpha\)-particle, a proton and an electron have the same kinetic energy. Which one of the following is correct in case of their de-Broglie wavelength?

1 \(\lambda_{\alpha}=\lambda_{p}=\lambda_{e}\)
2 \(\lambda_{\alpha} < \lambda_{p} < \lambda_{e}\)
3 \(\lambda_{\alpha}>\lambda_{p}>\lambda_{e}\)
4 \(\lambda_{\alpha}>\lambda_{p} < \lambda_{c}\)
PHXII11:DUAL NATURE OF RADIATION AND MATTER

357939 What is the de Broglie wavelength of a nitrogen molecule in air at \(300\;K\) ? Assume that the molecule is moving with the root-mean-square speed of molecules at this temperature.(Atomic mass of nitrogen \( = 14.0076\,u\) )

1 \(0.09\;nm\)
2 \(0.01\;nm\)
3 \(0.2\;nm\)
4 \(0.03\;nm\)
PHXII11:DUAL NATURE OF RADIATION AND MATTER

357940 An electron accelerated through a potential difference \(V_{1}\) has a de-Broglie wavelength of \(\lambda\). When the potential is changed to \(V_{2}\), its deBroglie wavelength increases by \(50 \%\). The value of \(\left(\dfrac{V_{1}}{V_{2}}\right)\) is equal to

1 3
2 \(\dfrac{9}{4}\)
3 4
4 \(\dfrac{3}{2}\)
PHXII11:DUAL NATURE OF RADIATION AND MATTER

357941 The de-Broglie wavelength of a molecule in a gas at room temperature \((300 K)\) is \(\lambda_{1}\). If the temperature of the gas is increased to \(600\;K\), then the de Broglie wavelength of the same gas molecule becomes

1 \(\sqrt{2} \lambda\)
2 \(\dfrac{1}{2} \lambda_{1}\)
3 \(2 \lambda_{1}\)
4 \(\dfrac{1}{\sqrt{2}} \lambda_{1}\)
PHXII11:DUAL NATURE OF RADIATION AND MATTER

357942 de Broglie wavelength of uncharged particles depends on

1 Mass of particle
2 Kinetic energy of particle
3 Velocity of particle
4 All the above
PHXII11:DUAL NATURE OF RADIATION AND MATTER

357943 An \(\alpha\)-particle, a proton and an electron have the same kinetic energy. Which one of the following is correct in case of their de-Broglie wavelength?

1 \(\lambda_{\alpha}=\lambda_{p}=\lambda_{e}\)
2 \(\lambda_{\alpha} < \lambda_{p} < \lambda_{e}\)
3 \(\lambda_{\alpha}>\lambda_{p}>\lambda_{e}\)
4 \(\lambda_{\alpha}>\lambda_{p} < \lambda_{c}\)