Wave Nature of Matter
« Previous Topic: Photoelectric Effect Last Topic in »
PHXII11:DUAL NATURE OF RADIATION AND MATTER

357926 An electron of mass \({m}\) when accelerated through a potential difference \({V}\), has de Broglie wavelength \({\lambda}\). The de-Broglie wavelength associated with a particle of mass \({m / 4}\) and charge \({e}\) accelerated through the same potential difference is \({n \lambda}\). Then find the value of \({n}\).

1 2
2 4
3 8
4 6
PHXII11:DUAL NATURE OF RADIATION AND MATTER

357927 An electron of mass \(m\) has de - Brogile wavelength \(\lambda\) when accelerated through potential difference \(V\). When proton of mass \(M\), is accelerated through potential difference \(9\;V\), the de - Brogile wavelength associated with it will be (assume that wavelength is determined at low voltage)

1 \(\frac{\lambda }{3}\sqrt {\frac{M}{m}} \)
2 \(\frac{\lambda }{3}\frac{M}{m}\)
3 \(\frac{\lambda }{3}\sqrt {\frac{m}{M}} \)
4 \(\frac{\lambda }{3}\frac{m}{M}\)
MHTCET - 2016
PHXII11:DUAL NATURE OF RADIATION AND MATTER

357928 If \(E_{1}, E_{2}, E_{3}\) are the respective kinetic energies of an electron, an alpha-particle and a proton, each having the same de-Broglie wavelength, then

1 \({E_1} > {E_3} > {E_2}\)
2 \(E_{2}>E_{3}>E_{1}\)
3 \({E_1} > {E_2} > {E_3}\)
4 \({E_1} = {E_2} = {E_3}\)
PHXII11:DUAL NATURE OF RADIATION AND MATTER

357929 The additional energy that should be given to an electron to reduce its de - Broglie wavelength from \(1\;nm\) to \(0.5\;nm\) is

1 2 times the initial kinetic energy
2 3 times the initial kinetic energy
3 0.5 times the initial kinetic energy
4 4 times the initial kinetic energy
KCET - 2005
PHXII11:DUAL NATURE OF RADIATION AND MATTER

357930 According to de - Brogile hypothesis, the wavelength associated with moving electron of mass ' \(m\) ' is \(\lambda_{e}\). Using mass energy relation and Planck's quantum theory, the wavelength associated with photon is \(\lambda_{p}\). If the energy (\(E\)) electron and photon is same, then relation between \(\lambda_{e}\) and \(\lambda_{p}\) is

1 \(\lambda_{p} \propto \lambda_{e}\)
2 \(\lambda_{p} \propto \lambda_{e}^{2}\)
3 \(\lambda_{p} \propto \sqrt{\lambda_{e}}\)
4 \(\lambda_{p} \propto \dfrac{1}{\lambda_{e}}\)
MHTCET - 2017
NEET DIGITAL LIBRARY
PHXII11:DUAL NATURE OF RADIATION AND MATTER

357926 An electron of mass \({m}\) when accelerated through a potential difference \({V}\), has de Broglie wavelength \({\lambda}\). The de-Broglie wavelength associated with a particle of mass \({m / 4}\) and charge \({e}\) accelerated through the same potential difference is \({n \lambda}\). Then find the value of \({n}\).

1 2
2 4
3 8
4 6
PHXII11:DUAL NATURE OF RADIATION AND MATTER

357927 An electron of mass \(m\) has de - Brogile wavelength \(\lambda\) when accelerated through potential difference \(V\). When proton of mass \(M\), is accelerated through potential difference \(9\;V\), the de - Brogile wavelength associated with it will be (assume that wavelength is determined at low voltage)

1 \(\frac{\lambda }{3}\sqrt {\frac{M}{m}} \)
2 \(\frac{\lambda }{3}\frac{M}{m}\)
3 \(\frac{\lambda }{3}\sqrt {\frac{m}{M}} \)
4 \(\frac{\lambda }{3}\frac{m}{M}\)
MHTCET - 2016
PHXII11:DUAL NATURE OF RADIATION AND MATTER

357928 If \(E_{1}, E_{2}, E_{3}\) are the respective kinetic energies of an electron, an alpha-particle and a proton, each having the same de-Broglie wavelength, then

1 \({E_1} > {E_3} > {E_2}\)
2 \(E_{2}>E_{3}>E_{1}\)
3 \({E_1} > {E_2} > {E_3}\)
4 \({E_1} = {E_2} = {E_3}\)
PHXII11:DUAL NATURE OF RADIATION AND MATTER

357929 The additional energy that should be given to an electron to reduce its de - Broglie wavelength from \(1\;nm\) to \(0.5\;nm\) is

1 2 times the initial kinetic energy
2 3 times the initial kinetic energy
3 0.5 times the initial kinetic energy
4 4 times the initial kinetic energy
KCET - 2005
PHXII11:DUAL NATURE OF RADIATION AND MATTER

357930 According to de - Brogile hypothesis, the wavelength associated with moving electron of mass ' \(m\) ' is \(\lambda_{e}\). Using mass energy relation and Planck's quantum theory, the wavelength associated with photon is \(\lambda_{p}\). If the energy (\(E\)) electron and photon is same, then relation between \(\lambda_{e}\) and \(\lambda_{p}\) is

1 \(\lambda_{p} \propto \lambda_{e}\)
2 \(\lambda_{p} \propto \lambda_{e}^{2}\)
3 \(\lambda_{p} \propto \sqrt{\lambda_{e}}\)
4 \(\lambda_{p} \propto \dfrac{1}{\lambda_{e}}\)
MHTCET - 2017
Join With Us for More Updates
PHXII11:DUAL NATURE OF RADIATION AND MATTER

357926 An electron of mass \({m}\) when accelerated through a potential difference \({V}\), has de Broglie wavelength \({\lambda}\). The de-Broglie wavelength associated with a particle of mass \({m / 4}\) and charge \({e}\) accelerated through the same potential difference is \({n \lambda}\). Then find the value of \({n}\).

1 2
2 4
3 8
4 6
PHXII11:DUAL NATURE OF RADIATION AND MATTER

357927 An electron of mass \(m\) has de - Brogile wavelength \(\lambda\) when accelerated through potential difference \(V\). When proton of mass \(M\), is accelerated through potential difference \(9\;V\), the de - Brogile wavelength associated with it will be (assume that wavelength is determined at low voltage)

1 \(\frac{\lambda }{3}\sqrt {\frac{M}{m}} \)
2 \(\frac{\lambda }{3}\frac{M}{m}\)
3 \(\frac{\lambda }{3}\sqrt {\frac{m}{M}} \)
4 \(\frac{\lambda }{3}\frac{m}{M}\)
MHTCET - 2016
PHXII11:DUAL NATURE OF RADIATION AND MATTER

357928 If \(E_{1}, E_{2}, E_{3}\) are the respective kinetic energies of an electron, an alpha-particle and a proton, each having the same de-Broglie wavelength, then

1 \({E_1} > {E_3} > {E_2}\)
2 \(E_{2}>E_{3}>E_{1}\)
3 \({E_1} > {E_2} > {E_3}\)
4 \({E_1} = {E_2} = {E_3}\)
PHXII11:DUAL NATURE OF RADIATION AND MATTER

357929 The additional energy that should be given to an electron to reduce its de - Broglie wavelength from \(1\;nm\) to \(0.5\;nm\) is

1 2 times the initial kinetic energy
2 3 times the initial kinetic energy
3 0.5 times the initial kinetic energy
4 4 times the initial kinetic energy
KCET - 2005
PHXII11:DUAL NATURE OF RADIATION AND MATTER

357930 According to de - Brogile hypothesis, the wavelength associated with moving electron of mass ' \(m\) ' is \(\lambda_{e}\). Using mass energy relation and Planck's quantum theory, the wavelength associated with photon is \(\lambda_{p}\). If the energy (\(E\)) electron and photon is same, then relation between \(\lambda_{e}\) and \(\lambda_{p}\) is

1 \(\lambda_{p} \propto \lambda_{e}\)
2 \(\lambda_{p} \propto \lambda_{e}^{2}\)
3 \(\lambda_{p} \propto \sqrt{\lambda_{e}}\)
4 \(\lambda_{p} \propto \dfrac{1}{\lambda_{e}}\)
MHTCET - 2017
For More Updates join with Us
PHXII11:DUAL NATURE OF RADIATION AND MATTER

357926 An electron of mass \({m}\) when accelerated through a potential difference \({V}\), has de Broglie wavelength \({\lambda}\). The de-Broglie wavelength associated with a particle of mass \({m / 4}\) and charge \({e}\) accelerated through the same potential difference is \({n \lambda}\). Then find the value of \({n}\).

1 2
2 4
3 8
4 6
PHXII11:DUAL NATURE OF RADIATION AND MATTER

357927 An electron of mass \(m\) has de - Brogile wavelength \(\lambda\) when accelerated through potential difference \(V\). When proton of mass \(M\), is accelerated through potential difference \(9\;V\), the de - Brogile wavelength associated with it will be (assume that wavelength is determined at low voltage)

1 \(\frac{\lambda }{3}\sqrt {\frac{M}{m}} \)
2 \(\frac{\lambda }{3}\frac{M}{m}\)
3 \(\frac{\lambda }{3}\sqrt {\frac{m}{M}} \)
4 \(\frac{\lambda }{3}\frac{m}{M}\)
MHTCET - 2016
PHXII11:DUAL NATURE OF RADIATION AND MATTER

357928 If \(E_{1}, E_{2}, E_{3}\) are the respective kinetic energies of an electron, an alpha-particle and a proton, each having the same de-Broglie wavelength, then

1 \({E_1} > {E_3} > {E_2}\)
2 \(E_{2}>E_{3}>E_{1}\)
3 \({E_1} > {E_2} > {E_3}\)
4 \({E_1} = {E_2} = {E_3}\)
PHXII11:DUAL NATURE OF RADIATION AND MATTER

357929 The additional energy that should be given to an electron to reduce its de - Broglie wavelength from \(1\;nm\) to \(0.5\;nm\) is

1 2 times the initial kinetic energy
2 3 times the initial kinetic energy
3 0.5 times the initial kinetic energy
4 4 times the initial kinetic energy
KCET - 2005
PHXII11:DUAL NATURE OF RADIATION AND MATTER

357930 According to de - Brogile hypothesis, the wavelength associated with moving electron of mass ' \(m\) ' is \(\lambda_{e}\). Using mass energy relation and Planck's quantum theory, the wavelength associated with photon is \(\lambda_{p}\). If the energy (\(E\)) electron and photon is same, then relation between \(\lambda_{e}\) and \(\lambda_{p}\) is

1 \(\lambda_{p} \propto \lambda_{e}\)
2 \(\lambda_{p} \propto \lambda_{e}^{2}\)
3 \(\lambda_{p} \propto \sqrt{\lambda_{e}}\)
4 \(\lambda_{p} \propto \dfrac{1}{\lambda_{e}}\)
MHTCET - 2017
NEET DIGITAL LIBRARY
PHXII11:DUAL NATURE OF RADIATION AND MATTER

357926 An electron of mass \({m}\) when accelerated through a potential difference \({V}\), has de Broglie wavelength \({\lambda}\). The de-Broglie wavelength associated with a particle of mass \({m / 4}\) and charge \({e}\) accelerated through the same potential difference is \({n \lambda}\). Then find the value of \({n}\).

1 2
2 4
3 8
4 6
PHXII11:DUAL NATURE OF RADIATION AND MATTER

357927 An electron of mass \(m\) has de - Brogile wavelength \(\lambda\) when accelerated through potential difference \(V\). When proton of mass \(M\), is accelerated through potential difference \(9\;V\), the de - Brogile wavelength associated with it will be (assume that wavelength is determined at low voltage)

1 \(\frac{\lambda }{3}\sqrt {\frac{M}{m}} \)
2 \(\frac{\lambda }{3}\frac{M}{m}\)
3 \(\frac{\lambda }{3}\sqrt {\frac{m}{M}} \)
4 \(\frac{\lambda }{3}\frac{m}{M}\)
MHTCET - 2016
PHXII11:DUAL NATURE OF RADIATION AND MATTER

357928 If \(E_{1}, E_{2}, E_{3}\) are the respective kinetic energies of an electron, an alpha-particle and a proton, each having the same de-Broglie wavelength, then

1 \({E_1} > {E_3} > {E_2}\)
2 \(E_{2}>E_{3}>E_{1}\)
3 \({E_1} > {E_2} > {E_3}\)
4 \({E_1} = {E_2} = {E_3}\)
PHXII11:DUAL NATURE OF RADIATION AND MATTER

357929 The additional energy that should be given to an electron to reduce its de - Broglie wavelength from \(1\;nm\) to \(0.5\;nm\) is

1 2 times the initial kinetic energy
2 3 times the initial kinetic energy
3 0.5 times the initial kinetic energy
4 4 times the initial kinetic energy
KCET - 2005
PHXII11:DUAL NATURE OF RADIATION AND MATTER

357930 According to de - Brogile hypothesis, the wavelength associated with moving electron of mass ' \(m\) ' is \(\lambda_{e}\). Using mass energy relation and Planck's quantum theory, the wavelength associated with photon is \(\lambda_{p}\). If the energy (\(E\)) electron and photon is same, then relation between \(\lambda_{e}\) and \(\lambda_{p}\) is

1 \(\lambda_{p} \propto \lambda_{e}\)
2 \(\lambda_{p} \propto \lambda_{e}^{2}\)
3 \(\lambda_{p} \propto \sqrt{\lambda_{e}}\)
4 \(\lambda_{p} \propto \dfrac{1}{\lambda_{e}}\)
MHTCET - 2017