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PHXII11:DUAL NATURE OF RADIATION AND MATTER

357781 The photoelectric work function for photo metal is $2.4 e V$ . Among the four wavelengths, the wavelength of light for which photo emission does not take place is

1

200 n m

2

300 n m

3

700 n m

4

400 n m

Explanation:

For photo electric emission wavelength $(λ)$ of radiation must be less than threshold wavelength $(λ_{0}) .$
$ω_{0} = 2.4 e V$
$λ_{0} = \frac{12400}{ω_{0}} = \frac{12400}{2.4}$
$λ_{0} = 5166 A^{0}$
$= 516.6 n m = maximum$
$∴$ For $λ = 700 n m$ photo electric effect does not take place. Correct option is (3).

KCET - 2024

PHXII11:DUAL NATURE OF RADIATION AND MATTER

357782 The maximum kinetic energy of emitted photoelectrons depends on

1 Intensity of incident radiation

2 Frequency of incident radiation

3 Speed of incident radiation

4 Number of photons in the incident rotation

Explanation:

According to Einstein's photoelectric equation,
$K_{max} = h v - ϕ_{0}$
Where $v$ is the frequency of incident radiation and $ϕ_{0}$ is the work function of a metal
Thus, the maximum kinetic energy $(K_{max})$ of emitted photoelectrons depends on frequency of incident radiation but not on its intensity, speed or number of photons in the incident radiation

PHXII11:DUAL NATURE OF RADIATION AND MATTER

357783 A photon of wavelength $4400$ $A^{\circ}$ is passing through vaccum. The effective mass and momentum of the photon are respectively

1

5 \times 10^{- 36} k g, 1.5 \times 10^{- 27} k g {m s}^{- 1}

2

5 \times 10^{- 35} k g, 1.5 \times 10^{- 26} k g {m s}^{- 1}

3 zero,

1.5 \times 10^{- 26} k g {m s}^{- 1}

4

5 \times 10^{- 36} k g, 1.67 \times 10^{- 43} k g {m s}^{- 1}

Explanation:

from de Broglie equation,
$P = \frac{h}{λ} = \frac{6.6 \times 10^{- 34}}{4400 \times 10^{- 10}} = 1.5 \times 10^{- 27} k g m s^{- 1}$
For photon, velocity $= c = 3 \times 10^{- 8} k g m s^{- 1}$
$∴ m = \frac{P}{c} = \frac{1.5 \times 10^{- 27}}{3 \times 10^{- 8}} = 5 \times 10^{- 36} k g$

PHXII11:DUAL NATURE OF RADIATION AND MATTER

357784 The work functions of Caesium $(C s)$ , Potassium $(K)$ and Sodium $(N a)$ are $2.14 e V, 2.30 e V a n d 2.75 e V$ respectively. If incident electromagnetic radiation has an incident energy of $2.20 e V$ , which of these photosensitive surfaces may emit photoelectrons?

1 Both

N a

and

K

2

K

only

3

N a

only

4

C s

only

Explanation:

Given energy of photon $E = 2.20 e V$ .
Only for $C s, W_{0} = 2.14 < E$ .
$\Rightarrow$ Only $C s$ emits photoelectrons.
Correct option is (4).

NEET - 2023

PHXII11:DUAL NATURE OF RADIATION AND MATTER

357785 Statement A :
In photon-particle collision the total energy and total momentum are conserved.
Statement B :
The number of photons are conserved in a collision.

1 Statement A is correct but Statement B is incorrect.

2 Statement A is incorrect but Statement B is correct.

3 Both statements are correct.

4 Both Statements are incorrect.

PHXII11:DUAL NATURE OF RADIATION AND MATTER

357781 The photoelectric work function for photo metal is $2.4 e V$ . Among the four wavelengths, the wavelength of light for which photo emission does not take place is

1

200 n m

2

300 n m

3

700 n m

4

400 n m

Explanation:

For photo electric emission wavelength $(λ)$ of radiation must be less than threshold wavelength $(λ_{0}) .$
$ω_{0} = 2.4 e V$
$λ_{0} = \frac{12400}{ω_{0}} = \frac{12400}{2.4}$
$λ_{0} = 5166 A^{0}$
$= 516.6 n m = maximum$
$∴$ For $λ = 700 n m$ photo electric effect does not take place. Correct option is (3).

KCET - 2024

PHXII11:DUAL NATURE OF RADIATION AND MATTER

357782 The maximum kinetic energy of emitted photoelectrons depends on

1 Intensity of incident radiation

2 Frequency of incident radiation

3 Speed of incident radiation

4 Number of photons in the incident rotation

Explanation:

According to Einstein's photoelectric equation,
$K_{max} = h v - ϕ_{0}$
Where $v$ is the frequency of incident radiation and $ϕ_{0}$ is the work function of a metal
Thus, the maximum kinetic energy $(K_{max})$ of emitted photoelectrons depends on frequency of incident radiation but not on its intensity, speed or number of photons in the incident radiation

PHXII11:DUAL NATURE OF RADIATION AND MATTER

357783 A photon of wavelength $4400$ $A^{\circ}$ is passing through vaccum. The effective mass and momentum of the photon are respectively

1

5 \times 10^{- 36} k g, 1.5 \times 10^{- 27} k g {m s}^{- 1}

2

5 \times 10^{- 35} k g, 1.5 \times 10^{- 26} k g {m s}^{- 1}

3 zero,

1.5 \times 10^{- 26} k g {m s}^{- 1}

4

5 \times 10^{- 36} k g, 1.67 \times 10^{- 43} k g {m s}^{- 1}

Explanation:

from de Broglie equation,
$P = \frac{h}{λ} = \frac{6.6 \times 10^{- 34}}{4400 \times 10^{- 10}} = 1.5 \times 10^{- 27} k g m s^{- 1}$
For photon, velocity $= c = 3 \times 10^{- 8} k g m s^{- 1}$
$∴ m = \frac{P}{c} = \frac{1.5 \times 10^{- 27}}{3 \times 10^{- 8}} = 5 \times 10^{- 36} k g$

PHXII11:DUAL NATURE OF RADIATION AND MATTER

357784 The work functions of Caesium $(C s)$ , Potassium $(K)$ and Sodium $(N a)$ are $2.14 e V, 2.30 e V a n d 2.75 e V$ respectively. If incident electromagnetic radiation has an incident energy of $2.20 e V$ , which of these photosensitive surfaces may emit photoelectrons?

1 Both

N a

and

K

2

K

only

3

N a

only

4

C s

only

Explanation:

Given energy of photon $E = 2.20 e V$ .
Only for $C s, W_{0} = 2.14 < E$ .
$\Rightarrow$ Only $C s$ emits photoelectrons.
Correct option is (4).

NEET - 2023

PHXII11:DUAL NATURE OF RADIATION AND MATTER

357785 Statement A :
In photon-particle collision the total energy and total momentum are conserved.
Statement B :
The number of photons are conserved in a collision.

1 Statement A is correct but Statement B is incorrect.

2 Statement A is incorrect but Statement B is correct.

3 Both statements are correct.

4 Both Statements are incorrect.

PHXII11:DUAL NATURE OF RADIATION AND MATTER

357781 The photoelectric work function for photo metal is $2.4 e V$ . Among the four wavelengths, the wavelength of light for which photo emission does not take place is

1

200 n m

2

300 n m

3

700 n m

4

400 n m

Explanation:

For photo electric emission wavelength $(λ)$ of radiation must be less than threshold wavelength $(λ_{0}) .$
$ω_{0} = 2.4 e V$
$λ_{0} = \frac{12400}{ω_{0}} = \frac{12400}{2.4}$
$λ_{0} = 5166 A^{0}$
$= 516.6 n m = maximum$
$∴$ For $λ = 700 n m$ photo electric effect does not take place. Correct option is (3).

KCET - 2024

PHXII11:DUAL NATURE OF RADIATION AND MATTER

357782 The maximum kinetic energy of emitted photoelectrons depends on

1 Intensity of incident radiation

2 Frequency of incident radiation

3 Speed of incident radiation

4 Number of photons in the incident rotation

Explanation:

According to Einstein's photoelectric equation,
$K_{max} = h v - ϕ_{0}$
Where $v$ is the frequency of incident radiation and $ϕ_{0}$ is the work function of a metal
Thus, the maximum kinetic energy $(K_{max})$ of emitted photoelectrons depends on frequency of incident radiation but not on its intensity, speed or number of photons in the incident radiation

PHXII11:DUAL NATURE OF RADIATION AND MATTER

357783 A photon of wavelength $4400$ $A^{\circ}$ is passing through vaccum. The effective mass and momentum of the photon are respectively

1

5 \times 10^{- 36} k g, 1.5 \times 10^{- 27} k g {m s}^{- 1}

2

5 \times 10^{- 35} k g, 1.5 \times 10^{- 26} k g {m s}^{- 1}

3 zero,

1.5 \times 10^{- 26} k g {m s}^{- 1}

4

5 \times 10^{- 36} k g, 1.67 \times 10^{- 43} k g {m s}^{- 1}

Explanation:

from de Broglie equation,
$P = \frac{h}{λ} = \frac{6.6 \times 10^{- 34}}{4400 \times 10^{- 10}} = 1.5 \times 10^{- 27} k g m s^{- 1}$
For photon, velocity $= c = 3 \times 10^{- 8} k g m s^{- 1}$
$∴ m = \frac{P}{c} = \frac{1.5 \times 10^{- 27}}{3 \times 10^{- 8}} = 5 \times 10^{- 36} k g$

PHXII11:DUAL NATURE OF RADIATION AND MATTER

357784 The work functions of Caesium $(C s)$ , Potassium $(K)$ and Sodium $(N a)$ are $2.14 e V, 2.30 e V a n d 2.75 e V$ respectively. If incident electromagnetic radiation has an incident energy of $2.20 e V$ , which of these photosensitive surfaces may emit photoelectrons?

1 Both

N a

and

K

2

K

only

3

N a

only

4

C s

only

Explanation:

Given energy of photon $E = 2.20 e V$ .
Only for $C s, W_{0} = 2.14 < E$ .
$\Rightarrow$ Only $C s$ emits photoelectrons.
Correct option is (4).

NEET - 2023

PHXII11:DUAL NATURE OF RADIATION AND MATTER

357785 Statement A :
In photon-particle collision the total energy and total momentum are conserved.
Statement B :
The number of photons are conserved in a collision.

1 Statement A is correct but Statement B is incorrect.

2 Statement A is incorrect but Statement B is correct.

3 Both statements are correct.

4 Both Statements are incorrect.

PHXII11:DUAL NATURE OF RADIATION AND MATTER

357781 The photoelectric work function for photo metal is $2.4 e V$ . Among the four wavelengths, the wavelength of light for which photo emission does not take place is

1

200 n m

2

300 n m

3

700 n m

4

400 n m

Explanation:

For photo electric emission wavelength $(λ)$ of radiation must be less than threshold wavelength $(λ_{0}) .$
$ω_{0} = 2.4 e V$
$λ_{0} = \frac{12400}{ω_{0}} = \frac{12400}{2.4}$
$λ_{0} = 5166 A^{0}$
$= 516.6 n m = maximum$
$∴$ For $λ = 700 n m$ photo electric effect does not take place. Correct option is (3).

KCET - 2024

PHXII11:DUAL NATURE OF RADIATION AND MATTER

357782 The maximum kinetic energy of emitted photoelectrons depends on

1 Intensity of incident radiation

2 Frequency of incident radiation

3 Speed of incident radiation

4 Number of photons in the incident rotation

Explanation:

According to Einstein's photoelectric equation,
$K_{max} = h v - ϕ_{0}$
Where $v$ is the frequency of incident radiation and $ϕ_{0}$ is the work function of a metal
Thus, the maximum kinetic energy $(K_{max})$ of emitted photoelectrons depends on frequency of incident radiation but not on its intensity, speed or number of photons in the incident radiation

PHXII11:DUAL NATURE OF RADIATION AND MATTER

357783 A photon of wavelength $4400$ $A^{\circ}$ is passing through vaccum. The effective mass and momentum of the photon are respectively

1

5 \times 10^{- 36} k g, 1.5 \times 10^{- 27} k g {m s}^{- 1}

2

5 \times 10^{- 35} k g, 1.5 \times 10^{- 26} k g {m s}^{- 1}

3 zero,

1.5 \times 10^{- 26} k g {m s}^{- 1}

4

5 \times 10^{- 36} k g, 1.67 \times 10^{- 43} k g {m s}^{- 1}

Explanation:

from de Broglie equation,
$P = \frac{h}{λ} = \frac{6.6 \times 10^{- 34}}{4400 \times 10^{- 10}} = 1.5 \times 10^{- 27} k g m s^{- 1}$
For photon, velocity $= c = 3 \times 10^{- 8} k g m s^{- 1}$
$∴ m = \frac{P}{c} = \frac{1.5 \times 10^{- 27}}{3 \times 10^{- 8}} = 5 \times 10^{- 36} k g$

PHXII11:DUAL NATURE OF RADIATION AND MATTER

357784 The work functions of Caesium $(C s)$ , Potassium $(K)$ and Sodium $(N a)$ are $2.14 e V, 2.30 e V a n d 2.75 e V$ respectively. If incident electromagnetic radiation has an incident energy of $2.20 e V$ , which of these photosensitive surfaces may emit photoelectrons?

1 Both

N a

and

K

2

K

only

3

N a

only

4

C s

only

Explanation:

Given energy of photon $E = 2.20 e V$ .
Only for $C s, W_{0} = 2.14 < E$ .
$\Rightarrow$ Only $C s$ emits photoelectrons.
Correct option is (4).

NEET - 2023

PHXII11:DUAL NATURE OF RADIATION AND MATTER

357785 Statement A :
In photon-particle collision the total energy and total momentum are conserved.
Statement B :
The number of photons are conserved in a collision.

1 Statement A is correct but Statement B is incorrect.

2 Statement A is incorrect but Statement B is correct.

3 Both statements are correct.

4 Both Statements are incorrect.

PHXII11:DUAL NATURE OF RADIATION AND MATTER

357781 The photoelectric work function for photo metal is $2.4 e V$ . Among the four wavelengths, the wavelength of light for which photo emission does not take place is

1

200 n m

2

300 n m

3

700 n m

4

400 n m

Explanation:

For photo electric emission wavelength $(λ)$ of radiation must be less than threshold wavelength $(λ_{0}) .$
$ω_{0} = 2.4 e V$
$λ_{0} = \frac{12400}{ω_{0}} = \frac{12400}{2.4}$
$λ_{0} = 5166 A^{0}$
$= 516.6 n m = maximum$
$∴$ For $λ = 700 n m$ photo electric effect does not take place. Correct option is (3).

KCET - 2024

PHXII11:DUAL NATURE OF RADIATION AND MATTER

357782 The maximum kinetic energy of emitted photoelectrons depends on

1 Intensity of incident radiation

2 Frequency of incident radiation

3 Speed of incident radiation

4 Number of photons in the incident rotation

Explanation:

According to Einstein's photoelectric equation,
$K_{max} = h v - ϕ_{0}$
Where $v$ is the frequency of incident radiation and $ϕ_{0}$ is the work function of a metal
Thus, the maximum kinetic energy $(K_{max})$ of emitted photoelectrons depends on frequency of incident radiation but not on its intensity, speed or number of photons in the incident radiation

PHXII11:DUAL NATURE OF RADIATION AND MATTER

357783 A photon of wavelength $4400$ $A^{\circ}$ is passing through vaccum. The effective mass and momentum of the photon are respectively

1

5 \times 10^{- 36} k g, 1.5 \times 10^{- 27} k g {m s}^{- 1}

2

5 \times 10^{- 35} k g, 1.5 \times 10^{- 26} k g {m s}^{- 1}

3 zero,

1.5 \times 10^{- 26} k g {m s}^{- 1}

4

5 \times 10^{- 36} k g, 1.67 \times 10^{- 43} k g {m s}^{- 1}

Explanation:

from de Broglie equation,
$P = \frac{h}{λ} = \frac{6.6 \times 10^{- 34}}{4400 \times 10^{- 10}} = 1.5 \times 10^{- 27} k g m s^{- 1}$
For photon, velocity $= c = 3 \times 10^{- 8} k g m s^{- 1}$
$∴ m = \frac{P}{c} = \frac{1.5 \times 10^{- 27}}{3 \times 10^{- 8}} = 5 \times 10^{- 36} k g$

PHXII11:DUAL NATURE OF RADIATION AND MATTER

357784 The work functions of Caesium $(C s)$ , Potassium $(K)$ and Sodium $(N a)$ are $2.14 e V, 2.30 e V a n d 2.75 e V$ respectively. If incident electromagnetic radiation has an incident energy of $2.20 e V$ , which of these photosensitive surfaces may emit photoelectrons?

1 Both

N a

and

K

2

K

only

3

N a

only

4

C s

only

Explanation:

Given energy of photon $E = 2.20 e V$ .
Only for $C s, W_{0} = 2.14 < E$ .
$\Rightarrow$ Only $C s$ emits photoelectrons.
Correct option is (4).

NEET - 2023

PHXII11:DUAL NATURE OF RADIATION AND MATTER

357785 Statement A :
In photon-particle collision the total energy and total momentum are conserved.
Statement B :
The number of photons are conserved in a collision.

1 Statement A is correct but Statement B is incorrect.

2 Statement A is incorrect but Statement B is correct.

3 Both statements are correct.

4 Both Statements are incorrect.