357670
In a photocell, frequency of incident radiation is increased by keeping other factors constant \(\left( {\nu > {\nu _0}} \right)\), the stopping potential
1 Decreases
2 Increases
3 Becomes zero
4 First decreases and the increases
Explanation:
We know that \(e V_{0}=h v-h v_{0}\) or \(e V_{0}=h\left(v-v_{0}\right)\) or \(V_{0}=\dfrac{h}{e}\left(v-v_{0}\right)\) Here \(V_{0}=\) stopping potential and \(V = \) frequency of incident radiation Therefore, stopping potential is directly proportional to the frequency of incident radiation. Hence, stopping potential \(V_{0}\) is increased.
MHTCET - 2018
PHXII11:DUAL NATURE OF RADIATION AND MATTER
357671
Light of wavelength \(\lambda\) which is less than threshold wavelength is incident on a photosensitive material. If incident wavelength is decreased, then stopping potential will
1 Increase
2 Decrease
3 Be zero
4 Become exactly half
Explanation:
According to photoelectric equation \(\frac{{hc}}{\lambda } - \phi = \frac{1}{2}m{v^2} = e{V_S}\) Symbols have their usual meaning If we decrease the wavelength \(\lambda\), then stopping potential \({V_S}\) will increase.
MHTCET - 2016
PHXII11:DUAL NATURE OF RADIATION AND MATTER
357672
The stopping potential of most energetic photoelectron emitted from a metal becomes three times of initial value when the wavelength of incident radiation is reduced from \({\lambda_{1}}\) to \({\lambda_{2}}\). The work function of metal is
357673
From the following graph of photo current aganist collector plate potential, for two different intensities of light \(I_{1}\) and \(I_{2}\) one can conclude
1 \(I_{1}=I_{2}\)
2 \(I_{1}>I_{2}\)
3 \({I_1} < {I_2}\)
4 comparsion is not possible
Explanation:
For a given frequency of incident radiation, light of higher intensity produces larger value of current. Hence \(I_{2}>I_{1}\).
357670
In a photocell, frequency of incident radiation is increased by keeping other factors constant \(\left( {\nu > {\nu _0}} \right)\), the stopping potential
1 Decreases
2 Increases
3 Becomes zero
4 First decreases and the increases
Explanation:
We know that \(e V_{0}=h v-h v_{0}\) or \(e V_{0}=h\left(v-v_{0}\right)\) or \(V_{0}=\dfrac{h}{e}\left(v-v_{0}\right)\) Here \(V_{0}=\) stopping potential and \(V = \) frequency of incident radiation Therefore, stopping potential is directly proportional to the frequency of incident radiation. Hence, stopping potential \(V_{0}\) is increased.
MHTCET - 2018
PHXII11:DUAL NATURE OF RADIATION AND MATTER
357671
Light of wavelength \(\lambda\) which is less than threshold wavelength is incident on a photosensitive material. If incident wavelength is decreased, then stopping potential will
1 Increase
2 Decrease
3 Be zero
4 Become exactly half
Explanation:
According to photoelectric equation \(\frac{{hc}}{\lambda } - \phi = \frac{1}{2}m{v^2} = e{V_S}\) Symbols have their usual meaning If we decrease the wavelength \(\lambda\), then stopping potential \({V_S}\) will increase.
MHTCET - 2016
PHXII11:DUAL NATURE OF RADIATION AND MATTER
357672
The stopping potential of most energetic photoelectron emitted from a metal becomes three times of initial value when the wavelength of incident radiation is reduced from \({\lambda_{1}}\) to \({\lambda_{2}}\). The work function of metal is
357673
From the following graph of photo current aganist collector plate potential, for two different intensities of light \(I_{1}\) and \(I_{2}\) one can conclude
1 \(I_{1}=I_{2}\)
2 \(I_{1}>I_{2}\)
3 \({I_1} < {I_2}\)
4 comparsion is not possible
Explanation:
For a given frequency of incident radiation, light of higher intensity produces larger value of current. Hence \(I_{2}>I_{1}\).
NEET Test Series from KOTA - 10 Papers In MS WORD
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PHXII11:DUAL NATURE OF RADIATION AND MATTER
357670
In a photocell, frequency of incident radiation is increased by keeping other factors constant \(\left( {\nu > {\nu _0}} \right)\), the stopping potential
1 Decreases
2 Increases
3 Becomes zero
4 First decreases and the increases
Explanation:
We know that \(e V_{0}=h v-h v_{0}\) or \(e V_{0}=h\left(v-v_{0}\right)\) or \(V_{0}=\dfrac{h}{e}\left(v-v_{0}\right)\) Here \(V_{0}=\) stopping potential and \(V = \) frequency of incident radiation Therefore, stopping potential is directly proportional to the frequency of incident radiation. Hence, stopping potential \(V_{0}\) is increased.
MHTCET - 2018
PHXII11:DUAL NATURE OF RADIATION AND MATTER
357671
Light of wavelength \(\lambda\) which is less than threshold wavelength is incident on a photosensitive material. If incident wavelength is decreased, then stopping potential will
1 Increase
2 Decrease
3 Be zero
4 Become exactly half
Explanation:
According to photoelectric equation \(\frac{{hc}}{\lambda } - \phi = \frac{1}{2}m{v^2} = e{V_S}\) Symbols have their usual meaning If we decrease the wavelength \(\lambda\), then stopping potential \({V_S}\) will increase.
MHTCET - 2016
PHXII11:DUAL NATURE OF RADIATION AND MATTER
357672
The stopping potential of most energetic photoelectron emitted from a metal becomes three times of initial value when the wavelength of incident radiation is reduced from \({\lambda_{1}}\) to \({\lambda_{2}}\). The work function of metal is
357673
From the following graph of photo current aganist collector plate potential, for two different intensities of light \(I_{1}\) and \(I_{2}\) one can conclude
1 \(I_{1}=I_{2}\)
2 \(I_{1}>I_{2}\)
3 \({I_1} < {I_2}\)
4 comparsion is not possible
Explanation:
For a given frequency of incident radiation, light of higher intensity produces larger value of current. Hence \(I_{2}>I_{1}\).
357670
In a photocell, frequency of incident radiation is increased by keeping other factors constant \(\left( {\nu > {\nu _0}} \right)\), the stopping potential
1 Decreases
2 Increases
3 Becomes zero
4 First decreases and the increases
Explanation:
We know that \(e V_{0}=h v-h v_{0}\) or \(e V_{0}=h\left(v-v_{0}\right)\) or \(V_{0}=\dfrac{h}{e}\left(v-v_{0}\right)\) Here \(V_{0}=\) stopping potential and \(V = \) frequency of incident radiation Therefore, stopping potential is directly proportional to the frequency of incident radiation. Hence, stopping potential \(V_{0}\) is increased.
MHTCET - 2018
PHXII11:DUAL NATURE OF RADIATION AND MATTER
357671
Light of wavelength \(\lambda\) which is less than threshold wavelength is incident on a photosensitive material. If incident wavelength is decreased, then stopping potential will
1 Increase
2 Decrease
3 Be zero
4 Become exactly half
Explanation:
According to photoelectric equation \(\frac{{hc}}{\lambda } - \phi = \frac{1}{2}m{v^2} = e{V_S}\) Symbols have their usual meaning If we decrease the wavelength \(\lambda\), then stopping potential \({V_S}\) will increase.
MHTCET - 2016
PHXII11:DUAL NATURE OF RADIATION AND MATTER
357672
The stopping potential of most energetic photoelectron emitted from a metal becomes three times of initial value when the wavelength of incident radiation is reduced from \({\lambda_{1}}\) to \({\lambda_{2}}\). The work function of metal is
357673
From the following graph of photo current aganist collector plate potential, for two different intensities of light \(I_{1}\) and \(I_{2}\) one can conclude
1 \(I_{1}=I_{2}\)
2 \(I_{1}>I_{2}\)
3 \({I_1} < {I_2}\)
4 comparsion is not possible
Explanation:
For a given frequency of incident radiation, light of higher intensity produces larger value of current. Hence \(I_{2}>I_{1}\).
