Explanation:
The slope of \(I\)-\(V\) graph gives the reciprocal of resistance.
i.e.,\(\tan \theta = \frac{1}{R}\)
where \(\theta \) is the angle which the line makes with the \(V\)-axis. From the graph,
\({\rm{As}}\,{\theta _Q} > {\theta _P}\)
\(\therefore \,\,{\rm{tan}}{\theta _Q} > \tan {\theta _P}\)
or \(\frac{1}{{{R_Q}}} > \frac{1}{{{R_P}}}\,\,\,\,or\,\,\,{R_P} > \,\,{R_Q}\)
