Kirchhoff’s Laws
PHXII03:CURRENT ELECTRICITY

357422 In the given figure \({R_1} = 10\,{\mkern 1mu} {\mkern 1mu} \Omega ,\) \({R_2} = 8{\mkern 1mu} {\mkern 1mu} \,\Omega ,\) \({R_3} = 4\,{\mkern 1mu} {\mkern 1mu} \Omega \) and \({R_4} = 8\,\,\Omega .\) Battery is ideal with emf \(12\,V.\) Equivalent resistance of the circuit and current supplied by the battery are respectively
supporting img

1 \(12\,\,\Omega \) and \(1\,A\)
2 \(10.5\,\,\Omega \) and \(1\,A\)
3 \(12\,\,\Omega \) and \(11.4\,A\)
4 \(10.5\,\,\Omega \) and \(1.14\,A\)
PHXII03:CURRENT ELECTRICITY

357423 In the circuit given the current in each resistance is:
supporting img

1 1 \(A\)
2 0 \(A\)
3 0.25 \(A\)
4 0.5 \(A\)
PHXII03:CURRENT ELECTRICITY

357424 The value of \(I\) in the figure shown below is
supporting img

1 \(19\,A\)
2 \(21\,A\)
3 \(8\,A\)
4 \(4\,A\)
PHXII03:CURRENT ELECTRICITY

357425 The potential difference between \(A\) and \(B\) in the following figure is
supporting img

1 \(24\,V\)
2 \(14\,V\)
3 \(32\,V\)
4 \(48\,V\)
PHXII03:CURRENT ELECTRICITY

357422 In the given figure \({R_1} = 10\,{\mkern 1mu} {\mkern 1mu} \Omega ,\) \({R_2} = 8{\mkern 1mu} {\mkern 1mu} \,\Omega ,\) \({R_3} = 4\,{\mkern 1mu} {\mkern 1mu} \Omega \) and \({R_4} = 8\,\,\Omega .\) Battery is ideal with emf \(12\,V.\) Equivalent resistance of the circuit and current supplied by the battery are respectively
supporting img

1 \(12\,\,\Omega \) and \(1\,A\)
2 \(10.5\,\,\Omega \) and \(1\,A\)
3 \(12\,\,\Omega \) and \(11.4\,A\)
4 \(10.5\,\,\Omega \) and \(1.14\,A\)
PHXII03:CURRENT ELECTRICITY

357423 In the circuit given the current in each resistance is:
supporting img

1 1 \(A\)
2 0 \(A\)
3 0.25 \(A\)
4 0.5 \(A\)
PHXII03:CURRENT ELECTRICITY

357424 The value of \(I\) in the figure shown below is
supporting img

1 \(19\,A\)
2 \(21\,A\)
3 \(8\,A\)
4 \(4\,A\)
PHXII03:CURRENT ELECTRICITY

357425 The potential difference between \(A\) and \(B\) in the following figure is
supporting img

1 \(24\,V\)
2 \(14\,V\)
3 \(32\,V\)
4 \(48\,V\)
NEET Test Series from KOTA - 10 Papers In MS WORD WhatsApp Here
PHXII03:CURRENT ELECTRICITY

357422 In the given figure \({R_1} = 10\,{\mkern 1mu} {\mkern 1mu} \Omega ,\) \({R_2} = 8{\mkern 1mu} {\mkern 1mu} \,\Omega ,\) \({R_3} = 4\,{\mkern 1mu} {\mkern 1mu} \Omega \) and \({R_4} = 8\,\,\Omega .\) Battery is ideal with emf \(12\,V.\) Equivalent resistance of the circuit and current supplied by the battery are respectively
supporting img

1 \(12\,\,\Omega \) and \(1\,A\)
2 \(10.5\,\,\Omega \) and \(1\,A\)
3 \(12\,\,\Omega \) and \(11.4\,A\)
4 \(10.5\,\,\Omega \) and \(1.14\,A\)
PHXII03:CURRENT ELECTRICITY

357423 In the circuit given the current in each resistance is:
supporting img

1 1 \(A\)
2 0 \(A\)
3 0.25 \(A\)
4 0.5 \(A\)
PHXII03:CURRENT ELECTRICITY

357424 The value of \(I\) in the figure shown below is
supporting img

1 \(19\,A\)
2 \(21\,A\)
3 \(8\,A\)
4 \(4\,A\)
PHXII03:CURRENT ELECTRICITY

357425 The potential difference between \(A\) and \(B\) in the following figure is
supporting img

1 \(24\,V\)
2 \(14\,V\)
3 \(32\,V\)
4 \(48\,V\)
PHXII03:CURRENT ELECTRICITY

357422 In the given figure \({R_1} = 10\,{\mkern 1mu} {\mkern 1mu} \Omega ,\) \({R_2} = 8{\mkern 1mu} {\mkern 1mu} \,\Omega ,\) \({R_3} = 4\,{\mkern 1mu} {\mkern 1mu} \Omega \) and \({R_4} = 8\,\,\Omega .\) Battery is ideal with emf \(12\,V.\) Equivalent resistance of the circuit and current supplied by the battery are respectively
supporting img

1 \(12\,\,\Omega \) and \(1\,A\)
2 \(10.5\,\,\Omega \) and \(1\,A\)
3 \(12\,\,\Omega \) and \(11.4\,A\)
4 \(10.5\,\,\Omega \) and \(1.14\,A\)
PHXII03:CURRENT ELECTRICITY

357423 In the circuit given the current in each resistance is:
supporting img

1 1 \(A\)
2 0 \(A\)
3 0.25 \(A\)
4 0.5 \(A\)
PHXII03:CURRENT ELECTRICITY

357424 The value of \(I\) in the figure shown below is
supporting img

1 \(19\,A\)
2 \(21\,A\)
3 \(8\,A\)
4 \(4\,A\)
PHXII03:CURRENT ELECTRICITY

357425 The potential difference between \(A\) and \(B\) in the following figure is
supporting img

1 \(24\,V\)
2 \(14\,V\)
3 \(32\,V\)
4 \(48\,V\)