Kirchhoff’s Laws
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PHXII03:CURRENT ELECTRICITY

357383 Find \(X\) in the figures. So that galvanometer shows null deflection.
supporting img

1 \(250\;\Omega \)
2 \(100\;\Omega \)
3 \(400\;\Omega \)
4 \(200\;\Omega \)
PHXII03:CURRENT ELECTRICITY

357384 In the circuit shown, current through the resistance \(2\,\Omega \) is \({i_{1}}\) and current through the resistance \(30\,\Omega \) is \({i_{2}}\). The ratio \({\dfrac{i_{1}}{i_{2}}}\) is
supporting img

1 5
2 9
3 12
4 3
PHXII03:CURRENT ELECTRICITY

357385 A circuit contain two resistances \(R_{1}\) and \(R_{2}\) are in series. Find the ratio of input voltage to voltage of \(R_{2}\).

1 \(\dfrac{R_{2}}{R_{1}+R_{2}}\)
2 \(\dfrac{R_{1}+R_{2}}{R_{2}}\)
3 \(\dfrac{R_{1}+R_{2}}{R_{1}}\)
4 \(\dfrac{R_{1}}{R_{1}+R_{2}}\)
PHXII03:CURRENT ELECTRICITY

357386 Figure represents a part of the closed circuit. The potential difference between points \({A}\) and
supporting img

1 \({+9 V}\)
2 \({-9 V}\)
3 \({+3 V}\)
4 \({+6 V}\)
PHXII03:CURRENT ELECTRICITY

357387 The potential difference between \(A\) and \(B\) in the given branch of a circuit is
supporting img

1 \(6\,V\)
2 \(12\,V\)
3 \(9\,V\)
4 \(0\,V\)
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PHXII03:CURRENT ELECTRICITY

357383 Find \(X\) in the figures. So that galvanometer shows null deflection.
supporting img

1 \(250\;\Omega \)
2 \(100\;\Omega \)
3 \(400\;\Omega \)
4 \(200\;\Omega \)
PHXII03:CURRENT ELECTRICITY

357384 In the circuit shown, current through the resistance \(2\,\Omega \) is \({i_{1}}\) and current through the resistance \(30\,\Omega \) is \({i_{2}}\). The ratio \({\dfrac{i_{1}}{i_{2}}}\) is
supporting img

1 5
2 9
3 12
4 3
PHXII03:CURRENT ELECTRICITY

357385 A circuit contain two resistances \(R_{1}\) and \(R_{2}\) are in series. Find the ratio of input voltage to voltage of \(R_{2}\).

1 \(\dfrac{R_{2}}{R_{1}+R_{2}}\)
2 \(\dfrac{R_{1}+R_{2}}{R_{2}}\)
3 \(\dfrac{R_{1}+R_{2}}{R_{1}}\)
4 \(\dfrac{R_{1}}{R_{1}+R_{2}}\)
PHXII03:CURRENT ELECTRICITY

357386 Figure represents a part of the closed circuit. The potential difference between points \({A}\) and
supporting img

1 \({+9 V}\)
2 \({-9 V}\)
3 \({+3 V}\)
4 \({+6 V}\)
PHXII03:CURRENT ELECTRICITY

357387 The potential difference between \(A\) and \(B\) in the given branch of a circuit is
supporting img

1 \(6\,V\)
2 \(12\,V\)
3 \(9\,V\)
4 \(0\,V\)
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NEET Test Series from KOTA - 10 Papers In MS WORD WhatsApp Here
PHXII03:CURRENT ELECTRICITY

357383 Find \(X\) in the figures. So that galvanometer shows null deflection.
supporting img

1 \(250\;\Omega \)
2 \(100\;\Omega \)
3 \(400\;\Omega \)
4 \(200\;\Omega \)
PHXII03:CURRENT ELECTRICITY

357384 In the circuit shown, current through the resistance \(2\,\Omega \) is \({i_{1}}\) and current through the resistance \(30\,\Omega \) is \({i_{2}}\). The ratio \({\dfrac{i_{1}}{i_{2}}}\) is
supporting img

1 5
2 9
3 12
4 3
PHXII03:CURRENT ELECTRICITY

357385 A circuit contain two resistances \(R_{1}\) and \(R_{2}\) are in series. Find the ratio of input voltage to voltage of \(R_{2}\).

1 \(\dfrac{R_{2}}{R_{1}+R_{2}}\)
2 \(\dfrac{R_{1}+R_{2}}{R_{2}}\)
3 \(\dfrac{R_{1}+R_{2}}{R_{1}}\)
4 \(\dfrac{R_{1}}{R_{1}+R_{2}}\)
PHXII03:CURRENT ELECTRICITY

357386 Figure represents a part of the closed circuit. The potential difference between points \({A}\) and
supporting img

1 \({+9 V}\)
2 \({-9 V}\)
3 \({+3 V}\)
4 \({+6 V}\)
PHXII03:CURRENT ELECTRICITY

357387 The potential difference between \(A\) and \(B\) in the given branch of a circuit is
supporting img

1 \(6\,V\)
2 \(12\,V\)
3 \(9\,V\)
4 \(0\,V\)
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PHXII03:CURRENT ELECTRICITY

357383 Find \(X\) in the figures. So that galvanometer shows null deflection.
supporting img

1 \(250\;\Omega \)
2 \(100\;\Omega \)
3 \(400\;\Omega \)
4 \(200\;\Omega \)
PHXII03:CURRENT ELECTRICITY

357384 In the circuit shown, current through the resistance \(2\,\Omega \) is \({i_{1}}\) and current through the resistance \(30\,\Omega \) is \({i_{2}}\). The ratio \({\dfrac{i_{1}}{i_{2}}}\) is
supporting img

1 5
2 9
3 12
4 3
PHXII03:CURRENT ELECTRICITY

357385 A circuit contain two resistances \(R_{1}\) and \(R_{2}\) are in series. Find the ratio of input voltage to voltage of \(R_{2}\).

1 \(\dfrac{R_{2}}{R_{1}+R_{2}}\)
2 \(\dfrac{R_{1}+R_{2}}{R_{2}}\)
3 \(\dfrac{R_{1}+R_{2}}{R_{1}}\)
4 \(\dfrac{R_{1}}{R_{1}+R_{2}}\)
PHXII03:CURRENT ELECTRICITY

357386 Figure represents a part of the closed circuit. The potential difference between points \({A}\) and
supporting img

1 \({+9 V}\)
2 \({-9 V}\)
3 \({+3 V}\)
4 \({+6 V}\)
PHXII03:CURRENT ELECTRICITY

357387 The potential difference between \(A\) and \(B\) in the given branch of a circuit is
supporting img

1 \(6\,V\)
2 \(12\,V\)
3 \(9\,V\)
4 \(0\,V\)
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PHXII03:CURRENT ELECTRICITY

357383 Find \(X\) in the figures. So that galvanometer shows null deflection.
supporting img

1 \(250\;\Omega \)
2 \(100\;\Omega \)
3 \(400\;\Omega \)
4 \(200\;\Omega \)
PHXII03:CURRENT ELECTRICITY

357384 In the circuit shown, current through the resistance \(2\,\Omega \) is \({i_{1}}\) and current through the resistance \(30\,\Omega \) is \({i_{2}}\). The ratio \({\dfrac{i_{1}}{i_{2}}}\) is
supporting img

1 5
2 9
3 12
4 3
PHXII03:CURRENT ELECTRICITY

357385 A circuit contain two resistances \(R_{1}\) and \(R_{2}\) are in series. Find the ratio of input voltage to voltage of \(R_{2}\).

1 \(\dfrac{R_{2}}{R_{1}+R_{2}}\)
2 \(\dfrac{R_{1}+R_{2}}{R_{2}}\)
3 \(\dfrac{R_{1}+R_{2}}{R_{1}}\)
4 \(\dfrac{R_{1}}{R_{1}+R_{2}}\)
PHXII03:CURRENT ELECTRICITY

357386 Figure represents a part of the closed circuit. The potential difference between points \({A}\) and
supporting img

1 \({+9 V}\)
2 \({-9 V}\)
3 \({+3 V}\)
4 \({+6 V}\)
PHXII03:CURRENT ELECTRICITY

357387 The potential difference between \(A\) and \(B\) in the given branch of a circuit is
supporting img

1 \(6\,V\)
2 \(12\,V\)
3 \(9\,V\)
4 \(0\,V\)