Electrical Instruments
PHXII03:CURRENT ELECTRICITY

357337 In potentiometer experiment, null point is obtained at a particular point for a cell on potentiometer wire cm long. If the length of the potentiometer wire is increased without changing the cell, the balancing length will ( driving source is not changed

1 \({\rm{Increase}}\)
2 \({\rm{Decrease}}\)
3 \({\rm{Not change}}\)
4 \({\rm{Become zero}}\)
PHXII03:CURRENT ELECTRICITY

357338 To determine the internal resistance of a cell by using a potentiometer the null point is at \(1\,m\) when the cell is shunted by \(3\,\Omega \) resistance and at a length \(1.5\,m.\) When cell is shunted by \(6\,\Omega \) resistance, the internal resistance of the cell is

1 \(4\,\Omega \)
2 \(8\,\Omega \)
3 \(3\,\Omega \)
4 \(6\,\Omega \)
PHXII03:CURRENT ELECTRICITY

357339 The resistivity of potentiometer wire is \(40 \times {10^{ - 8}}\) ohm-metre and its area of cross-section is \(8 \times {10^{ - 6}}{m^2}\). If 0.2 ampere current is flowing through the wire, then the potential gradient of the wire is

1 \({10^{ - 1}}V/m\)
2 \({10^{ - 2}}V/m\)
3 \({10^{ - 3}}V/m\)
4 \({10^{ - 4}}V/m\)
PHXII03:CURRENT ELECTRICITY

357340 Resistance of 100 \(cm\) long potentiometer wire is \(10\,\Omega \), it is connected to a battery (2 volt) and a resistance \(R\) in series. A source of 10 \(mV\) gives null point at 40 \(cm\) length, then external resistance \(R\) is

1 \(590\,\Omega \)
2 \(790\,\Omega \)
3 \(990\,\Omega \)
4 \(490\,\Omega \)
PHXII03:CURRENT ELECTRICITY

357337 In potentiometer experiment, null point is obtained at a particular point for a cell on potentiometer wire cm long. If the length of the potentiometer wire is increased without changing the cell, the balancing length will ( driving source is not changed

1 \({\rm{Increase}}\)
2 \({\rm{Decrease}}\)
3 \({\rm{Not change}}\)
4 \({\rm{Become zero}}\)
PHXII03:CURRENT ELECTRICITY

357338 To determine the internal resistance of a cell by using a potentiometer the null point is at \(1\,m\) when the cell is shunted by \(3\,\Omega \) resistance and at a length \(1.5\,m.\) When cell is shunted by \(6\,\Omega \) resistance, the internal resistance of the cell is

1 \(4\,\Omega \)
2 \(8\,\Omega \)
3 \(3\,\Omega \)
4 \(6\,\Omega \)
PHXII03:CURRENT ELECTRICITY

357339 The resistivity of potentiometer wire is \(40 \times {10^{ - 8}}\) ohm-metre and its area of cross-section is \(8 \times {10^{ - 6}}{m^2}\). If 0.2 ampere current is flowing through the wire, then the potential gradient of the wire is

1 \({10^{ - 1}}V/m\)
2 \({10^{ - 2}}V/m\)
3 \({10^{ - 3}}V/m\)
4 \({10^{ - 4}}V/m\)
PHXII03:CURRENT ELECTRICITY

357340 Resistance of 100 \(cm\) long potentiometer wire is \(10\,\Omega \), it is connected to a battery (2 volt) and a resistance \(R\) in series. A source of 10 \(mV\) gives null point at 40 \(cm\) length, then external resistance \(R\) is

1 \(590\,\Omega \)
2 \(790\,\Omega \)
3 \(990\,\Omega \)
4 \(490\,\Omega \)
PHXII03:CURRENT ELECTRICITY

357337 In potentiometer experiment, null point is obtained at a particular point for a cell on potentiometer wire cm long. If the length of the potentiometer wire is increased without changing the cell, the balancing length will ( driving source is not changed

1 \({\rm{Increase}}\)
2 \({\rm{Decrease}}\)
3 \({\rm{Not change}}\)
4 \({\rm{Become zero}}\)
PHXII03:CURRENT ELECTRICITY

357338 To determine the internal resistance of a cell by using a potentiometer the null point is at \(1\,m\) when the cell is shunted by \(3\,\Omega \) resistance and at a length \(1.5\,m.\) When cell is shunted by \(6\,\Omega \) resistance, the internal resistance of the cell is

1 \(4\,\Omega \)
2 \(8\,\Omega \)
3 \(3\,\Omega \)
4 \(6\,\Omega \)
PHXII03:CURRENT ELECTRICITY

357339 The resistivity of potentiometer wire is \(40 \times {10^{ - 8}}\) ohm-metre and its area of cross-section is \(8 \times {10^{ - 6}}{m^2}\). If 0.2 ampere current is flowing through the wire, then the potential gradient of the wire is

1 \({10^{ - 1}}V/m\)
2 \({10^{ - 2}}V/m\)
3 \({10^{ - 3}}V/m\)
4 \({10^{ - 4}}V/m\)
PHXII03:CURRENT ELECTRICITY

357340 Resistance of 100 \(cm\) long potentiometer wire is \(10\,\Omega \), it is connected to a battery (2 volt) and a resistance \(R\) in series. A source of 10 \(mV\) gives null point at 40 \(cm\) length, then external resistance \(R\) is

1 \(590\,\Omega \)
2 \(790\,\Omega \)
3 \(990\,\Omega \)
4 \(490\,\Omega \)
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PHXII03:CURRENT ELECTRICITY

357337 In potentiometer experiment, null point is obtained at a particular point for a cell on potentiometer wire cm long. If the length of the potentiometer wire is increased without changing the cell, the balancing length will ( driving source is not changed

1 \({\rm{Increase}}\)
2 \({\rm{Decrease}}\)
3 \({\rm{Not change}}\)
4 \({\rm{Become zero}}\)
PHXII03:CURRENT ELECTRICITY

357338 To determine the internal resistance of a cell by using a potentiometer the null point is at \(1\,m\) when the cell is shunted by \(3\,\Omega \) resistance and at a length \(1.5\,m.\) When cell is shunted by \(6\,\Omega \) resistance, the internal resistance of the cell is

1 \(4\,\Omega \)
2 \(8\,\Omega \)
3 \(3\,\Omega \)
4 \(6\,\Omega \)
PHXII03:CURRENT ELECTRICITY

357339 The resistivity of potentiometer wire is \(40 \times {10^{ - 8}}\) ohm-metre and its area of cross-section is \(8 \times {10^{ - 6}}{m^2}\). If 0.2 ampere current is flowing through the wire, then the potential gradient of the wire is

1 \({10^{ - 1}}V/m\)
2 \({10^{ - 2}}V/m\)
3 \({10^{ - 3}}V/m\)
4 \({10^{ - 4}}V/m\)
PHXII03:CURRENT ELECTRICITY

357340 Resistance of 100 \(cm\) long potentiometer wire is \(10\,\Omega \), it is connected to a battery (2 volt) and a resistance \(R\) in series. A source of 10 \(mV\) gives null point at 40 \(cm\) length, then external resistance \(R\) is

1 \(590\,\Omega \)
2 \(790\,\Omega \)
3 \(990\,\Omega \)
4 \(490\,\Omega \)