Electrical Instruments
PHXII03:CURRENT ELECTRICITY

357294 A potentiometer wire is 4\(m\) long and potential difference of 3\(V\) is maintained between the ends. The emf of the cell, which balances aganist a length of 100 \(cm\) of the potentiometer wire is

1 \(0.60\,V\)
2 \(0.50\,V\)
3 \(0.25\,V\)
4 \(0.75\,V\)
PHXII03:CURRENT ELECTRICITY

357295 Two cells of emfs \(E_{1}\) and \(E_{2}\left(E_{1}>E_{2}\right)\) are connected as shown in figure.
supporting img
When a potentiometer is connected between \(A\) and \(B\),
then the balancing length of the potentiometer wire is
\(300\,cm.\) On connecting the same potentiometer between
\(A\) and \(C\), the balancing length is \(100\,cm\). The ratio \({E_1}/{E_2}\) is

1 \(3: 1\)
2 \(1: 3\)
3 \(2: 3\)
4 \(3: 2\)
PHXII03:CURRENT ELECTRICITY

357296 The daniel cell is balanced on \(125\;cm\) length of a potentiometer. Now, the cell is short circuited by a resistance of \(2\, \Omega\) and the balance point is obtained at \(100\;cm\). The internal resistance of the daniel cell is

1 \(\dfrac{4}{3}\, \Omega\)
2 \(1.5\, \Omega\)
3 \(1.25\, \Omega\)
4 \(0.5\, \Omega\)
PHXII03:CURRENT ELECTRICITY

357297 A potentiometer \(PQ\) is set up to comapre two resistances as shown in the figure. The ammeter \(A\) in the circuit reads 1.0 \(A\) when two way key \({K_3}\) is open. The balance point is at a length cm from \(P\) when two way key \({K_3}\) is plugged in between 2 and 1, while the balance point is at a length \({l_2}\) \(cm\) from \(P\) when key \({K_3}\) is plugged in between 3 and 1. The ratio of the two resistance \(\frac{{{R_1}}}{{{R_2}}}\), is found to be -
supporting img

1 \(\frac{{{l_1}}}{{{l_2} - {l_1}}}\)
2 \(\frac{{{l_2}}}{{{l_2} - {l_1}}}\)
3 \(\frac{{{l_1}}}{{{l_1} - {l_2}}}\)
4 \(\frac{{{l_2}}}{{{l_2} - {l_1}}}\)
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PHXII03:CURRENT ELECTRICITY

357294 A potentiometer wire is 4\(m\) long and potential difference of 3\(V\) is maintained between the ends. The emf of the cell, which balances aganist a length of 100 \(cm\) of the potentiometer wire is

1 \(0.60\,V\)
2 \(0.50\,V\)
3 \(0.25\,V\)
4 \(0.75\,V\)
PHXII03:CURRENT ELECTRICITY

357295 Two cells of emfs \(E_{1}\) and \(E_{2}\left(E_{1}>E_{2}\right)\) are connected as shown in figure.
supporting img
When a potentiometer is connected between \(A\) and \(B\),
then the balancing length of the potentiometer wire is
\(300\,cm.\) On connecting the same potentiometer between
\(A\) and \(C\), the balancing length is \(100\,cm\). The ratio \({E_1}/{E_2}\) is

1 \(3: 1\)
2 \(1: 3\)
3 \(2: 3\)
4 \(3: 2\)
PHXII03:CURRENT ELECTRICITY

357296 The daniel cell is balanced on \(125\;cm\) length of a potentiometer. Now, the cell is short circuited by a resistance of \(2\, \Omega\) and the balance point is obtained at \(100\;cm\). The internal resistance of the daniel cell is

1 \(\dfrac{4}{3}\, \Omega\)
2 \(1.5\, \Omega\)
3 \(1.25\, \Omega\)
4 \(0.5\, \Omega\)
PHXII03:CURRENT ELECTRICITY

357297 A potentiometer \(PQ\) is set up to comapre two resistances as shown in the figure. The ammeter \(A\) in the circuit reads 1.0 \(A\) when two way key \({K_3}\) is open. The balance point is at a length cm from \(P\) when two way key \({K_3}\) is plugged in between 2 and 1, while the balance point is at a length \({l_2}\) \(cm\) from \(P\) when key \({K_3}\) is plugged in between 3 and 1. The ratio of the two resistance \(\frac{{{R_1}}}{{{R_2}}}\), is found to be -
supporting img

1 \(\frac{{{l_1}}}{{{l_2} - {l_1}}}\)
2 \(\frac{{{l_2}}}{{{l_2} - {l_1}}}\)
3 \(\frac{{{l_1}}}{{{l_1} - {l_2}}}\)
4 \(\frac{{{l_2}}}{{{l_2} - {l_1}}}\)
PHXII03:CURRENT ELECTRICITY

357294 A potentiometer wire is 4\(m\) long and potential difference of 3\(V\) is maintained between the ends. The emf of the cell, which balances aganist a length of 100 \(cm\) of the potentiometer wire is

1 \(0.60\,V\)
2 \(0.50\,V\)
3 \(0.25\,V\)
4 \(0.75\,V\)
PHXII03:CURRENT ELECTRICITY

357295 Two cells of emfs \(E_{1}\) and \(E_{2}\left(E_{1}>E_{2}\right)\) are connected as shown in figure.
supporting img
When a potentiometer is connected between \(A\) and \(B\),
then the balancing length of the potentiometer wire is
\(300\,cm.\) On connecting the same potentiometer between
\(A\) and \(C\), the balancing length is \(100\,cm\). The ratio \({E_1}/{E_2}\) is

1 \(3: 1\)
2 \(1: 3\)
3 \(2: 3\)
4 \(3: 2\)
PHXII03:CURRENT ELECTRICITY

357296 The daniel cell is balanced on \(125\;cm\) length of a potentiometer. Now, the cell is short circuited by a resistance of \(2\, \Omega\) and the balance point is obtained at \(100\;cm\). The internal resistance of the daniel cell is

1 \(\dfrac{4}{3}\, \Omega\)
2 \(1.5\, \Omega\)
3 \(1.25\, \Omega\)
4 \(0.5\, \Omega\)
PHXII03:CURRENT ELECTRICITY

357297 A potentiometer \(PQ\) is set up to comapre two resistances as shown in the figure. The ammeter \(A\) in the circuit reads 1.0 \(A\) when two way key \({K_3}\) is open. The balance point is at a length cm from \(P\) when two way key \({K_3}\) is plugged in between 2 and 1, while the balance point is at a length \({l_2}\) \(cm\) from \(P\) when key \({K_3}\) is plugged in between 3 and 1. The ratio of the two resistance \(\frac{{{R_1}}}{{{R_2}}}\), is found to be -
supporting img

1 \(\frac{{{l_1}}}{{{l_2} - {l_1}}}\)
2 \(\frac{{{l_2}}}{{{l_2} - {l_1}}}\)
3 \(\frac{{{l_1}}}{{{l_1} - {l_2}}}\)
4 \(\frac{{{l_2}}}{{{l_2} - {l_1}}}\)
PHXII03:CURRENT ELECTRICITY

357294 A potentiometer wire is 4\(m\) long and potential difference of 3\(V\) is maintained between the ends. The emf of the cell, which balances aganist a length of 100 \(cm\) of the potentiometer wire is

1 \(0.60\,V\)
2 \(0.50\,V\)
3 \(0.25\,V\)
4 \(0.75\,V\)
PHXII03:CURRENT ELECTRICITY

357295 Two cells of emfs \(E_{1}\) and \(E_{2}\left(E_{1}>E_{2}\right)\) are connected as shown in figure.
supporting img
When a potentiometer is connected between \(A\) and \(B\),
then the balancing length of the potentiometer wire is
\(300\,cm.\) On connecting the same potentiometer between
\(A\) and \(C\), the balancing length is \(100\,cm\). The ratio \({E_1}/{E_2}\) is

1 \(3: 1\)
2 \(1: 3\)
3 \(2: 3\)
4 \(3: 2\)
PHXII03:CURRENT ELECTRICITY

357296 The daniel cell is balanced on \(125\;cm\) length of a potentiometer. Now, the cell is short circuited by a resistance of \(2\, \Omega\) and the balance point is obtained at \(100\;cm\). The internal resistance of the daniel cell is

1 \(\dfrac{4}{3}\, \Omega\)
2 \(1.5\, \Omega\)
3 \(1.25\, \Omega\)
4 \(0.5\, \Omega\)
PHXII03:CURRENT ELECTRICITY

357297 A potentiometer \(PQ\) is set up to comapre two resistances as shown in the figure. The ammeter \(A\) in the circuit reads 1.0 \(A\) when two way key \({K_3}\) is open. The balance point is at a length cm from \(P\) when two way key \({K_3}\) is plugged in between 2 and 1, while the balance point is at a length \({l_2}\) \(cm\) from \(P\) when key \({K_3}\) is plugged in between 3 and 1. The ratio of the two resistance \(\frac{{{R_1}}}{{{R_2}}}\), is found to be -
supporting img

1 \(\frac{{{l_1}}}{{{l_2} - {l_1}}}\)
2 \(\frac{{{l_2}}}{{{l_2} - {l_1}}}\)
3 \(\frac{{{l_1}}}{{{l_1} - {l_2}}}\)
4 \(\frac{{{l_2}}}{{{l_2} - {l_1}}}\)