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PHXII03:CURRENT ELECTRICITY

357102 Assertion :
There is no current in the metals in the absence of electric field.
Reason :
Motion of free electron is random.

1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.

2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.

3 Assertion is correct but Reason is incorrect.

4 Assertion is incorrect but reason is correct.

PHXII03:CURRENT ELECTRICITY

357103 A graph drawn between current through a conductor and time $t$ . Total charge flown through the conductor is
supporting img

1

2 I_{0} t_{0}

2

I_{0} t_{0} / 2

3

I_{0} t_{0}

4

I_{0} t_{0} / 4

Explanation:

Total charge
$q = \int I d t = a r e a o f t h e g r a p h$
$\Rightarrow q = \frac{1}{2} I_{0} t_{0}$

PHXII03:CURRENT ELECTRICITY

357104 The electron of hydrogen atom is considered to be revolving round a proton in circular orbit of radius $r$ with velocity $v$ . The current $i$ is

1

\frac{e v}{4 r}

2

\frac{e v}{2 r}

3

\frac{e v}{r}

4

\frac{e v}{2 π r}

Explanation:

$i = \frac{e}{t} = \frac{e}{2 π r / v} = \frac{e v}{2 π r}$

PHXII03:CURRENT ELECTRICITY

357105 The electric current through a wire varies with time as $I = I_{0} + β t$ , where $I_{0} = 20 A$ and $β = 3 A / s .$ The amount of electric charge crossed through a section of the wire in $20 s$ is

1

1000 C

2

800 C

3

80 C

4

1600 C

Explanation:

Given: $I = I_{0} + β t$
$I_{0} = 20 A; β = 3 A / s; t = 20 s$
Amount of charge passing through the wire
As $i = \frac{d q}{d t}$
$∴ q = \int_{0}^{20} I \cdot d t = \int_{0}^{20} (20 + 3 t) d t$
$: q = {[20 t + \frac{3 t^{2}}{2}]}_{0}^{20} = 20 (20 - 0) + \frac{3}{2} (20^{2} - 0^{2})$
$q = 1000 C$

JEE - 2024

PHXII03:CURRENT ELECTRICITY

357102 Assertion :
There is no current in the metals in the absence of electric field.
Reason :
Motion of free electron is random.

1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.

2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.

3 Assertion is correct but Reason is incorrect.

4 Assertion is incorrect but reason is correct.

PHXII03:CURRENT ELECTRICITY

357103 A graph drawn between current through a conductor and time $t$ . Total charge flown through the conductor is
supporting img

1

2 I_{0} t_{0}

2

I_{0} t_{0} / 2

3

I_{0} t_{0}

4

I_{0} t_{0} / 4

Explanation:

Total charge
$q = \int I d t = a r e a o f t h e g r a p h$
$\Rightarrow q = \frac{1}{2} I_{0} t_{0}$

PHXII03:CURRENT ELECTRICITY

357104 The electron of hydrogen atom is considered to be revolving round a proton in circular orbit of radius $r$ with velocity $v$ . The current $i$ is

1

\frac{e v}{4 r}

2

\frac{e v}{2 r}

3

\frac{e v}{r}

4

\frac{e v}{2 π r}

Explanation:

$i = \frac{e}{t} = \frac{e}{2 π r / v} = \frac{e v}{2 π r}$

PHXII03:CURRENT ELECTRICITY

357105 The electric current through a wire varies with time as $I = I_{0} + β t$ , where $I_{0} = 20 A$ and $β = 3 A / s .$ The amount of electric charge crossed through a section of the wire in $20 s$ is

1

1000 C

2

800 C

3

80 C

4

1600 C

Explanation:

Given: $I = I_{0} + β t$
$I_{0} = 20 A; β = 3 A / s; t = 20 s$
Amount of charge passing through the wire
As $i = \frac{d q}{d t}$
$∴ q = \int_{0}^{20} I \cdot d t = \int_{0}^{20} (20 + 3 t) d t$
$: q = {[20 t + \frac{3 t^{2}}{2}]}_{0}^{20} = 20 (20 - 0) + \frac{3}{2} (20^{2} - 0^{2})$
$q = 1000 C$

JEE - 2024

PHXII03:CURRENT ELECTRICITY

357102 Assertion :
There is no current in the metals in the absence of electric field.
Reason :
Motion of free electron is random.

1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.

2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.

3 Assertion is correct but Reason is incorrect.

4 Assertion is incorrect but reason is correct.

PHXII03:CURRENT ELECTRICITY

357103 A graph drawn between current through a conductor and time $t$ . Total charge flown through the conductor is
supporting img

1

2 I_{0} t_{0}

2

I_{0} t_{0} / 2

3

I_{0} t_{0}

4

I_{0} t_{0} / 4

Explanation:

Total charge
$q = \int I d t = a r e a o f t h e g r a p h$
$\Rightarrow q = \frac{1}{2} I_{0} t_{0}$

PHXII03:CURRENT ELECTRICITY

357104 The electron of hydrogen atom is considered to be revolving round a proton in circular orbit of radius $r$ with velocity $v$ . The current $i$ is

1

\frac{e v}{4 r}

2

\frac{e v}{2 r}

3

\frac{e v}{r}

4

\frac{e v}{2 π r}

Explanation:

$i = \frac{e}{t} = \frac{e}{2 π r / v} = \frac{e v}{2 π r}$

PHXII03:CURRENT ELECTRICITY

357105 The electric current through a wire varies with time as $I = I_{0} + β t$ , where $I_{0} = 20 A$ and $β = 3 A / s .$ The amount of electric charge crossed through a section of the wire in $20 s$ is

1

1000 C

2

800 C

3

80 C

4

1600 C

Explanation:

Given: $I = I_{0} + β t$
$I_{0} = 20 A; β = 3 A / s; t = 20 s$
Amount of charge passing through the wire
As $i = \frac{d q}{d t}$
$∴ q = \int_{0}^{20} I \cdot d t = \int_{0}^{20} (20 + 3 t) d t$
$: q = {[20 t + \frac{3 t^{2}}{2}]}_{0}^{20} = 20 (20 - 0) + \frac{3}{2} (20^{2} - 0^{2})$
$q = 1000 C$

JEE - 2024

PHXII03:CURRENT ELECTRICITY

357102 Assertion :
There is no current in the metals in the absence of electric field.
Reason :
Motion of free electron is random.

1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.

2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.

3 Assertion is correct but Reason is incorrect.

4 Assertion is incorrect but reason is correct.

PHXII03:CURRENT ELECTRICITY

357103 A graph drawn between current through a conductor and time $t$ . Total charge flown through the conductor is
supporting img

1

2 I_{0} t_{0}

2

I_{0} t_{0} / 2

3

I_{0} t_{0}

4

I_{0} t_{0} / 4

Explanation:

Total charge
$q = \int I d t = a r e a o f t h e g r a p h$
$\Rightarrow q = \frac{1}{2} I_{0} t_{0}$

PHXII03:CURRENT ELECTRICITY

357104 The electron of hydrogen atom is considered to be revolving round a proton in circular orbit of radius $r$ with velocity $v$ . The current $i$ is

1

\frac{e v}{4 r}

2

\frac{e v}{2 r}

3

\frac{e v}{r}

4

\frac{e v}{2 π r}

Explanation:

$i = \frac{e}{t} = \frac{e}{2 π r / v} = \frac{e v}{2 π r}$

PHXII03:CURRENT ELECTRICITY

357105 The electric current through a wire varies with time as $I = I_{0} + β t$ , where $I_{0} = 20 A$ and $β = 3 A / s .$ The amount of electric charge crossed through a section of the wire in $20 s$ is

1

1000 C

2

800 C

3

80 C

4

1600 C

Explanation:

Given: $I = I_{0} + β t$
$I_{0} = 20 A; β = 3 A / s; t = 20 s$
Amount of charge passing through the wire
As $i = \frac{d q}{d t}$
$∴ q = \int_{0}^{20} I \cdot d t = \int_{0}^{20} (20 + 3 t) d t$
$: q = {[20 t + \frac{3 t^{2}}{2}]}_{0}^{20} = 20 (20 - 0) + \frac{3}{2} (20^{2} - 0^{2})$
$q = 1000 C$

JEE - 2024

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