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PHXII03:CURRENT ELECTRICITY

357093 A current of 1 $m A$ flows through a copper wire. How many electrons will pass through a given point in each second

1

6.25 \times 10^{8}

2

6.25 \times 10^{31}

3

6.25 \times 10^{19}

4

6.25 \times 10^{15}

Explanation:

Current , $I = \frac{C h a r g e}{T i m e}$
as charge $q = n \times 1.6 \times 10^{- 19}$
$10^{- 3} a m p = \frac{n \times 1.6 \times 10^{- 19}}{1 \sec} n = 6.25 \times 10^{15} .$

PHXII03:CURRENT ELECTRICITY

357094 An electric current is given by the expression $I (t) = 100 \sin (120 π t) A$ . The total charge carried by the current from $t = 0 \sec$ to $t = \frac{1}{240} s e c$ is

1

2.65 C

2

0.265 C

3

26.5 C

4

265 C

Explanation:

$I = \frac{d q}{d t} \Rightarrow \int d q = \int I d t \Rightarrow q = \int_{t_{1}}^{t_{2}} i d t$
$\int I d t = \int_{0}^{\frac{1}{240}} 100 \sin (120 π t) d t = 0.265 C$

PHXII03:CURRENT ELECTRICITY

357095 An electron revolves in a circle at the rate of $10^{19}$ rounds per second. The equivalent current is $(e = 1.6 \times 10^{- 19} C$ )

1

1.0 A

2

1.6 A

3

2.0 A

4

2.6 A

Explanation:

Here,
frequency of electron $= 10^{19}$ round per sec.
$= 10^{19} H z$
$∴ T = \frac{1}{v} = 10^{- 19} \sec$
Electric charge on electron
$e = 1.6 \times 10^{- 19} C$
$∴$ Equivalent current
$= \frac{e}{T} = \frac{1.6 \times 10^{- 19}}{10^{- 19}} = 1.6 A$

PHXII03:CURRENT ELECTRICITY

357096 Assertion :
The current in a wire is due to flow of free electrons in a definite direction.
Reason :
A current carrying wire should be charged.

1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.

2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.

3 Assertion is correct but Reason is incorrect.

4 Assertion is incorrect but reason is correct.

PHXII03:CURRENT ELECTRICITY

357097 The flow of the electric current through a metallic conductor is

1 Only due to electrons

2 Only due to

+ v e

charges

3 Due to both nuclei and electrons

4 Cannot be predicted

PHXII03:CURRENT ELECTRICITY

357093 A current of 1 $m A$ flows through a copper wire. How many electrons will pass through a given point in each second

1

6.25 \times 10^{8}

2

6.25 \times 10^{31}

3

6.25 \times 10^{19}

4

6.25 \times 10^{15}

Explanation:

Current , $I = \frac{C h a r g e}{T i m e}$
as charge $q = n \times 1.6 \times 10^{- 19}$
$10^{- 3} a m p = \frac{n \times 1.6 \times 10^{- 19}}{1 \sec} n = 6.25 \times 10^{15} .$

PHXII03:CURRENT ELECTRICITY

357094 An electric current is given by the expression $I (t) = 100 \sin (120 π t) A$ . The total charge carried by the current from $t = 0 \sec$ to $t = \frac{1}{240} s e c$ is

1

2.65 C

2

0.265 C

3

26.5 C

4

265 C

Explanation:

$I = \frac{d q}{d t} \Rightarrow \int d q = \int I d t \Rightarrow q = \int_{t_{1}}^{t_{2}} i d t$
$\int I d t = \int_{0}^{\frac{1}{240}} 100 \sin (120 π t) d t = 0.265 C$

PHXII03:CURRENT ELECTRICITY

357095 An electron revolves in a circle at the rate of $10^{19}$ rounds per second. The equivalent current is $(e = 1.6 \times 10^{- 19} C$ )

1

1.0 A

2

1.6 A

3

2.0 A

4

2.6 A

Explanation:

Here,
frequency of electron $= 10^{19}$ round per sec.
$= 10^{19} H z$
$∴ T = \frac{1}{v} = 10^{- 19} \sec$
Electric charge on electron
$e = 1.6 \times 10^{- 19} C$
$∴$ Equivalent current
$= \frac{e}{T} = \frac{1.6 \times 10^{- 19}}{10^{- 19}} = 1.6 A$

PHXII03:CURRENT ELECTRICITY

357096 Assertion :
The current in a wire is due to flow of free electrons in a definite direction.
Reason :
A current carrying wire should be charged.

1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.

2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.

3 Assertion is correct but Reason is incorrect.

4 Assertion is incorrect but reason is correct.

PHXII03:CURRENT ELECTRICITY

357097 The flow of the electric current through a metallic conductor is

1 Only due to electrons

2 Only due to

+ v e

charges

3 Due to both nuclei and electrons

4 Cannot be predicted

PHXII03:CURRENT ELECTRICITY

357093 A current of 1 $m A$ flows through a copper wire. How many electrons will pass through a given point in each second

1

6.25 \times 10^{8}

2

6.25 \times 10^{31}

3

6.25 \times 10^{19}

4

6.25 \times 10^{15}

Explanation:

Current , $I = \frac{C h a r g e}{T i m e}$
as charge $q = n \times 1.6 \times 10^{- 19}$
$10^{- 3} a m p = \frac{n \times 1.6 \times 10^{- 19}}{1 \sec} n = 6.25 \times 10^{15} .$

PHXII03:CURRENT ELECTRICITY

357094 An electric current is given by the expression $I (t) = 100 \sin (120 π t) A$ . The total charge carried by the current from $t = 0 \sec$ to $t = \frac{1}{240} s e c$ is

1

2.65 C

2

0.265 C

3

26.5 C

4

265 C

Explanation:

$I = \frac{d q}{d t} \Rightarrow \int d q = \int I d t \Rightarrow q = \int_{t_{1}}^{t_{2}} i d t$
$\int I d t = \int_{0}^{\frac{1}{240}} 100 \sin (120 π t) d t = 0.265 C$

PHXII03:CURRENT ELECTRICITY

357095 An electron revolves in a circle at the rate of $10^{19}$ rounds per second. The equivalent current is $(e = 1.6 \times 10^{- 19} C$ )

1

1.0 A

2

1.6 A

3

2.0 A

4

2.6 A

Explanation:

Here,
frequency of electron $= 10^{19}$ round per sec.
$= 10^{19} H z$
$∴ T = \frac{1}{v} = 10^{- 19} \sec$
Electric charge on electron
$e = 1.6 \times 10^{- 19} C$
$∴$ Equivalent current
$= \frac{e}{T} = \frac{1.6 \times 10^{- 19}}{10^{- 19}} = 1.6 A$

PHXII03:CURRENT ELECTRICITY

357096 Assertion :
The current in a wire is due to flow of free electrons in a definite direction.
Reason :
A current carrying wire should be charged.

1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.

2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.

3 Assertion is correct but Reason is incorrect.

4 Assertion is incorrect but reason is correct.

PHXII03:CURRENT ELECTRICITY

357097 The flow of the electric current through a metallic conductor is

1 Only due to electrons

2 Only due to

+ v e

charges

3 Due to both nuclei and electrons

4 Cannot be predicted

PHXII03:CURRENT ELECTRICITY

357093 A current of 1 $m A$ flows through a copper wire. How many electrons will pass through a given point in each second

1

6.25 \times 10^{8}

2

6.25 \times 10^{31}

3

6.25 \times 10^{19}

4

6.25 \times 10^{15}

Explanation:

Current , $I = \frac{C h a r g e}{T i m e}$
as charge $q = n \times 1.6 \times 10^{- 19}$
$10^{- 3} a m p = \frac{n \times 1.6 \times 10^{- 19}}{1 \sec} n = 6.25 \times 10^{15} .$

PHXII03:CURRENT ELECTRICITY

357094 An electric current is given by the expression $I (t) = 100 \sin (120 π t) A$ . The total charge carried by the current from $t = 0 \sec$ to $t = \frac{1}{240} s e c$ is

1

2.65 C

2

0.265 C

3

26.5 C

4

265 C

Explanation:

$I = \frac{d q}{d t} \Rightarrow \int d q = \int I d t \Rightarrow q = \int_{t_{1}}^{t_{2}} i d t$
$\int I d t = \int_{0}^{\frac{1}{240}} 100 \sin (120 π t) d t = 0.265 C$

PHXII03:CURRENT ELECTRICITY

357095 An electron revolves in a circle at the rate of $10^{19}$ rounds per second. The equivalent current is $(e = 1.6 \times 10^{- 19} C$ )

1

1.0 A

2

1.6 A

3

2.0 A

4

2.6 A

Explanation:

Here,
frequency of electron $= 10^{19}$ round per sec.
$= 10^{19} H z$
$∴ T = \frac{1}{v} = 10^{- 19} \sec$
Electric charge on electron
$e = 1.6 \times 10^{- 19} C$
$∴$ Equivalent current
$= \frac{e}{T} = \frac{1.6 \times 10^{- 19}}{10^{- 19}} = 1.6 A$

PHXII03:CURRENT ELECTRICITY

357096 Assertion :
The current in a wire is due to flow of free electrons in a definite direction.
Reason :
A current carrying wire should be charged.

1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.

2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.

3 Assertion is correct but Reason is incorrect.

4 Assertion is incorrect but reason is correct.

PHXII03:CURRENT ELECTRICITY

357097 The flow of the electric current through a metallic conductor is

1 Only due to electrons

2 Only due to

+ v e

charges

3 Due to both nuclei and electrons

4 Cannot be predicted

PHXII03:CURRENT ELECTRICITY

357093 A current of 1 $m A$ flows through a copper wire. How many electrons will pass through a given point in each second

1

6.25 \times 10^{8}

2

6.25 \times 10^{31}

3

6.25 \times 10^{19}

4

6.25 \times 10^{15}

Explanation:

Current , $I = \frac{C h a r g e}{T i m e}$
as charge $q = n \times 1.6 \times 10^{- 19}$
$10^{- 3} a m p = \frac{n \times 1.6 \times 10^{- 19}}{1 \sec} n = 6.25 \times 10^{15} .$

PHXII03:CURRENT ELECTRICITY

357094 An electric current is given by the expression $I (t) = 100 \sin (120 π t) A$ . The total charge carried by the current from $t = 0 \sec$ to $t = \frac{1}{240} s e c$ is

1

2.65 C

2

0.265 C

3

26.5 C

4

265 C

Explanation:

$I = \frac{d q}{d t} \Rightarrow \int d q = \int I d t \Rightarrow q = \int_{t_{1}}^{t_{2}} i d t$
$\int I d t = \int_{0}^{\frac{1}{240}} 100 \sin (120 π t) d t = 0.265 C$

PHXII03:CURRENT ELECTRICITY

357095 An electron revolves in a circle at the rate of $10^{19}$ rounds per second. The equivalent current is $(e = 1.6 \times 10^{- 19} C$ )

1

1.0 A

2

1.6 A

3

2.0 A

4

2.6 A

Explanation:

Here,
frequency of electron $= 10^{19}$ round per sec.
$= 10^{19} H z$
$∴ T = \frac{1}{v} = 10^{- 19} \sec$
Electric charge on electron
$e = 1.6 \times 10^{- 19} C$
$∴$ Equivalent current
$= \frac{e}{T} = \frac{1.6 \times 10^{- 19}}{10^{- 19}} = 1.6 A$

PHXII03:CURRENT ELECTRICITY

357096 Assertion :
The current in a wire is due to flow of free electrons in a definite direction.
Reason :
A current carrying wire should be charged.

1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.

2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.

3 Assertion is correct but Reason is incorrect.

4 Assertion is incorrect but reason is correct.

PHXII03:CURRENT ELECTRICITY

357097 The flow of the electric current through a metallic conductor is

1 Only due to electrons

2 Only due to

+ v e

charges

3 Due to both nuclei and electrons

4 Cannot be predicted

Explanation:

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