Drift of Electrons and the Origin of Resistivity
PHXII03:CURRENT ELECTRICITY

357056 Wheatstone bridge principle is used to measure the specific resistance \(\left(S_{1}\right)\) of given wire,having length \(L\), radius \(r\). If \(X\) is the resistance of wire, then specific resistance is; \({S_1} = X\left( {\frac{{\pi {r^2}}}{L}} \right).\)
If the length of the wire gets doubled then the value of specific resistance will be:

1 \(\dfrac{S_{1}}{2}\)
2 \(S_{1}\)
3 \(\dfrac{S_{1}}{4}\)
4 \(2 S_{1}\)
PHXII03:CURRENT ELECTRICITY

357057 The electric resistance of a certain wire of iron is \(R\). If its length and radius are both doubled, then

1 The resistance will be doubled and the specific resistance will be halved
2 The resistance and the specific resistance, will both remain unchanged
3 The resistance will be halved and the specific resistance will be doubled
4 The resistance will be halved and the specific resistance will remain unchanged
PHXII03:CURRENT ELECTRICITY

357058 The radius \((r)\), length \((l)\) and resistance \((R)\) of a metal wire was measured in the laboratory as \(r = (0.35 \pm 0.05)cm,\) \(R = (100 \pm 10)ohm,\) \(l = (15 \pm 0.2)\,cm.\) The percentage error in resistivity of the material of the wire is

1 \(35.6 \%\)
2 \(39.9 \%\)
3 \(25.6 \%\)
4 \(37.3 \%\)
PHXII03:CURRENT ELECTRICITY

357059 A portion of length \(L\) is cut out of a conical solid wire. The two ends of this portion have circular cross-sections of \({r_1}\;\) and \({r_2}({r_1} > {r_2})\) radii. It is connected lengthwise to a circuit and a current \(I\) is flowing in it. The resistivity of the material of the wire \(\rho .\) Calculate the voltage developed across it.

1 \(\frac{{\rho LI}}{{\pi {r_1}}}\)
2 \(\frac{{\rho LI}}{{\pi {r_2}}}\)
3 \(\frac{{\rho LI}}{{\pi {r_1}{r_2}}}\)
4 \(\frac{{\rho LI}}{{\pi r_1^2}}\)
NEET Test Series from KOTA - 10 Papers In MS WORD WhatsApp Here
PHXII03:CURRENT ELECTRICITY

357056 Wheatstone bridge principle is used to measure the specific resistance \(\left(S_{1}\right)\) of given wire,having length \(L\), radius \(r\). If \(X\) is the resistance of wire, then specific resistance is; \({S_1} = X\left( {\frac{{\pi {r^2}}}{L}} \right).\)
If the length of the wire gets doubled then the value of specific resistance will be:

1 \(\dfrac{S_{1}}{2}\)
2 \(S_{1}\)
3 \(\dfrac{S_{1}}{4}\)
4 \(2 S_{1}\)
PHXII03:CURRENT ELECTRICITY

357057 The electric resistance of a certain wire of iron is \(R\). If its length and radius are both doubled, then

1 The resistance will be doubled and the specific resistance will be halved
2 The resistance and the specific resistance, will both remain unchanged
3 The resistance will be halved and the specific resistance will be doubled
4 The resistance will be halved and the specific resistance will remain unchanged
PHXII03:CURRENT ELECTRICITY

357058 The radius \((r)\), length \((l)\) and resistance \((R)\) of a metal wire was measured in the laboratory as \(r = (0.35 \pm 0.05)cm,\) \(R = (100 \pm 10)ohm,\) \(l = (15 \pm 0.2)\,cm.\) The percentage error in resistivity of the material of the wire is

1 \(35.6 \%\)
2 \(39.9 \%\)
3 \(25.6 \%\)
4 \(37.3 \%\)
PHXII03:CURRENT ELECTRICITY

357059 A portion of length \(L\) is cut out of a conical solid wire. The two ends of this portion have circular cross-sections of \({r_1}\;\) and \({r_2}({r_1} > {r_2})\) radii. It is connected lengthwise to a circuit and a current \(I\) is flowing in it. The resistivity of the material of the wire \(\rho .\) Calculate the voltage developed across it.

1 \(\frac{{\rho LI}}{{\pi {r_1}}}\)
2 \(\frac{{\rho LI}}{{\pi {r_2}}}\)
3 \(\frac{{\rho LI}}{{\pi {r_1}{r_2}}}\)
4 \(\frac{{\rho LI}}{{\pi r_1^2}}\)
PHXII03:CURRENT ELECTRICITY

357056 Wheatstone bridge principle is used to measure the specific resistance \(\left(S_{1}\right)\) of given wire,having length \(L\), radius \(r\). If \(X\) is the resistance of wire, then specific resistance is; \({S_1} = X\left( {\frac{{\pi {r^2}}}{L}} \right).\)
If the length of the wire gets doubled then the value of specific resistance will be:

1 \(\dfrac{S_{1}}{2}\)
2 \(S_{1}\)
3 \(\dfrac{S_{1}}{4}\)
4 \(2 S_{1}\)
PHXII03:CURRENT ELECTRICITY

357057 The electric resistance of a certain wire of iron is \(R\). If its length and radius are both doubled, then

1 The resistance will be doubled and the specific resistance will be halved
2 The resistance and the specific resistance, will both remain unchanged
3 The resistance will be halved and the specific resistance will be doubled
4 The resistance will be halved and the specific resistance will remain unchanged
PHXII03:CURRENT ELECTRICITY

357058 The radius \((r)\), length \((l)\) and resistance \((R)\) of a metal wire was measured in the laboratory as \(r = (0.35 \pm 0.05)cm,\) \(R = (100 \pm 10)ohm,\) \(l = (15 \pm 0.2)\,cm.\) The percentage error in resistivity of the material of the wire is

1 \(35.6 \%\)
2 \(39.9 \%\)
3 \(25.6 \%\)
4 \(37.3 \%\)
PHXII03:CURRENT ELECTRICITY

357059 A portion of length \(L\) is cut out of a conical solid wire. The two ends of this portion have circular cross-sections of \({r_1}\;\) and \({r_2}({r_1} > {r_2})\) radii. It is connected lengthwise to a circuit and a current \(I\) is flowing in it. The resistivity of the material of the wire \(\rho .\) Calculate the voltage developed across it.

1 \(\frac{{\rho LI}}{{\pi {r_1}}}\)
2 \(\frac{{\rho LI}}{{\pi {r_2}}}\)
3 \(\frac{{\rho LI}}{{\pi {r_1}{r_2}}}\)
4 \(\frac{{\rho LI}}{{\pi r_1^2}}\)
PHXII03:CURRENT ELECTRICITY

357056 Wheatstone bridge principle is used to measure the specific resistance \(\left(S_{1}\right)\) of given wire,having length \(L\), radius \(r\). If \(X\) is the resistance of wire, then specific resistance is; \({S_1} = X\left( {\frac{{\pi {r^2}}}{L}} \right).\)
If the length of the wire gets doubled then the value of specific resistance will be:

1 \(\dfrac{S_{1}}{2}\)
2 \(S_{1}\)
3 \(\dfrac{S_{1}}{4}\)
4 \(2 S_{1}\)
PHXII03:CURRENT ELECTRICITY

357057 The electric resistance of a certain wire of iron is \(R\). If its length and radius are both doubled, then

1 The resistance will be doubled and the specific resistance will be halved
2 The resistance and the specific resistance, will both remain unchanged
3 The resistance will be halved and the specific resistance will be doubled
4 The resistance will be halved and the specific resistance will remain unchanged
PHXII03:CURRENT ELECTRICITY

357058 The radius \((r)\), length \((l)\) and resistance \((R)\) of a metal wire was measured in the laboratory as \(r = (0.35 \pm 0.05)cm,\) \(R = (100 \pm 10)ohm,\) \(l = (15 \pm 0.2)\,cm.\) The percentage error in resistivity of the material of the wire is

1 \(35.6 \%\)
2 \(39.9 \%\)
3 \(25.6 \%\)
4 \(37.3 \%\)
PHXII03:CURRENT ELECTRICITY

357059 A portion of length \(L\) is cut out of a conical solid wire. The two ends of this portion have circular cross-sections of \({r_1}\;\) and \({r_2}({r_1} > {r_2})\) radii. It is connected lengthwise to a circuit and a current \(I\) is flowing in it. The resistivity of the material of the wire \(\rho .\) Calculate the voltage developed across it.

1 \(\frac{{\rho LI}}{{\pi {r_1}}}\)
2 \(\frac{{\rho LI}}{{\pi {r_2}}}\)
3 \(\frac{{\rho LI}}{{\pi {r_1}{r_2}}}\)
4 \(\frac{{\rho LI}}{{\pi r_1^2}}\)
NEET Test Series from KOTA - 10 Papers In MS WORD WhatsApp Here