Explanation:
Given: \({A_c} - {A_m} = {80_V}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\left( 1 \right)\)
\({A_c} - {A_m} = {120_V}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\left( 2 \right)\)
Adding equation (1) and (2), we get \(A_{c}=100 {~V}\)
Amplitude of each side bond,
\(A = \frac{{\mu {A_c}}}{2}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\left( 3 \right)\)
where, \(\dfrac{A_{\max }-A_{\min }}{A_{\max }+A_{\min }}=\mu=\dfrac{120-80}{120+80}=\dfrac{40}{200}\)
Putting the value in (3),
\(A=\left(\dfrac{40}{200}\right) \times \dfrac{100}{2}=10 {~V}\)
