The Line Spectra of the Hydrogen Atom
« Previous Topic: Miscellaneous Problems on Atoms Next Topic: X Rays »
Join With Us for More Updates
PHXII12:ATOMS

356616 An electron makes a transition from orbit \(n = 4\) to the orbit \(n = 2d\) of a hydrogen atom. The wave number of the emitted radiations (\(R = \) Rydberg’s constant) will be

1 \(\frac{{3R}}{{16}}\)
2 \(\frac{{4R}}{{16}}\)
3 \(\frac{{2R}}{{16}}\)
4 \(\frac{{16}}{{3R}}\)
PHXII12:ATOMS

356617 Total energy of electron in an excited state of hydrogen atom is \( - 3.4\,eV\). The kinetic and potential energy of electron in this state

1 \(K = - 3.4\,{\text{ }}eV\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,{\text{ }}U = - 6.8\,{\text{ }}eV\)
2 \(K = 3.4\,{\text{ }}eV\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,{\text{ }}U = - 6.8\,{\text{ }}eV\)
3 \(K = - 6.8\,eV\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,{\text{ }}U = + 3.4\,{\text{ }}eV\)
4 \(K = + 10.2\,eV\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,{\text{ }}U = - 13.6\,{\text{ }}eV\)
KCET - 2016
PHXII12:ATOMS

356618 For Balmer series, wavelengthh of first line is \({\lambda _1}\) and for Brackett series, wavelength of first line is \({\lambda _2}\), then \(\frac{{{\lambda _1}}}{{{\lambda _2}}}\) is

1 \(0.081\)
2 \(0.162\)
3 \(0.198\)
4 \(0.238\)
MHTCET - 2015
PHXII12:ATOMS

356619 In the line spectra of hydrogen atom, the difference between the largest and the shortest wavelengths of the Lyman series is \(304\mathop A\limits^o \). The corresponding difference for the Paschan series in \(\mathop A\limits^o \) is : ____.

1 10533
2 1055
3 3550
4 15501
JEE - 2020
For More Updates join with Us
NEET Test Series from KOTA - 10 Papers In MS WORD WhatsApp Here
PHXII12:ATOMS

356616 An electron makes a transition from orbit \(n = 4\) to the orbit \(n = 2d\) of a hydrogen atom. The wave number of the emitted radiations (\(R = \) Rydberg’s constant) will be

1 \(\frac{{3R}}{{16}}\)
2 \(\frac{{4R}}{{16}}\)
3 \(\frac{{2R}}{{16}}\)
4 \(\frac{{16}}{{3R}}\)
PHXII12:ATOMS

356617 Total energy of electron in an excited state of hydrogen atom is \( - 3.4\,eV\). The kinetic and potential energy of electron in this state

1 \(K = - 3.4\,{\text{ }}eV\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,{\text{ }}U = - 6.8\,{\text{ }}eV\)
2 \(K = 3.4\,{\text{ }}eV\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,{\text{ }}U = - 6.8\,{\text{ }}eV\)
3 \(K = - 6.8\,eV\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,{\text{ }}U = + 3.4\,{\text{ }}eV\)
4 \(K = + 10.2\,eV\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,{\text{ }}U = - 13.6\,{\text{ }}eV\)
KCET - 2016
PHXII12:ATOMS

356618 For Balmer series, wavelengthh of first line is \({\lambda _1}\) and for Brackett series, wavelength of first line is \({\lambda _2}\), then \(\frac{{{\lambda _1}}}{{{\lambda _2}}}\) is

1 \(0.081\)
2 \(0.162\)
3 \(0.198\)
4 \(0.238\)
MHTCET - 2015
PHXII12:ATOMS

356619 In the line spectra of hydrogen atom, the difference between the largest and the shortest wavelengths of the Lyman series is \(304\mathop A\limits^o \). The corresponding difference for the Paschan series in \(\mathop A\limits^o \) is : ____.

1 10533
2 1055
3 3550
4 15501
JEE - 2020
NEET DIGITAL LIBRARY
PHXII12:ATOMS

356616 An electron makes a transition from orbit \(n = 4\) to the orbit \(n = 2d\) of a hydrogen atom. The wave number of the emitted radiations (\(R = \) Rydberg’s constant) will be

1 \(\frac{{3R}}{{16}}\)
2 \(\frac{{4R}}{{16}}\)
3 \(\frac{{2R}}{{16}}\)
4 \(\frac{{16}}{{3R}}\)
PHXII12:ATOMS

356617 Total energy of electron in an excited state of hydrogen atom is \( - 3.4\,eV\). The kinetic and potential energy of electron in this state

1 \(K = - 3.4\,{\text{ }}eV\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,{\text{ }}U = - 6.8\,{\text{ }}eV\)
2 \(K = 3.4\,{\text{ }}eV\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,{\text{ }}U = - 6.8\,{\text{ }}eV\)
3 \(K = - 6.8\,eV\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,{\text{ }}U = + 3.4\,{\text{ }}eV\)
4 \(K = + 10.2\,eV\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,{\text{ }}U = - 13.6\,{\text{ }}eV\)
KCET - 2016
PHXII12:ATOMS

356618 For Balmer series, wavelengthh of first line is \({\lambda _1}\) and for Brackett series, wavelength of first line is \({\lambda _2}\), then \(\frac{{{\lambda _1}}}{{{\lambda _2}}}\) is

1 \(0.081\)
2 \(0.162\)
3 \(0.198\)
4 \(0.238\)
MHTCET - 2015
PHXII12:ATOMS

356619 In the line spectra of hydrogen atom, the difference between the largest and the shortest wavelengths of the Lyman series is \(304\mathop A\limits^o \). The corresponding difference for the Paschan series in \(\mathop A\limits^o \) is : ____.

1 10533
2 1055
3 3550
4 15501
JEE - 2020
Join With Us for More Updates
PHXII12:ATOMS

356616 An electron makes a transition from orbit \(n = 4\) to the orbit \(n = 2d\) of a hydrogen atom. The wave number of the emitted radiations (\(R = \) Rydberg’s constant) will be

1 \(\frac{{3R}}{{16}}\)
2 \(\frac{{4R}}{{16}}\)
3 \(\frac{{2R}}{{16}}\)
4 \(\frac{{16}}{{3R}}\)
PHXII12:ATOMS

356617 Total energy of electron in an excited state of hydrogen atom is \( - 3.4\,eV\). The kinetic and potential energy of electron in this state

1 \(K = - 3.4\,{\text{ }}eV\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,{\text{ }}U = - 6.8\,{\text{ }}eV\)
2 \(K = 3.4\,{\text{ }}eV\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,{\text{ }}U = - 6.8\,{\text{ }}eV\)
3 \(K = - 6.8\,eV\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,{\text{ }}U = + 3.4\,{\text{ }}eV\)
4 \(K = + 10.2\,eV\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,{\text{ }}U = - 13.6\,{\text{ }}eV\)
KCET - 2016
PHXII12:ATOMS

356618 For Balmer series, wavelengthh of first line is \({\lambda _1}\) and for Brackett series, wavelength of first line is \({\lambda _2}\), then \(\frac{{{\lambda _1}}}{{{\lambda _2}}}\) is

1 \(0.081\)
2 \(0.162\)
3 \(0.198\)
4 \(0.238\)
MHTCET - 2015
PHXII12:ATOMS

356619 In the line spectra of hydrogen atom, the difference between the largest and the shortest wavelengths of the Lyman series is \(304\mathop A\limits^o \). The corresponding difference for the Paschan series in \(\mathop A\limits^o \) is : ____.

1 10533
2 1055
3 3550
4 15501
JEE - 2020
For More Updates join with Us