356594 Assertion :
Between any two given energy levels, the number of absorption transitions is always less than the number of emission transitions.
Reason :
Absorption transitions start from the lowest energy level only and may end at any higher energy level. But emission transitions may start trom any higher energy level and end at any energy level below it.

356595 If the wavelength of the first member of Lyman series of hydrogen is \(\lambda\). The wavelength of the second member will be

356596 If the electron in the hydrogen atom jumps from third orbit to second orbit, the wavelength of the emitted radiation in term of Rydberg constant is

356597 Assertion :
It is essential that all the lines available in the emission spectrum will also be available in the absorption spectrum.
Reason :
The spectrum of hydrogen atom is only absorption spectrum.

356598 Assertion :
Balmer series lies in the visible region of electromagnetic spectrum.
Reason :
\(\frac{1}{\lambda } = R\left( {\frac{1}{{{2^2}}} - \frac{1}{{{n^2}}}} \right),\) where \(n = 3,4,5...\)

356594 Assertion :
Between any two given energy levels, the number of absorption transitions is always less than the number of emission transitions.
Reason :
Absorption transitions start from the lowest energy level only and may end at any higher energy level. But emission transitions may start trom any higher energy level and end at any energy level below it.

356595 If the wavelength of the first member of Lyman series of hydrogen is \(\lambda\). The wavelength of the second member will be

356596 If the electron in the hydrogen atom jumps from third orbit to second orbit, the wavelength of the emitted radiation in term of Rydberg constant is

356597 Assertion :
It is essential that all the lines available in the emission spectrum will also be available in the absorption spectrum.
Reason :
The spectrum of hydrogen atom is only absorption spectrum.

356598 Assertion :
Balmer series lies in the visible region of electromagnetic spectrum.
Reason :
\(\frac{1}{\lambda } = R\left( {\frac{1}{{{2^2}}} - \frac{1}{{{n^2}}}} \right),\) where \(n = 3,4,5...\)

356594 Assertion :
Between any two given energy levels, the number of absorption transitions is always less than the number of emission transitions.
Reason :
Absorption transitions start from the lowest energy level only and may end at any higher energy level. But emission transitions may start trom any higher energy level and end at any energy level below it.

356595 If the wavelength of the first member of Lyman series of hydrogen is \(\lambda\). The wavelength of the second member will be

356596 If the electron in the hydrogen atom jumps from third orbit to second orbit, the wavelength of the emitted radiation in term of Rydberg constant is

356597 Assertion :
It is essential that all the lines available in the emission spectrum will also be available in the absorption spectrum.
Reason :
The spectrum of hydrogen atom is only absorption spectrum.

356598 Assertion :
Balmer series lies in the visible region of electromagnetic spectrum.
Reason :
\(\frac{1}{\lambda } = R\left( {\frac{1}{{{2^2}}} - \frac{1}{{{n^2}}}} \right),\) where \(n = 3,4,5...\)

356594 Assertion :
Between any two given energy levels, the number of absorption transitions is always less than the number of emission transitions.
Reason :
Absorption transitions start from the lowest energy level only and may end at any higher energy level. But emission transitions may start trom any higher energy level and end at any energy level below it.

356595 If the wavelength of the first member of Lyman series of hydrogen is \(\lambda\). The wavelength of the second member will be

356596 If the electron in the hydrogen atom jumps from third orbit to second orbit, the wavelength of the emitted radiation in term of Rydberg constant is

356597 Assertion :
It is essential that all the lines available in the emission spectrum will also be available in the absorption spectrum.
Reason :
The spectrum of hydrogen atom is only absorption spectrum.

356598 Assertion :
Balmer series lies in the visible region of electromagnetic spectrum.
Reason :
\(\frac{1}{\lambda } = R\left( {\frac{1}{{{2^2}}} - \frac{1}{{{n^2}}}} \right),\) where \(n = 3,4,5...\)

356594 Assertion :
Between any two given energy levels, the number of absorption transitions is always less than the number of emission transitions.
Reason :
Absorption transitions start from the lowest energy level only and may end at any higher energy level. But emission transitions may start trom any higher energy level and end at any energy level below it.

356595 If the wavelength of the first member of Lyman series of hydrogen is \(\lambda\). The wavelength of the second member will be

356596 If the electron in the hydrogen atom jumps from third orbit to second orbit, the wavelength of the emitted radiation in term of Rydberg constant is

356597 Assertion :
It is essential that all the lines available in the emission spectrum will also be available in the absorption spectrum.
Reason :
The spectrum of hydrogen atom is only absorption spectrum.

356598 Assertion :
Balmer series lies in the visible region of electromagnetic spectrum.
Reason :
\(\frac{1}{\lambda } = R\left( {\frac{1}{{{2^2}}} - \frac{1}{{{n^2}}}} \right),\) where \(n = 3,4,5...\)